append
DESCRIPTION
ytgfdTRANSCRIPT
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Lampiran 1. Surat keterangan sampel
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Lampiran 2. Hasil identifikasi tumbuhan
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Lampiran 3. Gambar Tumbuhan Temu Giring
Tumbuhan Temu Giring
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Lampiran 3. (lanjutan)
Rimpang Temu Giring
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Lampiran 3. (lanjutan). Gambar makroskopik simplisia dan serbuk simplisia rimpang temu giring
Simplisia Rimpang Temu Giring
Serbuk Simplisia Rimpang Temu Giring
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Lampiran 4. Gambar mikroskopik serbuk simplisia rimpang temu giring pada perbesaran 10 x 40
Mikroskopik serbuk simplisia rimpang temu giring pada perbesaran 10 x 40
Keterangan : 1 = fragmen jaringan gabus
2 = butir pati (diperbesar)
3 = rambut penutup
4 = fragmen pembuluh kayu
5 = butir minyak atsiri
6 = fragmen parenkim
1
2
3
4
5
6
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Lampiran 5. Bagan penelitian direndam dengan etanol 96% dibiarkan selama 5 hari sambil sering diaduk diserkai, diperas, dicuci ampas dengan etanol 96% secukupnya dipindahkan ke dalam bejana tertutup dibiarkan di tempat sejuk, terlindung dari cahaya selama 2 hari disaring diuapkan dengan rotary evaporator dikeringkan dengan freeze dryer
Serbuk Simplisia
Maserat
Ekstrak Kental
Skrining Fitokimia Uji Aktivitas Karakteristik
Alkaloid Saponin Tanin Steroid/Triterpenoid Flavonoid Glikosida
Pk Air Pk Abu Total Pk Abu Tidak Larut Asam
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Lampiran 6. Gambar alat spektrofotometer UV-Visibel (UVmini-1240 Shimadzu)
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Lampiran 7. Perhitungan hasil karakterisasi serbuk simplisia rimpang temu Giring I. Perhitungan Penetapan Kadar Air
% Kadar Air = Volume air
Berat Sampel x 100%
1. % Kadar Air I = 0,45,094
x100% = 7,85%
2. % Kadar Air II = 0,55,075
x100% = 9,85%
3. % Kadar Air III = 0,55,148
x100% = 9,71%
% Kadar Air Rata-Rata = 7,85+ 9,85 + 9,71
3= 9,14%
II. Perhitungan Penetapan Kadar Sari Larut Air
No BeratSampel (g) Berat Sari (g)
1.
2.
3.
5,005
5,006
5,007
0,17
0,172
0,174
% Kadar Sari Larut Etanol = Berat Sari
Berat Sampel x 10020
x100%
1. % Kadar Sari I = 0,175,005
x 10020
x100% = 16,95%
No BeratSampel (g) Volume Air (ml)
1.
2.
3.
5,094
5,075
5,148
0,4
0,5
0,5
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Lampiran 7. (lanjutan)
2. % Kadar Sari II = 0,1725,006
x 10020
x100% = 17,18%
3. % Kadar Sari III = 0,1745,007
x 10020
x100% = 17,38%
% Kadar Sari Larut Etanol Rata-Rata = 16,95%+ 17,18% + 11,38%
3
= 17,18%
III. Perhitungan Penetapan Kadar Sari Larut Etanol
No BeratSampel (g) Berat Sari (g)
1.
2.
3.
5,001
5,004
5,007
0,246
0,249
0,250
% Kadar Sari Larut Air = Berat Sari
Berat Sampel x 10020
x100%
1. % Kadar Sari I = 0,2465,001
x 10020
x100% = 24,79%
2. % Kadar Sari II = 0,2495,004
x 10020
x100% = 24,88%
3. % Kadar Sari III = 0,2505,007
x 10020
x100% = 24,96%
% Kadar Sari Larut Air Rata-Rata = 24,79%+ 24,88% + 24,96%
3
= 24,87%
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Lampiran 7. (lanjutan)
IV. Perhitungan Penetapan Kadar Abu Total
No BeratSampel (g) Berat Abu (g)
1.
2.
3.
2,0116
2,0069
2,0104
0,0920
0,0910
0,0909
% Kadar Abu Total = Berat Abu
Berat Sampel x100%
1. % Kadar Abu Total I = 0,09022,0116
x100% = 4,57%
2. % Kadar Abu Total II = 0,09102,0069
x100% = 4,53%
3. % Kadar Abu Total I = 0,09092,0104
x100% = 4,52%
% Kadar Abu Total Rata-Rata = 4,57%+ 4,53% +4,52%
3= 4,54%
V. Perhitungan Penetapan Kadar Abu tidak Larut Asam
No BeratSampel (g) Berat Abu (g)
1.
2.
3.
