проект по геометрии

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Post on 17-Jun-2015

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2. - ! ! ! 3. . 500 . .. 80 . 4. , . , , , , , . , , . . 5. , . , , . . , . . , . 6. : 7. : , , , , , , , . 8. ( ):" , , , ". *** ( 900 . . . ), ( 12 .), :" , , , , , ". *** Geometria Culmonensis ( 1400 .) :", , , , , , ". *** "", . . , :" , , , ". 9. . 10. 500 (, , ..). 11. . , . , , . , ABC : , , 4 , , , . 12. : ABC - : SABDE = SACFG + SBCHI 13. : ABDE - , ABC, ACFG BCHI -, . C CP DE ABDE Q; C E, B G. 14. ACE GBA QPBD CFGA; QPAE CHIB. , , ABDE ACFG BCHI, .. . , CAE = GAB(=A+90 ); , ACE AGB ( ) ( ). ACE PQEA; AE AP, , SPQEA = 2SACE. FCAG BAG GA AC; , SFCAG = 2SGAB. 15. : 1) CD . 2) s=AD/AC=AC/AB, AB*AD=AC2. 3) s=BD/BC=BC/AB, AB*BD=BC2. 4) , : AC2+BC2=*(AD + DB); AB2=AC2+BC2. . : ABC : AB2 = AC2 + BC2 16. : ABC - : BC2=AB2+AC2 : 1) CD AB AC ABC. ED AD, AC, B E. 2) ABED , : SABED=2*AB*AC/2+BC2/2 3) ABED , , : SABED= (DE+AB)*AD/2. 4) , : AB*AC+BC2/2=(DE+AB)(CD+AC)/2 AB*AC+BC2/2= (AC+AB)2/2 AB*AC+BC2/2= AC2/2+AB2/2+AB*AC BC2=AB2+AC2. 1882 . 17. - . , . 18. - , , , , . , , , , , . - , , , , , . 19.