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Llogatitja e armatures se Shkalleve

Shkallet e katit Tip

  Seksion llogarites

h=  (

  1

30;  1

35)

lk=

1

30;  1

35

¿)*375=(10.72 ; 12.5) cm

Rekomandohet qe lartesise se solete se shkalle ti shtohet 2 cm (per shkak e ngarkesaete medha)

!rano" h=1# cm

• Ngarkesat llogaritesea) Rampa

$ !llaka 0.015 * (0.17%0.2&) * 1 * 2700 *1

0.328  = 55.' dam

$ lac 0.02 * (0.17%0.2&) * 1 * 2000 *1

0.328  = 5#.+ dam

$ ,-sh"a 0.0& * (0.17%0.2&) * 1 * 2#00 *1

0.328 = 17#.2 dam

$ /oleta 0.1# * 1 * 1 * 2500 = 350 dam$ /a 0.02 * 1 * 1 * 2000 = #0 dam

• garkesa e perhereshme e normar gn = 55.' % 5#.+ % 17#.2 % 350 % #0 = '7#.7

dam

•

garkesa e perkohshme p

n

=#00 dam g"atesi horiontale!=pn * cos = #00 * 0.&55 = 3#2 dam

  Ngarkesa totale  q = 1.35*g % 1.5*p = 1.35*'7#.7% 1.5*3#2 = 1#23dam

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-) /heshpshimi

$ !llaka 0.015 * 1 * 1 * 2700 = #0.5 dam$ lac 0.02 * 1 * 1 * 2000 = #0 dam$ /oleta 0.1# * 1 * 1 * 2500 = 350 dam$ /a 0.02 * 1 * 1 * 2000 = #0 dam

• garkesa e perhereshme e normar gn = #0.5 % #0 % 350 % #0 = #70.5 dam2

• garkesa e perkohshme pn=#00 dam

Ngarkesa totale  q = 1.35*g % 1.5*p = 1.35*#70.5% 1.5*#00 = 1235dam

  Skema llogaritese

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Armimi

$ Ne rampe,omenti ,=2'3500 daxcm ( marre nga program /44!)

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 = M 

b d ² f cd =263500

100∗12 ²∗167 =0.10+560.1'7

=80.5%

2

√0.25−k 

1.134 9*d=80.5%

2

√0.25−0.1095

1.134 9*12=10.7 cm

4s= M 

0.87∗f y∗ z =263500

0.87∗5000∗10.7 =5.''1 cm2 prano" & :10

- Ne sheshpushim  ,omenti ,= 1#1+00 daxcm ( marre nga program /4!)

 = M 

b d ² f cd =

141900

100∗12²∗167 =0.05+ 60.1'7

=80.5%

2

√0.25−  k 

1.134 9*d=80.5%

2

√0.25−0.059

1.134 9*13=11.33+ cm

4s=

 M 

0.87∗f y∗ z =171000

0.87∗5000∗11.339 =2.&7 cm2 !rano" 5 :10

Shkallet e podrumit

  Seksion llogarites

h=  (

  1

30;  1

35)

lk=

1

30;  1

35

¿)*375=(10.72 ; 12.5) cm

Rekomandohet qe lartesise se solete se shkalle ti shtohet 2 cm (per shkak e ngarkesaete medha)!rano" h=1# cm

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  Skema llogaritese

 

Armimi$ Ne rampe

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,omenti ,=37'200 daxcm ( marre nga program /4!)

 = M 

b d ² f cd =376200

100∗12 ²∗167 =0.15'#60.1'7

=80.5%

2

√0.25−  k 

1.134 9*d=80.5%

2

√0.25−0.1564

1.134 9*12=10.02 cm

4s=  M 0.87∗f y∗ z =

3762000.87∗5000∗10.02 =&.'31 cm2 prano" & :12

Reaksionet ne m-eshtet"e te marra nga skemat e shkallee ia transmeto"me traree

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