perhitungan tjr i

8/17/2019 Perhitungan TJR I

http://slidepdf.com/reader/full/perhitungan-tjr-i 1/207

PERANCANGAN GEOMETRIK JALAN

Rico Desrianto / D 111 10 251

LANGKAH - LANGKAH KERJA

I. Penentuan Data Perencanaan Geometrik

II. Penentuan Trase Jalan

III. Menentukan Klasifikasi MedanIV. Perhitungan Alinemen Horisontal

1. Menghitung dan merencanakan enis tikungan

!. Menghitung kece"atan tikungan

#. Menghitung su"erele$asi tikungan

%. Menghitung "ele&aran "erkerasan tikungan

'. Menghitung arak "andang

(. Menggam&ar tikungan dan su"erele$asi

V. Menggam&ar Profil Memanang

VI. Perhitungan Alinemen Vertikal

1. Menghitung Alinemen Vertikal )em&ung

!. Menghitung Alinemen Vertikal )ekung

VII. Perhitungan Te&al Perkerasan

1. Menghitung lintas harian rata*rata +,H- a/al umur rencana

!. Menghitung lintas harian rata*rata +,H- akhir umur rencana

#. Menghitung angka eki$alen +0

%. Menghitung lintas eki$alen "ermulaan +,0P

'. Menghitung lintas eki$alen akhir +,0A

(. Menghitung lintas eki$alen tegah +,0T

. Menghitung lintas eki$alen rencana +,0-

2. Menentukan inde3 te&al "erkerasan +ITP &erdasarkan ,0-

4. Menghitung te&al "erkerasan

15. Menggam&ar susunan "erkerasan

VIII.Perhitungan Volume Galian dan Tim&unan

1. Menggam&ar "rofil melintang

!. Menghitung luas &idang galian dan tim&unan

#. Menghitung $olume galian dan tim&unan

%. Menghitung $olume total galian dan tim&unan

6I. Perhitungan Volume Material Masing*masing -uas Jalan

ANALISIS DESAIN

PENENTUAN DATA PERENCANAAN GEOMETRIK +"ada soal

PENENTUAN TRASE JALAN

+ terlam"ir

MENENTUKAN KLASIFIKASI MEDAN

J07I8 M0DA7 K0MI-I7GA7 M0,I7TA7G -ATA*-ATA

Datar 5 * !.4 9

Per&ukitan # * !%:4 9

Pegunungan ; !' 9

4.31 Perhitungan ketinggian stasiun

a Tinggi 8ta. < a * " 3 + a * &

" 1 = 5'5 " = >

4.3.2 Perhitungan kemiringan lereng (%)

<?eda tinggi

3 155Jarak stasiun

4.3.3 Perhitungan Panjang Lintasan Tikungan

Untuk Tikungan 1 Untuk Tikungan 2

- < 1%5 - < 1%5

< 45 5 < 45 5

3 ! 3 #.1% 3 1%5 , <45

3 ! 3 #.1% 3 1%5#(5 #(5

< !14.25 m < !14.25 m

3 ! π -

Untuk Tikungan 5 Untuk Tikungan

- < %5 - < %5

< !% 5 < 1' 5

3 ! 3 #.1% 3 %5 , <1'

3 ! 3 #.1% 3 %5#(5 #(5

< 14(.2 m < 14#.# m

Untuk Tikungan ! Untuk Tikungan "

- < %5 - < 1!5

< 1' 5 < 45 5

3 ! 3 #.1% 3 %5 , <45

3 ! 3 #.1% 3 1!5#(5 #(5

< 14#.# m < 122.'5 m

Untuk Tikungan # Untuk Tikungan 1$

- < 15 - < 1#5

< (5 5 < 5

3 ! 3 #.1% 3 15 , <

3 ! 3 #.1% 3 1#5#(5 #(5

< 12.5! m < 1%.1 m

- < #25 - < 1%5

< #5 5 < 5 5

3 ! 3 #.1% 3 #25 , <5

3 ! 3 #.1% 3 1%5#(5 #(5

< 142.4 m < 11.5% m

Untuk Tikungan 1% Untuk Tikungan 1&

- < %5 - < 1%5

< !' 5 < 5 5

3 ! 3 #.1% 3 %5 , <5

3 ! 3 #.1% 3 1%5#(5 #(5

< !5'.52 m < 11.5% m

- < %5 - < ''5

< 1 5 < !1 5

3 ! 3 #.1% 3 %5 , <!1

3 ! 3 #.1% 3 ''5#(5 #(5

< !14.'( m < !51.'4 m

Untuk Tikungan 1! Untuk Tikungan 1"

- < ''5 - < 1!5

< !1 5 < ' 5

3 ! 3 #.1% 3 ''5 , <'

3 ! 3 #.1% 3 1!5#(5 #(5

< !51.'4 m < 1'.52 m

Untuk Tikungan 1# Untuk Tikungan 2$

- < 15 - < !45

< (5 5 < %5 5

3 ! 3 #.1% 3 15 , <%5

3 ! 3 #.1% 3 !45#(5 #(5

< 12.5! m < !5!.%( m

- < !15 - < !15

< '1 5 < '1 5

3 ! 3 #.1% 3 !15 , <'1

3 ! 3 #.1% 3 !15#(5 #(5

< 12(.4! m < 12(.4! m

Untuk Tikungan 2% Untuk Tikungan 2&

- < 15 - < 1%5

< (5 5 < 5 5

3 ! 3 #.1% 3 15 , <5

3 ! 3 #.1% 3 1%5#(5 #(5

< 12.5! m < 11.5% m

- < 1!5 - < 1%5

< ' 5 < 5 5

3 ! 3 #.1% 3 1!5 , <5

3 ! 3 #.1% 3 1%5#(5 #(5

< 1'.52 m < 11.5% m

-eka"itulasi Panang Tikungan

TIKUNGANR

L(m)(m)

1 140 90 219.80

2 140 90 219.80

3 0 0 0.00

4 0 0 0.00

5 470 24 196.87

6 740 15 193.73

7 740 15 193.73

8 120 90 188.50

9 170 60 178.02

10 130 77 174.71

11 380 30 198.97

12 140 70 171.04

13 470 25 205.08

14 140 70 171.0415 740 17 219.56

16 550 21 201.59

17 550 21 201.59

18 120 75 157.08

19 170 60 178.02

20 290 40 202.46

21 210 51 186.92

22 210 51 186.92

23 170 60 178.02

24 140 70 171.04

25 120 75 157.08

26 140 70 171.0427 0 0 0.00

28 0 0 0.00

29 0 0 0.00

'A' I(

ANALISIS DATA PERHITUNGAN

&)1 P*+,i M./an0ang

Ta&el %.1 Profil Memanang

7omor 8tasiun Ket.

A 5 = 5 11!.44#

'5 1.%'2 !.4! D

1 5 = '5 111.'#'

'5 5.24 1.4 D

! 5 = 155 115.(#2

'5 !.%52 %.2! ?

# 5 = 1'5 152.!#

'5 5.2 1.'( D

% 5 = !55 15.%'

'5 1.4' #.41 ?

' 5 = !'5 15'.%4#

'5 !.5( %.1# ?

( 5 = #55 15#.%!(

'5 1.52# !.1 D

5 = #'5 15!.#%#

'5 %.''% 4.11 ?

2 5 = %55 4.24'5 5.2!4 1.(( D

4 5 = %'5 4(.4(

'5 1.!(! !.'! D

15 5 = '55 4'.(42

'5 1.5!' !.5' D

11 5 = ''5 4%.(#

'5 5.%4( 5.44 D

1! 5 = (55 4%.1

'5 5.!%2 5.'5 D

1# 5 = ('5 4%.%!'

'5 *5.5! 1.%5 D

1% 5 = 55 4#.!#

'5 *1.# !.% D

1' 5 = '5 4'.54#

'5 *1.!!% !.%' D

1( 5 = 255 4#.2(4

'5 %.#'1 2.5 ?

1 5 = 2'5 24.'12

'5 #.(!! .!% ?

12 5 = 455 2'.24(

'5 5.#( 5.# D

14 5 = 4'5 2(.!(#

'5 '.1#' 15.! ?!5 1 = 5 21.1!2

'5 5.%1' 5.2# D

Jarak8tasiun

Tinggi Titik+m

?edaTinggi

Kemiringan+9

TI7GGI-07)A7A

!1 1 = '5 25.1#

'5 1.'' #.15 D

!! 1 = 155 4.1(#

'5 *1.## !.(( D

!# 1 = 1'5 25.%4#

'5 '.5#( 15.5 ?

!% 1 = !55 '.%'

'5 5.154 5.!! D

!' 1 = !'5 '.#%2

'5 *1.25! #.(5 ?

!( 1 = #55 .1'

'5 *1.22# #. ?

! 1 = #'5 4.5##

!2 1 = #'5 4.5##

155 5.4 5.4 D

!4 1 = %'5 2.!%#

'5 *5.14 5.#2 D

#5 1 = '55 2.%##

'5 *5.#5' 5.(1 D#1 1 = ''5 2.#2

'5 1.1' !.#5 D

#! 1 = (55 .'22

'5 5.%'( 5.41 D

## 1 = ('5 .1#!

155 1.%!! 1.%! D

#% 1 = '5 '.1

155 *5.#1! 5.#1 D

#' 1 = 2'5 (.5!!

'5 5.!#% 5.% D

#( 1 = 455 '.22

'5 *5.!# 5.%( D# 1 = 4'5 (.512

'5 *5.#! 5.(% D

#2 ! = 5 (.##2

'5 5.!4 5.'2 D

#4 ! = '5 (.5%2

'5 1 !.55 D

%5 ! = 155 '.5%2

155 *12.4'! 12.4' ?

Sumber : Hasil Perhitungan kelomok !""

Keterangan @

D < Datar

? < ?ukit

G < Gunung

Maka di"eroleh kesim"ulan rata*rata alan ang akan didesain memiliki keadaan DATA-

RICO DESRIANTO D111 10 251

&)2 PERHITUNGAN GALIAN DAN TIM'UNAN

Menggam&ar Profil Melintang

Ta. P*+,i M.intang

7omor 8tasiun8TA.

Tinggi #5 meter se&elah kiri TI7GGI Tinggi #5 meter se&elah kanan Kemiringan

Tinggi Titik ?eda Tinggi Kemiringan Titik Tinggi Titik ?eda Tinggi Kemiringan -ata*rata

+m +m +m +m +m +m +m +m +m

A 5 = 5 115.555 5.555 5.555 115 152.2!# *1.1 *#.4!# 1.4(!

1 5 = '5 1!1.### 5.## !.%%# 1!5.( 1!5.555 *5.(55 *!.555 5.!!!

! 5 = 155 1!.### 5.## !.%%# 1!(.( 1!2.((( !.5(( (.22 %.(('

# 5 = 1'5 1#!.'55 1.#55 %.### 1#1.! 1#5.555 *1.!55 *%.555 5.1(

% 5 = !55 1#(.%1 5.41 #.!#' 1#'.' 1#'.!(5 *5.!%5 *5.255 1.!12

' 5 = !'5 1%!.!!! 5.(!! !.5# 1%1.( 1%1.111 *5.%24 *1.(#5 5.!!!

( 5 = #55 1%%.%%% 1.#%% %.%25 1%#.1 1%#.222 5.22 !.(! #.''#

5 = #'5 1%(.2%5 1.5%5 #.%( 1%'.2 1%'.!(# *5.'# *1.45 5.2#2

2 5 = %55 1%2.### 1.1## #. 1%.! 1%(.111 *1.524 *#.(#5 5.5%

4 5 = %'5 1%2.222 1.(22 '.(! 1%.! 1%(.((( *5.'#% *1.25 1.4!#

15 5 = '55 1%2.4% 1.% '.2!# 1%.! 1%'.24 *1.%11 *%.5# 5.'(5

11 5 = ''5 1%(.111 5.411 #.5# 1%'.! 1%%.'55 *5.55 *!.### 5.#'!

