2.balok-t.ppt

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    170 cm170 cm

    170 cm

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    1.71.7

    qM= 1414 kg / m

    P M = 126 KG

    Ly

    126 kg

    1414 kg

    1.2.1.1

    2

    P t q t/m

    Ly = 7.5m

    Pt = Total Beban Garis (PM +PH )

    qt = Total Beban Terbagi Rata (qM +q H)

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    q= 3873 kg/m /lebar balok T

    P=16154kg/lebar balok T

    7.5m

    diaprag

    ma

    1.2.1.3Beban H!"#$H% &'at $'%

    Total Beban Terbagi ata ber!aktor

    Total q = "1#6$%1.&6'"q($ ) "1#2$%1414"qM$ =&*7&kg/m

    Total Beban Gari+ "Terp,+at$ ber!aktor =

    Total P-= "1#6$%"1'''2#16$"P($)"1#2$% "126$ "PM$ =16154kg

    1.2.2 Momen ma% g teradi

    1.2.2.1 Momen Ma% g Teradi"Mn$

    0 % "16154$% 7.5

    3

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    Ac =Luas beton yg bisa menaan gaya te!an a!ibat Momen Lentur

    = bm " a

    bm= lebar man#aat saya$ yg bisa menaan gaya te!an Momen Lentur

    a=tinggi man#aat saya$ yg bisa menaan gaya te!an Momen Lentur

    T=As " #y %= &' " bm " a " #c( = T

    &' " bm " a " #c = As " #y

    a= )* + ,y / $ -.85 + bm + , %

    As = * a=tau

    ',&M

    t=2&

    b-=.&

    bm=&cm

    a

    1.2.5. 'enent"kan lebar man,aat *aya#

    bm / =0 t+ bo =0 " 2& + .& = &cm

    bm2 /=bo + L 1 = .& + ,& 1 =& cm

    bm./ =bo + L1&+ bt 12 = .&+,& 1& + ,&12 =& cm

    bm3 /=bt =,& cm

    bm ar 0g Terkel = 15-m

    Ac

    AsTinggi bidang tekan (a)

    4

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    2.1.1 )LT)T 2itent,kan 3,a+ Be+i Tarik "+$ 6 22=6%"1/4 %222$=22*1mm2

    iari tinggi -

    Perkiraan - *'' mm

    ari re!eren+i 3T89T:; 1

    e!eren+i '1 kgm=71>'.1%1'5 9mm " liat (al +ebel,m$

    Ternyata 'omen yg b*a !taan $'t % >

    'omen yg ter

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    q=3873 kg/m /lebar balok TP=16154 kg/lebar balok T

    6.5 / 7.5 x 16154 =14000kg 16154 kg

    x 7.5 x 3873 = 14524 kg

    7500 kg275 / 3,75 ! 14524 kg = 1"651 kg

    rata = $14524&1-651%/2=12588 kg

    7.5 m

    3.75 m1m

    6.5 m

    1m

    tot rata rata 1m !r te# =D"= 14--- & 12588 =26588 kg

    =26588- eEton.

    Gaya gee! !ata !ata yg te!"adi #1m da!i te$i (%& )

    2.75 m

    3.75 m

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    65-

    mm

    $!

    %

    28 15-mm$*engkang%$ * = 15- mm %.

    ,y= 414 / mm

    , = 275 / mmF

    Tahanan geser ma! #g bisa di$ahan be$o

    $

    t .%=, / 6 / mmF= 2 85 / 6=-.87/ mmF(!&m&)

    ;"at ge*er ma+ beton $ D . %=

    $

    t . % + bE + !

    =-.87 + 65-- + 3--=1560003

    '&at gee! max yg bia ditaan 2 t&. ba"a ( engkang )

    =* x +y = 2 x , 8- x 414 = 4158#72 etn

    '&at gee! max yg bia ditaan t&. ba"a ( engkang )

    #eeba! bidang gee! ( % ) =* x +y x d /s

    =41598.72 x 650/150= 180261#1eEton

    3-- mm

    $ bE %

    Dn = ( %c % ) = 0#8 .( 156000 180261.1 ) =26008#etn %& Dn Gke$265880 etn'/ 26008#etn)

    ;"at ge*er $ Dn %anya beton !an *engkang tan#a t"l mrng

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    28915-mm 28915-mm

    8 22 mm

    8 22

    28915-mm

    1m 1m

    4 22 mm

    2 22

    2892-mm

    1m

    Tul $ra!tis

    0& mm

    ,&&mm

    .&&mm

    2&&mm

    4i$ili 5Alt

    2 22