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Chemical Thermodynamics : Georg Duesberg Chemical Thermodynamics : Georg Duesberg
Chapter 1 : Slide 1
Chapter 3
Real gases
Chapter11111 1 : Slide 1
Chemical Thermodynamics : Georg Duesberg
Real Gases • Perfect gas: only contribution to energy is KE of molecules • Real gases: Molecules interact if they are close enough, have a
potential energy contribution. • At large separations, attractions predominate (condensation!) • At contact molecules repel each other (condensed states have volume!)
Ideal (Isotherms) Real (CO2)
F
A
p Thermo meter
Pressure gauge 2
Chemical Thermodynamics : Georg Duesberg Chemical Thermodynamics : Georg Duesberg
Chapter33333 1 : Slide 3
Pressure region
I (very Low) Molecules have large separations -> no interactions -> Ideal Gas Behavior: Z =1
II (moderate) Molecules are close -> attractive forces apply -> The gas occupies less volumes as expected from Boyles law: Z<1
III (high) Molecules compressed highly -> repulsive forces dominate -> hardly further decrease in volume Z>1
Deviations from ideality can be described by the COMPRESSION FACTOR, Z (sometimes called the compressibility). Z = pV/(nRT) = pVm/(RT) For ideal gases Z = 1
Chemical Thermodynamics : Georg Duesberg Chemical Thermodynamics : Georg Duesberg
Chapter 1 : Slide 4
Microscopic interpretation: Leonard Jones Potential
When p is very high, r is small so short-range repulsions are important. The gas is more difficult to compress than an ideal gas, so Z > 1. When p is very low, r is large and intermolecular forces are negligible, so the gas acts close to ideally and Z ∼ 1. At intermediate pressures attractive forces are important and often Z < 1.
Chemical Thermodynamics : Georg Duesberg
Real Gases: What happens if we press down the piston
A – B perfect gas behavior (isotherm) B – C slight deviation from perfect
behavior – less pressure than expected C – D – E no change in pressure reading
over further compression – but increasing amount of liquid observed
E – F : steep in crease in P, only liquid visible (At contact molecules repel each other condensed states have volume!)
5
( at 20 °C, gas: carbon dioxide)
The line C – D – E is the vapour pressure of a liquid at this tempeature
Chemical Thermodynamics : Georg Duesberg
• Attractive forces vary with nature of gas • At High Pressures repelling forces dominate
Deviations from ideality can be described by the COMPRESSION FACTOR, Z (sometimes called the compressibility). Z = pV/(nRT) = pVm/(RT) For ideal gases Z = 1
Z =
Chemical Thermodynamics : Georg Duesberg
• At Low Temperatures the attractive regime is pronounced • higher Temperature ->faster motion -> less interaction
Deviations from ideality can be described by the COMPRESSION FACTOR, Z (sometimes called the compressibility). Z = pV/(nRT) = pVm/(RT) For ideal gases Z = 1
Z =
7
Chemical Thermodynamics : Georg Duesberg Chemical Thermodynamics : Georg Duesberg
Chapter 1 : Slide 8
Boyle Temperatur The temperature at which this occurs is the Boyle temperature, TB, and then the gas behaves ideally over a wider range of p than at other temperatures. Each gas has a characteristic TB, e.g. 23 K for He, 347 K for air, 715 K for CO2.
The compression factor approaches 1 at low pressures, but does so with different slopes. For a perfect gas, the slope is zero, but real gases may have either positive or negative slopes, and the slope may vary with temperature. At the Boyle temperature, the slope is zero and the gas behaves perfectly over a wider range of conditions than at other temperatures.
Virial Equation of State
B = 0 at Boyle temperature
Most fundamental and theoretically sound Polynomial expansion Viris (lat.): force (Kammerling Onnes 1901)
Also allow derivation of exact correspondence between virial coefficients and intermolecular interactions
Virial coefficients: p Vm = RT (1 + B’p + C’p2 + ...)
i.e. p Vm = RT (1 + B/Vm + C/Vm2 + ...)
This is the virial equation of state and B and C are the second and third virial coefficients. The first is 1. B and C are themselves functions of temperature, B(T) and C(T). Usually B/Vm >> C/Vm
2
Chemical Thermodynamics : Georg Duesberg Chemical Thermodynamics : Georg Duesberg
Chapter1010101010 1 : Slide 10
Johannes Diderik van der Waals got the Noble price in physics in 1910
( )22
or ⎟⎟⎠
⎞⎜⎜⎝
⎛−
−==−⎟
⎟⎠
⎞⎜⎜⎝
⎛⎟⎠
⎞⎜⎝
⎛+mm Va
bVRTPnRTnbV
VnaP
Real gas – Van der Waals equation.