1! 5 = (55 1%4.555 .%55 !%.(( 1%1.( 1%5.'22 *1.51! *#.## 15.(%

1# 5 = ('5 1'1.555 !.'55 2.### 1%2.' 1%(.((( *1.2#% *(.11# 1.115

1% 5 = 55 1'5.%'% #.%'% 11.'1# 1% 1%'.555 *!.555 *(.(( !.%!#

1' 5 = '5 1%#.### #.### 11.115 1%5 1#4.541 *5.454 *#.5#5 %.5%5

1( 5 = 255 1#(.111 1.111 #.5% 1#' 1##.### *1.(( *'.'' 5.4!

1 5 = 2'5 1#'.222 5.222 !.4(5 1#' 1#!.4%1 *!.5'4 *(.2(# 1.4'!

12 5 = 455 1#.5'2 *5.%%! *1.%# 1#.' 1#'.!4% *!.!5( *.#'# %.%1#

14 5 = 4'5 1#2.2!% 5.'!# 1.%' 1#2.# 1#2.'5 5.%'5 1.'55 1.(!!

!5 1 = 5 1%5.555 5.555 5.555 1%5 1%1.555 1.555 #.### 1.((

!1 1 = '5 1%'.555 5.555 5.555 1%' 1%'.555 5.555 5.555 5.555

!! 1 = 155 1%'.555 5.555 5.555 1%' 1%'.555 5.555 5.555 5.555

!# 1 = 1'5 1%.555 *5.(55 *!.555 1%.( 1%'.555 *!.(55 *2.(( '.###

!% 1 = !55 1'5.555 5.%55 1.### 1%4.( 1%2.1!' *1.%' *%.41 1.4!

!' 1 = !'5 1'(.((( !.((( 2.22 1'% 1'!.((( *1.##% *%.%% !.!!5

1' 1 = #55 1%#.### #.### 11.115 1%5 1#4.541 *5.454 *#.5#5 %.5%5

1( 1 = #'5 1#(.111 1.111 #.5% 1#' 1##.### *1.(( *'.'' 5.4!

1 1 = %55 1#'.222 5.222 !.4(5 1#' 1#!.4%1 *!.5'4 *(.2(# 1.4'!

12 1 = %'5 1#.5'2 *5.%%! *1.%# 1#.' 1#'.!4% *!.!5( *.#'# %.%1#

14 1 = '55 1#2.2!% 5.'!# 1.%' 1#2.# 1#2.'5 5.%'5 1.'55 1.(!!

!5 1 = ''5 1%5.555 5.555 5.555 1%5 1%1.555 1.555 #.### 1.((

!1 1 = (55 1%'.555 5.555 5.555 1%' 1%'.555 5.555 5.555 5.555

!! 1 = ('5 1%'.555 5.555 5.555 1%' 1%'.555 5.555 5.555 5.555

!# 1 = 55 1%.555 *5.(55 *!.555 1%.( 1%'.555 *!.(55 *2.(( '.###

!% 1 = '5 1'5.555 5.%55 1.### 1%4.( 1%2.1!' *1.%' *%.41 1.4!

!' 1 = 255 1'(.((( !.((( 2.22 1'% 1'!.((( *1.##% *%.%% !.!!5

!5 1 = 2'5 1%5.555 5.555 5.555 1%5 1%1.555 1.555 #.### 1.((

!1 1 = 455 1%'.555 5.555 5.555 1%' 1%'.555 5.555 5.555 5.555

!! 1 = 4'5 1%'.555 5.555 5.555 1%' 1%'.555 5.555 5.555 5.555

!# ! = 5 1%.555 *5.(55 *!.555 1%.( 1%'.555 *!.(55 *2.(( '.###

!% 1 = '5 1'5.555 5.%55 1.### 1%4.( 1%2.1!' *1.%' *%.41 1.4!

!' ! = 155 1'(.((( !.((( 2.22 1'% 1'!.((( *1.##% *%.%% !.!!5

!( ! = 115 1''.''' 1.''' '.12# 1'% 1'#.1'5 *5.2'5 *!.2## 1.1'

! ! = !15 1'5.555 5.555 5.555 1'5 1%4.1(5 *5.2%5 *!.255 1.%55

'' # = 145 !1!.1%! '.%2! 12.!# !5(.(( 14(.((( *4.44% *##.#1# .'!5

'( # = !%5 !1!.2' %.'! 1'.545 !52.## 142.'1 *4.'4 *#!.'#5 2.!5

' # = !45 !1'.### #.### 11.115 !1! !5'.555 *.555 *!#.### (.11!

'2 # = ##5 !12.1!' #.1!' 15.%1 !1' !11.!'5 *#.'5 *1!.'55 1.5%!

'4 # = %#5 !!1.'55 !.'5 4.1( !12.' !1'.555 *#.'5 *1!.'55 1.((

(5 # = '#5 !!2.555 #.'(5 11.2( !!%.%% !!5.555 *%.%%5 *1%.255 1.%(

(1 # = '5 !##.'5 #.1#5 15.%## !#5.(! !!(.555 *%.(!5 *1'.%55 !.%2#

(! # = (!5 !#.'55 !.'55 2.### !#' !#!.'55 *!.'55 *2.### 5.555

(# # = (5 !%5.((( 5.'#( 1.2 !%5.1# !#2.222 *1.!%! *%.1%5 1.1

(% # = !5 !%#.555 5.555 5.555 !%# !%#.555 5.555 5.555 5.555

(' # = %5 !%%.((( 5.55( 5.5!5 !%%.(( !%%.((( 5.55( 5.5!5 5.5!5

(( # = 2%5 !'5.555 *5.2#5 *!.( !'5.2# !'5.(4 *5.5(1 *5.!5# 1.%2'

( # = 2'5 !'5.4' *5.(2' *!.!2# !'1.(( !'1.1'# *5.'5 *1.(45 1.42

(2 # = 455 !'1.!1! *!.112 *.5(5 !'#.## !'#.254 5.%4 1.'4 !.#!

(4 # = 4'5 !'!.(52 *1.#5! *%.#%5 !'#.41 !''.!1 1.#5 %.#' 5.552

5 # = 1555 !'#.### *1.(( *'.'' !'' !'(.((( 1.((( '.''# 5.55!

1 % = #5 !'#.'5 *1.25 *(.!## !''.(! !'.'55 1.225 (.!( 5.51

! % = 1#5 !'!.'25 *!.!'5 *.'55 !'%.2# !'(.%% 1.41% (.#25 5.'(5

# % = !#5 !'%.555 *#.555 *15.555 !' !(5.555 #.555 15.555 5.555

% % = ##5 !''.555 *#.'5 *1!.'55 !'2.' !(1.### !.'2# 2.(15 1.4%'

' % = %#5 !''.555 *#.'5 *1!.'55 !'2.' !(1.### !.'2# 2.(15 1.4%'

( % = '#5 !'%.'55 *#.!5 *15.455 !'. !(5.((( !.24( 4.('# 5.(!#

% = (#5 !'%.((( *!.%% *2.!% !'.1% !'4.!2' !.1%' .1'5 5.'%2

2 % = #5 !'%.14# *1.4! *(.%!# !'(.1! !'2.5(% 1.4%% (.%25 5.5!2

4 % = 2#5 !'%.14# *1.4! *(.%!# !'(.1! !'2.5(% 1.4%% (.%25 5.5!2

25 % = 245 !'%.%2! *!.%52 *2.5! !'(.24 !'2.4(' !.5' (.41 5.'''

21 % = 4%5 !''.#2% *#.5( *15.!'# !'2.%( !(5 1.'%5 '.1## !.'(5

2! % = 445 !'(.% *!.%55 *2.555 !'2.2 !(5.4' !.1' .!'5 5.#'

2# ' = %5 !(5.''' *5.'' *!.'1 !(1.#1 !(1.4'1 5.(%1 !.1# 5.145

2% ' = 25 !(1.212 *5.4'! *#.1# !(!. !(#.222 1.112 #.! 5.!

2' ' = 125 !(.1%! *1.'12 *'.5(5 !(2.(( !(4.%11 5.'1 !.'5# 1.!2

2( ' = !25 !(.555 *!.555 *(.(( !2 !4 1.555 #.### 1.((

2 ' = #(5 !21.51 *1.%!4 *%.(# !2!.' !2%.1(( 1.((( '.''# 5.#4'

22 ' = %15 !2%.255 *5.255 *!.(( !2'.( !2(.% 5.255 !.(( 5.555

24 ' = %(5 !2.'55 *1.'45 *'.#55 !24.54 !24.( 5.'15 1.55 1.255

45 ' = '15 !4!.5'2 *5.1(! *5.'%5 !4!.!! !41 *1.!!5 *%.5( !.#5#

41 ' = '#5 !4#.### 5.#(# 1.!15 !4!.4 !41.45% *1.5(( *#.''# 1.1!

4! ' = (#5 !42.2!# 1.51# #.# !4.21 !4(.((( *1.1%% *#.21# 5.!12

4# ' = #5 #5#.'!4 *5.141 *5.(# #5#.! #51.#22 *!.##! *.# %.!5'

4% ' = 255 #5(.4%% 1.!% %.!% #5'.( #5' *5.(5 *!.!## 1.55

4' ' = 2'5 #54.%'4 1.(24 '.(#5 #5. #5(.%2( *1.!2% *%.!25 5.('

4( ' = 455 #15.%5 1.#!5 %.%55 #54.%! #5.%!2 *1.44! *(.(%5 1.1!5

4 ' = 4'5 #1!.555 !.555 (.(( #15 #52 *!.555 *(.(( 5.555

42 ' = 425 #1!.'25 !.'25 2.(55 #15 #52.((( *1.##% *%.%% !.5

? 44 ( = 25 #1!.4%1 1.1 '.45# #11.1 #52.222 *!.!2! *.(5 5.2'!

155 ( = 125 #1!.'55 !.125 .!( #15.#! #52.%# *1.22# *(.! 5.%4'

151 ( = !25 #1'.454 #.124 15.(#5 #1!.! #15.454 *1.211 *(.5# !.!4

15! ( = #!5 #1.#41 !.211 4.#5 #1%.'2 #1!.% *!.125 *.!( 1.5'!

15# ( = #5 #12.255 !.1%5 .1## #1(.(( #1%.!2' *!.#' *.41 5.#4!

15% ( = %!5 #!5.215 !.215 4.#( #12 #1(.!' *1.'5 *'.2## 1.(

15' ( = %5 #!1.521 !.!51 .## #12.22 #1(.'2' *!.!4' *.('5 5.1'

15( ( = '15 #!5.24 1.'24 '.!4 #14.! #12 *1.!55 *%.555 5.(%2

15 ( = (15 #1(.%!2 !.1%2 .1(5 #1%.!2 #1!.1%! *!.1#2 *.1! 5.51

152 ( = 15 #!!.((( #.!4( 15.42 #14.# #1(.!' *#.1!5 *15.%55 5.!4#

154 ( = 5 #!(.2' #.'%' 11.21 #!#.## #!5 *#.##5 *11.155 5.#'2

115 ( = 2!5 ##5.555 #.'5 1!.'55 #!(.!' #!!.' *#.'5 *1!.'55 5.555

111 ( = 25 ##5.555 #.#%5 11.1## #!(.(( #!#.### *#.#! *11.545 5.5!!

11! ( = 4!5 #!.!! !.!! .'# #!' #!!.! *!.!# *.' 5.55!

