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Moment Distribution Method 1 F AB B A AB M L 3 2 L EI 2 M ± Δ θ + θ = ) ( F BA B A BA M L 3 2 L EI 2 M ± Δ θ + θ = ) ( บทที6 Moment Distribution Method ใชวิเคราะห Indeterminate Beam และ Rigid Frame ไดทุกชนิด ประยุกตมาจากสมการ Slope-Deflection ซึ่งแยกโมเมนตที่ปลายชิ้นสวนใหเปนผลของ 4 เหตุการณ 1) Fixed End Moments 2) ผลของ Rotation ทีA อยางเดียว 3) ผลของ Rotation ทีB อยางเดียว 4) ผลของ Relative Translation ของปลาย A และ B Moment Distribution Method 2 ขั้นตอนของการทํา Moment Distribution Locking จํากัดใหทุก Joint ไมมีการเคลื่อนทีแรงที่มากระทําในชิ้นสวนของโครงสรางทําให เกิด Fixed End Moments ขึ้น (M F AE ,M F EA ,M F ED ,.... ) Unlocking Unbalanced Moment ที่จุด E ทําใหโครงสราง เคลื่อนที่ไปจนเกิดแรงตานรวมพอดีที่สมดุล ขณะเดียวกันการบิดของโครงสรางทําใหเกิด โมเมนตที่ปลายดานไกล (A ,B ,C หรือ D ) ของชิ้นสวนเรียกวา “ Carry-Over Moment ” ทําทั้ง 2 ขั้นตอนจนกวาจะไดสภาพที่สอดคลองกับฐานรองรับและจุดตอของโครงสราง โมเมนตที่ปลายใด หาไดจากผลรวมของโมเมนตจากทุกขั้นตอน B A C D E M F AE M F DE M F CE M F EA M F ED M F EA +M F EB +M F BC +M F ED B A C D E

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  • Moment Distribution Method 1

    FABBAAB ML

    32LEI2

    M

    += )(

    FBABABA ML

    32LEI2

    M

    += )(

    6 Moment Distribution Method Indeterminate Beam Rigid Frame Slope-Deflection

    4 1) Fixed End Moments2) Rotation A 3) Rotation B 4) Relative Translation A B

    Moment Distribution Method 2

    Moment DistributionLocking Joint

    Fixed End Moments (MFAE ,MFEA ,MFED ,.... )

    Unlocking Unbalanced Moment E (A ,B ,C D ) Carry-Over Moment

    2

    B

    A C

    D

    EMFAE

    MFDE

    MFCEMFEA

    MFED

    MFEA+MFEB+MFBC+MFED

    B

    A C

    D

    E

  • Moment Distribution Method 3

    Moment Distribution

    Moment Slope-Deflection Moment

    Rotation

    Fixed End Moments ( Slope-Deflection )

    + -

    +-

    Moment Distribution Method 4

    Fixed-End MomentsP

    L

    L/28

    PL8

    PL WL12

    WL2

    12WL2

    W

    L

    a

    )( 2222

    a3aL8L6L12

    Wa+ )( a3L4

    L12Wa

    2

    3

    P

    L

    a2

    2

    LPab b

    2

    2

    LbPa

    ML

    a)( a2b

    LMb

    2 b

    )( ab2LMa

    2

    WL20

    WL2

    30WL2

    W

    L96WL5 2

    96WL5 2

    L/2

    1

    3

    5

    2

    4

    6

    7

  • Moment Distribution Method 5

    Distribution Factor Distribution Joint

    MFEDM

    B

    A C

    D

    E MFEC

    MFEB

    MFEA

    Frame

    Joint E

    ()

    E

    M

    B

    A C

    D

    E

    B

    A C

    D

    E

    Moment Distribution Method 6

    Slope-Deflection

    EEAEEAEA 4K4LEI

    M == )(

    EECEECEC 4K4LEI

    M == )(

    EEBEEBEB 4K4LEI

    M == )(

    EEDEEDED 4K4LEI

    M == )(

  • Moment Distribution Method 7

    Joint E

    K4KKKK4MMMMM EEDECEBEAEEDECEBEA =+++=+++= )(

    MK

    KM

    KK

    MK

    KM

    KK

    K4M EDECEBEA

    E )()()()( +

    +

    +

    =

    =

    EDECEBEA MMMMM +++=

    Distributed Moments

    Distribution Factor

    DEA DEB DBC DED Joint E Distribution Factor

    Moment Distribution Method 8

    Carry-Over Factor Carry-Over Moment (A) (B)

    Slope-Deflection

    MBAMAB A BA

    AAB LEI

    4M = ABA LEI

    2M =

    ABAB M21

    M =

    Carry-Over Moment

    Carry-Over Factor (CBA) (B) Fixed End

  • Moment Distribution Method 9

    EX.1 ( 1Joint) Moment Distribution

    B

    A C

    D

    E3I

    2I

    4II

    1.2 k/ft.

    10 ft10 ft

    10 ft

    10 ft

    Moment Distribution Method 10

    1) Fixed End Moments (FEM)

    2) Distributed Moments (DM)

    Fixed End Moment

    Distributed Moments

    D

    B

    A CE10 k-ft. .

    .ftk10

    121021

    12WL

    FEMFEM22

    AEEA =

    ===

    100.1100.210

    0.310

    0.410

    )( 0FEM =

    EI2010EI2

    LEI

    KEI1010EI

    LEI

    K EBEA .;. ======

    EI4010EI4

    LEI

    KEI3010EI3

    LEI

    K EDEC .;. ======

    EIEI40EI30EI20EI10K =+++= ....

