mechanism building creating of kinematic chain · 2015-11-12 · creating of kinematic chain....
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Ing. Šimon Kovář, Ph.D.
Mechanism building
CREATING OF KINEMATIC CHAIN
GEOMETRICAL PRECISION OF MECHANISMS
Slider crank mechanism
manufacturing tolerance - Δr
error in the position of the slider - Δs=?
Analytical determine slider position error.
crank
slider
coupler
frame
Mechanism Building| 12.11.2015
Slider crank mechanism
For small dimensions is possible: 𝑑𝑟 = Δ𝑟
𝑑𝑠 = Δ𝑠
Mechanism Building| 12.11.2015
Swinging mechanism
For small dimensions is possible:
𝑑𝐻 = Δ𝐻
𝑑𝜓 = Δ𝜓
Mechanism Building| 12.11.2015
Swinging mechanism
manufacturing tolerance - ΔH
error in the position of the
slider - ΔΨ = ?
Analytical determine rocker
position error.
crank
slider
rocker
frame
Mechanism Building| 12.11.2015
Swinging mechanism
Δ𝜓 = −Δ𝐻 ∗ 𝑟 ∗ 𝑠𝑖𝑛𝜑
(𝐻 − 𝑟 ∗ 𝑐𝑜𝑠𝜑)2+𝑟2 ∗ 𝑠𝑖𝑛2𝜑
𝑐𝑜𝑠2𝜓 =(𝐻 − 𝑟 ∗ 𝑐𝑜𝑠𝜑)2
(𝐻 − 𝑟 ∗ 𝑐𝑜𝑠𝜑)2+𝑟2 ∗ 𝑠𝑖𝑛2𝜑
Mechanism Building| 12.11.2015
4 bar mechanism
Transfer function
manufacturing tolerance - Δb
error in the position of the
rocker - Δ=?
Analytical determine slider
position error.
Mechanism Building| 12.11.2015
4 bar mechanism
For small dimensions is possible:
𝑑𝑏 = Δ𝑏
𝑑𝜓 = Δ𝜓
Δ𝜓𝐶 = Δ𝜓𝑎 + Δ𝜓𝑏 + Δ𝜓𝑐 + Δ𝜓𝑑For finish error valid:
Mechanism Building| 12.11.2015
TRNASFORMATION OF MECHANISMS
Definition for transformation angle
The angle between the direction
of absolute motion and direction
of the relative motion of the
point in which the driven
member gets the motion impulse
Mechanism Building| 12.11.2015
4 bar mechanism
Mechanism Building| 12.11.2015
4 bar mechanism
Important limits for analysis: maximal and minimal values of transformation angle
𝑎𝑝𝑝𝑜𝑖𝑛𝑡 𝜓1 = 0° 𝑎𝑛𝑑 𝜓2 = 180° to
Mechanism Building| 12.11.2015
4 bar mechanism
Ideal transfer between the driving and the driven parts is 90°. Optimal transformation angle is 90°.
Mechanism Building| 12.11.2015
4 bar mechanisms
Very important milestone is transformation in reversal points of mechanism.
Mechanism Building| 12.11.2015
4 bar mechanisms - example
𝜇 1,2 =?
a
d
b
c
Mechanism Building| 12.11.2015
4 bar mechanisms - example
𝜇 1,2 =?
Mechanism Building| 12.11.2015
4 bar mechanisms - example
Results: 𝜇1 = 𝜇𝑚𝑖𝑛 = 104°00´
𝜇2 = 𝜇𝑚𝑎𝑥 = 81°50´
𝜓𝑂𝑃𝑇1 = 105°20´
𝜓𝑂𝑃𝑇2 = 254°40´
𝜇𝑈1 = 87°10´
𝜇𝑈2 = 98°40´
𝜓𝑈1 = 121°40´
𝜓𝑈2 = 302°00´
Mechanism Building| 12.11.2015
Slider – crank mechanism
Mechanism Building| 12.11.2015
Slider – crank mechanism
Valid for maximum and
minimum
reversal points
Mechanism Building| 12.11.2015
Slider – crank mechanism
example
r= 13 mml= 39 mme= 3 mm
𝜇 1,2 =?e
l
r
Mechanism Building| 12.11.2015
Slider – crank mechanism - example
r= 13 mml= 39 mme= 3 mm
𝜇 1,2 =?
Mechanism Building| 12.11.2015
Slider – crank mechanism - example
Results: 𝜇1 = 𝜇𝑚𝑖𝑛 = 64°40´
𝜇2 = 𝜇𝑚𝑎𝑥 = 104°50´
𝜓𝑂𝑃𝑇1 = 193°20´
𝜓𝑂𝑃𝑇2 = 346°40´
𝜇𝑈1 = 86°40´
𝜇𝑈2 = 83°20´
𝜓𝑈1 = 183°20´
𝜓𝑈2 = 6°40´
Mechanism Building| 12.11.2015
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