( )( ) nRTyVxP =−+
nRTgasideal =PV :
Chemical Thermodynamics : Georg Duesberg Chemical Thermodynamics : Georg Duesberg
Chapter 1 : Slide 11
1. The molecules occupy a significant fraction of the volume. -> Collisions are more frequent. -> There is less volume available for molecular motion.
Real gas molecules are not point masses (Vid = Vobs - const.) or Vid = Vobs - nb
– b is a constant for different gases
Real gas – Van der Waals equation: b
Other explanation: What happens if we reduce T to zero. Is volume of the gas, V, going to become zero? We can set P ≠ 0. By the ideal gas law we would have V = 0, which cannot be true. We can correct for it by a term equal to the total volume of the gas molecules, when totally compressed (condensed) nb. Now at T = 0 and P ≠ 0 we have V = nb. nRTnbVP =− )(
Very roughly, b ∼ 4/3 πr3 where r is the molecular radius.
Chemical Thermodynamics : Georg Duesberg
Real gas – Van der Waals equation: a
aVn2
2 a describes attractive force between pairs of molecules. Goes as square of the concentration (n/V)2 .
2) There are attractive forces between real molecules, which reduce the pressure: p ∝ wall collision frequency and
p ∝ change in momentum at each collision. Both factors are proportional to concentration, n/V, and p is reduced by an amount a(n/V)2, where a depends on the type of gas. [Note: a/V2 is called the internal pressure of the gas]. Real gas molecules do attract one another (Pid = Pobs + constant) Pid = Pobs + a (n / V)2 a is also different for different gases
Chemical Thermodynamics : Georg Duesberg
13
Van der Waals equation of state
• Parameters depend on the gas, but are taken to be independent of T. • a is large when attractions are large, b scales in proportion to molecular size
(note units)
Substance a/(atm dm6 mol−2) b/(10−2 dm3 mol−1)
Air 1.4 0.039
Ammonia, NH3 4.169 3.71
Argon, Ar 1.338 3.20
Carbon dioxide, CO2 3.610 4.29
Ethane, C2H6 5.507 6.51
Ethene, C2H4 4.552 5.82
Helium, He 0.0341 2.38
Hydrogen, H2 0.2420 2.65
Nitrogen, N2 1.352 3.87
Oxygen, O2 1.364 3.19
Xenon, Xe 4.137 5.16
( )22
or ⎟⎟⎠
⎞⎜⎜⎝
⎛−
−==−⎟
⎟⎠
⎞⎜⎜⎝
⎛⎟⎠
⎞⎜⎝
⎛+mm Va
bVRTPnRTnbV
VnaP
If 1 mole of nitrogen is confined to 2l and is at P=10atm what is Tideal and TVdW? Tip: R =0.082dm3atmK-1mol-1
Chemical Thermodynamics : Georg Duesberg Chemical Thermodynamics : Georg Duesberg
Chapter 1 : Slide 14
CONDENSATION or LIQUEFACTION This demonstrates that there are attractive forces between gas molecules, if they are pushed close enough together. E.G. CO2 liquefies under pressure at room temperature. Above 31 0C no amount of pressure will liquefy CO2: this is the CRITICAL TEMPERATURE, Tc.
Chemical Thermodynamics : Georg Duesberg Chemical Thermodynamics : Georg Duesberg Chapter 1 :
Slide 15
Carbon dioxide: a typical pV diagram for a real gas:
Tc, pc and Vm,c are the critical constants for the gas. The isotherm at Tc has a horizontal inflection at the critical point dp/dV = 0 and d2p/dV2 = 0.
Experimental isotherms of carbon dioxide at several temperatures. The `critical isotherm', the isotherm at the critical temperature, is at 31.04 °C. The critical point is marked with a star.
Chemical Thermodynamics : Georg Duesberg
16
Critical Point
dp/dV = 0 and d2p/dV2 = 0. Consider 1 mol of gas, with molar volume V, at the critical point (Tc, pc, Vc) 0 = dp/dV = -RTc(Vc-b)-2 + 2aVc
-3 0 = d2p/dV2 = 2RTc(Vc-b)-3 - 6aVc
-4 The solution is Vc = 3b, pc = a/(27b2), Tc = 8a/(27Rb).