    10EIEI10KKDF EAEA ././ ===

    40DF30DF20DF EDECEB .;.;. ===

  • Moment Distribution Method 11

    2) Distributed Moments (DM) - Unbalance Moment

    E = (0.110) + (0.210) + (0.310) + (0.410) = -10 ()

    0010DFUMDM AEAE === 11010DFUMDM EAEA === .

    0010DFUMDM BEBE === 22010DFUMDM EBEB === .

    0010DFUMDM CECE === 33010DFUMDM ECEC === .

    0010DFUMDM DEDE === 44010DFUMDM EDED === .

    DFMomentUnbalanceDM =

    Moment Distribution Method 12

    3) Carry-Over Moments (COM)COM = DM () / 2

    4) ()

    Carry-Over Moments

    DF 0 0.1 0 0.2 0 0.3 0 0.4 AE EA BE EB CE EC DE ED1) FEM -10 10 0 0 0 0 0 02) DM 0 -1 0 -2 0 -3 0 -43) COM -0.5 0 -1 0 -1.5 0 -2 04) -10.5 9 -1 -2 -1.5 -3 -2 -4

    B

    A C

    D

    1 2

    342

    0.5

    1.51

    DF= 0.1+0.2+0.3+0.4 = 1

  • Moment Distribution Method 13

    EX.2 Moment Distribution( EI )

    B C

    60 ft. 20 ft. 20 ft.

    A1 k/ft. 20 k

    Moment Distribution Method 14

    1) Fixed End Moments (FEM)

    Fixed End Moments2) Distributed Moments (DM)

    - Distribution Factor (DF)

    Distributed Moments

    B CA300 k-ft. 300 k-ft. 100 k-ft. 100 k-ft.

    .ftk30012601

    12WL

    FEMFEM22

    ABBA =

    ===

    .ftk1008

    40208

    PLFEMFEM CBBC =

    ===

    EI025040EI

    KEI01667060EI

    K BCBA .;. ====

    EI041670EI0250EI016670K ... =+=

    )(Fixed0DFAB =

    200

    BCA

    80 12060 ft. 20 ft. 20 ft.

    40EI041670EI016670KKDF BABA .././ ===

    )(Fixed0DFCB =

    60EI041670EI02570KKDF BCBc .././ ===

  • Moment Distribution Method 15

    2) Distributed Moments (DM) - Unbalance Moment

    A ; (-300) = 300 ()

    B ; (300-100) = -200 ()

    C ; 100 = -100 ()

    00300DFUMDM ABAAB ===

    8040200DFUMDM BABBA === .

    12060200DFUMDM BCBBC === .

    00100DFUMDM CBCCB ===

    Moment Distribution Method 16

    3) Carry-Over Moments (COM)COM = DM () / 2

    4) ()

    DF 0 0.4 0.6 0 AB BA BC CB1)FEM -300 300 -100 1002)DM 0 -80 -120 03)COM -40 0 0 -604) -340 220 -220 40

    B CA340 220 220 40

    B CA40 80 120 60

    Carry-Over Moments

  • Moment Distribution Method 17

    EX.3 A 0.0016 Rad. Moment Distribution ( EI = 10,000 k-ft2.)

    B C

    A

    10 ft.

    20 ft.

    2II =0.0016 Rad.

    Moment Distribution Method 18

    1) = 0.0016 Rad. FEM

    2) Distributed Moment (DM)

    - Distribution Factor (DF)

    ..., ftk4610

    00160000104LEI4

    FEMAB =

    =

    =

    ..., ftk2310

    00160000102LEI2

    FEMBA =

    =

    =

    B

    A

    10 ft.=0.0016 Rad.

    3.2

    6.4

    EI1020EI2

    KEI1010EI

    K BCBA .;. ==== EI20EI10EI10K ... =+=

    )(Fixed0DFAB = 50EI20EI10KKDF BABA .././ ===

    )(Fixed0DFCB = 50EI20EI10KKDF BCBC .././ ===

  • Moment Distribution Method 19

    2) Distributed Moments (DM) - Unbalance Moment

    A ; 6.4 = -6.4 ()

    B ; (3.2 - 0) = -3.2 ()

    C ; 0

    0046DFUMDM ABAAB === .

    615023DFUMDM BABBA ... ===

    615023DFUMDM BCBBC ... ===

    0DFUMDM CBCCB ==

    Moment Distribution Method 20

    3) Carry-Over Moments (COM)COM = DM () / 2

    4) ()

    DF 0 0.5 0.5 0 AB BA BC CB1)FEM 6.4 3.2 0 02)DM 0 -1.6 -1.6 03)COM -0.8 0 0 -0.84) 5.6 1.6 -1.6 -0.8

    BC

    A5.6

    1.6 0.8

  • Moment Distribution Method 21

    Joint Joint Moment Distribution

    FEM (Locking) DM (Unlocking) COM ()

    Joint 1 Joint Moment Distribution Carry-Over Moment

    FEM DM COM COM ()

    Moment Distribution Method 22

    EX.4 Moment Distribution ( E I )

    BC

    4 m. 2 m. 2 m.

    A 300 kg/m.800 kg

    EI EI

  • Moment Distribution Method 23

    1) Fixed End Moments (FEM)

    2) Distributed Moments (DM)

    BC

    4 m. 2 m. 2 m.

    A300 kg/m.