11# ( = 4'5 #!.555 #.555 15.555 #!% #!!.!! *1.!2 *'.(5 !.1!5

11% = '5 #!5.555 1.2' (.!'5 #12.1!' #1(.% *1.('' *'.'1 5.#(

11' = 1'5 #52.4!2 5.4!2 #.54# #52 #5(.'!1 *1.%4 *%.4#5 5.412

11( = !'5 #5.1%! !.2(! 4.'%5 #5%.!2 #51.111 *#.1(4 *15.'(# 5.'1!

11 = #'5 #5!.555 #.'25 11.4## !42.%! !4'.''' *!.2(' *4.''5 1.14!

112 = %'5 !4.41( #.#5( 11.5!5 !4%.(1 !4!.' *!.115 *.5## 1.44#

114 = '55 !4.2' !.1% .1' !4'.1 !4#.!1% *!.%4( *2.#!5 5.'2!

1!5 = ''5 !42.555 !.555 (.(( !4( !4% *!.555 *(.(( 5.555

1!1 = (55 !42.#2 1.4# (.%' !4(.%' !4%.'1( *1.4#% *(.%% 5.55'

1!! = (!5 !44.(!4 !.!!4 .%#5 !4.% !4%.(%! *!.'2 *4.14# 5.22!

1!# = !5 #5(.((( #.##( 11.1!5 #5#.## !42.' *%.'25 *1'.!( !.5#

1!% = 2!5 #1%.555 #.455 1#.555 #15.1 #5(.%!2 *#.(! *1!.!%5 5.#25

1!' = 4!5 #1%.(1 !.2(1 4.'# #11.4 #54 *!.455 *4.(( 5.5('

1!( = 45 #11.45% 1.45% (.#% #15 #52.(#( *1.#(% *%.'% 5.455

1! 2 = !5 #5(.4!# 5.!(# 5.2 #5(.(( #5%.!! *1.4#2 *(.%(5 !.4!

1!2 2 = 5 #5!.2' *5.15# *5.#%# #5!.4( #5#.%(1 5.'51 1.(5 5.((#

1!4 2 = 45 #51.%!2 *5.15! *5.#%5 #51.'# #51.4!# 5.#4# 1.#15 5.%2'

) 1#5 2 = 145 !4#.2%( 5.54( 5.#!5 !4#.' !4'.(#( 1.22( (.!2 #.#5#

1#1 2 = !45 !2'.555 5.45 !.(## !2%.!1 !2%.!1 5.555 5.555 1.#1

1#! 2 = #%5 !2.222 *5.21! *!.5 !4. !25 5.#55 1.555 5.2'#

1## 2 = #45 !'.2## *5.(# *!.1!# !(.% !.' 1.5#5 #.%## 5.(''

1#% 2 = %%5 !#.'!4 *1.#11 *%.#5 !%.2% !(.!' 1.%15 %.55 5.1('

1#' 2 = %5 !1.212 *1.(1! *'.## !#.%# !'.1(1 1.#1 '.5 5.142

1#( 2 = '5 !(2.((( *1.4'% *(.'1# !5.(! !!.5'2 1.%#2 %.4# 5.2(5

1# 2 = (5 !(%.(1' *!.5%' *(.21 !((.(( !(2.'1 1.411 (.#5 5.!!#

1#2 2 = 15 !(!.2' *1.(!# *'.%15 !(%.%2 !(( 1.'!5 '.5( 5.1!

1#4 2 = (5 !(1.### *1.#! *%.%!# !(!.(( !(%.((( !.55( (.(2 1.1#!

1%5 2 = 215 !'2.!#' *1.(' *'.22# !(5 !(1.2' 1.2' '.4'5 5.5##

1%1 2 = 2(5 !'#.### *#.#! *11.545 !'(.(( !'4 !.#%5 .255 1.(%'

1%! 2 = 455 !'#.555 *#.555 *15.555 !'( !'4 #.555 15.555 5.555

1%# 2 = 1555 !'!.(52 *!.(5! *2.(# !''.!1 !'.#41 !.121 .!5 5.5!

1%% 4 = 155 !''.1! *1.4(2 *(.'(5 !'.1% !'4.!2' !.1%' .1'5 5.!4'

1%' 4 = !55 !'(.((( *1.44% *(.(% !'2.(( !(5.# 1.15 '.55 5.%#

1%( 4 = #55 !'(.(% *1.'( *'.2'# !'2.'! !(5.# 1.2'5 (.1( 5.1'

1% 4 = ##5 !'(.((( *1.((% *'.'% !'2.## !'4.%%% 1.11% #.1# 5.41

1%2 4 = #25 !''.1%! *1.!#2 *%.1! !'(.#2 !'.15' 5.!' !.%1 5.2''

1%4 4 = %#5 !'!. *5.45# *#.515 !'#.(2 !'%.!1 5.'#5 1.( 5.(!!

1'5 4 = %25 !'1.111 5.551 5.55# !'1.11 !'1.111 5.551 5.55# 5.55#

1'1 4 = '55 !'5.555 1.1!5 #.## !%2.22 !%2.%!1 *5.%'4 *1.'#5 1.15!

1'! 4 = (55 !#2.(!5 *5.#55 *1.555 !#2.4! !#2.%(1 *5.%'4 *1.'#5 1.!('

1'# 4 = 55 !#!.555 *5.5(5 *5.!55 !#!.5( !#1.%!2 *5.(#! *!.15 1.1'#

1'% 4 = #5 !#5.### 5.### 1.115 !#5 !!2.222 *1.11! *#.5 1.!42

1'' 4 = 25 !!.### 1.(!# '.%15 !!'.1 !!#.2%( *1.2(% *(.!1# 5.%5!

1'( 4 = 2#5 !!'.!4% 5.(2% !.!25 !!%.(1 !!!.' *!.115 *.5## !.#

1' 4 = 225 !!.'55 #.#%5 11.1## !!%.1( !!!.52# *!.5 *(.4!# !.15'

1'2 4 = 415 !!4.555 !.245 4.(## !!(.11 !!!. *#.### *11.115 5.#2

1'4 15 = 15 !!'.1# *!.2(# *4.'%# !!2 !!! *(.555 *!5.555 1%.!

1(5 15 = 115 !!5.454 !.454 4.(4 !12 !1'.%'% *!.'%( *2.%2 5.(5'

1(1 15 = !15 !12.555 !.%55 2.555 !1'.( !1#.! *!.%55 *2.555 5.555

1(! 15 = !(5 !1(.4!# 1.4!# (.%15 !1' !1!.#5 *!.(4# *2.4 1.!2#

1(# 15 = #15 !1'.#' 1.2 '.4' !1#.' !11.%21 *!.524 *(.4(# 5.'5#

1(% 15 = #(5 !1!.((( 5.4%( #.1'# !11.! !15 *1.!5 *'.## 1.!45

1(' 15 = #45 !11.### 1.### %.%%# !15 !52.%(1 *1.'#4 *'.1#5 5.#%#

1(( 15 = %45 !5'.4!' 1.#1' %.#2# !5%.(1 !5#.### *1.! *%.!' 5.5(#

1( 15 = ''5 !5!.#5 1.1' #.2' !51.1' !55 *1.1'5 *#.2## 5.51!

1(2 15 = (55 14(.!'5 *5.%15 *1.#( 14(.(( 14(.((( 5.55( 5.5!5 5.(#

1(4 15 = ('5 145.''' *1.15' *#.(2# 141.(( 14# 1.#%5 %.%( 5.#4!

15 15 = 55 12!.#5 *#.'!# *11.%# 12'.2# 145 %.15 1#.455 1.52

11 15 = #5 12.!#' *#.%!' *11.%1 121.(( 12'.%'% #.4% 1!.(% 5.(1'

1! 15 = 2#5 15.555 *1.((5 *'.'## 11.(( 1#.'!4 1.2(4 (.!#5 5.#%2

1# 15 = 225 1(1.((( *.##% *!%.%% 1(4 1(4.' 5.'5 !.'55 15.4#

1% 15 = 4#5 1'4.!#5 *!.5 *4.!## 1(! 1(' #.555 15.555 5.#2#

1' 15 = 425 1'(.4!# *'.( *12.4!# 1(!.( 1(#.' 5.455 #.555 .4(!

1( 11 = #5 1''.555 *.%55 *!%.(( 1(!.% 1(!.4' 5.''5 1.2## 11.%1

1 11 = 1#5 1%2.121 *#.214 *1!.#5 1'! 1'!.( 5.(55 !.555 '.#('

12 11 = !#5 1%5.454 *1.#(1 *%.'# 1%!.! 1%#.(#( 1.#(( %.''# 5.552

14 11 = ##5 1#5.1% *#.4%( *1#.1'# 1#%.(( 1#2 #.#%5 11.1## 1.515

125 11 = #5 1!.'55 *%.(%5 *1'.%( 1#!.1% 1#(.((( %.'!( 1'.52 5.145

121 11 = %!5 1!(.555 *.##5 *!%.%## 1##.## 1%5.2## .'5# !'.515 5.!22

12! 11 = %5 1!(.555 *.##5 *!%.%## 1##.## 1%1.%!2 2.542 !(.44# 1.!25

12# 11 = '!5 1!2.### *'.(( *12.245 1#% 1%5 (.555 !5.555 5.'''

12% 11 = '(5 1!2.'5 *%.#!5 *1%.%55 1##.5 1#.(4! %.(!! 1'.%5 5.'5#

12' 11 = ((5 1!.'55 *!.'55 *2.### 1#5 1##.'!4 #.'!4 11.(# 1.1'

12( 11 = (5 1!!.555 *!.555 *(.(( 1!% 1!(.111 !.111 .5# 5.12'

12 11 = 2(5 154.2(% *1.4( *'.42 111.(( 11%.1(( !.'5( 2.#'# 1.12#

122 11 = 4(5 11!.#25 *5.4'5 *#.1( 11#.## 11%.'!# 1.14# #.4 5.%5'

124 11 = 445 111.145 *5.15 *!.#( 111.4 11!.2' 5.4' #.145 5.%1!

145 1! = %5 15.#(2 *!.(#! *2.# 115 115.4'! 5.4'! #.1# !.255

141 1! = 45 15!.!!! *#.#!2 *11.54# 15'.'' 152.2!# #.!# 15.415 5.54!

14! 1! = 1%5 42.!#' *#.12' *15.(1 151.%! 15' #.'25 11.4## 5.('2

14# 1! = 125 4'.1% *!.2'( *4.'!5 42.' 15% '.%#5 12.155 %.!45

14% 1! = !25 4'.555 *!.'55 *2.### 4.' 155 !.'55 2.### 5.555

14' 1! = ##5 4%.!#5 *1.%25 *%.4## 4'.1 4.2' !.1% .1' 1.11!

14( 1! = #25 4!.1%! *1.2'2 *(.14# 4% 4( !.555 (.(( 5.!#

14 1! = %#5 45.555 *1.##5 *%.%## 41.## 4# 1.(5 '.'( 5.'(

142 1! = %(5 2.1%! *1.#2 *'.4# 22.22 45.#%% 1.%(% %.225 5.%'

144 1! = '(5 4.(!4 *1.((1 *'.'# 21.!4 2#.1!' 1.2#' (.11 5.!45

!55 1! = ((5 '.555 *1.!'5 *%.1( (.!' .2!( 1.'( '.!'# 5.'%#

!51 1! = (5 (2.'1 *5.2#4 *!.4 (4.%1 5.%1( 1.55( #.#'# 5.!2

!5! 1! = 2(5 (#.%!2 *1.51! *#.## (%.%% ('.''' 1.11' #.1 5.1!