At the critical temperature the densities of the liquid and gas become equal - the boundary disappears. The material will fill the container so it is like a gas, but may be much denser than a typical gas, and is called a 'supercritical fluid'. The isotherm at Tc has a horizontal inflection at the critical point
Chemical Thermodynamics : Georg Duesberg Chemical Thermodynamics : Georg Duesberg
Chapter1717171717 1 : Slide 17
Critical Point drying
Applications: TEM sample prep, porous materials, MEMS
Chemical Thermodynamics : Georg Duesberg Chemical Thermodynamics : Georg Duesberg
CNT
Chemical Thermodynamics : Georg Duesberg Chemical Thermodynamics : Georg Duesberg
Metal contacts on CNT
Chemical Thermodynamics : Georg Duesberg Chemical Thermodynamics : Georg Duesberg
Etch
Chemical Thermodynamics : Georg Duesberg Chemical Thermodynamics : Georg Duesberg
Etch
Freely suspended CNT
Chemical Thermodynamics : Georg Duesberg Chemical Thermodynamics : Georg Duesberg
Freely suspended CNT
Etch
TEM electron beam
Chemical Thermodynamics : Georg Duesberg Chemical Thermodynamics : Georg Duesberg
Protective resist
Etch
Chemical Thermodynamics : Georg Duesberg Chemical Thermodynamics : Georg Duesberg
Protective resist
Etch
Chemical Thermodynamics : Georg Duesberg Chemical Thermodynamics : Georg Duesberg
Chemical Thermodynamics : Georg Duesberg Chemical Thermodynamics : Georg Duesberg
Chemical Thermodynamics : Georg Duesberg Chemical Thermodynamics : Georg Duesberg
Chemical Thermodynamics : Georg Duesberg Chemical Thermodynamics : Georg Duesberg
Chemical Thermodynamics : Georg Duesberg Chemical Thermodynamics : Georg Duesberg
Suspended on contacted individual CNTs – Platform for combined investigations
Structure and Electronic Properties can be related:
Individual tubes or bundels?
What kinds of CNT
(MWCNT, SWCNT, (n,m), peapods..)
Chemical Thermodynamics : Georg Duesberg
Combined TEM and Raman investigations on individual SWCNTs
Chemical Thermodynamics : Georg Duesberg
31
Maxwell Construction Below Tc calculated vdW isotherms have oscillations that are unphysical. In the Maxwell construction these are replaced with horizontal lines, with equal areas above and below, to generate the isotherms. (The line is the vapour pressure of a liquid at this temperature, or liquid-vapor equilibrium)
Chemical Thermodynamics : Georg Duesberg
32
Features of vdW equation • Reduces to perfect gas equation at high T
and V • Liquids and gases coexist when
attractions ≈ repulsions • Critical constants are related to
coefficients. • Flat inflexion of curve when T=Tc. • Can derive (by setting 1st and 2nd
derivatives of equation to zero) expression for critical constants • Vc = 3b, • pc = a/27b2, • Tc =8a/27Rb
• Can derive expression for the Boyle Temperature • TB = a/Rb
,
Chemical Thermodynamics : Georg Duesberg
33
• Can derive (by setting 1st and 2nd derivatives of equation to zero) expression for critical constants
00.,. 2
2
=⎟⎟⎠
⎞⎜⎜⎝
⎛
∂
∂=⎟
⎠
⎞⎜⎝
⎛∂
∂
== cc TTTT vpand
vpei we have,
2va
bvRTP −−
=
( ) 32
2va
bvRT
vp
T
+−
−=⎟
⎠
⎞⎜⎝
⎛∂
∂∴
( ) 432
2 62va
bvRT
vpand
T
−−
=⎟⎟⎠
⎞⎜⎜⎝
⎛
∂
∂
At critical points the above equation reduces to
( )02
32 =+−
−
va
bvRT
( )062
43 =−− v
abvRTand
Features of vdW equation
Chemical Thermodynamics : Georg Duesberg Chemical Thermodynamics : Georg Duesberg
Chapter3434343434 1 : Slide 34
We also can say 2va
bvRT
P cc −
−=
By dividing those equations and simplifying we get
3cvb =
Substituting for b and solving for ‘a’ from 2nd derivative we get, a = 9RTcvc Substituting these expressions for a and b in equation (P(c) and solving for vc, we get
c
cc p
RTv
83
=c
c
pRT
b8
=∴c
c
pTR
aand22
6427⎟⎠
⎞⎜⎝
⎛=
Note: Usually constants a and b for different gases are given.
Features of vdW equation
Chemical Thermodynamics : Georg Duesberg
Critical constants pc
atm Vc cm3/mol
Tc
K Zc TB
K
Ar 48.0 75.3 150.7 0.292 411.5
CO2 72.9 94.0 304.2 0.274 714.8
He 2.26 57.8 5.2 0.305 22.64
O2 50.14 78.0 154.8 0.308 405.9
The general Van der Waals pVT surface
Chemical Thermodynamics : Georg Duesberg Chemical Thermodynamics : Georg Duesberg
Chapter 1 : Slide 36
The principle of corresponding states Gases behave differently at a given pressure and temperature, but they behave very much the same at temperatures and pressures normalized with respect to their critical temperatures and pressures. The ratios of pressure, temperature and specific volume of a real gas to the corresponding critical values are called the reduced properties. Define reduced variables pr = p/pc
Tr = T/Tc Vr = Vm/Vm,c
Van der Waals hoped that different gases confined to the same Vr at the same Tr would have the same pr.
