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7/25/2019 anls strktr

1/19

DISTRIBUSI MOMEN

FAKTOR KEKAKUAN

TITIK B

KBA =4.EI

L

=4.EI

5=0.8EI


2/19

KBC =4.2EI

L

=4.2EI5

=8EI5

=1.6EI

KB = 0.8EI + 1.6EI = 2.4EI

TITIK C

KCD=

4.EI

L

=4.EI

5=0.8EI

KCB =4.2EI

L

=4.2EI

5=8EI

5=1.6EI

KC = 0.8EI + 1.6EI = 2.4EI


3/19

FAKTOR DISTRIBUSI

TITIK B

BA = KBA

KB

=0.8EI

2.4EI=0.33

BC =KBC

KB

=1.6EI2.4EI

=0.67

KONTROL B = 0.33 + 0.67 = 1

TITIK C

CD =KCD

KC

=0.8EI

2.4EI=0.33

CB =KCB

KC


4/19

=1.6EI

2.4EI=0.67

KONTROL C = 0.33 + 0.67 = 1

MOMEN PRIMER

TITIK A

MAB =p AB

2

L2

=6.3.22

52 = -2,88 t.m

MAB =-2,88 t.m

TITIK B

MBA =+p A

2B

L2

=+6.32 .2

52 = 4,23 t.m

MBC =q . L2

12


5/19

=3.52

12= -6,25 t.m

MBA + MBC = -2,02 t.m

TITIK C

MCB =q . L

2

12

=+6.3

2

.2

52 = 4,23 t.m

TITIK D

MDE =

l

q .( 2)12

=

4

6.( 2)12

=

8 t.m

TITIK C


6/19

MCF =p .l8

=

2.48

= -1 t.m

MF = Mf + Mf!

= -5.33 + 1 = -4.33 t.m

MC = M!f

= -1 t.m

ME = M" + Mf

= -8 + 5.33 = -2.67 t.m

TABEL DISTRIBUSI MOMEN

TITIK A D B E F C

CABANG AD DA DE BE EB ED EF FE FC CF

#.$I%TRIB&%I 0.00 0.33 0.67 0.00 0.33 0.33 0.33 0.67 0.33 0.00


7/19

#.IN$&K%I 0.50 0.50 0.50 0.50 0.50 0.50 0.50 0.50 0.50 0.50

M.'RIMER 0.00 0.00 8.00 0.00 0.00 -8.00 5.33 -5.33 1.00 -1.00

M.'ERL()(N(N 0.00 -2.67 -5.33 0.00 0.8* 0.8* 0.8* 2.8* 1.44 0.00

M.IN$&K%I -1.33 0.00 0.44 0.00 1.44 0.44 0.72

M.'ERL()(N(N 0.00 0.00 0.00 0.00 0.00 0.00 0.00 -0.30 -0.15 0.00

M.IN$&K%I 0.00 0.00 0.00 0.00 -0.15 0.00 -0.07

M.'ERL()(N(N 0.00 0.00 0.00 0.00 0.00 0.00 0.00 0.00 0.00 0.00

M.(KIR -1.33 -2.67 2.67 0.44 0.8* -7.11 7.52 -2.30 2.30 -0.35

M (KIR 1.33 2.67 -2.67 -0.44 -0.8* 7.11 -7.52 2.30 -2.30 0.35

DEFLEKSI LERENG


8/19

FAKTOR KEKAKUAN

TITIK F

KFC =4

EIL

=4EI

4=1EI


9/19

KFE =4.2EI

L

=4.2EI

4=8EI

4=2EI

KF = 1EI + 2EI = 3EI

TITIK E

KEF =4.2EI

L

=4.2EI4

=8EI4

=2EI

KED =4.2EI

L

=4.2EI

4=8EI

4=2EI

KEB =4.2EI

L

=4.2EI

4=8EI

4=2EI

KE = 2EI + 2EI + 2EI = 6EI


10/19

TITIK D

KDE =4.2EI

L

=

4.2EI

4

=8EI

4

=2EI

KDA =4EI

L

=4EI

4=1EI

K

D = 2EI + 1EI = 3EI

MOMEN PRIMER

TITIK F


11/19

MFE =

l

q .(2)12

=4.(42)