2,0116
2,0069
2,0104
0,0335
0,0352
0,0316
% Kadar Abu tidak Larut Asam = Berat Abu
Berat Sampel x100%
1. % Kadar Abu Total I = 0,03352,0116
x100% = 1,67%
2. % Kadar Abu Total II = 0,03522,0069
x100% = 1,75%
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Lampiran 7. (lanjutan)
3. % Kadar Abu Total I = 0,03162,0104
x100% = 1,57%
% Kadar Abu tidak Larut Asam Rata-Rata
= 1,67%+ 1,75% + 1,57%
3= 1,4%
Hasil Karakterisasi Serbuk Simplisia Rimpang Temu Giring
(Depkes., RI. 1995)
No Karakteristik serbuk simplisia Simplisia
Kadar (%) Persy. MMI 1 Kadar air 9,14 < 10 2 Kadar sari larut dalam air 17,18 > 16 3 Kadar sari larut dalam etanol 24,87 > 6 4 Kadar abu total 4,54 < 9 5 Kadar abu tidak larut dalam asam 1,4 < 1,5
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Lampiran 8. Perhitungan karakterisasi ekstrak etanol rimpang temu giring
I. Perhitungan Penetapan Kadar Air
No BeratSampel (g) Volume Air (ml)
1.
2.
3.
5,007
5,018
5,012
0,2
0,2
0,2
% Kadar Air = Volume air
Berat Sampel x 100%
1. % Kadar Air I = 0,25,007
x100% = 3,94%
2. % Kadar Air II = 0,25,018
x100% = 3,99%
3. % Kadar Air III = 0,25,012
x100% = 3,99%
% Kadar Air Rata-Rata = 3,94+ 3,99 + 3,99
3= 3,97%
II. Perhitungan Penetapan Kadar Abu Total
No BeratSampel (g) Berat Abu (g)
1.
2.
3.
2,0003
2,0004
2,0004
0,0080
0,0081
0,0088
% Kadar Abu Total = Berat Abu
Berat Sampel x100%
1. % Kadar Abu Total I = 0,00802,0003
x100% = 0,40%
2. % Kadar Abu Total II = 0,00812,0004
x100% = 0,41%
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Lampiran 8. (lanjutan)
3. % Kadar Abu Total I = 0,00882,0004
x100% = 0,44%
% Kadar Abu Total Rata-Rata = 0,40%+0,41% +0,44%
3= 0,42%
III. Perhitungan Penetapan Kadar Abu tidak Larut Asam
No Berat Sampel (g) Berat Abu (g)
1. 2. 3.
2,0003
2,0004
2,0004
0,0020
0,0022
0,0020
% Kadar Abu tidak Larut Asam = Berat Abu
Berat Sampel x100%
1. % Kadar Abu Total I = 0,00202,0003
x100% = 0,10%
2. % Kadar Abu Total II = 0,00222,0004
x100% = 0,11%
3. % Kadar Abu Total I = 0,00202,0004
x100% = 0,10%
% Kadar Abu tidak Larut Asam Rata-Rata
= 0,10%+0,11% + 0,10%
3 = 0,10%
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Lampiran 9. Perhitungan nilai aktivitas antioksidan metode DPPH ekstrak etanol rimpang temu giring
% Peredaman DPPH Pengukuran I
Tabel data absorbansi DPPH pengukuran I
No, Konsentrasi Larutan Uji (ppm) Absorbansi
1, 0 1,047
2, 20 0,917
3, 40 0,772
4, 60 0,653
5, 80 0,563
% Peredaman = 100% x kontrolA
sampelA - kontrolA
Keterangan : Akontrol = Absorbansi tidak mengandung sampel
Asampel = Absorbansi sampel
Perhitungan % peredaman ekstrak etanol rimpang temu giring
- Konsentrasi 20 ppm
% Peredaman = 100% x kontrolA
sampelA - kontrolA
% Peredaman = 100% x 047,1
917,0047,1 −
= 12,47%
- Konsentrasi 40 ppm
% Peredaman = 100% x kontrolA
sampelA - kontrolA
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Lampiran 9. (lanjutan)
% Peredaman = 100% x 047,1
772,0047,1 −
= 26,32%
- Konsentrasi 60 ppm
% Peredaman = 100% x kontrolA
sampelA - kontrolA
% Peredaman = 100% x 047,1
653,0047,1 −
= 37,64%
- Konsentrasi 80 ppm
% Peredaman = 100% x kontrolA
sampelA - kontrolA
% Peredaman = 100% x 047,1
563,0047,1 −
= 46,24%
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Lampiran 10. Perhitungan nilai IC50 metode DPPH
Ekstrak Etanol Rimpang Temu Giring
Tabel IC50 ekstrak etanol rimpang temu giring
X Y XY X2
0 0 0 0
20 12,47 249,4 400
40 26,32 1052,8 1600
60 37,64 2258,4 3600
80 46,24 3699,2 6400
ΣX= 200
x = 40
ΣY= 122,67
y = 24,534 ΣXY= 7259,8 ΣX2= 12000
X = Konsentrasi (ppm)
Y = % Peredaman
a = n /X)()X(
n / Y)X)(( -XY)(22 ∑−∑
∑∑∑
= 0,58825 40002353
5 / )200()12000(5/)122,67)(200()7259,8(
2 ==−
−
b = y - xa
= 24,53 – (0,5882)(40) = 1,004
Jadi, persamaan garis regresi Y = 0,5882X + 1,004
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Lampiran 10. (lanjutan)
Nilai IC50 = Y = 0,5882X + 1,004
50 = 0,5882X + 1,004
X = 83,29
IC50 = 83,29 ppm