apendice práctica no2 sistemas de circuitos de fluidos experimetales parte iii y iv
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-
Apndice.
Clculo de factor f para cada tubera.
- Tuberas de cobre tipo L, e = 1.5x10-6 m A. Para Q1 (5,69x10-5 m3/s)
Tubera DN = , Di = 0.013843 m (e/Di = 1.0836x10-4)
"
" 0,035988
Tubera de DN = , Di = 0.019939 m (e/Di = 7.5229x10-5)
"
" 0,039922
Tubera de DN = 1, Di = 0.026035 m (e/Di = 5.7615x10-5)
"
" 0,043225
B. Para Q2 (2,5x10-5 m3/s)
Tubera DN = , Di = 0.013843 m (e/Di = 1.0836x10-4)
"
Re = 4.(5,69x105 m3 s )
.(0,013843m).(9,0369x107 m2 s )= 5791,2550 f
1f = 4 log
(1,0836x104 )3,7 +
1,2565791,2550 f f =
Re = 4.(5,69x105 m3 s )
.(0,019939m).(9,0369x107 m2 s )= 4020,6802 f
1f = 4 log
(7.5229x10-5 )3,7 +
1,2564020,6802 f f =
Re = 4.(5,69x105 m3 s )
.(0,026035m).(9,0369x107 m2 s )= 3079,2526 f
1f = 4 log
(5.7615x10-5 )3,7 +
1,2563079,2526 f f =
Re = 4.(2,5x105 m3 s )
.(0,013843m).(9,0369x107 m2 s )= 2544,4881 f
-
" 0,0458907
Tubera de DN = , Di = 0.019939 m (e/Di = 7.5229x10-5)
" =64/Re=0,0362286
Tubera de DN = 1, Di = 0.026035 m (e/Di = 5.7615x10-5)
" =64/Re=0,047304
Clculo de (L/D) para cada accesorio
- Todos los accesorios se encuentran en la tubera de 1
- (L/D) se determina a partir de la ecuacin (7)
"
A. Para Q1 (5,69x10-5 m3/s), f = 0,043225
A partir de la ecuacin (2): "
Codo estndar 90
!
Conexin T
" x2=252.0494
Vlvula de compuerta completamente abierta
1f = 4 log
(1.0836x10-4 )3,7 +
1,2562544,4881 f f =
Re = 4.(2,5x105 m3 s )
.(0,019939m).(9,0369x107 m2 s )= 1766,5554 f
Re = 4.(2,5x105 m3 s )
.(0,026035m).(9,0369x107 m2 s )= 1352,9229 f
A = .Di2
4 = .(0,026035m)2
4 = 5,323x104m2
V = 5,69x105 m3 s
5,3236x104m2 = 0,106882m / s
LD
=
2.(9,8 m s2 ).(0,003175m)(0,043225).(0,106882 m s)2
= 126,0247
LD
=
2.(9,8 m s2 ).(0,003175m)(0,043225).(0,106882 m s)2
= 126,0247
-
!
Vlvula de compuerta 50% abierta
!
B. Para Q2 (2,5x10-5 m3/s), f = 0,047304
A partir de la ecuacin (2): "
Codo estndar 90
"
Conexin T
" x2=3582,9522
Vlvula de compuerta completamente abierta
"
Vlvula de compuerta 50% abierta
"
LD
=
2.(9,8 m s2 ).(0m)(0,043225).(0,106882 m s)2
= 0
LD
=
2.(9,8 m s2 ).(0,06675m)(0,043225).(0,106882 m s)2
= 2649,49555
V = 2,5x105 m3 s
5,3236x104m2 = 0,046936m / s
LD
=
2.(9,8 m s2 ).(0,03175m)(0,047304).(0,046936 m s)2
= 5971,5872
LD
=
2.(9,8 m s2 ).(0,009525m)(0,047304).(0,46936 m s)2
= 1791,4761
LD
=
2.(9,8 m s2 ).(0,0445m)(0,047304).(0,46936 m s)2
= 8369,6262
LD
=
2.(9,8 m s2 ).(0,08255m)(0,047304).(0,46936 m s)2
= 15526,1269
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