apendice práctica no2 sistemas de circuitos de fluidos experimetales parte iii y iv

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Apéndice. Cálculo de factor f para cada tubería. - Tuberías de cobre tipo L, e = 1.5x10 -6 m A. Para Q1 (5,69x10 -5 m 3 /s) Tubería DN = ½”, Di = 0.013843 m (e/Di = 1.0836x10 -4 ) 0,035988 Tubería de DN = ¾”, Di = 0.019939 m (e/Di = 7.5229x10 -5 ) 0,039922 Tubería de DN = 1”, Di = 0.026035 m (e/Di = 5.7615x10 -5 ) 0,043225 B. Para Q2 (2,5x10 -5 m 3 /s) Tubería DN = ½”, Di = 0.013843 m (e/Di = 1.0836x10 -4 ) Re = 4.(5,69 x10 5 m 3 s ) π .(0,013843m).(9,0369 x10 7 m 2 s ) = 5791,2550 f 1 f = 4 log (1,0836 x10 4 ) 3, 7 + 1,256 5791,2550 f f = Re = 4.(5,69 x10 5 m 3 s ) π .(0,019939 m).(9,0369 x10 7 m 2 s ) = 4020, 6802 f 1 f = 4 log (7.5229x10 -5 ) 3, 7 + 1,256 4020, 6802 f f = Re = 4.(5,69 x10 5 m 3 s ) π .(0,026035 m).(9,0369 x10 7 m 2 s ) = 3079, 2526 f 1 f = 4 log (5.7615x10 -5 ) 3, 7 + 1,256 3079, 2526 f f = Re = 4.(2,5 x10 5 m 3 s ) π .(0,013843m).(9,0369 x10 7 m 2 s ) = 2544, 4881 f

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Apendice Práctica No2 Sistemas de Circuitos de Fluidos Experimetales Parte III y IV

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  • Apndice.

    Clculo de factor f para cada tubera.

    - Tuberas de cobre tipo L, e = 1.5x10-6 m A. Para Q1 (5,69x10-5 m3/s)

    Tubera DN = , Di = 0.013843 m (e/Di = 1.0836x10-4)

    "

    " 0,035988

    Tubera de DN = , Di = 0.019939 m (e/Di = 7.5229x10-5)

    "

    " 0,039922

    Tubera de DN = 1, Di = 0.026035 m (e/Di = 5.7615x10-5)

    "

    " 0,043225

    B. Para Q2 (2,5x10-5 m3/s)

    Tubera DN = , Di = 0.013843 m (e/Di = 1.0836x10-4)

    "

    Re = 4.(5,69x105 m3 s )

    .(0,013843m).(9,0369x107 m2 s )= 5791,2550 f

    1f = 4 log

    (1,0836x104 )3,7 +

    1,2565791,2550 f f =

    Re = 4.(5,69x105 m3 s )

    .(0,019939m).(9,0369x107 m2 s )= 4020,6802 f

    1f = 4 log

    (7.5229x10-5 )3,7 +

    1,2564020,6802 f f =

    Re = 4.(5,69x105 m3 s )

    .(0,026035m).(9,0369x107 m2 s )= 3079,2526 f

    1f = 4 log

    (5.7615x10-5 )3,7 +

    1,2563079,2526 f f =

    Re = 4.(2,5x105 m3 s )

    .(0,013843m).(9,0369x107 m2 s )= 2544,4881 f

  • " 0,0458907

    Tubera de DN = , Di = 0.019939 m (e/Di = 7.5229x10-5)

    " =64/Re=0,0362286

    Tubera de DN = 1, Di = 0.026035 m (e/Di = 5.7615x10-5)

    " =64/Re=0,047304

    Clculo de (L/D) para cada accesorio

    - Todos los accesorios se encuentran en la tubera de 1

    - (L/D) se determina a partir de la ecuacin (7)

    "

    A. Para Q1 (5,69x10-5 m3/s), f = 0,043225

    A partir de la ecuacin (2): "

    Codo estndar 90

    !

    Conexin T

    " x2=252.0494

    Vlvula de compuerta completamente abierta

    1f = 4 log

    (1.0836x10-4 )3,7 +

    1,2562544,4881 f f =

    Re = 4.(2,5x105 m3 s )

    .(0,019939m).(9,0369x107 m2 s )= 1766,5554 f

    Re = 4.(2,5x105 m3 s )

    .(0,026035m).(9,0369x107 m2 s )= 1352,9229 f

    A = .Di2

    4 = .(0,026035m)2

    4 = 5,323x104m2

    V = 5,69x105 m3 s

    5,3236x104m2 = 0,106882m / s

    LD

    =

    2.(9,8 m s2 ).(0,003175m)(0,043225).(0,106882 m s)2

    = 126,0247

    LD

    =

    2.(9,8 m s2 ).(0,003175m)(0,043225).(0,106882 m s)2

    = 126,0247

  • !

    Vlvula de compuerta 50% abierta

    !

    B. Para Q2 (2,5x10-5 m3/s), f = 0,047304

    A partir de la ecuacin (2): "

    Codo estndar 90

    "

    Conexin T

    " x2=3582,9522

    Vlvula de compuerta completamente abierta

    "

    Vlvula de compuerta 50% abierta

    "

    LD

    =

    2.(9,8 m s2 ).(0m)(0,043225).(0,106882 m s)2

    = 0

    LD

    =

    2.(9,8 m s2 ).(0,06675m)(0,043225).(0,106882 m s)2

    = 2649,49555

    V = 2,5x105 m3 s

    5,3236x104m2 = 0,046936m / s

    LD

    =

    2.(9,8 m s2 ).(0,03175m)(0,047304).(0,046936 m s)2

    = 5971,5872

    LD

    =

    2.(9,8 m s2 ).(0,009525m)(0,047304).(0,46936 m s)2

    = 1791,4761

    LD

    =

    2.(9,8 m s2 ).(0,0445m)(0,047304).(0,46936 m s)2

    = 8369,6262

    LD

    =

    2.(9,8 m s2 ).(0,08255m)(0,047304).(0,46936 m s)2

    = 15526,1269