第三章 反应速率和化学平衡
DESCRIPTION
第三章 反应速率和化学平衡. 化学热力学,讨论化学反应的 可能性和化学反应进行的程度。. 但实际上反应能否发生,平衡 状态要多长时间才能实现,是化学 动力学研究的范畴。. 化学反应速率,是化学动力学的 基础。. 过程的自发与否、反应进行程度 的大小,和反应的快慢是截然不同的 概念,看下面例子。. H 2 ( g ) + O 2 ( g ) —— H 2 O ( l ) = - 237.1 kJ • mol - 1. r G ⊖. m. 这个反应自发趋势很大,平衡 转化率极高。. - PowerPoint PPT PresentationTRANSCRIPT
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3. 1
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moldm3s1moldm3min1 moldm3h1 da
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3. 1. 1 2 H2O2 2 H2O + O2
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t 2 [ H2O2 ] 2 [ O2 ] 2t 3[ H2O2 ] 3 [ O2 ] 3 t 1 [ H2O2 ] 1 [ O2 ] 1
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O2 t1 t2 2 H2O2 2 H2O + O2 t 1 [ H2O2 ] 1 [ O2 ] 1t 2 [ H2O2 ] 2 [ O2 ] 2
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t2 t3 2 H2O2 2 H2O + O2t 2 [ H2O2 ] 2 [ O2 ] 2t 3[ H2O2 ] 3 [ O2 ] 3
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H2O2
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H2O2 2 H2O2 2 H2O + O2
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3. 1. 2
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[ O2 ] t
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AB
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t1 t2 t0
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t0 t0
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t0 t0 t0 t0 +
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t0 t0 +
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0 AB O CD
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AB CD
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d[O2] [O2] dt t
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H2O2 H2O2 2 H2O2 2 H2O + O2
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1
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2 t0
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3 CE DE
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CD t0
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a A + b B g G + h H 0
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3. 2
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3. 2. 1
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1 103 moldm3 2 HIg H2g+ I2g 973 K
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s dm3 3.5 1028 = 5.8 104moldm3s1
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1.
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1. 4
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E E E
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NO2 + CO NO + CO2
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NO2 + CO NO + CO2
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a NO2 + CO NO + CO2
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b NO2 + CO NO + CO2
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P
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P f
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2.
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Ea Ea Ea
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2 SO2 + O2 2 SO3 Ea = 251 kJmol1 N2 + 3 H2 2 NH3 Ea = 175.5 kJmol1
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HCl + NaOH NaCl + H2O Ea 20 kJmol1
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1 NO2 + CO NO + CO2
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NO2 + CO NO + CO2 N O C O
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2. NO2 + CO NO + CO2
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NO2 + CO NO + CO2 E E
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NO2 + CO NO + CO2 E
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Ea E E Ea
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1
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1 Ea rH1= Ea
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2
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2
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1 + 2 NO2 + CO NO + CO2 rH = rH1+ rH2 = Ea Ea
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rH = Ea Ea
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Ea > Ea rH > 0 rH = Ea Ea
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Ea> Ea rH < 0 rH = Ea Ea
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rH Ea Ea T Ea
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3. 3 3. 3.1
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NO2 + CO NO + CO2
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H2 + I2 2 HI 1 I2 2 I 2 I + I + H2 2 HI
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H2 + I2 2 HI 12
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3. 3. 2
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aA + bB gG + hH i = ki [ A ]a [ B ]b
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i = ki [ A ]a [ B ]b
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H2O aA + bB gG + hH G G = kG [ A ]a [ B ]b
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G = kG [ A ]a [ B ]b
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aA + bB gG + hH A A = kA [ A ]a [ B ]b
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A
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[ A ][ B ] A = kA [ A ]a [ B ]b
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i i AB [ A ][ B ] A = kA [ A ]a [ B ]b
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ki ki ki A = kA [ A ]a [ B ]b
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a b A = kA [ A ]a [ B ]b
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a + b A a B b A = kA [ A ]a [ B ]b
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aA + bB gG + hH a A b B a + ba + b
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3. 1
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1 i = ki [ SO2Cl2 ] SO2Cl2 SO2 + Cl2 1
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2 i = ki [ NO2 ]2 2 NO2 2 NO + O2 2
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3 i = ki [ NO2 ] [ CO ] NO2 + CO NO + CO2 3 2 2
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3. 3. 3
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3. 2 a A + b B g G + h H 1 1.0 1.0 1.2 102 2 2.0 1.0 2.3 102 3 1.0 2.0 4.8 102
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1 2 [ A ]0 2 G0 2 G [ A ] 1 a A + b B g G + h H 1 1.0 1.0 1.2 102 2 2.0 1.0 2.3 102
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1 3 [ B ]0 2 G0 4 G [ B ] 21 1.0 1.0 1.2 1023 1.0 2.0 4.8 102 a A + b B g G + h H
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G = kG [ A ] [ B ] 2 1 G [ A ] 1 G [ B ] 2
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1 G = kG [ A ] [ B ]2 1 kG
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= 1.2 102dm6 mol2s1 G = kG [ A ] [ B ] 2
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[ A ][ B ] G AB H
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3. 3 H2 + I2 2 HI 1 I2 2 I 2 2 I I2 3 2 I + H2 2 HI
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12 3 1 I2 2 I 2 2 I I2 3 2 I + H2 2 HI 123
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1 I2 2 I 2 2 I I2 3 2 I + H2 2 HI
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ABC D E 5 E ABC E 20 D 10