!5# 1! = 225 (!. *5.2## *!. (#.(1 ('.%5' 1.4' '.42# 1.(5#

!5% 1! = 4#5 (5.(!' *1.2' *(.!'5 (!.' (%.#' 1.2' (.!'5 5.555

!5' 1! = 425 (5.555 *1.25 *(.!## (1.2 (#.' 1.225 (.!( 5.51

!5( 1# = #5 (5.555 *!.1%5 *.1## (!.1% ('.454 #.(4 1!.'(# !.1'

!5 1# = 25 (5.''' *1.((' *'.''5 (!.!! ( %.25 1'.4## '.14!

!52 1# = 125 (5.212 *!.1#! *.15 (!.4' (%.54 1.1%5 #.255 1.('#

!54 1# = !25 (5.2(4 *1.!11 *%.5# (!.52 (#.%2 1.#42 %.((5 5.#1!

!15 1# = #25 (5.2## *1.4# *(.%' (!. (%.%%% 1.(% '.'25 5.%#2

Klasifikasi

PERENCANAAN GEOMETRIK JALAN

RICO DESRIANTOD111 10 251

&)")% M.ngitung (+u/. Gaian 3an Ti/unan

Ta. Hitungan Lua4 3an (+u/. gaian ti/unan 6*+,i /.intang 7

Pat+k Sta4iun

Lua4 /87R.ka6 Lua4 /87

ki*i kanan

Gaian Ti/unan gaian ti/unan Gaian Ti/unan

A 5 = 5 .1'%2 !.1'( .!!5 ! 1%.%!(2 %.#'1!

P1 5 = 5 %.'1% 5.5555 %.%!41 5 2.4%(' 5.5555155

P! 5 = 5 ( 5.5555 %.214' 5.5555 11.!'4 5.5555

P# 5 = 5 %.5#('# 5 %.5(#% 5 2.1555 5.5555

P% 5 = 5 1.%'%(#% '.('%2 1.5#4(! '.('%2 #.1'2( 11.#54(

P' 5 = 5 !.!((' 5 !.(44# 5 %.4%(' 5.5555

P( 5 = 5 !.!#'%# 5 !.15' 5 %.4%(5 5.5555

P 5 = 5 !.'4 5.5555 !.4'#( 5 '.'#1' 5.5555

P2 5 = 5 %.5'15 5 %.5'15 5.5555 2.15!5 5.5555'5

P4 5 = 5 %.%'%2 5.5555 %.!5!! 5 2.('5 5.5555

P15 5 = 5 %.5%5 5 %.1%5 5 2.!%25 5.5555

P11 5 = 5 1.24(% 5 !.!241 5 %.12'' 5.5555

P1! 5 = 5 1.(25( 5.5555 1.(25( 5 #.#(1! 5.5555

J a * a k

Pat+k Sta4iun

Lua4 /87R.ka6 Lua4 /87

ki*i kanan

Gaian Ti/unan gaian ti/unan Gaian Ti/unan

P1# 5 = 5 '.%'2 5 '.''%# 5.5555 11.51#5 5.5555

P1% 5 = 5 '.#(( 5 %.(5% 5.5555 15.%55 5.5555

P1' 5 = 5 1.212 # 1.212 %.!!( #.(#% .%'%1155

P1( 5 = 5 '.4452 # '.4452 # 11.421 '.'24

P1 5 = 5 %.4(2 # (.#%% # 11.#!%! (.5#4

P12 5 = 5 .'#24 1 1.5##' 1 2.'!% !.%#1%

P14 5 = 5 1.'1# 1.5#5 1.%%(2 15 !.4(%1 15.!5

P!5 5 = 5 #.5555 5.5555 #.1255 5 (.1255 5.5555

P!1 5 = 5 %.2%55 5.5555 %.2%55 5 4.(255 5.5555

P!! 5 = 5 ' 5.5555 %.2%55 5 4.(255 5.5555155

P!# 5 = 5 '.5!2% 5.5555 '.!'1( 5 15.!255 5.5555

P!% 5 = 5 (.55' 5 %.##(2 5 15.#%!' 5.5555

P!' 5 = 5 (.#1#( 5 (.5#!% 5 1!.#%(5 5.5555

P!( 5 = 5 '.4412 5.5555 (.5%5 5 1!.5#!' 5.5555

J a * a k

PERENCAN

RICO D

? 5 = 5 ! 5.5555 1.'1# 5.5555 #.!'1# 5

&)")& M.ngitung (+u/. T+ta Gaian 3an Ti/unan

Total Volume Galian < 1%5.!''# mB

Total Volume Tim&unan < #!(4.(1'' mB

8elisih Volume Galian dan Tim&unan < 1%%5.(#42 mB

(+u/. /97

Gaian Ti/unan

'2%.##12 152.4%

1511.1!1' 5.5555

4(2.4(' 5.5555

'(!.4!42 '('.%255

%5'.!'%2 '('.%255

!%.#1!' 5.5555

!(1.4#' 5.5555

#%5.2#' 5.5555

%12.4'5 5.5555

!'#.''5 5.5555

(!1.('5 5.5555

#.###! 5.5555

12.52! 5.5555

(+u/. /97

Gaian Ti/unan

151.5555 5.5555

5!.!!5 #!.5('

25.4'# ((5.('!

'2!.(%'# !4%.4!15

%4.%1#5 !11.#14

!22.%115 #!2.4'45

1#.1(15 1(5.45'5

4#.5555 5.5555

4(2.5555 5.5555

442.5555 5.5555

15#1.1!'5 5.5555

11#%.%!'5 5.5555

1!12.4!'5 5.5555

(%.12( 5.5555

DIAGRAM MASS HOUL

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15

16 17 18 19 20 21 22 23 24 25 26

galian timbunan

Keterangan:Sumbu X = Pato !ang "igali#"itimbunSumbu $% = &olume 'alianSumbu $- = &olume (imbunan

&)2 P.*itungan Ja*ak Pan3ang

A. Perhitungan Jarak Pandang Henti

1. Cntuk alan datar @

2. )ntu *alan "engan elan"aian tertentu

Dimana @ Jh < Jarak "andang henti +m

< Kece"atan rencana < (5 kmam

g < Perce"atan gra$itasi: diteta"kan 4.2

f" < Koefisien gesek memanang antara &an kendaraan dengan

"erkerasan alan as"al: Diam&il < 5.# +AA8HTE

, < ,andai alan +9 +lihat "rofil memanang

T < Faktu tangga": diteta"kan !.' detik

Kontrol untuk kelandaian tertentu Jh Jhmin Jhmin < ' m

+Perencanaan Teknik Jalan -aa: 8hirle ,. H:Ta&el '.1: hal 41

Perhitungan alan datar @

< 5.!2 (5 !.'(5 !

< 22.4 m ≥ Jhmin < ' m!'% 5.#

Perhitungan alan dengan kelandaian tertentu @

)ontoh "erhitungan "ada Tikungan

, <0le$.-encana '* 0le$.-encana 1

< 5Panang Tikungan !14.25

< 5.!2 (5 !.'(5 !

< 22.4%%54 ≥ Jhmin < '!'% 5.# 5.55

Maka di"eroleh arak "andang minimum aitu ' m.

+ + %+

+ + %+ %

T ! %h !'%.!2:5

+!'%.!2:5

! T ! %h

# # ±

! T ! %h

!'%.!2:5

+!'%.!2:5

! T ! %h

# ±+=

?. Perhitungan Jarak Pandang Menia"

Dimana @

< Jarak ang ditem"uh selama /aktu tangga" +m< Jarak ang ditem"uh selama mendahului sam"ai dengan kem&ali ke

laur semula +m5

< Jarak antar kendaraan ang mendahului dengan kendaraan ang datang

dari arah ang &erla/anan setelah "roses mendahului selesai +m

< Jarak ang ditem"uh oleh kendaraan ang datang dari arah &erla/anan

-umus ang digunakan @

Dimana @ < Faktu dalam detik:

m < Per&edaan kece"atan dari kendaraan ang menia" dan kendaraanang disisi": Diam&il 15 kmam

+Perencanaan Teknik Jalan -aa: 8hirle ,. H: Ta&el '.!: hal 4!

Dikletahui @

< #.(2 detik

< 4.%% detik

a < !.! detik

m < 15 kmam

< 5.!2 #.(2 (5 15!.! 4.%%

< (!.15%!

< 5.!2 (5 4.%% < 1'.%'4! m

< #5 m

< !# 3 1'.%'4! < 15%.4!2 m

Jd < (!.15% 1'.%'4! #5 15%.4!2

< #'%.'#'(5! m

Di dalam "erencanaan: seringkali arak "andangan menia" standar ini ter&atasi oleh

kekurangan &iaa: sehingga arak "andangan menia" da"at mem"ergunakan arak

!:1! = 5:5!( V-

Faktu kendaraan &erada di alur la/an +detik: < (:'(= 5:5%2 V-

Perce"atan rata*rata kmamdetik: < !:5'! =5:55#( V-

"andangan menia" minimum + dmin

+ - % +

%#!1 & & & & % & +++=

..!2.5 1

T am! T & #

!! ..!12.5 T ! &

#5# =&

!% #D! & & =

d! = d# = d%#

< 15%.4!2 = #5 = 15%.4!2

< !#4.4%'( m

Maka di"eroleh arak "andang menia" aitu !%5 m.

&)% P.*itungan D.*a0at L.ngkung Ma: Pa3a S.tia6 Tikungan

Kendaraan saat melalui tikungan dengan kece"atan +V akan menerima gaa

sentrifugal ang akan mene&a&kan kendaraan tidak sta&il. Cntuk mengim&angi gaa

sentrifugal terse&ut: "erlu di&uat suatu kemiringan melintang alan "ada tikungan ang

dise&ut 8u"erele$asi +ePada saat kendaraan melalui daerah su"erele$asi: akan teradi gesekan arah

melintang alan antara &an kendaraan dan "ermukaan as"al ang menim&ulkan gaa

melintang ($).

Cntuk menghindari teradina kecelakaan: maka untuk kece"atan tertentu da"at

dihitung ari*ari minimum untuk su"erele$asi maksimum dan koefisien gesekan

maksimum.

Dimana @

D < Deraat lengkung

Perhitungan "ada Tikungan 1@

Diketahui @ < (5 kmam

< *5.555(' (5 = 5.14! < 5.1'#

#(5 < !#.2#!%1%(%! (5

< 11!.5%1##52 m1! 5.1 5.1'#

<12141#.'# 5.1 5.1'#

< 1!.2%%2(#((5 !

melintang . Per&andingan antara gaa gaa normal dise&ut koe$isien gesekan

< Jari*ari tikungan minimum +m

< Kece"atan kendaraan rencana +kmam

< su"erele$asi maksimum: +9

< Koefisien gesekan melintang maksimum

< Deraat maksimum

Cntuk "ertim&angan "erencanaan: digunakan emak

< 15 9 dan f mak

dengan "ersamaan

Maka di"eroleh Dmaks 1!.2

# ' #(5

mak mak

.+'#:12141#

mak mak mak

14!.5555('.5 +−= #mak ! $

Ta. &)2) Hitungan Lua4 3an (+u/. gaian ti/unan 6*+,i /.intang 7

Patok 8tasiun

,uas +m

kiri kanan ki

galian tim&unan galian tim&unan galian

P5 5 = 5 5.5' 5.5! 1.#4 * !.'5P1 5 = '5 5.!5 5.'( 1.%4 * 15.5%

P! 5 = 155 * 5.!# 5.%5 5.(5 *

P# 5 = 1'5 1.!' 5.1! 1.'( * (!.5

P% 5 = !55 5.'5 * .(1 * !'.15

P' 5 = !'5 1.!% * 15.4# * (1.4%

P( 5 = #55 5.! * %.' * 1#.!4

P 5 = #'5 5.#4 5.51 5.22 * 14.#(

P2 5 = %55 5.'( * 5.'1 5.55 !.2#

P4 5 = %'5 5.!4 5.#! 5.' * 1%.(%

P15 5 = '55 5.' * '.#% * !2.'%

P11 5 = ''5 5.41 * .5 * %'.!'