    800 kg

    EI EI

    -400 400 -800 800 .mkg40012

    430012WL

    FEM22

    AB =

    ==

    .mkg8008

    480012

    43008PL

    12WL

    FEM22

    BC =

    ==

    .mkg40012

    430012WL

    FEM22

    BA =

    ==

    .mkg8008

    480012

    43008

    PL12WL

    FEM22

    CB =

    +

    =+=

    EI2504EI

    KEI2504EI

    K BCBA .;. ==== EI50EI250EI250K ... =+=

    )(Fixed0DFAB = 50EI50EI250KKDF BABA .././ ===

    )(Hinge1DFCB = 50EI500EI250KKDF BCBc .././ ===

    Moment Distribution Method 24

    2) Distributed Moments (DM) - Unbalance Moment

    A ; 400 = -400 ()

    B ; (400-800) = -400 ()

    C ; 800 = -800 ()

    00400DFUMDM ABAAB ===

    20050400DFUMDM BABBA === .

    20050400DFUMDM BCBBC === .

    8001800DFUMDM CBCCB ===

  • Moment Distribution Method 25

    DF 0 0.5 0.5 1FEM -400 400 -800 800DM 0 200 200 -800COM 100 0 -400 100DM 0 200 200 -100COM 100 0 -50 100DM 0 25 25 -100COM 12.5 0 -50 12.5DM 0 25 25 -12.5COM 12.5 0 -6.25 12.5DM 0 3.125 3.125 -12.5COM 1.563 0 -6.25 1.563DM 0 3.125 3.125 -1.563COM 1.563 0 -0.781 1.563DM 0 0.391 0.391 -1.563 -172 857 -857 0

    3) Carry-Over Moments (COM)COM = DM () / 2

    4) ()

    BA

    300 kg/m.172 857

    B C

    300 kg/m.800 kg

    857

    Moment Distribution Method 26

    EX.5 Moment Distribution (SFD) (BMD)( E I )

    B

    C

    A3 m.

    6 m.

    2EIEI3 T/m.

    2.5 T

    3EI

    6 m.

    DE

    6 T3 m.

    3 m.

    2EI

  • Moment Distribution Method 27

    1) Fixed End Moments (FEM)

    2) Distributed Moments (DM)

    B

    C

    A3 m.

    6 m.

    2EIEI

    3 T/m. 2.5 T

    3EI

    6 m.

    DE

    6 T3 m.

    3 m.

    2EI.// mT9126312WLFEM 22BD ===

    ..// mT548668PLFEMCB ===.// mT9126312WLFEM 22DB ===

    ..// mT548668PLFEMBC ===... mT57352PLFEMDE ===

    0FEMFEM BAAB ==

    EI50006EI3

    KEI333306EI2

    KEI166706EI

    K BCBDBA .;.;. ======

    EIEI5000EI3330EI1670K =++= ...

    )(Fixed0DFAB =

    1670KKDF BABA ./ == 5000KKDF BCBC ./ ==3330KKDF BDBD ./ ==

    )(Fixed0DFCB = )(Cantiliver0DFED = )(Hinge1DFDB =

    Moment Distribution Method 28

    A B C D AB BA BD BC CB DB DEDF 0 0.167 0.333 0.5 0 1 0FEM 0 0 -9 4.5 -4.5 9 -7.5DM 0 0.75 1.5 2.25 0 -1.5 0

    COM 0.35 0 -0.75 0 1.125 0.75 0DM 0 0.125 0.25 0.375 0 -0.75 0COM 0.063 0 -0.35 0 0.188 0.125 0DM 0 0.058 0.117 0.275 0 -0.125 0COM 0.029 0 -0.063 0 0.088 0.059 0DM 0 0.011 0.021 0.032 0 -0.059 0COM 0.006 0 -0.03 0 0.016 0.011 0DM 0 0.005 0.01 0.015 0 -0.011 0 0.45 0.95 -8.30 7.35 -3.08 7.5 -7.5

  • Moment Distribution Method 29

    (BMD) (SFD)

    B

    C

    AD E

    0.45

    -0.95-8.30

    -3.08

    -7.35

    -7.50

    (T.-m.)

    B

    C

    A D E-0.23

    -0.23

    -3.71

    9.13

    -8.87

    2.5

    (T.)

    Moment Distribution Method 30

    Modified Stiffness Factor (K) (Far End) 4 1) Stiffness Factor Fixed ()

    KAB = EI/L ( Stiffness Factor )

    )( AAB 2LEI2

    M = ALEI

    4 = )(BA

  • Moment Distribution Method 31

    2) Stiffness Factor Hinge (Modified Stiffness Factor K)

    KAB = 3EI/4L (Modified Stiffness Factor Hinge)

    3) Stiffness Factor (B = - A)

    KAB = EI/2L (Modified Stiffness Factor B = - A)

    )( BAAB 2LEI2

    M +=BA

    2 AB /=

    )( BAAB 2LEI2

    M = AL2EI1

    4 = )(

    AL4EI3

    4 = )(

    BABA

    Moment Distribution Method 32

    4) Stiffness Factor (B = A)

    KAB = 3EI/2L (Modified Stiffness Factor B = A)

    )( BAAB 2LEI2

    M += AL2EI3

    4 = )(

    BA BA=

  • Moment Distribution Method 33

    EX.6 4 Moment Distribution( E I )

    BC

    4 m. 2 m. 2 m.

    A 300 kg/m.800 kg

    EI EI

    Moment Distribution Method 34

    2) BC ( Hinge)

    DF 0 0.571 0.429 1 AB BA BC CBFEM -400 400 -800 800DM 0 228.4 171.6 -800COM 114.2 0 -400 0DM 0 228.2 171.6 0COM 114.2 0 0 0DM 0 0 0 0 -171.6 856.8 -856.8 0

    4EI

    LEI

    KBA == 16EI3

    L4EI3

    KBC ==

    BC

    4 m. 2 m. 2 m.A

    300 kg/m.800 kg

    EI EI-400 400 -800 800

    3

    16EI7

    16EI3

    4EI

    K =+=

  • Moment Distribution Method 35

    EX.7 Moment Distribution ( EI )

    B C

    A1.2 k/ft.

