bai tap chuong+4 5 hvnh

8/7/2019 Bai Tap Chuong+4 5 hvnh

1/22

BI TP CHNG 4-5


2/22

Bai 8

YdYdMPCCC .75,0145. !!355!! II

550!!GG

YYtTT .2,010. !!

298!! XEEX

YYIM .4,0. !!


3/22

a, Vit hm s tng cu, mc sn lng cn bng?Biu din trn th?

Hm tng cu:

? AYMPMMPCtMPCICAD .).1(. !

? AYAD .4,075,0.2,0110.75,02985503551450

!

625,16750 ! Y

Trng thi cn bng ca nn kinh t: AD0 = Y

AD0 = 1340,5 + 0,2.Y

YY ! .2,05,1340


4/22

b, Xu hng nhp khu cn bin gim cn 0,25, sn

lng cn bng, cn cn ngn sch, cn cnthng mi thay i ntn?

Hm tng cu mi:

? AYMPMMPCtTMPCXEGICAD .).1(.11

!

308,20621! Y

Trng thi cn bng mi ca nn kinh t: AD1 = Y

AD1 = 1340,5 + 0,35.Y

1340,5 + 0,35.Y = Y

S thay i sn lng: Y = 2062,308 1675,625 = 386,683

? AYAD .25,075,0.2,0110.75,02985503551451

!


5/22

AD

0

450

Y2062,3

E1

E01340,5

AD0 = 1340,5 + 0,2.Y

1675,6

AD1 = 1340,5 + 0,35.Y


6/22

Cn cn ngn sch ban u: B0 = T0 G0

S thay i cn cn ngn sch: B = B1 B0

= - 87,538 (- 204,875) = 117,336

Cn cn ngn sch BT thm ht 117,336

B0 = 10 + 0,2. 1675,625 550 = - 204,875

Cn cn ngn sch

Cn cn ngn sch sau khi c s thay i: B1 = T1 G1

B1 = 10 + 0,2. 2062,308 550 = - 127,538


7/22

Cn cn thng mi ban u: NX0 = EX0 IM0

S thay i cn cn thng mi: NX = NX1 NX0 =

Cn cn thng mi bt thm ht:

NX0 = 298 0,4. 1675,625 =

Cn cn thng mi

Cn cn thng mi sau khi c s thay i: NX1 = EX1 IM1

NX1 = 298 - 0,25. 2062,308 =


8/22

0

450

2262,3

E1

E01340,5

1685

AD1 = 1340,5 + 0,35.Y

c, Nu Y* = 1685, MPM thay i tc ng ntn n

nn kinh t? a Y = Y*,C

P cn a ra chnhsch ng ph ntn?

AD

0Y

AD2


9/22

Bai 9

YdYdMPCCC .8,055. !!115!! II

260!!GG

YYtTT .25,0. !!

125!! XEEXYYMPMIM .2,0. !!


10/22

a, Vit hm s tit kim, hm tng cu. Biu dintrn th?

Hm tng cu:

? AYMPMMPCtMPCICAD .).1(. ! ? AYAD .2,08,0.25,01125260115550 !

9250 ! YTrng thi cn bng ca nn kinh t: AD0 = Y

AD0 = 555 + 0,4.Y

Hm tiu dng: )( TYMPCCC ! YC 6,055!

Hm tit kim: )( TYMPSCS ! YS 15,055!


11/22

450

925

E0

555

366,67

AD0 = 555 + 0,4.Y

AD

Y

C = 55 + 0,6.Y

55

- 55

S = - 55 + 0,15.Y


12/22

AD

0

450

555

AD0 = 555 + 0,4.Y

925

E0

Y

b, Khi sn lng thc t l 1000, nn kinh t d

cung hay cu? Mt lng l bao nhiu? a snlng v mc 1000, CP cn thc hin CSTK ntn?

1000

955


13/22

Bai 11

C = 297 + 0,7 Yd

EX = 240 I = 100 8,4 i MPM = 0,4 T = 0,2 Y + 10 G = 350 MD = 0,2 Y 8 i MS = 200 P =2


14/22

a, Xy dng ng IS

, LM. Xc nh li sut v snlng cn bng. Minh ha trn th

Y

nd

MPMMPCt

nd

TMPCICiIS .

)1(1._)(

0

!

)..(1

_)(0

P

MSYk

hiLM !

(IS0): Y = 1166,7 10 i

(LM0): Y = 500 + 40 i

im cn bng E0 (i0, Y0)

!

!

Yi

Yi

025,05,12

1,067,116

!

!

33,1033

33,13

0

0

Y

i

(IS0): i = 116,67 0,1 Y

(LM0): i = 12,5 + 0,025Y


15/22

b, NHTWmua 5 t ng tri phiu trn OMO, s = 0,2;

rb = 0,1, rex= 0. Quyt nh ny nh hng ntn nnn kinh t?

!

!

exbrrs

smm

1

!

!

Yi

Yi

025,075,13

1,067,116

ng LM dch phi n LM1

(LM1): Y = 550 + 40 i

im cn bng mi E1 (i1, Y1)

!

!

33,1043

33,12

1

1

Y

i

MBmmMS (!( .

)..(1

_)( 11

P

MSYk

hiM !

MS = 4 . 5 = 20 t

MS1 = MS0 + MS =

(LM1): i = 13,75 + 0,025Y


16/22

LM1

E112,33

1043,33

i

Y0

LM0

IS0

1033,33

13,33

E0

Y = 10 t

i = - 1 %


17/22

Bai 13

C = 150 + 0,7 Yd

EX = 290 I = 80 12 i MPM = 0,14 T = 0,2 Y + 20 G = 150 MD = 0,2 Y 10 i MS = 200 P = 1


18/22

a, Vit phng trnh ng IS

, LM.T

nh li sut vsn lng cn bng, biu din trn th

(IS0): Y = 1131,034 20,69 i

(LM0): Y = 1000 + 50 i

im cn bng E0 (i0, Y0)

!

!

683,1092

854,1

0

0

Y

i

ng IS: tha mn iu kin cn bng th trng hng ha

AD= Y

ng LM: tha mn iu kin cn bng th trng tin t

MD= MS/P


19/22

i

Y0

LM0IS0

1092,68

E01,854


20/22

b, Nu chnh ph tng chi tiu thm 60 th snlng cn bng v li sut thay i ntn?

ng IS dch phi n IS1

(IS1): Y = 1234,48 20,69 i

im cn bng mi E1 (i1, Y1)

!

!

854,1165

317,3

1

1

Y

i


21/22

i

Y0

LM0IS0

E0

IS1

E1

Y =

i =


22/22

b, VicCP tng chi tiu gy tc ng g? Nu ko c tc ng

ny mc sn lng cao nht c th t c l bao nhiu? t c mc sn lng cao nht trn CP cn lm g?

Thoi lui u t

Quy m ca thoi lui u t

Y2 - Y1 =

Chnh ph c th a nnkinh t v im cn bngmi E2 bng CSTT m rng

i

Y0

LM0IS0

1092

1,854

E0

IS1

E1

3,317

1165

E2

Ymax = 1196

1196

LM1

MS = 20,69

bai tap chuong+4 5 hvnh

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