02 excercise 01 coaxialcable -...
TRANSCRIPT
![Page 1: 02 Excercise 01 CoaxialCable - uniroma1.itmwl.diet.uniroma1.it/people/pisa/SitoWeb2015/LezioneDD_matriceS/… · Help Microsoft PowerPoint x 10 Riempimento forma D' Contorno forma](https://reader034.vdocuments.pub/reader034/viewer/2022052018/6031bc472f455e3a9a54521f/html5/thumbnails/1.jpg)
25/09/15
1
0 5 10 15 20 25 30 35 40−180
−160
−140
−120
−100
−80
−60
−40
−20
0
Freq [MHz]
unwrapped phase of S21
Coaxial Cable
S21(ω) = exp(-γL) = exp(-αL –jβL)= exp (-α’sqrt(ω)L – j ω τ)
τ = √εr L/c =electrical delay βL = (ω/c) √εr L = ω τ
|S21|dB \S21
Open Coaxial Cable
Coax. Cable
� = S11
open end
Ideal Case
0
|�|dB
Frequency
0 Frequency
\�
Radia.on + Losses 0
|�|dB
pf
� ⇡ e�↵0p!2Le�j2⇡f2⌧
� =b1a1
= e�j2⇡f2⌧
τ = √εr L/c
![Page 2: 02 Excercise 01 CoaxialCable - uniroma1.itmwl.diet.uniroma1.it/people/pisa/SitoWeb2015/LezioneDD_matriceS/… · Help Microsoft PowerPoint x 10 Riempimento forma D' Contorno forma](https://reader034.vdocuments.pub/reader034/viewer/2022052018/6031bc472f455e3a9a54521f/html5/thumbnails/2.jpg)
25/09/15
2
Coaxial cable: reflection and transmission
0 500 1000 1500 2000 2500 3000−3
−2.5
−2
−1.5
−1
−0.5
0
Freq [MHz]
Module of S11
0 500 1000 1500 2000 2500 3000
−1.2
−1
−0.8
−0.6
−0.4
−0.2
0
Freq [MHz]
Module of S21
Coax. Cable
� = S11
open end
|�|dB
|S21|dB
Coax. Cable
Port 1 Port 2
/ �p!
/ �2p!
Open Coaxial Cable: resonance
L = m λ/2 λm = 2L/m fm = m (c/n)/ 2L
Δf = (c/n)/2L
n = c/(Δf 2 L)
n = refraction index n= √εr
best matching