Проект по Преобразувателна техника
Post on 28-Jul-2015
109 views
Embed Size (px)
TRANSCRIPT
1
.
:
: , IV , IV , I , . : 045217
: . .......................... // .
: 23.12.2007
2
:
- . -, :
n1, n2 n3. D3 . , :
3
1. , T T . . D2 e , D1 D3 . . i Uin/L, L .
2.
T1 . i . , i D1 ( ) . i2 : i 1 .n1 = i 2 .n2 , i 1 = i 2 . n1 n21 . ( n ).U i , 2
n
n1
(
n1 U i ).( ) n2 L .
n - n1 = n2. 2 ( ) . D2 , , . L2 D3.
4
3.
, , 2. D1 . D2. D3
:
5+ 5 V J 1 + 5 9 1 R 2 N M 3 7 4 1 E D 2 C 3 9 3 7 3 3 0 R L D 2 R 2 7 0 0 u 2 . 9 u C 3 1 3 0 0 u 0 C O J m C 3 4 3 0 0 0 u + 2 - 2 4 V 4 V 1 2 3 C O N 3 N 3 2 2 V 1 2
V
c 1 C 1 2 0 0 0 u / 4 8 0 V
V
i n L 1 4 1 n a v
1
T
1
5
V
o
D 1 u1 t 1 2 1 N 4
L
D
R
1
J
2 1 2 ~ 2 2 0 V 1 U N 2 4 + D 3 R 1 1 + 5 V k
4 ( 1
C
O
02 B B 0 4 G
D 1 1 D 2 7 1 N C 4 9 6 V L 2
5 N 4 9 3
8 s e c t i o n ) T R A N S F O T 2 D 3 1 5V o 1 u t 2 2 7 4 T R 6 8 A V N 1 N o S 4 u t 3 F O 9
0
2
3 7 1
D 1
6 N E R
C
. 4 9 1 1 1 0 u
4 93 33 70 C T
R
M
D B C 5 1 n 3
8 Z
1 X 8 4
3 3
8
u 7
0/ S O T
0
P R D 9 1 N 2 Q F 1 Q 4 3 7 6 R 5 1 k 1 1 4 0 k
R
2 2 k R 3 1 k
0
R 1 k
6
0R R P 7 O P 1 k 2 1 4 8 R 1 0 1 5 0 k 3 7 K 1 n U V C R V I S V A C 3 1 F B O U 6 T 1 0 1 8 2 k R 2 9 . 7 k P 7
N
8 C
0 7 1 n
1 Q U 2
C
0
6 4 n
R 2
7 . 2 k
K
A
4
3
1
0R 3 3 1 D 2 1 0 R E D 1 R 4 2 B C 4 C 2 2 1 2 0 n 9 7 1 n 1 k 2 1 N N 4 1 6 D 1 1 1 4 7 4 9 1 4 8 1 1 0 4 k R 0 1 . 3 3 / 1 W
R 2
1 . 2
1 k
1 2
3 4
O M P T / C T R E F E C N G N D S
0
P Q
C
8 1
7
R 1 0
1 0
7 k
C 5
8 6
8
5
0
:
I.
: :
1.
6
: = 0,8 0,9. = 0,85. :
n2 =
U 2m 5 = = 0,024 U 1m . 242 .0,85
n3 =
U 3m 24 = = 0,117 U 1m . 242 .0,85
:R2 = U 2m 5 = = 0,5 I 2m 10 R3 = U 3m 24 = = 24 I 3m 1
: :
,` R2 =
R2 0,5 = = 846,251 2 n 2 0,024 2
' R3 =
R3 24 = = 1763 2 n3 0,117 2
:
7
1 1 1 = ' + ' R2' R2 R31 1 1 = + ' R2 846 ,251 1763
1 = 0,00118 + 0,000567 ' R2 1 = 0,00174 ' R2 ' 0,00174 R2 = 1 ' R2 = 571,79
' Ri. .R2 20.571,79 11435,8 Re = = = = 19,324 ' Ri + R2 20 + 571,79 591,79
L1 , , . , ( R2, R3 R4) 2,7% ( p = UUm
2,7% )
L1 =
Re .t p p
=
19 ,324 .12 .10 6 = 0,012 H 2,7 / 100
8
2.
: :
N27. : :
V =
0 . .U 12m .t 2 pB 2 .L1
4. .10 7.3230 .242 2.(12.10 6 ) = = 61000 .10 9 m 3 = 61000 mm 3 2 0,22 .0,0122
V = 61000 mm3 B67332. : A=52mm; B=30,7 1 mm; C=23,9 0,4 mm; F= 14,4 0,7 mm; H = 46,1 0,8 mm; D= 11,15 0,2 mm; d= 3,25 0,15mm; R1 = 5,3 mm; R2 = 0,6 mm; R3 = 1 mm; R4 = 3 mm; l = 148 mm; Q = 93 mm2; V = 61 000 mm3; G = 70g. :L1 .l e = 0 . .Q 0,012 .0,148 = 67 ,423 4. .10 7.3230 .93 .10 6
W1OP =
. B:
B =
U 1m .t p W1OP .Q
=
242 .12 .10 6 1510 = = 0,46T 6 6968 ,22 67 ,423 .93 .10
9
B , = 3230. (3230 3230) 1%, . n, :
W2 = n 2 .W1 = 0.024 .67 ,423 = 1,639W3 = n3 .W1 = 0,117 .67 ,423 = 7,867
. , - . , . . , W2 = 2 W1 W3:
W1 2 = W1 = 83 1,639 67 ,423
W3 2 = W3 = 10 1,639 7,867
. , . , W1= 83 B:
10
B =
U 1m .t p W1 .Q
=
242 .12 .10 6 = 0,376 T 83 .93 .10 6
B = 0,376 = 3260. (3260 3230) 1%, . : :
P 2 = I 22m R2 + I 32m .R3 = 1 20.0,5 + 12.2 =4 7 W4 :
I1m =
P 2 74 = = 0,3 6A .U 1m 0,8 5.2 4 2
I 1m =
U 1m .t p L1
=
242 .12 .10 6 = 0,25 A 0,012
- I1m = 0,36 . fp = 50.103 Hz, I1m = 0,36 A tp = 12.10-6 s :I 1 = I 1m . I 2 = I 2m . I 3 = I 3m . f p .t p = 0,36 . 50 .10 3.12 .10 6 = 0,279 A f p .t p =10 . 50 .10 3.12 .10 6 = 7,746 A f p .t p =1. 50 .10 3.12 .10 6 = 0,775 A
11
=7 A : mm 2
d1 = 1,13.d 2 = 1,13 .
I1 0,279 = 1,13 = 0,2255 .10 3 m 6 7.10I2 7,746 = 1,13 = 1,189 .10 3 m 6 7.10
d 3 = 1,13.
I3 0,775 = 1,13 = 0,3759 .10 3 m 6 7.10
, 2.20 -1, , - . : d1 = 0,23 mm; d1 = 0,265 mm; q1 = 0,04155 mm2; ro1 = 0,422 /m; d2 = 1,20 mm; d2 = 1,265 mm; q2 = 1,1310 mm2; ro2 = 0,0156 /m; d3 = 0,38 mm; d3 = 0,425 mm; q3 = 0,11335 mm2; ro3 = 0,155 /m;
3. : : . , . .
12
0 b b, .K = 0 bn
.