chapter 4 notes packet on quadratic functions and · pdf fileunit 2 notes packet on quadratic...

1

Name:_______________________________ Period:____

Unit 2 Notes Packet on Quadratic Functions and Factoring

Notes #15: Graphing quadratic equations in standard form, vertex form, and intercept form.

A. Intro to Graphs of Quadratic Equations: 2y ax bx c

A ____________________ is a function that can be written in the form 2y ax bx c where

a, b, and c are real numbers and a 0. Ex: 25y x 22 7y x 2 3y x x

The graph of a quadratic function is a U-shaped curve called a ________________. The

maximum or minimum point is called the _____________

Identify the vertex of each graph; identify whether it is a minimum or a maximum.

1.) 2.)

Vertex: ( , ) _________ Vertex: ( , ) _________

3.) 4.)

Vertex: ( , ) _________ Vertex: ( , ) _________

B. Key Features of a Parabola: 2y ax bx c

Direction of Opening: When 0a , the parabola opens ________:

When 0a , the parabola opens ________:

Width: When 1a , the parabola is _______________ than 2y x

When 1a , the parabola is the ________ width as 2y x

When 1a , the parabola is ________ than 2y x

Vertex: The highest or lowest point of the parabola is called the vertex, which is on the axis of

symmetry. To find the vertex, plug in 2

bx

a

and solve for y. This yields a point (____, ____)

Axis of symmetry: This is a vertical line passing through the vertex. Its equation is: 2

bx

a

x-intercepts: are the 0, 1, or 2 points where the parabola crosses the x-axis. Plug in y = 0 and

solve for x.

y-intercept: is the point where the parabola crosses the y-axis. Plug in x = 0 and solve for y.

2

Without graphing the quadratic functions, complete the requested information:

5.) 2( ) 3 7 1f x x x

What is the direction of opening? _______

Is the vertex a max or min? _______

Wider or narrower than y = x2 ? __________

6.) 25( ) 3

4g x x x



Wider or narrower than y = x2 ? ___________

7.) 2211

3y x



Wider or narrower than y = x2 ? __________

8.) 20.6 4.3 9.1y x x



Wider or narrower than y = x2 ? ___________

The parabola y = x2

is graphed to the right.

Note its vertex (___, ___) and its width.

You will be asked to compare other parabolas to

this graph.

C. Graphing in STANDARD FORM ( 2y ax bx c ): we need to find the vertex first.

Vertex

- list a = ____, b = ____, c = ____

- find x = 2

b

a

- plug this x-value into the function (table)

- this point (___, ___) is the vertex of the parabola

Graphing

- put the vertex you found in the center of

your x-y chart.

- choose 2 x-values less than and 2 x-values more

than your vertex.

- plug in these x values to get 4 more points.

- graph all 5 points

Find the vertex of each parabola. Graph the function and find the requested information

9.) f(x)= -x2 + 2x + 3 a = ____, b = ____, c = ____

-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9 10

x

-10

-9

-8

-7

-6

-5

-4

-3

-2

-1

1

2

3

4

5

6

7

8

9

10

y

Vertex: _______

Max or min? _______

Direction of opening? _______

Axis of symmetry: ________

Compare to the graph of y = x2

_________________________

3

10.) h(x) = 2x2 + 4x + 1

-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9 10

x

-10

-9

-8

-7

-6

-5

-4

-3

-2

-1

1

2

3

4

5

6

7

8

9

10

y

Vertex: _______

Max or min? _______




_________________________

11.) k(x) = 2 – x –1

2x

2

-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9 10

x

-10

-9

-8

-7

-6

-5

-4

-3

-2

-1

1

2

3

4

5

6

7

8

9

10

y

Vertex: _______

Max or min? _______




_________________________

12.) State whether the function y = 3x2 + 12x 6 has a minimum value or a maximum

value. Then find the minimum or maximum value.

13.) Find the vertex of 215 7

2y x x . State whether it is a minimum or maximum. Find that

minimum or maximum value.

4

Another useful form of the quadratic function is the vertex form: ________________________________.

GRAPH OF VERTEX FORM y = a(x h)2 + k

The graph of y = a(x h)2 + k is the parabola y = ax

2 translated ___________ h units and ___________ k

units.

The vertex is (___, ___).

The axis of symmetry is x = ___.

The graph opens up if a ___ 0 and down if a ___ 0.

Find the vertex of each parabola and graph.

13.) 2

1 2y x

-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9 10

x

-10

-9

-8

-7

-6

-5

-4

-3

-2

-1

1

2

3

4

5

6

7

8

9

10

y

Vertex: _______

14.) 21

1 53

y x

-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9 10

x

-10

-9

-8

-7

-6

-5

-4

-3

-2

-1

1

2

3

4

5

6

7

8

9

10

y

Vertex: _______

15.) Write a quadratic function in vertex form for the function whose graph has its vertex

at (-5, 4) and passes through the point (7, 1).

