conditie de suprafata
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Conditie de suprafata
1. m vapori =6 t/h
mAT= = = = =136,3 t/h
136,3 t/h *1000=37,86 kg/s
Np = =22,72
=22,72
Conditia de amestec
mAT= = = = =
= =71,97 t/h
71,97 t/h *1000= 19,99 kg/s
Np= =11,9948
=11,9940
2. mv=100 Kg/h=0.02778Condensatorul de suprafata
mAR= = =2272,08 Kg/h0.63 Kg/s
Kp= =22,72
Condensatorul de amestec
mAR= = = = =
=1203,95 Kg/h /3600 =0,33 Kg/s
Np= =12,04
Condensatorul de amestec este mai eficient, Up mai mic,ΔT mai mare,debit de AR mai micMv=2400 Kg/h=0,6667 Kg/s
mAT= = = =54594,98 Kg/h
Qp=0Qced= Qprim=mv(i’’-i’)=mAT*CpAT(Tf-Ti)
Q=0,6667*2380 *4185,25
ΔTM=echivalent
ΔTM= = = = =13,966 K
K= = = = =1200,48[W/m2 *k]
λotel carbon(<1,5 %)(50 °C)= 20,85[W/m2*k)
A= = =94,64 m2
1586666,67 1586666,67
20 °C
45 °C
Tcond=50 °C
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