    12 k

    D

    12 k

    10 ft.10 ft. 10 ft. 10 ft.20 ft.

    Moment Distribution Method 36

    - Fixed End Moments (FEM)

    DF 0 0.667 0.333 AB BA BCFEM -30 30 -40DM 0 6.67 3.33COM 3.33 0 0DM 0 0 0 -26.27 36.67 -36.67 36.67 -36.67 26.67

    .// ftk30820128PLFEMAB ===

    ././ ftk4012202112WLFEM 22BC ===

    ./ ftk3082012FEMBA ==

    ./. ftk40122021FEM 2CB ==

    .// ftk30820128PLFEMCD === ./ ftk3082012FEMDC ==

    40EI

    340EI

    20EI

    K20EI

    KBA =+== ,

  • Moment Distribution Method 37

    EX.8 Moment Distribution ( EI )

    DC

    1.2 k/ft. 1.2 k/ft. 1.2 k/ft.

    A B E F

    24 ft. 24 ft. 24 ft. 24 ft. 24 ft.

    Moment Distribution Method 38

    - Fixed End Moments (FEM)

    - Stiffness Factor (K) Distribution Factor (DF) B

    C

    .././ ftk65712242112WLFEMFEM 22BAAB ====

    96EI7

    24EI

    32EI

    K24EI

    LEI

    K32EI

    L4EI3

    K BCBA =+===== ,,

    .././ ftk65712242112WLFEMFEM 22DCCD ====

    .././ ftk65712242112WLFEMFEM 22FEEF ====

    16EI

    48EI

    24EI

    K48EI

    242EI1

    K24EI

    LEI

    K CDCB =+===== ,,

    5710KKDF4290KKDF BCBCBABA ./;./ ====

    3330KKDF6670KKDF CDCDCBCB ./;./ ====

  • Moment Distribution Method 39

    DF 1 0.429 0.571 0.667 0.333FEM -57.6 57.6 0 0 -57.6DM 57.6 -24.7 -32.9 38.4 19.2COM 0 28.8 19.2 -16.5 0DM 0 -20.6 -27.4 -11 5.5COM 0 0 5.5 -13.7 0DM 0 -2.36 -3.14 9.14 4.56COM 0 0 4.57 -1.57 0DM 0 -1.96 -2.61 1.05 0.52COM 0 0 0.53 -1.31 0DM 0 -0.23 -0.30 0.87 0.44COM 0 0 0.44 -0.15 0DM 0 -0.19 -0.25 0.10 0.05COM 0 0 0.05 -0.13 0DM 0 -0.02 -0.03 0.09 0.04 0 36.3 -36.3 27.3 -27.3

    Moment Distribution Method 40

    Moment Distribution Joint

    Joint(=0)

    Frame Joint

    Frame (Sway)

  • Moment Distribution Method 41

    Superposition ( Joint Translation) 1) Joint Translation R Joint- Moment Distribution R 2) R R- Joint

    R

    R=

    +

    Moment Distribution Method 42

    R Joint Joint Translation

    R Joint Translation

    1) Joint Translation Joint- F.E.M. Lock Joint

    2) Joint Rotation 1)- Unlock Joint Moment Distribution

    Note - Moment Distribution F.E.M. Joint Translation

    =

    +

    R1

    R2

  • Moment Distribution Method 43

    EX.9 Moment Distribution ( E I )

    3EIa

    Wb

    L

    EIc

    L

    Moment Distribution Method 44

    1) Joint Translation

    ac ca cb bcDF 0 0.75 0.25 0FEM -0.0833 0.0833 -0.0833 0.0833 WL2

    DM 0 0 0 0 -0.0833 0.0833 -0.0833 0.0833 WL2

    R

    wL/2wL/2

    w

    wL/2

    -0.0833wL2 wwL/2 wL/2

    0.0833wL20.0833wL2

    bccbcaac FEMFEMFEMFEM ===

    222 WL121

    12242112WL === /./

    LEI4

    KLEI

    KLEI3

    K cbca === ;;

    R3EIa

    Wb

    L

    EIc

    L

    )(Fixed0DFac =

    750LEI4LEI3DFca .)//()/( ==

    )(Fixed0DFbc =

    250LEI4LEIDFcb .)//()/( ==

    - Fixed End Moment (FEM)

    - Stiffness Factor (K)

    - Distribution Factor (DF)

  • Moment Distribution Method 45

    WL3EIa W b

    L

    EIc

    L

    22ac LEI18

    LEI36

    FEM

    =

    =)(

    2) R Joint-Translation Fixed-End Moment Moment Distribution

    - Fixed End Moment (FEM) ac ca cb bcDF 0 0.75 0.25 0FEM -18 -18 6 6 EI/L2

    COM 4.5 0 0 1.5DM 0 0 0 0 -13.5 -9 9 7.5 EI/L2

    22ca LEI18

    LEI36

    FEM

    =

    =)(

    2cb LEI6

    FEM

    = 2bc LEI6

    FEM

    =

    3EI

    a b

    L

    EIcL

    Moment Distribution Method 46

    Fy = 0

    ac ca cb bc -13.5 -9 9 7.5 EI/L2 = 1 / 39(1) -0.0833 0.0833 -0.0833 0.0833(2) -0.3462 -0.2308 0.2308 0.1923

    M -0.4295 -0.1475 0.1475 0.2756 WL2

    WL3EI

    a22.5EI/L2

    b

    L

    EIc

    L

    16.5EI/L22LEI516522WL /)..( +=

    39WL

    LEI 2

    2 =

  • Moment Distribution Method 47

    EX.10 Joint Moment Distribution( E I )

    9 kN.

