医 用 化 学
DESCRIPTION
医 用 化 学. 生 化 教 研 室 (8403) 张 学 礼. 概 述. 一、 《 医用化学 》 主要内容 二、为什么要学习 《 医用化学 》 三、怎样学好 《 医用化学 》 四、课程安排. 一、 《 医用化学 》 主要内容 第一部分 溶液(第 1 章) 第二部分 有机化学( 2 ~ 8 章) 第三部分 生物分子化学( 9 ~ 12 章). 二、为什么要学习 《 医用化学 》. 通过学习掌握医学上必需的化学基本知识。. CO 2 + H 2 O. 脂肪酸. 乙酰乙酸 丙酮. ╳. - PowerPoint PPT PresentationTRANSCRIPT
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(8403)
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1
2~8
9~12
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42
30 1 6 2~8 13 9~12 11
12(3467
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(60%) + (40%)
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NaCl
= +
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1/3
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*
=+
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* 1.
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1/3
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2.
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>100 nm
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1~100 nm
*1.
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2.*
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3.
4. * 1. 2.
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1. 1~100 nm* 1 2 3* 1 2 3
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2. < 1nm* 1 2 3
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() 100ml mg/dlmg% 90 mg/dl10090
mg ml 100%
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1. 80~120mg/dl 9~11mg/dl2. g/dl g % 4~5g/dl3. ug/dlug % , 50~174 ug/dl
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24hr5%10%500ml 0.9% 500 = 4.5g 5% 500 + 10% 500 2 = 125g
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1.
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2.,
=
=
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Ca2+= 40g/2 = 20g Cl-= 35.5g/1 =35.5g CaOH2 = 74g /2 = 37g NaCl = 58.5 g/ 1 = 58.5g CuO = 80g / 2 = 40g H2SO4 = 98g / 2 = 49g
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3.
=1000Ca2+= 40 mg/2 = 20mg H2SO4 = 98 mg / 2 = 49mg
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4.
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g gmEq mg mg = 1000Eq=mEq=
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14g NaOH
NaOH = 40g/1 = 40g NaOH = 4g/40g = 0.1 Eq
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20.5Eq H2SO4
H2SO4 = 98g/2 = 49g H2SO4 = 0.5 49g = 24.5g
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31.95g K+
K+ = 39g/1000 =0.039g=39mg
K+ = 1.95g/0.039g = 50mEq
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() Na2SO4mEq Na2SO4 2Na+ + SO42+ 142 2 23=46 96 142mg/71mg 46mg/23mg 96mg/48mg 2 2 2 *
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*
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0.9%NaClml,Na+ Cl-
00mlNaCl 0.9% 500ml = 4.5g = 4500 mg NaCl58.5 mg NaCl4500mg/58.5mg = 77 mEq NaClNa+ = Cl-77 mEq
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80mEqmEq, 10%KCl ml?
1NaCl 80mEq 80 58.5 =4680mg=4.68g 4.68 0.9% = 520ml 2KCl 4mEq 4 74.5 =298mg=0.298g 0.298 10% = 3ml
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() 1/ mEq/L
= mEq/L
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mg/dl(mg%) mEq/LNa+K+Ca2+Mg2+ 32620102.4142552358.4154Cl-HCO3-SO42-HPO42-365.7164.71.69.617.5700010327125167559.1 154
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Na+ 326mg /dl,Na+ mEq Na+ 326mg/dl Na+ 3260 mg Na+ 3260/23=142mEq/L 32610 3262323/10
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/10 f mEq/L = 100ml/f 100ml=mEq/L f
100/10=/L*
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2. *
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0.1MHAcpH3NaAc[H+][HAc]HAcpH35
HAc H+ + Ac-NaAc Na+ + Ac-
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*
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pH7.35 7.45
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pH*
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.() CH3COOH CH3COONa (HAc NaAc) H2CO3 NaHCO3 NH3H2O NH4ClC6H5NH2~C6H5NH2.HCl NaH2PO4 K2HPO4
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.* H2CO3 NaHCO3 H2CO3 H+ + HCO3-
NaHCO3 Na+ + HCO3-
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HCl HCl H+ + Cl- H+ + HCO3- H2CO3pHHCO3-NaOH NaOH Na+ + OH- OH- + H+ H2O )H2CO3 H+ + HCO3- pHH2CO3
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2NaH2PO4 Na2HPO4
H2PO4- H+ + HPO42-
Na2HPO4 2Na+ + HPO42-
NaH2PO4 Na+ + H2PO4-
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HCl HCl H+ + Cl- H+ + HPO42- H2PO4-pHHPO42-NaOH NaOH Na+ + OH- OH- + H+ H2O )H2PO4- H+ + HPO42- pH,H2PO4-
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pH
pH7.35 7.45H2CO3NaHCO3
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pH HA MAHA H+ + A-MA M+ + A- [HA]A-MA Ka = = [ H+] [A-] [ H+][]
[HA] [][ H+]= Ka [][]
pH = -lgKa lg( ) -lgKapKa
pH = pKa + lg ( )-*[][][][]
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110.1mol HAc0.2mol NaAcPH25HAcKa = 1.7610-5
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210ml 0.1M NaH2PO41ml 0.2M Na2HPO4PHH3PO4Ka2= 6.210-8
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1pH
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2[] /[] [] /[] =1pH=pKa, 3456*
1 [] /[] =1/1010pH pHpKa 1pKb 1
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1.pKa(pKb)pH2.pKapHpH3.0.05M~0.2M
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7 pH=51000ml? 1: HAc pKa(3.7~5.6) HAc ~NaAc 2pH = pKa + lg[]/[] 5.0 =4.75 + lg[]/[] lg[]/[]) =5.0-4.75 = 0.25 []/[] =1.78 ( 3 ) 0.1M HAc 0.1M NaAc []/[] =C.V/C.V = V/ V=1.78 ( 4 ) V+V = 1000 ml ( 5 ) 34 V=641 ml; V= 359 ml
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pH7.35~7.45
pH< 7.3 pH >7.5
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, NaHCO 3 pH 7.35
H 2 CO 3 pH
( ) NaHCO 3 pH 7.45
H 2 CO 3 pH pH = pKa + lg
[NaHCO3][H2CO3]
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*
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Pa* 1 2
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*
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/mOsm/L mmol/Lmmol/L
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1 5% mOsm/L (5 10 1000)/180 = 278(mOsm/L)
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2 0.9%NaCl mOsm/L (0.9 10 1000)
= 308 (mOsm/L) 58.5 2
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3 330mg %Na+mOsm/L. (330 10)/23 = 144(mOsm/L)
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1. *280~ 320mOsm/L 0.9%NaCl5%1.9%1.4%NaHCO3 280mOsm/L0.3%NaCl.,320mOsm/L 50%
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NaCl0.9% NaCl1.5% NaCl0.5% NaCl
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2.*
NaClNaHCO3 C6H12O6
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12 Na+ K+
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Na+ K+GlcAACO2O2Cl-HCO-
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12
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4.53 2.93 1.60 2.93 H2O0 H2O 0 H2O
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1.2.3.4.5.6.23457.8.-9 9.10.