P1! 5 = (55 5.!' 5.5 1.1' * 1!.%4

P1# 5 = ('5 1.5 * 5.!! 5.%( '#.#(

P1% 5 = 55 5.44 * 5.! 5.!4 %4.(5

P1' 5 = '5 5.44 * 5.#! 5.1% %4.((

P1( 5 = 255 5.41 * 2.' * %'.%(

P1 5 = 2'5 5.# * %.! * #(.(4

P12 5 = 455 5.!4 * '.15 * 1%.#1

P14 5 = 4'5 5.54 5.#1 1.5# * %.(2P!5 1 = 5 5.55 1.'5 5.24 * 5.5

P!1 1 = '5 5.1( 5.(2 5.4 * 2.15

P!! 1 = 155 * %.'5 1.#( * *

P!# 1 = 1'5 5.!% 5.#2 5.44 * 1!.14

P!% 1 = !55 5.%2 * '.45 * !#.4(

P!' 1 = !'5 5.% * .% * #.!#

P!( 1 = #55 5.!( 5.!2 1.#( * 1!.45

P! 1 = #'5 * #.(5 5.5% !.!% *

P!2 1 = %55 5.!# 5.%# 1.%4 * 11.(4

P!4 1 = %'5 5.!! 5.%2 1.'' * 11.5#

P#5 1 = '55 5.12 5.(# 1.'2 * 4.5!

P#1 1 = ''5 * 5.(# 5.51 !.'2 *

P#! 1 = (55 * 5.1( 5.1! 1.1 *

P## 1 = ('5 5.#! 5.1# 1.5' * 1(.52

P#% ! = 55 5.2! * 2.#5 * %1.15

P#' ! = '5 5.21 * 4.5# * %5.('

P#( ! = 255 5.(5 * .%' * #5.55

P# ! = 2'5 5.(( * (.4! * ##.1'

P#2 ! = 455 5.## * !.22 * 1(.%4P#4 ! = 4'5 5.%2 * 1.2# * !%.52

P%5 ! = 5 5.24 * 5.% * %%.'2

P%1 ! = '5 1.!5 * 5.'( * '4.4%

P%! ! = 155 1.54 * 5.4% * '%.'2

P%# ! = 115 1.1# * 5.## * '(.#2

P%% ! = !15 5. * 5.%' * #2.(#

umlah !#.12'#!' 1'.5#'1' 1!2.%!21 2.5!% 11'4.!((!'

Sumber : Hasil Perhitungan

JCM,AH GA,IA7 1'1.(1 M!

JCM,AH TIM?C7A7 !#.5( M!

80,I8IH 1!2.'' M!

Volume +mB

ri kanan

tim&unan galian tim&unan

1.55 (4.'2 *!.4( %.%! *

11.5 !5.54 *

(.1' 2.15 *

* #25.%5 *

* '%(.1 *

* !!2.(' *

5.!( %#.2# *

* !'.#4 *

1(.!# #.!' *

* !(.!% *

* #2%.2' *

#.'5 '.%5 *

* 15.4( *

* 1#.(5 *

* 1(.1( *

* %!2.%2 *

* !#(.55 *

* !''.11 *

1'.%% '1.! *%.4( %%.%! *

#%.5( %2.#' *

!!%.21 (2.1' *

14.5! %4.'( *

* !4%.2# *

* ##.'( *

1#.4# (.22 *

14.21 1.2' *

!1.(1 %.(# *

!#.( .'( *

#1.'5 4.55 *

#1.%2 5.'' *

2.51 (.1' *

(.' '!.'% *

* %1'.5! *

* %'1.!' *

* #!.## *

* #%'.2' *

* 1%#.( ** 41.!' *

* !#.%! *

* !2.55 *

* %(.4( *

* 1(.(' *

* !!.%! *

'1.'2' (%!1.%5' *

:'25.( M#

'1.( M#

(:2!2.41 M#

&)& ALIN;EMEN HORI<ONTAL

M.ngitung 3an M.*.n=anakan J.ni4 Tikungan

A) M.n.ntukan J.ni4 Tikungan

8arat Tikungan @

*Tikungan 8"iral*)ircle*8"iral + 8*)*8 &ila L= > 25 /

P > $?25 /

L= @ 2L4 2T4

*Tikungan 8"iral*8"iral &ila P > $?25 /

L= 25 /

Dimana @

Tikungan I

-c < 14 m

D <1%#!.#4

<1%#!.#4

< 2.55!1254- 14

15 9 dan D < 2.55!1254 : di"eroleh @

e < 5.542

,s < 5 m

< 1.1%5'4'4!% 3 14

< 11.!5#52'%#.1% 14

<45 * ! 11.!5#1

3 #.1% 3 1125

< !11.1!'%!%4(# m

8arat Tikungan @ L= > 25 / 211)1!25&2 m ; 25

P > $?25 / 1)1&$5#5# m ; $)25

*Tikungan Lull )ircle &ila P $?25 /

Ls di"eroleh "ada ta&el %. ?uku Perencanaan Geometrik Jalan

Dari Ta&el %.( untuk emak

Digunakan Tikungan S6i*a - Ci*=. - S6i*a

)#( ) s

L( π θ

!+ −∆=

s π θ

)#( ) s

L( π θ

!+ −∆= #

:!ee − .+ #:#

:!ee − .+ !ee − .+ !ee − .+ !ee − .+ #:#

:!ee − .+ !ee − .+ !ee − .+ #:#

:!!!!ee − .+ ee − .+ ee − .+ ee − .+ ee − .+ !ee − .+ !ee − .+ !ee − .+ !ee − .+ !ee − .+ !ee − .+ !ee − .+ !ee − .+ !ee − .+ !ee − .+ !ee − .+ !ee − .+ ! ee − + !ee − + !ee − + ! #( s

') Di4t*iu4i Su6.* ..Ba4i

)ontoh "erhitungan "ada tikungan I

<2.55!

5.1 < 5.52%#122 < 2.%#!4.1!5

2.%# 9 15 9 EK

C) P.*itungan .ngkung P.*aian

Keterangan @6s < a&sis titik 8) "ada garis tangen: arak dari titik T8 ke 8) + arak lurus lengkung

"eralihan .

Ns < Erdinanat titik 8) "ada garis tegak lurus garis tangen: arak tegak lurus ke titik

8) "ada lengkung

,s < Panang lengkung "eralihan + "anang dari titik T8 ke 8) atau )8 ke 8T

,c < Panang &usur lingkaran + "anang dari titik 8) ke )8

Ts < Panang tangen dari titik PI ke titik P8 atau ke titik 8T

T8 < Titik dari tangen ke s"iral

8c < Titik dari s"iral ke lingkaran

0s < Jarak dari PI ke &usur lingkaran

Os < 8udut lengkung s"iral

-c < Jari*ari lingkaran

" < Pergeseran tangen terhada" s"iral

k < A&sis dari " "ada garis tangen s"iral

kontrol e emak

Komonen S--S

! e!!##

.θ!! e!!##

.! e!!##

)ontoh "errhitungan "ada tikungan 8 * ) * 8 "ada tikungan I

dik@ -c < 14 m

< (5 kmam

,s < 5 m

< 5 + 15 !

%5 14 !

< %.'(!#215%

14 1 5( 14

< 5 *5 #

* 14 1 < !%'1#4(.55 m%5 14 !

< 14 1%(55%.# 1 !%'1#4(.55 < !%24'4.#### m

< 14 1%(55%.# 1.%1% 14 < !5('''.%'!'4!4 m

< !11.1 = 1%5 < #'1.1!'%!%4(#

.- , -

Ls LS -s

cos1+(

s #( #(

Ls θ −−=

s #(Sin #(

Ls Lsk θ −−=

k #(Ts +∆+= !D1tan+

#( #( /s −∆+= !D1sec+

Ls L( Ltot !+=

() #**#T & ++= !TLs =Ls 1!1.!5!!.5 −= !Ls =() #**#T & ++= !() #**#T & ++= !() #**#T & ++= !TLs =Ls 1!1.!5!!.5 −= !Ls = TLs =Ls 1!1.!5!!.5 −= !Ls = TLs =Ls 1!1.!5!!.5 −= !Ls = TLs =Ls 1!1.!5!!.5 −= !Ls =() #**#T & ++= !() #**#T & ++= !() #**#T & ++= !TLs =Ls 1!1.!5!!.5 −= !Ls = TLs =Ls 1!1.!5!!.5 −= !Ls = TLs =Ls 1!1.!5!!.5 −= !Ls =() #**#T & ++= !() #**#T & ++= !() #**#T & ++= !() #**#T & ++= !() #**#T & ++= !() #**#T & ++= !() #**#T & ++= !() #**#T & ++= !() #**#T & ++= !() #**#T & ++= !() #**#T & ++= !() #**#T & ++= !() #**#T & ++= !() #**#T & ++= !() #**#T & ++= !() #**#T & ++= !() #**#T & ++= !() #**#T & ++= !() #**#T & ++= !() #**#T & ++= !TLs =Ls 1!1.!5!!.5 −= TLs =Ls 1!1.!5!!.5 −= TLs =Ls 1!1.!5!!.5 −= TLs =Ls 1!1.!5!!.5 −= !Ls = !Ls = !Ls = !Ls = !Ls = TLs =Ls 1!1.!5!!.5 −= !Ls = TLs =Ls 1!1.!5!!.5 −= !Ls = TLs =Ls 1!1.!5!!.5 −= !Ls = TLs =Ls 1!1.!5!!.5 −= !Ls = TLs =Ls 1!1.!5!!.5 −= !Ls = TLs =Ls 1!1.!5!!.5 −= !Ls = TLs =Ls 1!1.!5!!.5 −= !Ls = TLs =Ls 1!1.!5!!.5 −= !Ls = TLs =Ls 1!1.!5!!.5 −= !Ls = TLs =Ls 1!1.!5!!.5 −= !Ls = TLs =Ls 1!1.!5!!.5 −= !Ls = TLs =Ls 1!1.!5!!.5 −= !Ls = TLs =Ls 1!1.!5!!.5 −= !Ls = TLs =Ls 1!1.!5!!.5 −= !Ls = TLs =Ls 1!1.!5!!.5 −= !Ls = TLs =Ls 1!1.!5!!.5 −=

< (4.#!#% m

< 1%(55%.## m

D) P..a*an Pa3a Tikungan

Dimana @ ? < ,e&ar total "ada "erkerasan di tikungan +m

n < Jumlah laur < !

& < ,e&ar lintasan truk di tikungan

P < Jarak as &elakang dan as muka truk +arak antar gandar < (.'

c < Ke&e&asan sam"ing + 5.% m * 5.2 m : diam&il 5.2 m

Td < ,e&ar melintang aki&at tonolan de"an +m

A < Tonolan de"an kendaraan < 1.' m

Q < ,e&ar tam&ahan aki&at kelainan dalam mengemudi +m

Cntuk Tikungan 1

Diketahui @ - < 14 m

< (5 kmam

,e&ar alan < 15 m

Maka @ & < !.% = 14 #!5%1 * %!.!' < !.'1

Td < #!5%1 = 1.' 1# = 1.' * 14 < 5

R <5.15' (5

< 5.%522 m14

? < ! !.'121 5.2 ! 1.5 5.5( = 5.%522 < .1(#4#!# M

? ,e&ar alan lurus

Jadi tidak di&utuhkan "ele&aran

!! +S%:!P # #b −−+=

, % , -

!! .+S%:!P # #b −−+=

+ T& n(bn 0 +−++= .1+.P+

! + #15':5=

( ){ } # * * #T& −++=!D1!