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D 10
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3 1 I2 2 I 2 2 I I2 3 2 I + H2 2 HI 3 i = ki3 [ H2 ] [ I ]2
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i = k i3 [ H2 ] [ I ]2 H2 + I2 2 HI
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k+ [ I2 ] = k [ I ]2 + =
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i = ki3 [ H2 ] [ I ]2
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i = ki [ H2 ] [ I2 ]
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H2 + I2 2 HI H2 + I2 2 HI
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3. 3 3. 3
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3. 4 CH3CHO CH4 + CO
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CH3CHO CH4 + CO
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CH4
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CH3CO CH3
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[ CH3CO ] 2 = 3
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[ CH3 ] 2 + 2 4 = 1 + 3
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2 + 2 4 = 1 + 3
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k1 [ CH3CHO ] = 2 k4 [ CH3 ]2
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k1 [ CH3CHO ] = 2 k4 [ CH3 ]2
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2 CH3 C2H6
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Na + 2 H2O 2 NaOH + H2 i = ki 0
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CO + Cl2 COCl2
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i = ki [ A ]m [ B ]n H2 + Br2 2 HBr
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HBr H2 + Br2 2 HBr
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0 3 1 2
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4 4
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3. 3. 4 1. i = ki [ A ]m [ B ]n ki [ A ][ B ] 1 i = ki ki
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i = ki [ A ]m [ B ]n ki ki ki
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2. i [ A ][ B ]
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i ki i = ki [ A ]m [ B ]n [ A ][ B ]
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ki
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3.
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i = ki ki i moldm3s1
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ki s1 i = ki [ A ]
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i = ki [ A ]2
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dm3mol1s1
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n ki moldm3n1s1 dm 3 n1 mol n1s1
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3. 4 aA bB
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3. 4. 1
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[A] = [A]0 ktd [A] = k d t
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[A] = [A]0 kt
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[A] = [A]0 kt
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[A] = [A]0 kt [A]0 k t [A]
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[A] t t1/2 [A] = [A]0 kt
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[A] = [A]0 kt
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k [A]0
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3. 4. 2 A = k [A]
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A = k [A]
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ln[A] ln[A]0 = kt
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ln[A] ln[A]0 = kt
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[A] t
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k
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3. 5 14C 14C 9.60 1014 %
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14C 1.10 1013 % 14C 5720
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[A] t
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k
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1121 t = 1121 a
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1
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1
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3. 5
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400 K
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Vant Hoff 10 K 2 ~ 4
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Vant Hoff 1901 2 N2O5 4 NO2 + O2
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3. 5. 1 k Arrhenius k T
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k Ea R T A k
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1 3
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Ea A T k
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1903
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3. 6 C2H5Cl C2H4 + HCl A = 1.6 1014 s1 Ea = 246.9 kJmol1 700 K k
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A = 1.6 1014 s1 Ea = 246.9 kJmol1
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= 6.02 105 s1 A = 1.6 1014 s1 Ea = 246.9 kJmol1
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710 K k710 = 1.09 104 s1 k700 = 6.02 105 s1 10 K 1.8
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500 K 510 K k 3.2 700 K 710 Kk 1.8
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Ea 500 ~ 510 K 700 ~ 710 K
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T1 k1T2 k2 Ea A
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21
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3. 7 2 NOCl 2 NO + Cl2 T1 = 300 K k1 = 2.8 105 dm3mol1s1 Ea A T2 = 400 K k2 = 7.0 101 dm3mol1s1
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= 101 kJmol1
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EaT1k1 A = 1.07 1013 dm3mol1s1 Ea = 101 kJmol1 T1 = 300 K k1 = 2.8 105 dm3mol1s1
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3. 5. 2
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Ea A 3. 7 k T Ea A
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Ea Ea
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3. 6 3. 6. 1
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Fe N2 + 3 H2 2 NH3
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2 SO2 + O2 2 SO3 aV2O5 bNO2c Pt CO + 2 H2 CH3OH CuOZnOCr2O3
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O2 O2
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NH3 Fe Al2O3 Fe
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Fe K2O Fe
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3. 6. 2 1. NO2 2 SO2 + O2 2 SO3
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2 MnO4 + 6 H+ + 5 H2C2O4 10 CO2 + 8 H2O + 2 Mn2+ Mn2+
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t0 tA tA tB
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tB
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Fe Ag H2O2
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2. 2 SO2 + O2 2 SO3 a V2O5b NO2c Pt
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a b + c d
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2 KClO3 2 KCl + 3 O2 MnO2 4 KClO3 3 KClO4 + KCl
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CO + 2 H2 CH3OH CuO ZnO Cr2O3 CO + 3 H2 CH4 + H2O Ni Al2O3
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3. A + B AB Ea
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Cat.
