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KONDISI PATAH TARIK ( 0,35 Cb) c=0,35.Cb= 0,35 . 45,2454 = 15,83589 cm a=0,85.c= 0,85 . 15,8359 = 13,4605 cm cc= 0,85 . f'c = 0,85. 255 . 13,4605 . 70 = 204,2294363 kg es' = (c-d')/c . ec = (15,8359-6,25)/ 15,8359 . 0,003 = 0,001816 < ey =0,00189 baja desak belum leleh ---> fs = epsilon s' . es = 0,001816 . 2,1 . 10^6 = 3814 kg/cm cs= as' . fs = 8. 4,908 . 3814 = 149752,896 kg baja tarik pasti sudah leleh ts= as. fy = 8 . 4,908 . 3978 = 156192,192 kg pn = cc + cs - ts = 204229,4363 + 149752,896 - 156,192 = 197790,1403 kg = 197,79 t mn = cc . ( 0,5 ht - a/2) + cs ( 0,5 . ht - d') + ts.(0,5 . ht - d') = 204229,4363 ( 80/2 - 13,4605/2) + 149752,896 . (80/2 - 6,25 ) + 156192,192 . ( 80/2 - 6,25 ) = 17120309,01 kgcm = 171,201 tm LENTUR MURNI (PN = 0) Cc = 0,85 . f'c . a . b = 0,85 . 255. a . 70 = 15172,5a kg Cs = As' . fs = As' . epsilons . Es = As' .(a-Betai.d')/a.epsilonc.Es = 8.4,908.(a-0,85.6,25)/a . 0,003 .2,1 .10^6 = (247363,2a-1314117)/a kg Ts = As.Fy = 8.4,909.3978 = 156192,192 kg Cc + Cs = Ts 15172,5a + (247363,2a - 1314117)/a = 156192,192 = ((15172,5a^2 + 91171,008a - 1314117))/a = 0 = 15172,5a^2 + 91171,008a - 1314117 = 0 a + 6,009a - 86,612 = 0 a = (-6,009 +- akar 6,009^2 + 4.1.86,612)/2.1 = 6,775 cm c = a/beta = 6,775/0,85 = 7,97 cm s' = (c-d')/c.epsilonc = 7,97-6,25/7,9.0,003 = 0,000647 < epsilonY = 0,00189 baja desak belum leleh ---> fs = epsilon s' . es = 0,000647.2,1.10^6 = 1359 kg/c m^2 = 0,85.f'c.a.b = 0,85.255.6,775.70 = 102793,6875 kg = As'.Fs = 8.4,908-1359 = 53359,776 kg = Cc . (h'-a/2) + Cs . (h'-d') = 102793,6875 . (73,75-6,775/2) + 53359,776 . (73,75-6,25) = 10834605,72 kgcm = 108,346 tm

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Rumus Algebra

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KONDISI PATAH TARIK ( 0,35 Cb)c=0,35.Cb= 0,35 . 45,2454 = 15,83589 cma=0,85.c= 0,85 . 15,8359 = 13,4605 cmcc= 0,85 . f'c = 0,85. 255 . 13,4605 . 70 = 204,2294363 kges' = (c-d')/c . ec = (15,8359-6,25)/ 15,8359 . 0,003 = 0,001816 < ey =0,00189baja desak belum leleh ---> fs = epsilon s' . es = 0,001816 . 2,1 . 10^6 = 3814 kg/cmcs= as' . fs = 8. 4,908 . 3814 = 149752,896 kgbaja tarik pasti sudah lelehts= as. fy = 8 . 4,908 . 3978 = 156192,192 kgpn = cc + cs - ts = 204229,4363 + 149752,896 - 156,192 = 197790,1403 kg = 197,79 tmn = cc . ( 0,5 ht - a/2) + cs ( 0,5 . ht - d') + ts.(0,5 . ht - d') = 204229,4363 ( 80/2 - 13,4605/2) + 149752,896 . (80/2 - 6,25 ) + 156192,192 . ( 80/2 - 6,25 ) = 17120309,01 kgcm = 171,201 tm

LENTUR MURNI (PN = 0)Cc = 0,85 . f'c . a . b = 0,85 . 255. a . 70 = 15172,5a kgCs = As' . fs = As' . epsilons . Es = As' .(a-Betai.d')/a.epsilonc.Es = 8.4,908.(a-0,85.6,25)/a . 0,003 .2,1 .10^6= (247363,2a-1314117)/a kgTs = As.Fy = 8.4,909.3978 = 156192,192 kgCc + Cs = Ts15172,5a + (247363,2a - 1314117)/a = 156192,192= ((15172,5a^2 + 91171,008a - 1314117))/a = 0= 15172,5a^2 + 91171,008a - 1314117 = 0a + 6,009a - 86,612 = 0a = (-6,009 +- akar 6,009^2 + 4.1.86,612)/2.1 = 6,775 cmc = a/beta = 6,775/0,85 = 7,97 cms' = (c-d')/c.epsilonc = 7,97-6,25/7,9.0,003 = 0,000647 < epsilonY = 0,00189baja desak belum leleh ---> fs = epsilon s' . es = 0,000647.2,1.10^6 = 1359 kg/cm^2= 0,85.f'c.a.b = 0,85.255.6,775.70 = 102793,6875 kg = As'.Fs = 8.4,908-1359 = 53359,776 kg= Cc . (h'-a/2) + Cs . (h'-d')= 102793,6875 . (73,75-6,775/2) + 53359,776 . (73,75-6,25)= 10834605,72 kgcm= 108,346 tm