    EI

    8/3EI

    6 m.

    6 m.

    A

    B C

    Moment Distribution Method 48

    - 9 kN. B

    - C BC Roller

    - Fixed End Moment (FEM)

    =1.

    6 m.

    6 m.

    RC

    A

    B

    6 m.

    6 m.

    9 kNC

    A

    B

    ;)(6EI

    LEI

    K ABBA ==

    6EI636EI2FEMFEM BAAB /)/(/ ===

    9EI4

    63EI8

    LEI

    K BCBC === )(

    3EI

    9EI4

    43

    KBC ==

    0FEMFEM CBBC ==

    2EI

    3EI

    6EI

    K =+=

  • Moment Distribution Method 49

    - Distribution Factor (DF)

    AB BA BC CBDF 0 0.333 0.667 1FEM -0.1667 -0.1667 0 0 EIDM 0 0.0556 0.1111 0COM 0.0278 0 0 0DM 0 0 0 0 -0.1389 -0.1111 0.1111 0 EI

    )(Fixed0DFAB = 3330EI500EI1670KKDF BABA .././ ===

    )(Hinge1DFCB = 6670EI500EI3330KKDF BCBC .././ ===

    Moment Distribution Method 50

    - B (Fx=0)0.0417EI = 9 kN. EI = 216 ( EI )

    AB BA BC CB

    -0.1389 -0.1111 0.1111 0 EI = 216M -30 -24 24 0

    9 kN.0.1111EI

    0.1111EI

    0.1389EIA

    BC

    0.0417EI

    0.1417EI

    0.1111EI

    0.1389EIA

    B0.1111EI

    0.0185EI 0.0185EI

    B C

  • Moment Distribution Method 51

    EI = Moment-Distribution 9 kN. Factor

    9 kN.24

    24

    30A

    B C

    Moment Distribution Method 52

    EX.11 Moment Distribution( E I )

    600 kg/m

    EI

    2EI

    2.5 m.

    1.5 m.300 kg

    1.5 m.

    1.0 m.A

    B C

    D

    1.5EI

  • Moment Distribution Method 53

    - Fixed End Moments (FEM)

    - Stiffness Factor (K) Distribution Factor (DF) B ; ;)(

    3EI

    LEI

    K BABA ==

    .. mkg51128

    33008PL

    FEMAB =

    =

    =

    .. mkg51128

    33008

    PLFEMBA =

    ==

    ... mkg531212

    5260012WL

    FEM22

    BC =

    =

    =

    ... mkg531212

    5260012WL

    FEM22

    CB =

    ==

    5EI4

    52EI2

    LEI

    K BCBC === .)(

    15EI17

    5EI4

    3EI

    K =+=

    600 kg/m

    EI

    2EI

    2.5 m.

    1.5 m.300 kg

    1.5 m.

    1.0 m.A

    B C

    D

    1.5EI

    )(Fixed0DFAB = 294015EI17

    3EI

    KK

    DF BABA ./ === 7060

    15EI17

    5EI4

    KK

    DF BCBC ./ ===

    Moment Distribution Method 54

    C ;

    1) Moment Distribution Joint Translation

    600 kg/m

    300 kg

    A

    B C

    D

    5EI4

    52EI2

    LEI

    K CBCB === .)(

    32EI9

    44EI513

    L4EI3

    K CDCD =

    ==.)(

    160EI173

    32EI9

    5EI4

    K =+=

    )(Hinge1DFDC =7400160EI173

    5EI4

    KK

    DF CBCB ./ === 2600

    160EI173

    32EI9

    KK

    DF CDCD ./ ===

  • Moment Distribution Method 55

    A B C D AB BA BC CB CD DCDF 0 0.294 0.706 0.740 0.260 1FEM -112.5 112.5 -312.5 312.5 0 0DM 0 58.8 141.2 -231.2 -81.3 0

    COM 29.4 0 -115.6 70.6 0 0DM 0 34.0 81.6 -52.2 -18.4 0 COM 17 0 -26.1 40.8 0 0DM 0 7.67 18.43 -30.2 -10.6 0COM 3.84 0 -15.1 9.22 0 0DM 0 4.44 10.66 -6.82 -2.40 0COM 2.22 0 -3.41 5.33 0 0DM 0 1.00 2.41 -3.94 -1.39 0COM 0.50 0 -1.97 1.21 0 0DM 0 0.58 1.39 -0.80 -0.31 0COM 0.29 0 -0.45 0.70 0 0DM 0 0.13 0.32 -0.52 -0.18 0(1) -59.3 219.1 -219.1 114.6 -114.6 0

    Moment Distribution Method 56

    (H) = 300-96.7-28.7= 174.6 kg.