Chemical Thermodynamics : Georg Duesberg Chemical Thermodynamics : Georg Duesberg
Substitute for the critical values:
22rr
r2
r
9bVa
b)3b27Rb(V8aRT
27bap
−−
=
2rr
rr V
313V
8Tp −−
=
Thus
Thus all gases have the same reduced equation of state (within the Van der Waals approximation).
Also:
Zc =pcVc/RTc = 3/8 =0.375
Proof: rewrite Van der Waals equation for 1 mol of gas, p = RT/(V-b)-a/V2, in terms of reduced variables:
2c
2rcr
crcr VV
abVV
TRTpp −−
=
Principle of Corresponding States
Compression factor plotted using reduced variables. Different curves are different TR
With reduced variables, different gases fall on the same curves -> Degree of generality ( principle of corresponding states) According to this law, there is a
functional relationship for all substances, which may be expressed mathematically as vR = f (PR,TR). From this law it is clear that if any two gases have equal values of reduced pressure and reduced temperature, they will have the same value of reduced volume. This law is most accurate in the vicinity of the critical point.
The compressibility factor of any gas is a function of only two properties, usually temperature and pressure so that Z1 = f (TR, PR) except near the critical point. This is the basis for the generalized compressibility chart. The generalized compressibility chart is plotted with Z versus PR for various values of TR. This is constructed by plotting the known data of one or more gases and can be used for any gas.
It may be seen from the chart that the value of the compressibility factor at the critical state is about 0.25. Note that the value of Z obtained from Van der waals’ equation of state at the critical point,
83
==c
ccc RT
vPZ which is higher than the actual value.
The following observations can be made from the generalized compressibility chart:
Ø At very low pressures (PR <<1), the gases behave as an ideal gas regardless of temperature.
Ø At high temperature (TR > 2), ideal gas behaviour can be assumed with good accuracy regardless of pressure except when (PR >> 1).
Ø The deviation of a gas from ideal gas behaviour is greatest in the vicinity of the critical point.
Chemical Thermodynamics : Georg Duesberg Chemical Thermodynamics : Georg Duesberg
Chapter 1 : Slide 41
There are many other equations of state for real gases 1) The Berthelot Equation. Replace Van der Waals' "a" with a temperature dependent term, a/T:
[p + a/(Vm2T)] [Vm - b] = RT
2) The Dieterici Equation : [p exp(a/VmRT)] [Vm - b] = RT 3) Redlich-Kwong 4) Peng-Robinson
Redlich-Kwong, Peng-Robinson are quantitative in region where gas liquefies Berthelot,Dieterici and others with more than ten parameters can give good
fits… with four free parameters, you can describe an elephant. With five his tail is
rotating …
)(2/1 BVVTA
BVRTp
mmm +−
−=
)()( βββα
β −++−
−=
mmmm VVVVRTp
Chemical Thermodynamics : Georg Duesberg Chemical Thermodynamics : Georg Duesberg
Chapter 1 : Slide 42
Summary: Real gases • REAL GASES: the COMPRESSION FACTOR and
INTERMOLECULAR FORCES. • pV diagrams: LIQUEFACTION and the CRITICAL POINT. • BOYLE TEMPERATURE • The VAN DER WAALS approximate equation of state p = RT/(Vm-b) -
a/Vm2 is more realistic for REAL GASES. There are other equations of
state which work well e.g The VIRIAL EQUATION REDUCED VARIABLES and the PRINCIPLE OF CORRESPONDING
STATES
Pressure region
I (very Low) Molecules have large separations -> no interactions -> Ideal Gas Behavior: Z =1
II (moderate) Molecules are close -> attractive forces apply -> The gas occupies less volumes as expected from Boyles law: Z<1
III (high) Molecules compressed highly -> repulsive forces dominate -> hardly further decrease in volume Z>1
Chemical Thermodynamics : Georg Duesberg
Real gas – Van der Waals equation.
For nitrogen a=0.14 and b=3.87x10-5. If 1.0 mole of nitrogen is confined to 2.00l and is at P=10atm what is Tideal and TVdW?
Under these conditions the temperature only changes by ~1%. Chapter 1 : Slide 43
( )
( )
( ) 240082.01/0387.0122114.01
/
2440.0822/110 /
2
2
2
=××−⎟⎟⎠
⎞⎜⎜⎝
⎛⎟⎠
⎞⎜⎝
⎛+
=−⎟⎟⎠
⎞⎜⎜⎝
⎛⎟⎠
⎞⎜⎝
⎛+
=−⎟⎟⎠
⎞⎜⎜⎝
⎛⎟⎠
⎞⎜⎝
⎛+
=××==
TnRnbVVnaP
nRTnbVVnaP
TnRPVnRTPV