introduction to thermodynamic geomodeling · phase - component ρ 2, t 2 ρ 1, t 1 Σ ρ 3, t 3 12...
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Introduction to thermodynamic geomodelingViktoriya YarushinaPGPfall semester 2009
Open system: matter and energy exchangeClosed system: energy exchengeIsolated system: no exchange
Thermodynamic system– system in thermodynamicequilibrium, i.e. all parameters areconst in time, d/dt = 0, d/dx = 0, no fluxes
Nonequilibrium system –d/dt ≠ 0 or d/dx ≠ 0
m, VΣ
m, VΣ
3
Homogeneous system –f(x) – continuousGas mixturesLiquid and solid solutions
Heterogeneous systemf(x) – discontinuous Partially molten rock Melting iceOil-gas mixture
Phase - Component
ρ2, T2 ρ1, T1
ρ3, T3Σ12
Σ13
Component is a chemically distinct constituent of a system. Their concentrations may be varied independently in the various phases.
Internal – External parameters
p = constp - external
V p
V = constV - external
ρ, p, V, e
but
x, v
x1
x2
v t2
t1
Thermodynamic parameters (internal)
Extensive Intensive
Mass TemperatureVolume DensityEnergy Pressure
V1 V2 V1+V2+ = T1 T2 T1+T2+?=
Energy
What is the energy?
Energy
Kinetic Potential InternalE = K + Epot + U
System as a whole, K = mv2
In external force fields, Epot = mghEverything else,
U = U(ai,T), ai – external parameters
Thermodynamics deals only with internal energy with some exceptions
WorkOne of the means of energy exchange when external parameters change
W = ∫F ds
dW is not a perfect differential∫dW depends on the path
W is not a state variable
dW = -p dVdW = V0∑σikdeik
A
B
dW ≠ WB-WA
Heat
One of the means of energy exchange when external parameters DO NOT change
dQ is not a perfect differential∫dQ depends on the path
Q is not a state variable
A
B
dQ ≠ QB-QA
12
The First Law or Energy Balance
For isolated systems: dE = 0
For closed systems: dU = dQ + dW
For open systems: ?
dU = dQ + ∑Aidaiai – external parameters U is perfect differentialAi – conjugate forces
Perpetuum mobile of the 1st kind is impossible: any device which indefinitely produces the work without consuming the energy is forbidden
A
B
dU=UB-UA
The Second Law or Entropy and absolute temperature
∫dQ/T = dS = SB-SA
Entropy S is a state variableT is thermodynamic (absolute) temperature (K)
dQ = TdSdS≥0
No process is possible whose sole effect is to transfer heat from cold body to a hot body
Perpetuum mobile of the 2nd kind is impossible: An engine that produces work by extracting heat from its surroundings is impossible
A
B
dS=SB-SA
Entropy
What is the entropy?
S = S1+S2
Gibb’s equation
dU = dW + dQ+
dQ = ?dW = ?
=?
Matter exchange – open systemsVariations in composition – chemical reactions
dU = dW + dQ+
dQ = ?dW = ?
=?
Thermodynamic processes
Isothermal: T = const, dU = -pdV + TdSIsochoric: V = const, dU = -pdV + TdSIsobaric: p = const, dU = -pdV + TdS
Adiabatic: Q = const, dU = -pdV + TdS
Thermodynamic potentialsGibbs energy G = U – TS: U=U(Ai,T)
Enthalpy H = U + pV: U=U(Ai,S)Helmholtz energy F = U – TS: U=U(ai,T)
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