    ()

    D 28.7

    28.7600 kg/m

    C701.8

    B708.2

    114.6

    300

    A

    B

    97.6

    203.3

    59.3

    219.1

  • Moment Distribution Method 57

    2) H Joint-Translation Fixed-End Moment

    Moment Distribution

    - Fixed End Moments (FEM)

    A

    B C

    D

    3EI2

    33

    3EI2

    FEMFEM BAAB

    =

    == )(

    0FEMFEM CBBC ==

    16EI9

    43

    4EI51

    2FEMFEM DCCD

    =

    == ))(.(

    174.6 kg

    A

    B C

    D

    Moment Distribution Method 58

    AB BA BC CB CD DCDF 0 0.294 0.706 0.740 0.260 1FEM -0.6667 -0.6667 0 0 -0.5625 -0.5625 EIDM 0 0.196 0.471 0.4163 0.1463 0.5625

    COM 0.098 0 0.2082 0.2355 0.2813 0DM 0 -0.0612 -0.1470 -0.3824 -0.1344 0COM -0.0306 0 -0.1912 -0.0735 0 0 DM 0 0.0562 0.1350 0.0544 0.0191 0COM 0.0281 0 0.0272 0.0675 0 0DM 0 -0.0080 -0.0192 -0.0500 -0.0175 0COM -0.0040 0 -0.0250 -0.0096 0 0DM 0 0.0074 0.0176 0.0071 0.0025 0COM 0.0037 0 0.0036 0.0088 0 0DM 0 -0.0011 -0.0025 -0.0065 -0.0023 0COM -0.0006 0 -0.0033 -0.0013 0 0DM 0 0.0010 0.0023 0.0010 0.0003 0(2) -0.5721 -0.4764 0.4764 0.2673 -0.2672 0 EI

  • Moment Distribution Method 59

    - EI (Fx =0)0.3495EI + 0.0668EI = 174.6EI = 174.6/0.4163 = 419.4 EI = 419.4 (2)

    (1) -59.3 219.1 -219.1 114.6 -114.6 0(2) -0.5721 -0.4764 0.4764 0.2673 -0.2672 0 EI = 419.4(2) -239.9 -199.8 199.8 112.1 -112.1 0

    AB BA BC CB CD DC(1)+(2) -299.2 19.3 -19.3 226.7 -226.7 0 kg.-m.

    174.6 kg

    A

    BC

    D 0.0668EI

    0.3495EI

    Moment Distribution Method 60

    EX.12 Moment Distribution ( EI )

    100 kg

    A

    B C

    D

    3 m. 5 m. 3 m.

    4 m.

    4 m.

  • Moment Distribution Method 61

    1) Joint Translation- Fixed End Moments- H = 100 kg.

    2) Joint Translation-

    100 kg

    A

    B C

    D

    3 m. 5 m. 3 m.

    4 m.

    4 m.H=100 kg

    100 kg

    A

    B C

    D

    Joint Translation

    =

    == EI256

    53

    5EI2

    FEMFEM BAAB )(

    0FEMFEM CBBC ==

    =

    == EI256

    53

    5EI2

    FEMFEM DCCD

    45

    SIN

    =

    =

    Moment Distribution Method 62

    - Stiffness Factor (K)

    B ;

    C ;

    - Distribution Factor (DF)

    ;)(5EI

    LEI

    K BABA == ;)( 5EI

    LEI

    K BCBC == 5EI2

    5EI

    5EI

    K =+=

    ;)(5EI

    LEI

    K CBCB == ;)( 5EI

    LEI

    K CDCD == 5EI2

    5EI

    5EI

    K =+=

    )(Fixed0DFAB = 50EI400EI20DFDF BCBA ../. ===

    )(Fixed0DFDC = 50EI400EI20DFDF CDCB ../. ===

  • Moment Distribution Method 63

    AB BA BC CB CD DCDF 0 0.5 0.5 0.5 0.5 0FEM -0.24 -0.24 0 0 0.24 0.24DM 0 0.12 0.12 -0.12 -0.12 0COM 0.06 0 -0.06 0.06 0 -0.06DM 0 0.03 0.03 -0.03 -0.03 0COM 0.015 0 -0.015 0.015 0 -0.015DM 0 0.0075 0.0075 -0.0075 -0.0075 0 COM 0.0038 0 -0.0038 -0.0038 0 -0.0038DM 0 0.0019 0.0019 -0.0019 -0.0019 0 COM 0.0009 0 -0.0009 0.0009 0 -0.0009DM 0 0.0004 0.0005 -0.0005 -0.0004 0COM 0.0002 0 -0.0003 0.0003 0 -0.0002DM 0 0.00015 0.00015 -0.00015 -0.00015 0

    -0.1601 -0.0801 0.0801 -0.0801 0.0801 0.1601 EI

    Moment Distribution Method 64

    - EI (Fx=0)100 = 0.0601EI 2 EI = 831.9 EI = 831.9

    -0.1601 -0.0801 0.0801 -0.0801 0.0801 0.1601 EI = 831.9

    -

    AB BA BC CB CD DCM -133.2 -66.6 66.6 -66.6 66.6 133.2 kg.-m.

    100 kg B CD

    A0.0601EI

    0.0601EI

  • Moment Distribution Method 65

    Joint Translation 1 Degree of Freedom Moment Distribution

    n DOF. Joint Translation n+1 case

    Case 1 Joint Translation Rotation Case 2 (n+1) Joint Translation Case 1 DOF.

    Lock Joint Translation Case

    Moment Distribution Method 66

    3 3 DOFS Joint Translation

    F1

    F2

    F3

    Case 1 Lock DOF

  • Moment Distribution Method 67

    F1 = x1 + r12 x2 + r13 x3F2 = r21 x1 + x2 + r23 x3F3 = r31 x1 + r32 x2 + x3

    r31 x1r21 x1

    x1

    Case 2 Lock DOF 1

    r32 x2

    r12 x2

    x2

    Case 3 Lock DOF 2

    r23 x3r13 x3

    x3

    Case 4 Lock DOF 3

    x1 , x2 x3

    Moment Distribution Method 68

    EX.13 Moment Distribution (EI )

    50 k

    100 k 20 ft.

    20 ft.

    10 ft.

    6 ft.4 ft.

    6 ft.4 ft.

