profile l, ll, i, u si t
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Relaţiile pentru calculul ariilor suprafeţelor cecompun suprafeţele secţiunilor transversale ale
profilelor din oţel laminat la cald1. Profil L cu aripi egale (STAS 424 - 91)
= ⋅ (2 ⋅ − )= ⋅ (4 − )4= ⋅ (4 − )4
Aria suprafeţei secţiunii transversale a profilului
St = S1 + S2 - 2S3
r1
r1
g
ga-
ga
r
a
S3S2
S1
S3
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2. Profil L cu aripi inegale (STAS 425 - 80)
= ⋅ ( + − )= ⋅ (4 − )4= ⋅ (4 − )4
Aria suprafeţei secţiunii transversale a profilului
St = S1 + S2 - 2S3
r1
g
r1r
g
b
a
S3S2
S1
S3
a-g
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3. Profil I (STAS 565 - 86)
ht
b/4
db
r
R
Panta 14%
R
t
((b-
2d)/4
)*tg
()
t+((
b-2d
)/4)*
tg(
)
b/4
r
/2-
/2-
S1
S4 S3
S2
b
h
(b/4
)*tg
t-(b/
4)*t
g
(b-d)/2
d/2
db/2
(b-2d)/4
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Panta 14% = = arctan(0,14) = 7°58’10,597”= ⋅= ⋅ tan − 2 ⋅4 − − 2 ⋅4= [4 ⋅ − ⋅ tan( )] ⋅ ( − )8= ⋅ tan − 2 ⋅4 − − 2 ⋅4
Aria suprafeţei secţiunii transversale a profilului
St = S1 + 4(S2 + S3 - S4)
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4. Profil U (STAS 564 - 86)
db
t
h
b/2
r
R
Panta 8%
b/2
b-d
b
r
/2-
R
/2-
((b-
2d)/2
)*tg
()
t+((
b-2d
)/2)*
tg(
)
t
h
S1 S2 S3 S4
d
(b/2
)*tg
(b-2d)/2
t-(b/
2)*t
g
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Panta 8% = = arctan(0,08) = 4°34’23,117”= ⋅= ⋅ tan − 2 ⋅4 − − 2 ⋅4= [2 ⋅ − ⋅ tan( )] ⋅ ( − )2= ⋅ tan − 2 ⋅4 − − 2 ⋅4
Aria suprafeţei secţiunii transversale a profilului
St = S1 + 2(S2 + S3 - S4)
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4. Profil T (STAS 566 - 86)
a/4a
t
g
Panta 2%
Pan
ta 2
%
r1 r
r2
h
a/4aB1
B2t r
g
c1
c2
c3
c4
b2b2
h/2
h
b1
r
r1 r1
r2 r2
S3 S4 S1 S4 S3
S5
S6
S2
S5
S6
Panta 2%
Pan
ta 2
%
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Panta 2% = = arctan(0,02) = 1°8’44,746”
= −2= 2 + ⋅ tan( )4 −= ⋅ cos( ) − ⋅ sin( )cos ( ) − sin ( )= ⋅ cos( ) − ⋅ sin( )cos ( ) − sin ( )= + 2 ⋅ ⋅ sin( )= − ⋅ tan( )= 2 + ⋅ cos( )= ⋅ sin( ) + − ⋅ tan( )4= − ⋅ tan( )4= ⋅ cos( )
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= ⋅= ( + ) ⋅2= ( + ) ⋅2= ⋅ tan − 4 ⋅4 − − 4 ⋅4= ⋅ tan − 2 ⋅4 − − 2 ⋅4= ⋅ tan − 2 ⋅4 − − 2 ⋅4
Aria suprafeţei secţiunii transversale a profilului
St = S1 + S2 + 2[S3 + S4 -(S4 + S6)]
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