( ){ } # * * #T& −++= !D1! !

#15':5

Ls 1!1.!5!!.5 #S π!=Ls 1!1.!5!!.5 Ls 1!1.!5!!.5 Ls 1!1.!5!!.5 Ls 1!1.!5!!.5 Ls 1!1.!5!!.5 Ls 1!1.!5!!.5 Ls 1!1.!5!!.5 Ls 1!1.!5!!.5 Ls 1!1.!5!!.5 Ls 1!1.!5!!.5 Ls 1!1.!5!!.5 Ls 1!1.!5!!.5 Ls 1!1.!5!!.5 Ls 1!1.!5!!.5 Ls 1!1.!5!!.5 Ls 1!1.!5!!.5 Ls 1!1.!5!!.5 Ls 1!1.!5!!.5 Ls 1!1.!5!!.5 Ls 1!1.!5!!.5 Ls 1!1.!5!!.5 Ls 1!1.!5!!.5 Ls 1!1.!5!!.5 Ls 1!1.!5!!.5 Ls 1!1.!5!!.5 Ls 1!1.!5!!.5 Ls 1!1.!5!!.5

E) P.*itungan Lan3ai R.ati,

Kemiringan melintang atau kelandaian "ada "enam"ang alan diantara te"i "erkerasan luar

dan sum&u alan se"anang lengkung "eralihan dise&ut landai relatif. Persentase kalandaian ini

disesuaikan dengan kece"atan rencana dan umlah laur ang ada.

Dimana @ 1m < ,andai relatif: +9

e < 8u"erele$asi Tikungan

en < kemiringan melintang normal < ! 9 < 5.5!

? < ,e&ar alur < % m

)ontoh Tikungan I

,s < '5

e < 5.15

5.15 5.5! %< 5.554%% < 5.4%% 9

Perhitungan Tikungan 1

1 (:# ,#),Γ(:# (:# ,#),Γ(:# (:# ,#),Γ(:# (:# ,#),Γ(:# (:# ,#),Γ(:# (:# ,#),Γ(:# (:# ,#),Γ(:# (:# ,#),Γ(:# (:# ,#),(:# ,#),(:# ,#),(:# ,#),Γ(:# Γ(:#Γ(:# Γ(:#Γ(:# (:# ,#),Γ(:# (:# ,#),Γ(:# (:# ,#),Γ(:# (:# ,#),Γ(:# (:# ,#),Γ(:# (:# ,#),Γ(:# (:# ,#),Γ(:# (:# ,#),Γ(:# (:# ,#),Γ(:# (:# ,#),Γ(:# (:# ,#),Γ(:# (:# ,#),Γ(:# (:# ,#),Γ(:# (:# ,#),Γ(:# (:# ,#),Γ(:# (:# ,#),

F) Pan0ang P.n=a6aian Su6.*..Ba4i

Panang lengkung "eralihan +,s: menurut: Menurut tata cara Perencanaan Geometrik

Jalan Antar Kota: 144: diam&il nilai ang ter&esar dari tiga "ersamaan di &a/ah ini.

a. ?erdasarkan /aktu tem"uh maksimum +#detik: untuk melintasi lengkung "eralihan:maka "anang lengkung @

+Perencanaan Teknik Jalan -aa: 8hirle ,. H:Ta&el '.1: hal 4

&. ?erdasarkan antisi"asi gaa sentrifugal: Digunakan rumus Modifikasi 8hortt: s&&@

c. ?erdasarkan tingkat "enca"aian "eru&ahan kelandaian

Dimana @ T < Faktu tem"uh < # detik

-c < Jari*ari &usur lingkaran:+m

) < Peru&ahan "erce"atan: + 5:# * 1:5 diam&il 5.%

< Tingkat "enca"aian "eru&ahan kelandaian melinang alan: s&&@

< 5.5%

< kemiringan melintang normal < ! 9 < 5.5!

Cntuk Tikungan I

< (5 Kmam

< 1%5 m

e < 5.542

a. <(5

3 # < '5 m#.(

< 5.5!!!1(555

* !.!(5 3 5.15

< %%.5!%!4'( 5.%

c. <5.1 * 5.5!

3 (5 < ##.########.( 3 5.5%

Cntuk V- U 5 km

emak D

# # .!.!5!!.5

nm ! ee

LsΓ−=(:#

Ls # # .

!.!5!!.5

(:# ,#),eΓ(:# (:# ,#),eΓ(:# (:# ,#),eΓ(:# (:# ,#),eΓ(:# (:# ,#),eΓ(:# (:# ,#),eΓ(:# (:# ,#),eΓ(:# (:# ,#),eΓ(:# (:# ,#),(:# ,#),(:# ,#),(:# ,#),eΓ(:# eΓ(:#eΓ(:# eΓ(:#eΓ(:# (:# ,#),eΓ(:# (:# ,#),eΓ(:# (:# ,#),eΓ(:# (:# ,#),eΓ(:# (:# ,#),eΓ(:# (:# ,#),eΓ(:# (:# ,#),eΓ(:# (:# ,#),eΓ(:# (:# ,#),eΓ(:# (:# ,#),eΓ(:# (:# ,#),eΓ(:# (:# ,#),eΓ(:# (:# ,#),eΓ(:# (:# ,#),eΓ(:# (:# ,#),eΓ(:# (:# ,#),

G) Ja*ak Pan3angan Pa3a L.ngkung H+*i4+nta

Jika Jh ,t @

Dimana @ - < Jari*ari tikungan +m

< Jari*ari sum&u laur dalam

< Jarak "andang henti +m < ' m

,t < Panang tikungan

? < ,e&ar alur < % m

)ontoh "erhitungan "ada Tikungan I

Diketahui @

- < (5 m

< - * ?! < (5 * ! < '2 m

0 < '2 1 5.42 < 11.52

−= "

,os # / #(5

PERENCANAAN GE

RICO DESRIAN

TABEL 3. VARIBEL ALINYEMEN HORISONTAL

Tikungan

Rc ∆ Ls

e Xs Ys өs p k Ts Es Lc Ltot( m ) ( o ) (m)

(iungan 1 belo Kanan , 0 0 0 0.00 &#0 &#0 0.00 &#0 &#0 &#0 &#0 0.00 0.00

rr:509 0 0 0 0.00 &#0 &#0 0.00 &#0 &#0 &#0 &#0 0.00 0.00

rr:509 0 0 0

0.00 &#0 &#0 0.00 &#0 &#0 &#0 &#0 0.00 0.00

PERENCANAAN G

RICO DESRIA

TikunganRc ∆ Ls

e Xs Ys өs p k Ts Es Lc Ltot( m ) ( o ) (m)

rr:509 0 0 0 0.00 &#0 &#0 0.00 &#0 &#0 &#0 &#0 0.00 0.00

(iungan 28 belo Kanan, 0 0 0 0.00 &#0 &#0 0.00 &#0 &#0 &#0 &#0 0.00 0.00

(iungan 29 belo Kiri, 0 0 0 0.00 &#0 &#0 0.00 &#0 &#0 &#0 &#0 0.00 0.00

Diagam !upe E"e#asi

(iungan ;/

X/ $/ / (/ / m , m,

1 179 90 70 69.732374 4.5623836 0.00 4.5624 69.73237 253.29 80.6

'ambar 4.1 iagram Suer le<a/i

Tikungan $ belo Kanan ,

/(S S(

iriiri

anananan

Sumbu *alan

;/ ;/;

2 3 41 4

0 0.00 140.00

4.6 PERHITUNGAN ALINYEMEN VERTIKAL

4.7.1 Panjang Leng!ng Ve"#$a%

Panang lengkung $ertikal dari P,V ke PTV < ,$ Dimana ,$ di"eroleh dari grafik

"erencanaan geometrik dengan mengetahui A dan Vr di"eroleh ,$

)ontoh 8TA 5 = #5

- Pa3a STA) 1 @ 25$

DikW < %.55 9

< 5.55 9

Vr < (5 KmJam

A < %.55 9

&erdasarkan grafik di"eroleh ,$< '5m

4.7.& Ben#! Leng!ng Ve"#$a%

'(n#() a%$ne*en #+,e -e*!ng

- Pa3a STA) 1 @ 125

DikW < %.55 9

< 5.55 9 D"h < 2

Vr < (5 KmJam A < %.55

Titik PP!

X 0le$asi PPV < (.## m

X Jarak PPV < 1 = 1!'

X Per&edaan ala&ar landai +A < m < %.55 * 5.

X Panang lengkung $ertikal dari P,V ke PTV < ,$ Dimana ,$ di"eroleh dari grafik

"erencanaan geometrik dengan mengetahui A dan Vr di"eroleh ,$ <

X Pergeseran $ertikal dari titik PPV ke &agian lengkung < ,$ '5 m

0$ <A.,$

<% . '5

< 5.!'5 m255 255

Titik PP!

X 0le$esi PPV < PPV * 0$

< (.## * 5.!'5 < (.52

X Jarak PPV < 1 = 1!' m

Titik PL!

X 0le$esi P,V <

< (.## * + %.55 9 . 1! . '5

X Jarak P,V < PPV * 1!.,$

< 1 = 1!' * 1! . '5 < 1 =

Titik PT! X 0le$esi PTV <

< (.## = + 5.55 9 . 1! . '5

X Jarak PTV < PPV = 1!.,$

< 1 = 1!' = 1! . '5 < 1 =

Titik P &an

3 < 1% .,$

< 1% . '5 < 1!.'55 m

< <%.55 . 1'(.!'

< 5.5(# m!55,$ !55 . '5

X 0le$asi P <

< (.## * + %.55 9 . 1!.'55 *

X Jarak P < PPV * 3

< 1 = 1!' * 1!.'55 < 1 * 11!.'5

X 0le$asi Y <

< (.## = + 5.55 9 . 1!.'55 *

X Jarak Y < PPV = 3

< 1 = 1!' = 1!.'55 < 1 = 1#.'5

GAM'AR LENGKUNG (ERTIKAL CEM'UNG STA) 1 @ 125

g1 * g

PPV * + g1 9 . 1!.,$

PPV = + g! 9 . 1!.,$

A . 3!

PPV * + g1 9 . 3 *

PPV = + g! 9 . 3 *

P;& PP&g1

!=0.063

6 < 1!.'55 6 < 1!.'55 6 < 1!.'55 6 < 1!.'5

0le$asi +m ((.## ((.52 (.52

Jarak +m 5 = 155.5 5 = 11!.'5 5 = 1!' 5 =

P<=0.25

55 < %.55 9

< ((.## m

< (.## m

5.5(# < ((. m

5.5(# < (.! m

(.! (.##

1#.'5 5 = 1'5.5

&)5 ALIN;EMEN (ERTIKAL

- Pa3a STA) 1 @ 15$

DikW < 5.55 9 D"h < 5

< *2.55 9 A < 2.55

Vr < (5 KmJam

Titik PPV

X 0le$asi PPV < 15'.55 m

X Jarak PPV < 1 = 1'5 m

X Per&edaan ala&ar landai +A < < 5.55 = *2.55

X Panang lengkung $ertikal dari P,V ke PTV < ,$ Dimana ,$ di"eroleh dari grafik

"erencanaan geometrik dengan mengetahui A dan Vr di"eroleh ,$ < 15' m

X Pergeseran $ertikal dari titik PPV ke &agian lengkung < ,$

0$ < A.,$ < 2.55!12 . 15' < 1.5'5 m255 255

Titik PPV

X 0le$esi PPV < PPV * 0$

< 15'.55 * 1.5'5 < 15#.4'

X Jarak PPV < 1 = 1'5 m

Titik P,V

X 0le$esi P,V <

< 15'.55 * + 5.55 9 . 1! . 15'

X Jarak P,V < PPV * 1!.,$< 1 = 1'5 * 1! . 15' < 1 =

Titik PTV

X 0le$esi PTV <

< 15'.55 * + 2.55 9 . 1! . 15'

X Jarak PTV < PPV = 1!.,$

< 1 = 1'5 = 1! . 15' < 1 =

Titik P dan Y

3 < 1% .,$

< 1% . 15' < !(.!'5 m

< <2.55 . (24.5(

< 5.!(# m!55,$ !55 . 15'

X 0le$asi P<

< 15'.55 * + 5.55 9 . !(.!'5 *

X Jarak P < PPV * 3

< 1 = 1'5 * !(.!'5 < 1 * 1!#.'