    A

    B

    C D

    E

    F

  • Moment Distribution Method 69

    - 2 DOF Joint Translation 3 Case (n+1)

    Case 1) DOF Joint Translation Lock - Fixed End Moments (FEM)

    .ftk14410

    64100L

    PabFEM 2

    2

    2

    2

    BE =

    ==

    0FEM =

    .ftk9610

    64100L

    bPaFEM 2

    2

    2

    2

    EB =

    ==

    .ftk7210

    6450L

    PabFEM 2

    2

    2

    2

    CD =

    ==

    .ftk4810

    6450L

    bPaFEM 2

    2

    2

    2

    EB =

    ==

    50 k

    100 k 20 ft.

    20 ft.

    10 ft.

    6 ft.4 ft.

    6 ft.4 ft.

    A

    B

    CD

    E

    F

    Moment Distribution Method 70

    - Distribution Factor (DF) B ;

    E ; C ;

    D ;

    Moment Distribution

    ;)(20EI

    LEI

    K BABA == ;20EI

    KBC = 5EI1

    10EI

    20EI

    20EI

    K =++=;10EI

    KBE =

    500DF250DF250DF BEBCBA .;.;. ===

    500DF250DF250DF EBEDEF .;.;. ===;)(

    20EI

    LEI

    K BACB == ;10EI

    KCD = 20EI3

    10EI

    20EI

    K =+=

    6670DF3330DF CDCB .;. ==

    6670DF3330DF DCDE .;. ==

    50 k

    100 k

    43.6

    20.4

    52.6

    40.893.4

    34.1

    41.2

    31.115.6

    3.06 2.345

    1.045

    0.3372.5

  • Moment Distribution Method 71

    Case 2) Joint B E Lock - Fixed End Moments (FEM)

    - Distribution Factor (DF) Case 1 Moment Distribution

    200EI3

    203

    20EI2

    FEMFEMFEMFEM EFFEBAAB

    =

    ==== )(

    0FEM =

    20 ft.

    20 ft.

    10 ft.

    A

    B

    C D

    E

    F

    x1200EI3

    203

    20EI2

    FEMFEMFEMFEM DEEDCBBC

    =

    ==== )(

    2.07x10.455x1

    2.07x1

    0.272x1 0.273x1

    0.273x10.273x1

    2.70x1 2.70x1

    0.21x12.49x12.07x1

    2.49x1x1

    Moment Distribution Method 72

    Case 3) Joint C D Lock - Fixed End Moments (FEM)

    - Distribution Factor (DF) Case 1 Moment Distribution

    0FEM =

    200EI3

    203

    20EI2

    FEMFEMFEMFEM DEEDCBBC

    =

    ==== )(20 ft.

    20 ft.

    10 ft.

    A

    B

    CD

    E

    F

    x2

    4.90x2

    1.19x2

    4.90x2

    0.095x2 0.095x2

    0.635x20.635x2

    1.27x2 1.27x2

    3.82x25.08x2

    2.07x25.08x2

    x2

  • Moment Distribution Method 73

    - 3

    D 1.045 = -0.455X1 + X2 E 0.330 = -X1 + 1.19X2

    X1 Case 2 X2 Case 3 Case 1 , Case 2 Case 3

    2 1 3

    21AB X6350X732420M ... +=

    .. ftk2116M AB =

    X1 = 1.99 kX2 = 1.95 k

    Moment Distribution Method 74

    EX.14 Moment Distribution1) B2) A , B C ( E I )

    6 m. 4 m.

    3EIA

    20 kN

    B EIC

    3 m.

  • Moment Distribution Method 75

    1) Joint Translation B- Fixed End Moments (FEM)

    - Stiffness Factor (K)

    FEM

    - Distribution Factor (DF)

    3EIA

    20 kNB

    6 m.EI C

    4 m.

    3 m.

    0FEMFEM BAAB ==

    .. mkN7534

    3120L

    bPaFEM 2

    2

    2

    2

    CB =

    ==

    .. mkN25114

    3120L

    PabFEM 2

    2

    2

    2

    BC =

    ==

    EI50KBA .= EI250KBC .=EI750K .=

    6670DFBA .= 3330DFBC .=

    PB C

    Lba

    Moment Distribution Method 76

    AB BA BC CBDF 0 0.667 0.333 0FEM 0 0 -11.3 3.8DM 0 7.5 3.8 0

    COM 3.8 0 0 1.9DM 0 0 0 0 3.8 7.5 -7.5 5.6

    1 B

    2 Joint Translation

    BABCB VVR =

    BCCBBCBC L320MMV /)( ++=

    .).( mkN317RB =

    ABBAABCB LMMV /)( +=

    RB

    VBA B VBC

    A

    RBB

    C= EI50FEMAB .= EI50FEMBA .= EI3750FEMBC .= EI3750FEMCB .

  • Moment Distribution Method 77

    AB BA BC CBDF 0 0.667 0.333 0

    FEM -0.5 -0.5 0.375 0.375DM 0 0.083 0.042 0

    COM 0.042 0 0 0.021DM 0 0 0 0 -0.458 -0.417 0.417 0.396 EI(2) -22.8 -20.7 20.7 19.7

    (1)+(2) -19 -13.2 13.2 25.3

    RB = 0.349EI EI = 17.3 / 0.349 = 49.7 / EI = 49.7 / EI

    A = -19.0 kN-m. B = 13.2 kN-m. C = -25.3 kN-m.

    Moment Distribution Method 78

    EX.15 Moment Distribution( EI)

    1.2 k/ft.

    24 ft. 24 ft. 24 ft. 24 ft.