12 = -5.33 t.m

MFC =p . l

8

=2.4

8 = 1 t.m

TITIK E

MED =

l

q .(2)12

=

4

6. ( 2)12

=

-8 t.m

MEF =

l

q .( 2)12


12/19

=

4

4.( 2)12

=

5.33 t.m

TITIK D

MDE =

l

q .( 2)12

=

4

6.( 2)12

=

8 t.m

TITIK C

MCF =p .l8

=2.48 = -1 t.m

MF = MFE + MFC

= -5.33 + 1 = -4.33 t.m

MC =

MCF

= -1 t.m


13/19

ME =

MED +MEF

= -8 + 5.33 = -2.67 t.m

RDA =

4

=

4.4

4=

4

4 = 1

REB =

4

=

4.4

4=

4

4 = 1

RFC =

4

=

4.4

4=

4

4 = 1

(,B,C = 0


14/19

PERSAMAAN DEFLEKSI LERENG

MAD = MAD + KAD -2 - " + R" /

= 0 + 1 EI -2 - " + 1R/ = 0 - 2EI - 1EI " + 1EI R

= -1EI " + 1EI R

MDA = MDA + KDA -2" - + R" /

= 0 + 1EI -2" - + 1R / = 0 - 2EI " - 1EI + 1EI R

= -2EI " + 1EI R

MBE = MBE + KBE -2 - + R /

= 0 + 2EI -2 - + 1R / = 0 - 4EI - 2EI + 2EI R

= -2EI + 2EI RMEB =

MEB +KEB -2 - + R /

= 0 + 2EI -2 - + 1R / = 0 - 4EI - 2EI + 2EI R

= -4EI + 2EI RMFC =

MFC +KFC -2f - ! + Rf! /

= 1 + 1EI -2f - ! + 1R / = 1 - 2EI f - 1EI ! + 1EI R

= 1 - 2EI f + 1EI RMCF =

MCF +KCF -2! - f + Rf! /

= -1 + 1EI -2! - f + 1R / = -1 - 2EI ! - 1EI f + 1EI R

= -1 - 1EI f + 1EI R


15/19

MDE =MDE +

KDE -2" - /

= 8 + 2EI -2" - / = 8 - 4EI " - 2EI MED =

MED +KED -2 - " /

= -8 + 2EI -2 - " / = -8 - 4EI - 2EI "MEF =

MEF +KEF -2 - f /

= 5.33 + 2EI -2 - f / = 5.33 - 4EI - 2EI fMFE =

MFE +KFE -2f - /

= -5.33 + 2EI -2f - / = -5.33 - 4EI f - 2EI

SYARAT SAMBUNGAN DAN SATU SYARAT GESERAN

Tt # =MFC +

MFE = 0

Tt E =MEF +

MED +MEB = 0

Tt $ =MDE +

MDA = 0

= -' +HA +

HB +HC = 0

HASIL DARI TITIK-TITIK PORTAL

MF = 1 - 2EI f + 1EI R / + 5.33 - 4EI f - 2EI /

= 6.33 + 6EI f - 2EI + 1EI R

-6.33 = 6EI f -2EI + 1EI R


16/19

ME = - 4EI + 2EI R / + -8 - 4EI - 2EI " / + 5.33 - 4EI - 2EI f /

= -3.33 - 12EI - 2 " - 2EI f + 2EI R

3.33 = - 12EI - 2EI " - 2EI f + 2EI R

MD = - 2EI " + 1EI R / + 8 - 4EI " - 2EI /

= 8 - 6EI " - 2EI + 1EI R

-8 = - 6EI " - 2EI + 1EI R

SYARAT KESETIMBANGAN

HA =MAD+MDA

4 =(1EI d+1EI R)+(2EI d+1EI R)

4

=(3EI d+2EI R)

4

HB =MBE+MEB

4 =(2EI e+2EI R )+(4EI e+2EI R)

4


17/19

=(6EI e+4EI R)

4

HC

=

MCF+MFC

4 =

(11EI f+1EI R)+(12EI f+1EI R)4

=(3EI f+2EIR)

4

E%ER(N = -' + + + !

= -2 +(3EI d+2EI R )

4 +(6EI e+4EI R )

4 +(3EI f+2EIR)

4

= -8

4 +(3EI d+2EI R)

4 +(6EI e+4EI R )

4 +(3EI f+2EIR)

4 / .4

= -8 + - 3EI " + 2EI R / + -6EI + 4EI R / + - 3EI f + 2EIR / = 0

= - 3EI f - 6EI - 3EI " + 8EIR = 8

6EI f -2EI + 1EI R = -6.33

2EI f - 12EI - 2EI " - + 2EI R = 3.33

- 2EI - 6EI " + 1EI R = -8- 3EI f - 6EI - 3EI " + 8EIR = 8

ELIMINASI


18/19

%ETEL( $I ELIMIN(%I MEN&N(K(N METO$E (&%% $I$('(TK(N (%IL

# = 0.37*7*

E = -0.227

$ = 1.67577

R = 1.60057

PERHITUNGAN MOMEN AKHIR

MAD = -1EI " + 1EI R

= -11.67577/ + 1 1.60057/

= -0.0751* EIMDA = -2EI " + 1EI R

= -21.67577/ + 11.60057/= -0.15038 EI

MBE = -2EI + 2EI R

= -2-0.227/ + 21.60057/

= 3.655172 EI

MEB = -4EI + 2EI R

= -4-0.227/ + 21.60057/

= 4.10*1*5 EI


19/19

MFC = 1 - 2EI f + 1EI R

= 1 20.37*7*/ + 11.60057/= 1.840**6 EI

MCF = -1 - 1EI f + 1EI R= -1 10.37*7*/ + 11.60057/

= 0.220785 EIMDE = 8 - 4EI " - 2EI

= 8 41.67577/ 2-0.227/

= 1.750*58 EIMED = -8 - 4EI - 2EI "

= -8 4-0.227/ 21.67577/= -10.4435 EI

MEF = 5.33 - 4EI - 2EI f

= 5.33 4-0.227/ 20.37*7*/

= 5.478467 EIMFE = -5.33 - 4EI f - 2EI

= -5.33 40.37*7*/ 2-0.227/

= -6.3*513 EI

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