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rH
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NO2 SO2 NO2
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Fe N2 H2 N2 + 3 H2 2 NH3 Ea
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N2 + 2 Fe 2 NFe NFe + HFe Fe2NH Fe3NH2 + HFe Fe4NH3 Fe2NH + HFe Fe3NH2 Fe4NH3 4 Fe + NH3 Fe H2 + 2 Fe 2 HFe
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N2 + 3 H2 2 NH3
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3. 7
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12
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3. 7. 1
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1
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K
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K K
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g + h =a + b K 1
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Kp Kc
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Kc Kp Kc Kp
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c moldm3 p Pa R = 8.314 103 Padm3mol1K1
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Kc Kp
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H2O
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K2 =K12 2 K 2 n K n
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7 = 5+6 K7 = K5K6
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3. 7. 2
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[ A ] = 5 moldm3
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pA = 10 100 kPa
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1
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x i = 1 x i = 1 1
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K K K 1
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K K p 1
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100 kPa Kp K
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= 100 kPa
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= 1
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3. 7. 3
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3. 9 Kc = 9CO H2O 0.02 moldm3 CO
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t0 0.02 0.02 0 0 t 0.02x 0.02x x x
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= 9
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[ CO ] 0.015 moldm3 x = 0.015 moldm3
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= 75
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Kc = 9 50 % Kc = 1
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K
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2 3 4 5 1
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3. 7. 4
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AB [ A ][ B ] Q
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Q K
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Q Kc Q < Kc
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a A b B b B a A
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= k [ B ]b = k [ B ]b b B a A
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= k [ B ]b = k [ B ]b < 1
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+ = k+ [ A ]a + = k+ [ A ]a + > + 2 a A b B
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, = + < + + > + 2 < 1
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Q > Kc Q = Kc = + Q < Kc
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a K K b Q K Q K
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3. 8. 1 a A + b B g G + h H Q
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rGm < 0 rGm = 0 rGm > 0 rGm
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rGm = 0 Q = K
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rGm = RTlnK + RTlnQ
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Q < K rGm < 0
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Q > K rGm > 0 Q = K rGm = 0
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3. 8. 2 H S G
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rHm rSm rGm 298 K
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3. 8. 3
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Kc 3. 10 N2g+ 3 H2g 2 NH3g [ H2 ] = 0.15 moldm3 [ N2 ] = 2.1 moldm3 [ NH3 ] = 19 moldm3
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Kc = 5.1 104 moldm32 N2g+ 3 H2g 2 NH3g
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Kc = 5.1 104 moldm32
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p K K ? c = 1 moldm3 K
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p c N2g+ 3 H2g 2 NH3g
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3. 11 2 NO2g N2O4g 298 K K
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= 99.8 51.3 2 = 2.8kJmol12 NO2g N2O4g
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K = 3.10 = 1.13
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K
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K = 8.9 1024
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= 8.9 1024 100 kPa = 8.9 1019 Pa
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298 K CaCO3 CO2 8.9 1019 Pa 298 K CO2 CaCO3
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Na2SO410 H2Os Na2SO4s+ 10 H2Og 273 K K = 4.08 1025
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Na2SO410 H2Os Na2SO4s+ 10 H2Og K = 4.08 1025
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273 K Na2SO410 H2O H2O 0.364 kPa H2O Na2SO410 H2O
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273 K H2O 0.611 kPa H2O 0.364 kPa
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3. 9 3. 9. 1
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AQ Q Q < K
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Q Q K Q
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K K Q K
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3. 9. 2 [ CO ] = [ H2O ] = 0.005 moldm3 [ CO2 ] = [ H2 ] = 0.015 moldm3
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H2Og [ H2O ] = 1.0 moldm3 CO
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Kc = 9 [ CO ] = [ H2O ] = 0.005 moldm3 [ CO2 ] = [ H2 ] = 0.015 moldm3
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Qc H2Og [ H2O ] = 1.0 moldm3
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H2Og [ H2O ] = 1.0 moldm3 [ CO ] = [ H2O ] = 0.005 moldm3 [ CO2 ] = [ H2 ] = 0.015 moldm3
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= 0.045
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Qc < Kc t0 0.005 1.0 0.015 0.015 t 0.005 x 1 x 0.015 + x 0.015 + x Kc = 9 Qc = 0.045
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x = 0.00495 = 9
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[ CO ] 0.015 moldm3 = 75 %
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[ CO ] = 0.02 moldm 3 = 99.75 %
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3. 9. 3
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N2g+ 3 H2g 2 NH3g 2
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Qp pi = p xi xi p 2 pi 2
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N2g+ 3 H2g 2 NH3g
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Qp < Kp
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Q K
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3. 9. 4 K
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T1 T2
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21
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RT1T2 > 0
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T2 > T1 T2 T1 > 0
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T2 < T1 T2 T1 < 0
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Le Chatelier
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K T rH
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k T Ea 3. 7