    DCA B E

  • Moment Distribution Method 79

    - C Joint C C= 0 Fixed Support

    - Fixed End Moments (FEM)

    - Stiffness Factor (K) Distribution Factor (DF)

    1.2 k/ft.

    24 ft. 24 ft.

    CAB

    ../ ftk65712WLFEMFEM 2BAAB ===

    96EI7

    24EI

    32EI

    K24EI

    LEI

    K32EI

    L4EI3

    K BCBA =+===== ,,

    ../ ftk65712WLFEMFEM 2DCCD ===

    5710KKDF4290KKDF BCBCBABA ./;./ ====

    B ;

    Moment Distribution Method 80

    AB BA BC CB CD DC DE EDDF 1 0.429 0.571 0FEM -57.6 57.6 -57.6 57.6DM 57.6 0 0 0COM 0 28.8 0 1.9DM 0 -12.36 -16.44 0COM 0 28.8 0 -8.22DM 57.6 0 0 0 0 74.04 -74.04 49.38 -49.38 74.04 -74.04 0

  • Moment Distribution Method 81

    -

    1.2 k/ft.

    24 ft. 24 ft. 24 ft. 24 ft.

    DCA B E1.2 k/ft.

    CB CD 0 Simply Support

    Moment Distribution Method 82

    - Fixed End Moments (FEM)

    - Stiffness Factor (K) Distribution Factor (DF)

    1.2 k/ft.

    DCA B E24 ft. 24 ft. 24 ft. 24 ft.

    1.2 k/ft.

    CB CD 0

    ../ ftk65712WLFEMFEM 2CBBC ===

    ../ ftk65712WLFEMFEM 2DCCD ===

    1.2 k/ft.

    24 ft. 24 ft.

    CAB

    16EI

    32EI

    32EI

    K32EI

    L4EI3

    K32EI

    L4EI3

    K BCAB =+===== ;;

    50161321DFDF CBBC .)//()/( ===

    B ;

    )(Hinge1DFAB =

  • Moment Distribution Method 83

    AB BA BC CB CD DC DE EDDF 0.6 0.46 0.23 1FEM 0 0 -57.6 57.6DM 0 28.8 28.8 0COM 0 0 0 0DM 0 0 0 0 0 28.8 -28.8 57.6 -57.6 -28.8 28.8 0

    Moment Distribution Method 84

    EX.16 Moment Distribution( ACI)

    2 k/ft. CA B4 k/ft. 2 k/ft.

    4 k/ft.4 k/ft. 2 k/ft.

    D

    EF G

    H

    I J K L

    EI

    EI

    EIEI

    EI EI

    EI

    EI

    2EI

    2EI2EI

    2EI2EI

    2EI

    16 ft. 16 ft. 16 ft.

    12 ft.

    12 ft.

  • Moment Distribution Method 85

    -

    - Fixed End Moments (FEM)

    - Stiffness Factor (K) Distribution Factor (DF)

    2 k/ft. CA B4 k/ft. 2 k/ft.

    D

    EEI

    2EI 2EI2EI

    16 ft. 16 ft. 16 ft.

    12 ft.FEI

    GEI

    HEI

    ../ ftk674212162FEMFEMFEMFEM 2DCCDBAAB =====

    60DF24EI5

    8EI

    12EI

    K8EI

    16EI2

    K12EI

    K ABABAE .;; ==+====

    460481381DFBA .)//()/( ==

    A ;

    ../ ftk338512164FEMFEM 2CBBC ===

    48EI13

    K12EI

    K16EI

    32EI2

    K8EI

    K BFBCBA ===== ;;; B ;

    2304813161DFBC .)//()/( ==

    Moment Distribution Method 86

    AB BA BCDF 0.6 0.46 0.23FEM -42.67 42.67 -85.33 DM 25.60 19.62 9.81COM 9.81 12.80 0DM -5.89 -5.89 -2.49COM -2.49 -2.49 0DM 1.76 1.35 0.68COM 0.68 0.88 0DM -0.41 -0.4 -0.40 -14.06 69.09 -77.98

  • Moment Distribution Method 87

    14.06 k-ft.(MAF)

    Joint [68.09+(-77.98)] = 9.89 k-ft.(MBF)

    AB BA BCM -14.06 69.09 -77.98

    7.03

    14.06

    14.06 68.09

    9.89

    77.98

    4.95

    77.98

    - 1/2 Carry-Over Unlock

    Moment Distribution Method 88

    - Fixed End Moments (FEM)

    - Stiffness Factor (K)

    ../ ftk674212162FEMFEMFEMFEM 2DCCDBAAB =====

    StiffnessColumn12EI

    KKKK FJBFEIAE ====

    ../ ftk338512164FEMFEM 2CBBC ===

    4 k/ft. GE F 2 k/ft.4 k/ft.

    H

    IEI

    2EI 2EI2EI

    16 ft. 16 ft. 16 ft.

    12 ft.JEI

    KEI

    LEI

    A

    EI

    B

    EI EI EI 12 ft.

    C D

    StiffnessBeam16EI

    K8EI

    K FGEF == ;;

  • Moment Distribution Method 89

    EF FE FGDF 0.43 0.35 0.18FEM -85.33 85.33 -42.67 DM 36.69 -14.93 -7.68COM -7.47 18.35 0DM 3.21 -6.42 -3.30COM -3.21 1.16 0DM 1.38 -0.56 -0.29 -54.73 83.38 -53.94

    Moment Distribution Method 90

    - Joint E 2 Stiffness Factor (K)

    ..).( ftk3727735421

    MM EIEA ===

    ..).( ftk713372721

    MM IEAE ===

    ..).( ftk7214442921

    MM FJFB ===

    ..).( ftk47721421

    MM JFBF ===