浙江省平阳中学 高树浪
DESCRIPTION
驾驭好知识 - 方法 - 思维三条线. ------ 谈 2012 高考化学二轮复习策略. 浙江省平阳中学 高树浪. 明线. 知识. 方法. 暗线. 思维. 主线. 高考考什么?知识 + 方法 + 思维. 抓考点,搭框架,完善知识结构. 抓重点,建核心,凝炼学科规律. 抓难点,重训练,提升思维能力. 考什么 ?. 怎么考 ?. 怎么复习 ?. 二轮复习最关键三个问题. 表 3.2009~2011 (新课程 I 卷). 表 3.2009~2011 (新课程 II 卷). 第 26 题:元素化合物、元素周期律、物质结构综合题. 09 高考. - PowerPoint PPT PresentationTRANSCRIPT
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3.2009~2011 I
2009201020117STS89Li-Al/FeS10B1112:13
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3.2009~2011 II
2009201020111414NaFeNNa2OFe2O3Na2CO3NaHCO315FeIS1515141516151417X14
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2626[14]CDXYZXYZXYZ10DGJMI0920102011
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2612
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2615XXXANaOHXABCDCNaOHBACD12161(1) C (2) X (3) A________(4) D (5) X_______(6) CNaOHYY [25KSPMg(OH)2=5.611012KSPAl(OH)3=31034]
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121IO35I6H===3I23H2O2Fe 3 2I==2Fe 2 I24KIO22H2O==2I24KOH201126
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2
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326(15)SO2NOxNa+Mg2+NH4+Cl-SO32-SO42-NO3-NO2-4KIBaCl2NaOHAgNO3KMnO4Ksp(Ag2SO4) = 1.2010-51 2KI 3Cl- 4NONOSO2O2 NO 2012
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201013)NO2-SO42-SO32-CO32-Cl-I-5pHpH7AgNO3BaCl2BaCl2NH42FeSO42KSCNNO2-CO32-Cl-A. B. C. D.
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(l)Na+Mg 2+NH 4+Cl- S032-S042-N03-N02-4S032- N02- ? AKIBBaCl2CNaOHDKMnO4(2)OH-H+NH4+Cl-c(NH4+)>cCl- (3)25Ksp(RX)=1.8 X 10-10, Ksp(RY)=1.8X 10-16, Ksp(R2Z)=1.8 X 10-12 RXRYR2ZR+
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K+Na+Fe 2+Fe 3+SO4 2-NO2-CO32-20mL (1) (2)NaOHxg (3)0.10 molL-lKMnO4VmL(4)ANa+Fe 3+SO42-K+CO32-B(1)SO42-C(2)(3)Fe 3+D(3)NO2-
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27109102
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KSP pH()
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.2011157002LCOH2O,CO(g)H2O(g) CO2H2(g) t1t2:A.t1minv(H2)0.40/t1 molL1 min1B.0.60molCO1.20 molH2On(CO2)0.40 molC.0.20molH2OCOH2OD.8000.64
/minn(CO)/molH2O/ mol01.200.60t10.80t20.20
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27(15)(t-BuNO)2(t-BuNO)2 2(t-BuNO) 1(t-BuNO)2c00.50 molL-12065 %20K = 2(t-BuNO)2 201227(2)0.10 molL-1 2060%20K =___________________( (4)________()2CH3COCH3(aq) CH3COCH2COH(CH3)2(aq)
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.NO2N2O4N2O42NO2()NO2N2O41 L
(1)XYX NO2abcdbd Xbd
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NO2N2O4N2O42NO2()NO2N2O41 L
(2)10 minNO2v(NO2)=0.04mol/(Lmin)25 min0.4 mol NO20.04mol/(Lmin)0.4 mol NO2
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NO2N2O4N2O42NO2()NO2N2O41 L
(3)25 min( ) A. B. C. D.N2O4B D
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NO2N2O4N2O42NO2()NO2N2O41 L
(4)K( )()c(NO2)/c(N2O4)( )() A.N2O4 B.NO2 C. D.DAB
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15 pHZn2+ Zn(OH)42-
1ZnCl22Zn(OH)2K sp= 3Zn2+ Zn2+ pH 41L 1.00 molL-1 ZnCl2NaOHpH=6NaOH 525PbCl2cHCl/ molL-1 0.50 1.00 2.04 2.90 4.02 5.16 5.78103 cPbCl2/ molL-15.10 4.91 5.21 5.90 7.48 10.81 14.01 aPbCl2 bPbCl20.50 molL-1 cPbCl2 dPbCl2 1NaOHZn(OH)42- 2pH=7lgZn2+=-3.0 Ksp=C(Zn2+) C2 (OH-)=10-3(10-7)2=10-17 3pH(8.0 12.0) 4Ksp=10-17pH=6C(Zn2+)=0.1mol/Ln(Zn2+)=0.9moln(NaOH)=1.8mol 5PbCl2Cl-PbCl2 Cl-PbCl2PbCl2 (1)Zn2++4OH-=[Zn(OH)4]2+ (2)10-17 (3)(8.0 12.0) (4)1.80 (5)abcd
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1+1
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1212
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1.20117A.pHpHB.20 mL0.5000 molL1 H2SO480mL0.1000 molL1 H2SO4C.2D.3Cl2HClD
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O2 H2 Cl2HCl H2S NH3CO2 SO2 NO2 NO COC2H4 C2H2
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1231234
123
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MgSO4NaClpH
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(?)
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2010
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2009Cl2
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16. ABCDE 1AKCl2DCl2CDDCO2HClD_ _______C_ ________ 1 2Cl2 + 2H2O (g) + C = 4HCl + CO2HClD
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2E___________________ 3DKACl2B_________B__________ 2E 3 Cl216. ABCDE
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412 mol L 110 mLMnO2Cl20.03 mol____5E______________ 45 Cl2 + 2OH = Cl + ClO + H2O 16. ABCDE
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C12Na2CO3(1)A (2)Y A. CC14 BNaCl C DNaHCO3(3)C NaHCO3D C 1NaHC03 2NaHC03 ()HN03BaCl2AgNO3
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4)CNa2CO30.1molCl2.1C
lcab 2 3
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1123
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Na2O2H2OH2O2Na2O2H2OH2O2()_________________________________________________________________MnO2,KMnO4 ,KI,Na2S,H2SFeCl2KSCN5 AFe2O3BCuOCNa2SiO3DMgSO4
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2HCNO
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3NaClOFeSO4
3mol/LH2SO4,0.01mol/KMnO4,3%H2O2-.
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*
gcm-320161.197.8*0.9624 155.695*0.9478100.00.9982
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H2SO4 55600.5h TKK a151155b34.61.83~48.0cdNaCl eMgSO4
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____________________________________________________ ___________________________ cd dNaCl eMgSO4______________ ________ ___ _____ _________________
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1 2221K13d b e c a (2) 11 1 142
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29111 2
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2009
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201010. B2AC17H22N4O6BCO2CNH3D
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201111ABpHCD
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12345
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1---
-NH-O
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ABCDFED
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....pKapKa=-lgKa
-COOH-SHH2OpKa3.79.816
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XC12H13O6Br
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2010
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10-2 B
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ABCXC16H14O41
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C4H8O275
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1---=0=1=2 4
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C20H16N2O5
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2---321C4H10O2C4H8O2
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2---CO2
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1Mannich23
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E1AA B E
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20119613-AA9-1ABCA B C
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ABC
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,
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,
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2912FC16H16O2 3D-COOH4DE 5E6B