X 0le$asi <

< 15'.55 * + 2.55 9 . !(.!'5 *

X Jarak Y < PPV = 3

< 1 = 1'5 = !(.!'5 < 1 = 1(.!'

GAM'AR LENGKUNG (ERTIKAL CEKUNG STA) 1 @ 15$

g1 * g

PPV * + g1 9 . 1!.,$

PPV = + g! 9 . 1!.,$

A . 3!

PPV * + g1 9 . 3 *

PPV = + g! 9 . 3 *

6 < !(.!'5 6 < !(.!'5 6 < !(.!'5

0le$asi +m 15'.55 15%.% 15#.4' 15!.(

Jarak +m 1 = 11'.5 1 = 1!5.55 1 = 1'5 1 =

< = -1.17 m

< 2.55 9

< 15'.55 m

< 155.25 m

!5!.' m

5.!(# < 15%.% m

5.!(# < 15!.(% m

6 < !(.!'5 m

% 155.25

1#5.55 1 = 1#'.5

= -0.29m

TA%EL &ARI%EL ALINYE'EN &ERTIKAL TYE E'%UNG

7o PATOK (g1 g2

A PP( /7 L EB PP( /7E.B E.B

PL( PT( P

1 8ta + 1 = 1'5 (5 %.( 5 %.( 2'.1! (! 5.#' 2%.( 2% 2'.1! 1'.'5 5.524 2%.#

! 8ta + 1 = 445 (5 '.52 5 '.52 1#%.!2 5 5.%%' 1##.2% 1## 1#%.!2 1.'5 5.111 1##.!

# 8ta + ! = #15 (5 15 5 15 1(1 1%5 1.'5 1'4.!' 1'% 1(1.55 #'.55 5.%#2 1'.5

% 8ta + ! = '45 (5 15 5 15 12( 1%5 1.'5 12%.!' 14 12(.55 #'.55 5.%#2 12!.5

' 8ta + ! = 4#5 (5 (.' 5 (.' !5#.' 45 5.#1 !5#.5! !51 !5#.' !!.'5 5.12# !5!.( 8ta + % = 445 (5 1.4 5 1.4 !'2.2 %5 5.54' !'2.1 !'2 !'2.25 15.55 5.5!% !'2.'

8ta + ' = %(5 (5 (.#% 5 (.#% !24.54 22 5.(4 !22.#4 !2( !24.54 !!.55 5.1% !2.'

2 8ta + ' = 4'5 (5 !.24 5 !.24 #15 %5 5.1%' #54.2( #54 #15.55 15.55 5.5#( #54.(

4 8ta + ( = 25 (5 #.## 5 #.## #!(.(( %1 5.11 #!(.%4 #!( #!(.(( 15.!' 5.5%# #!(.!

15 8ta + = 45 (5 5 *2.(% 2.(% #11.4 1!5 1.!4( #15.(5 #1! #5(.! #5.55 5.#!% #11.'

11 8ta + 4 = #25 (5 5 *.22 .22 !'2.## 115 1.52% !'.!' !'2 !'%.55 !.'5 5.!1 !'2.5

1! 8ta + 4 = 25 (5 5 *!.#2 !.#2 !!4.! %5 5.114 !!4.52 !!4 !!2.! 15.55 5.5#5 !!4.

1# 8ta + 11 = '!5 (5 5.## 5 5.## 1##.## %5 5.51 1##.#1 1## 1##.## 15.55 5.55% 1##.!

1% 8ta + 1! = ##5 (5 5 *(.(# (.(# 4.' 4! 5.(! 4(.% 42 4%.%' !#.55 5.141 4.#

TA%EL &ARI%EL ALINYE'EN &ERTIKAL TYE EKUNG

7o Sta (g1 g2

A PP( /7 L EB PP( /7E.B E.B

PL( PT( P

1 8ta + 1 = 1'5 5 5 2.1 *2.1 15' 11' *1.1% 15#.2# 15' 154.5 !2.' *5.!4% 15'.

! 8ta + 1 = '15 (5 5 '.(5 *'.( 1!1.4 % *5.'12 1!1.#2 1!1.4 1!#.4 12.'5 *5.1#5 1!!.

# 8ta + # = !%5 (5 5 2.22 *2.22 !5' 1!# *1.#(' !5#.(# !5' !15.%( #5.' *5.#%1 !5'.

% 8ta + # = (!5 (5 5 2.#% *2.#% !#! 11( *1.!54 !#5.4 !#! !#(.2% !4.55 *5.#5! !#!.

' 8ta + # = 4'5 (5 5 %.4' *%.4' !'1.(( (2 *5.%!1 !'1.!% !'1.(( !'#.#% 1.55 *5.15' !'1.( 8ta + ( = %!5 (5 5 '.1% *'.1% #1%.'2 5 *5.%'5 #1%.1# #1%.'2 #1(.#2 1.'5 *5.11! #1%.

8ta + = ''5 (5 5 #.44 *#.44 !4%.(1 '5 *5.!%4 !4%.#( !4%.(1 !4'.(1 1!.'5 *5.5(! !4%.

2 8ta + 2 = #45 (5 *4.'% 5.55 *4.'% !(.% 1#5 *1.''5 !%.4! !2!.(1 !(.% #!.'5 *5.#22 !4.

4 8ta + 2 = 215 (5 *%.%2 5.55 *%.%2 !(5 (2 *5.#21 !'4.(! !(1.'!#! !(5.55 1.55 *5.54' !(5.

15 8ta + 15 = #15 (5 *!.5# 5.55 *!.5# !1#.' %5 *5.15! !1#.% !1#.4( !1#.' 15.55 *5.5!' !1#.

11 8ta + 15 = 55 (5 *4.2# 5.55 *4.2# 12'.(( 1#( *1.(1 12#.44 14!.#%%% 12'.(( #%.55 *5.%12 124.

1! 8ta + 15 = 4#5 (5 *4.(( 5.55 *4.(( 1(( 1!2 *1.'%( 1(%.%' 1!.12!% 1((.55 #!.55 *5.#2( 1(4.

1# 8ta + 1! = 45 (5 *4.4 5.55 *4.4 15! 1#4 *1.!5 155.!2 152.225' 15!.55 #%.' *5.%#5 15'.

1% 8ta + 1! = 425 (5 *1.# 5.55 *1.# (5 %5 *5.5(' '4.4% (5.!( (5.55 15.55 *5.51( (5.1

JALAN LURUS

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&)! PERHITUNGAN TE'AL PERKERASANP.*itungan C'R Tana Da4a*

a. ntuk ruas jalan stasiun 5 (*) samai stasiun 657 (0)

Diketahui harga )?- +9 adalah #:% : %:2 : ':( : (:2

7o )?-+9 Jumlah ang sama atau le&ih &esar Prosentase +9

1 #.% 1 = # < % 155

! %.2 1 = ! < # '

# '.( 1 = 1 < ! '5

% (.2 1 = 5 < 1 !'

?entuk grafiknaW

Diam&il adalah )?- 45 9 < %)"

!"# #"$ 5"% %"$

'BR /0

P"(2en#a2e /0

b. ntuk ruas jalan stasiun 657 (0 )samai stasiun (, )

Diketahui harga )?- +9 adalah %:! : #:( : ':% : (:1

7o )?-+9 Jumlah ang sama atau le&ih &esar Prosentase +9

1 #.( 1 = # < % 155

! %.! 1 = ! < # '

# '.% 1 = 1 ! '5

% (.1 1 = 5 < 1 !'

?entuk grafiknaW

Diam&il adalah )?- 45 9 < %)!

!"% #"2 5"# %"10

'BR /0

P"(2en#a2e /0

MENGHITUNG TE'AL PERKERASAN JALAN 'ARU

A. -uas alan A * ? + Metode Analisa Kom"onen < ?ina Marga

Perhitungan data*data hasil sur$e lalu lintas ang dilakukan "ada tahun 144

/8"S 9/8'*#**8 JCM,AH K07DA-AA7

#*S *L*8 (*) (0)

Kendaraan ringan ! ton + ! @ 1 %255

?us 2 ton + # @ ' 1(55

Truck ! as 15 ton +%@( 2%5

Truck # as 1# ton +'@2 %15

Truck ' as 1' ton + (@4 %5

Data @

Cmur rencana

Program "eningkatan alan dimulai "ada tahun !55!

Perkem&angan ,alu ,intas "er tahun adalah < 2 9Laktor -egional +L- < 1 daerah "edataran

?ahan*&ahan "erkerasan @

,a"isan "ermukaan @ As&uton

,a"isan "ondasi atas @ ?atu Pecah A

,a"isan "ondasi &a/ah @ 8irtu A

< ,H-i 3

Dimana @,H-i < ,intas harian rata*rata tia" enis kendaraan

a < Perkem&angan lalu lintas "er tahun

n < Jumlah tahun dari saat diadakan "engamatan sam"ai alan

terse&ut di&uka

< !55! * 144

< ' tahun

< + 1 = 5.1 !

< 1.!15

;.1 <enghitung lintas harian ratarata a=al umur renana (LH#a=al

,H- a/al +1 = an

+1 = an

Kendaraan ringan ! ton + ! @ 1 < %255 3 1.!15 < '252 &uah

?us 2 ton + # @ ' < 1(55 3 1.!15 < 14#( &uah

Truck ! as 15 ton +%@( < 2%5 3 1.!15 < 151(.% &uah

Truck # as 1# ton +'@2 < %15 3 1.!15 < %4(.1 &uah

Truck ' as 1' ton + (@4 < %5 Z 1.!15 < %2.% &uah

< 4#5%.4 &uah

hari ! urusan

Dimana @

,H-i < ,intas harian rata*rata a/al umur rencana

r < Perkem&angan lalu lintas "er tahun < 15 9

n < Cmur rencana alan terse&ut

< ' tahun< + 1 = 5.1 '

< 1.(11

Kendaraan ringan ! ton + ! @ 1 < '252.5 3 1.(11 < 4#'#.2% &uah

?us 2 ton + # @ ' < 14#(.5 3 1.(11 < #11.4' &uah

Truck ! as 15 ton +%@( < 151(.% 3 1.(11 < 1(#(.4! &uah

Truck # as 1# ton +'@2 < %4(.1 3 1.(11 < 42.4% &uah

Truck ' as 1' ton + (@4 < %2.% Z 1.(11 < .4%2 &uah

,H-akhir < 1%452 &uah

;.3 <enghitung angka eki>alen (/)

#umus 0ina <arga

,H- a/al

;.2 <enghitung lintas harian ratarata akhir umur renana (LH#akhir

,H- akhir

,H- a/al +1 = rn ZZ1

+1 = rn

0 sum&u tunggal < +&e&an sum&u tunggal : kg21(5%

0 sum&u ganda < +&e&an sum&u ganda: kg21(5%. 5:52(

Penentuan distri&usi &e&an sum&u "ada &er&agai enis kendaraan &erdasarkan ta&el %.%

Kendaraan ringan ! ton + ! @ 1

0 < + !#. !55521(5 = + 1#. !55521(5

< 5.5551 = 5.5555% < 5.555(

?us 2 ton + # @ '

0 < + #2. 255521(5 = + '2. 255521(5

< 5.12!%4 = 5.1%54 < 5.#!#%(

Truck ! as 15 ton +%@(

0 < + %15. 1555521(5 = + (15.1555521(5

< 5.%%''# = 5.#%%1( < 5.24(4

Truck # as 1# ton +'@2

0 < + '1#. 1#55521(5 = + 21#.1#55521(5

< 1.!!% = 5.42!4' < !.!''%!

