c5 pauta.pdf

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  • 7/25/2019 C5 Pauta.pdf

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    2133 1

    2012

    C : 100 / 50 C

    . :

    1: 2(. 1) + 3 2(. 2)2 3 (. 3)

    1 2 10%.

    ,

    .

    ,

    3, 0.5% 2

    0.5% 2 . 50

    C, . A, 2

    328,35 /.

    425 C

    1. A ,

    .

    )

    . A,

    .

    = 50

    = 100

    123

    IC

    Condensador

    = 50

    = 50

    = 328.35

    = 425

    = 328.35

    1.5 pts

    1.5 pts 1.5 pts

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    2133 1

    2012

    : 1.5 pts

    1. : N11

    N21=1

    3

    2. 1: N= 0.9 N

    3. N= 0.005 N

    4. :N= 0.005 N

    : 1, C ( )

    2 C C 1 C

    BC B BC B BC B BC B BC B BC B BC B

    11 8 8 6 14 10 11 8 7 5 7 5 30 21

    0 0 1 1 0 0 1 0 1 1 2 1 3 2

    4 3 4 3 6 5 4 3 4 3 4 3 23 17

    2 1 0 0 3 1 3 1 2 1 3 1 6 2

    1 1 0 0 0 0 2 2 1 1 1 1 4 4

    4 3 5 4 5 4 3 2 1 1 1 1 0 0

    2, C : 2 C C 1 C

    BC B BC B BC B BC B BC B BC B BC B

    11 8 8 6 9 5 11 8 7 5 7 5 30 21

    0 0 1 1 0 0 1 0 1 1 2 1 3 2

    4 3 4 3 1 0 4 3 4 3 4 3 23 17

    2 1 0 0 3 1 3 1 2 1 3 1 6 2

    1 1 0 0 0 0 2 2 1 1 1 1 4 4

    4 3 5 4 5 4 3 2 1 1 1 1 0 0

    ,

    . 1.

    .

    = 100 /

    = +

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    2133 1

    2012

    1: 2(. 1) + 3 2(. 2)2 3 (. 3)

    1:

    =

    3 = + 3 = 100 = 25

    = 75

    B :

    1 = =

    2 3 = = 75 3 =

    3 =

    A B

    2 C C 1 C

    BC B BC B BC B BC B BC B BC B BC B

    4 3 5 4 5 4 3 2 1 1 1 1 0 0

    0 0a 0 0 0 0 (31) (31) 0 0

    4 3 5 4 5 4 1 1 1 1 0 0

    : .

    : 3 1 () .

    : (1 ).

    A, B :

    Condensador

    = 50

    = 50

    = 328.35

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    2133 1

    2012

    :

    1

    0.005 = =

    2

    0.005 = =

    = + = 600 2 5 3 25

    = = .

    = .

    = + = 2002 5 25

    = = .

    = =

    = .

    = =

    = .

    = = ,

    =

    A 2 C C 1 C

    BC B BC B BC B BC B BC B BC B BC B

    4 3 5 4 5 4 1 1 1 1 0 0

    0 0 3 3 4 4 0 0 1 1 1 1

    4 3 2 1 1 0 1 0 0 0

    : C B ,

    2.

    : .

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    2133 1

    2012

    A 1:

    :

    1

    = 0.9 = 0.9 109.45 = .

    B 1:

    A 2 C C 1 C

    BC B BC B BC B BC B BC B BC B BC B 4 3 2 1 1 0 1 0 0 0 0 0

    3 3 1(2) 1

    1 0

    = 109.45

    = 328.35

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    2133 1

    2012

    A 2:

    B 2:

    = = 110 + 13,505 = .

    3 = = 3 13,505 + 330 = .

    + 2 = = 48.9 2 13.505 = .

    A

    2 C C 1 C

    BC B BC B BC B BC B BC B BC B BC B

    1 0

    , B, BC ()

    .