Truk ' as 1' ton +(@4

0 < + '1#. 1'55521(5 = + 21#.1'55521(5

< !.!''%2 = 1.%!#1 < #.444

Menentukan koefisien distri&usi kendaraan + )

+ untuk alan ! alur ! arah

Kendaraan ringan + )1 < 5.'

Kendaraan &erat + )! < 5.'

;.4 <enghitung lintas eki>alen ermulaan (L/P)

i<n< ,H-a/al . 0i . )i

,H-i . + 1 = a n . 0i . )i

Dimana @

0i < Angka eki$alen tia" enis kendaraan

)i < Koefisien distri&usi tia" enis kendaraan

Maka @

Kendaraan ringan ! ton + ! @ 1 < '252.5 3 5.555( 3 5.' < !.144 &uah

?us 2 ton + # @ ' < 14#(.5 3 5.#!#%( 3 5.' < #1#.15' &uah

Truck ! as 15 ton +%@( < 151(.% 3 5.24(4 3 5.' < %51.#14 &uah

Truck # as 1# ton +'@2 < %4(.1 3 !.!''%! 3 5.' < ''4.%'2 &uah

Truck ' as 1' ton + (@4 < %2.% 3 #.444 3 5.' < 4(.%( &uah

,0P < 1#!.2!2 &uah

;.? <enghitung lintas eki>alen akhir (L/*)

,0A < ,0P . + 1 = r

Maka @

Kendaraan ringan ! ton + ! @ 1 < !.144' 3 1.(11 < #.'%!!2#!(42 &uah

?us 2 ton + # @ ' < #1#.15' 3 1.(11 < 5%.!'22!4( &uah

Truck ! as 15 ton +%@( < %51.#14 3 1.(11 < (.#!2'2 &uah

Truck # as 1# ton +'@2 < ''4.%'2 3 1.(11 < 1.51!%25## &uah

Truck ' as 1' ton + (@4 < 4(.%( 3 1.(11 < 1''.2111(!(% &uah

,0A < !!15.4'! &uah

;.6 <enghitung lintas eki>alen tengah (L/T)

,0T <1

+ ,0P = ,0A !

1#!.2!2 = !!15.4'!'!

< 141.24 &uah

;.; <enghitung lintas eki>alen renana (L/#)

,0- < ,0T . LP

Dimana @ Maka @

LP < Laktor "enesuaian < C-15 < +'15 ,0- < 141.2455!1 3 5.'

< 5.' < 24'.4%'5152' &uah

C- < Cmur rencana

PENENTUAN TE'AL PERKERASAN

+ Metode ?ina Marga

Sta4iun $@$$$ A7 Sa/6ai 4ta4iun 1@25 '7

;.7 <enghitung in&e tebal erkerasan ("TP)

Diketahui @ )?- 45 9 < #.2

L- < Laktor regional < 1

IPo <Indeks "ermukaan a/al

< Di"eroleh dari indeks "ermukaan a/al timur rencana +ta&el '.!

Disesuaikan dengan enis la"isan "ermukaan ang akan digunakan

< #:4 * #:'

IPt < Indeks "ermukaan akhir

Dari korelasi antara nilai )?- dan DDT + Gam&ar '.! di"eroleh DDT < %

< Di"eroleh dari ta&el '.# +Indeks "ermukaan "ada akhir umur rencana

Dari gam&ar '.2 +7omogram untuk I"t < 1:' dan I"o < #:% * # +!'

Di"eroleh @

ITP < 11:'+Inde3 te&al "erkerasan

Menentukan koefisien kekuatan relatif &erdasarkan ta&el ':%

[ < 5.#'

[ < 5.1%

[ < 5.1#

?atas minimum te&al la"is "erkerasan dengan ITP < 11:' &erdasarkan ta&el '.'

+Te&al minimum la"isan

[ ,a"isan "ondasi +?atu Pecah A < [[ cm

[ ,a"isan &a/ah +sirtu A < [[ cm

11.' < 5:#' . D1 = 5:1% . !5 = 5:1! . !'

< 1(.!2' < 1 cm

Jadi susunan la"isan "erkerasan @

,a"isan "ermukaan +As&uton < !5 cm

,a"isan "ondasi atas +&atu "ecah A < !' cm

,a"isan "ondasi &a/ah +sirtu A < 1 cm

,a"en +mekanis +a1

?atu "ecah A +a!

8irtu A +a#

a1 . D

PENENTUAN TE'AL PERKERASAN

+Metode )?-

?. -uas alan ? * ) + Metode )?-

1. Perhitungan &ata lalu lintas tahun 1@@@ (Lintas harian ratarata)

Kendaraan ringan ! ton + ! @ 1 < #%55 &uah

?us 2 ton + # @ ' < %5 &uah

Truck ! as 15 ton +%@( < %'5 &uah

Truck # as 1# ton +'@2 < !55 &uah

Truck ' as 1' ton + (@4 < 1' &uah

< %25' &uahhari! urusan

Data @

Cmur rencana 1' tahun

Program "eningkatan alan dimulai "ada tahun !55!

Perkem&angan ,alu ,intas "er tahun adalah <' 9@

Laktor -egional +L- < 1.5

?ahan*&ahan "erkerasan @

la"isan "ermukaan @ As&uton

,a"isan "ondasi atas @ ?atu "ecah A

,a"isan "ondasi &a/ah @ 8irtu A

< ,H-ii<1

Dimana @

,H-i < ,intas harian rata*rata tia" enis kendaraan

a < Perkem&angan lalu lintas "er tahun + ' 9

n < Jumlah tahun dari saat diadakan "engamatan sam"ai alan

terse&ut di&uka

< !55! * 144

< ' tahun

< + 1 = 5.5' '

< 1.!(

Kendaraan ringan ! ton + ! @ 1 < #%55 3 1.!2 < %##4.#( &uah?us 2 ton + # @ ' < %5 3 1.!2 < 4%%.%%2 &uah

Truck ! as 15 ton +%@( < %'5 3 1.!2 < '%.#! &uah

Truck # as 1# ton +'@2 < !55 3 1.!2 < !''.!'( &uah =

Truck ' as 1' ton + (@4 < 1' 3 1.!2 < 14.1%%! &uah

,H-a/al < (1#!.' &uah

<enghitung lintas harian ratarata a=al umur renana (LH#a=al

,H- a/al +1 = an

+1 = an

<enghitung lintas harian ratarata akhir umur renana (LH#akhir

,H- akhir

,H- a/al +1 = rn

Dimana @

,H-i < ,intas harian rata*rata a/al umur rencana

r < Perkem&angan lalu lintas "er tahun + 2 9

n < Cmur rencana alan terse&ut

< 1' tahun

< + 1 = 5.5' 1'

< !.54

Kendaraan ringan ! ton + ! @ 1 < %##4.% 3 !.54 < 45!1.! &uah

?us 2 ton + # @ ' < 4%%.% 3 !.54 < 14(#.% &uah

Truck ! as 15 ton +%@( < '%.# 3 !.54 < 114%.5 &uah

Truck # as 1# ton +'@2 < !''.# 3 !.54 < '#5. &uah =

Truck ' as 1' ton + (@4 < 14.1 3 !.54 < #4.2 &uah

,H-akhir < 1!54 &uah

P.n.ntuan T.a a6i4an P.*k.*a4an Rua4 Jaan ' - C

Sta4iun 1@25 '7 Sa/6ai 4ta4iun 2@"$$ C7

Konstruksi "erkerasan umumna terdiri dari tiga la"isan se"erti tergam&ar @

Dimana @I < ,a"isan "ermukaan +,AP07

II < ,a"isan "ondasi atas + &atu "ecah A

III < ,a"isan "ondasi &a/ah + sirtu ?

h& < Tinggi konstruksi sam"ai &ase

hs& < Tinggi konstruksi sam"ai su& &ase

htd < Tinggi konstruksi sam"ai tanah dasar

< Te&al la"isan "ermukaan

< Te&al la"isan "ondasi atas

< Te&al la"isan "ondasi &a/ah

+1 = rn

(0) ( , )

(4 &uah

'#' &uah

1%4 &uah

!1 &uah

-umus @

1. h& < !5Po +1 = log %.d.h.n

+ )?- ?ase

!. hs& < !5Po +1 = log %.d.h.n

+ )?- 8u& ?ase

#. htd < !5Po +1 = log %.d.h.n

+ )?- tanah dasar

Dimana @

Po < Tekanan gandar tunggal 4 ton untuk alan kelas II Po < ' ton

C < Cmur rencana < 1' tahun

d < Laktor keadaan drainase < !:'

h < )urah huan < 4

n < ,H-akhir < 1!54.# &uah

)?- &ase < min. 25 9

)?- su& &ase < min. !5 9

)?- tahah asli < di"eroleh dari grafik < #.

Maka @

1. h& < !5' +1 = log '.!:'.4.1!54:#

< 1#.#% < 1% cm25

!. hs& < !5' +1 = log '.!:'.4.1!54:#

< !(.%4# < ! cm!5

#. htd < !5' +1 = log '.!:'.4.1!54:#

< '2.4(#% < '4 cm#.

h& <hs& < = < h& =

htd < = = < hs& =

Dimana @

< < 7ilai eki$alen te&al la"isan*la"isan "erkerasan terhada"

&atu "ecah

< 5:#'5:1% < 1.2'

< 1: : .

a1 . D1

a1 . D

Maka @

<1%.55

< .2% < 2 cm1.4

<hs& * h&

<14.1(

< 14.1( < !5 cm1.55

<htd * hs&

<#4.2%

< %!.4 < %# cm

Karena D# ; !' cm: maka di&eri la"isan "asir dengan te&al < %# * !' < 12 cm

Jadi susunan la"isan "erkerasan @

,a"isan "ermukaan +,AP07 < 2 cm

,a"isan "ondasi atas +&atu "ecah A < !5 cm

,a"isan "ondasi &a/ah +sirtu ? < !' cm

,a"isan "asir < 12 cm

PERENCANAAN GE

RICO DESRIANTO

&)#) PERHITUNGAN (OLUME MATERIAL MASING - MASING RUAS JALAN

-uas alan A * ? dan ? * )

8tasiunTe&al "erkerasan +m Volume &ahan "erkerasan +m#

As&uton ?.Pecah A 8irtu A Pasir As&uton ?.Pecah A 8irtu A Pasir

8ta.55=555

(525 2 5.! 5.!' 5.1 5 4!2 1!1(5 2!(2.2 55(=525

8ta.5(=525

5!=115 2 5.52 5.! 5.!' 5.12 1#'5.% ##( %!!5 #5#2.%52=145

JUMLAH 1''#( 1!%22.2 1%21

Jarak alan +m

,e&ar alan +m

@A @BCB KPB(B@ @B@B K;BS DB;B@

1 $);B ( )(BC 70 ;AKB;

2 EB@ 60 B(

3 FB); BKGB 50 KA;K(A G

4 @)FB$B( 70 KA;K(A B

5 B;BCS$BF 80 B(

6 S)'@' ($ P. 60 KA;K(A 7 AK$ SBP)(B 60 KA;K(A B

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