5

GRAPH OF INTERCEPT FORM y = a(x p)(x q):

Characteristics of the graph y = a(x p)(x q):

The x-intercepts are ___ and ___.

The axis of symmetry is halfway between (___, 0) and ( ___ , 0)

and it has equation x =

2

The graph opens up if a ___ 0 and opens down if a ___ 0.

16.) Graph y = 2(x 1)(x 5)

-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9 10

x

-10

-9

-8

-7

-6

-5

-4

-3

-2

-1

1

2

3

4

5

6

7

8

9

10

y

x-intercepts: _______, _______

Vertex: _______

Converting between forms:

From intercept form to standard form

Use FOIL to multiply the binomials

together

Distribute the coefficient to all 3 terms

Ex: 2 5 8y x x

From vertex form to standard form

Re-write the squared term as the

product of two binomials

Use FOIL to multiply the binomials

together

Distribute the coefficient to all 3 terms

Add constant at the end

Ex: 2

4 1 9f x x

HW #15: Pg. 202: 47-63 odd

pg. 240 #3-39 x 6’s

pg. 249 #4-40 x 4’s

6

Notes 16: Sections 4-3 and 4-4: Solving quadratics by Factoring

A. Factoring Quadratics

Examples of monomials:_______________________________

Examples of binomials:________________________________

Examples of trinomials:________________________________

Strategies to use: (1) Look for a GCF to factor out of all terms

(2) Look for special factoring patterns as listed below

(3) Use the X-Box method

(4) Check your factoring by using multiplication/FOIL

Factor each expression completely. Check using multiplication.

1.) 23 15x x 2.) 26 24x 3.) 2 5 24x x

4.) 225 81x 5.) 2 22 121m m 6.) 24 12 9x x

7

7.) 25 17 6x x 8.) 23 5 12x x 9.) 25t2 110t + 121

10.) 216 36x

11.) 29 42 49a a

12.) 26 33 36x x

B. Solving quadratics using factoring

To solve a quadratic equation is to find the x values for which the function is equal to _____. The

solutions are called the _____ or _______of the equation. To do this, we use the Zero Product

Property:

Zero Product Property

List some pairs of numbers that multiply to zero:

(___)(___) = 0 (___)(___) = 0 (___)(___) = 0 (___)(___) = 0

What did you notice? _______________________________________________

ZERO PRODUCT PROPERTY

If the _________ of two expressions is zero, then _______ or _______ of

the expressions equals zero.

Algebra If A and B are expressions and AB = ____ , then A = _____ or B = __.

Example If (x + 5)(x + 2) = 0, then x + 5 = 0 or x + 2 = 0. That is,

x = __________ or x = _________.

Use this pattern to solve for the variable:

1. get the quadratic = 0 and factor completely

2. set each ( ) = 0 (this means to write two new equations)

3. solve for the variable (you sometimes get more than 1 solution)

8

Find the roots of each equation:

13.) 2 7 30 0x x

14.) 2 6 4 8

03 7 5 9

x x

15.)

23 2 21x x

Find the zeros of each equation:

16.) 22 8 30 34x x x 17.) v(v + 3) = 10 18.) 22 15x x

Find the zeros of the function by rewriting the function in intercept form:

19.) 26 3 63y x x

20.) 212 6 6f x x x 21.) 249 16g x x

Graph the function. Label the vertex and axis of symmetry:

22.) 2 1 ( 3)y x x

-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9 10

x

-10

-9

-8

-7

-6

-5

-4

-3

-2

-1

1

2

3

4

5

6

7

8

9

10

y

Vertex: _______

Maximum or minimum value: _______

x-intercepts: _______


Compare width to the graph of y = x2

_________________________

HW #16:

pg. 255 #4-52 x 4’s, pg. 263 #4-52 x 4’s, Pg. 265: #78-81

Study for Quiz on Sec. 4.1-4.4 (Quiz is tomorrow!)

9

Notes #17: Section 4-5 Solve Quadratic Equations by Finding Square Roots

A. Simplifying Square Roots:

Make a factor tree; circle pairs of “buddies.”

One of each pair comes out of the root, the non-paired numbers stay in the root.

Multiply the terms on the outside together; multiply the terms on the inside together

Simplify:

1.) 3 120 2.) 5 72

B. Multiplying Square Roots:

Simplify each radical completely by taking out “buddies”

(outside • outside) inside inside or ( )( ) ________a b c d

Simplify your answer, if possible

Simplify:

3.) 5 12 3 15 4.) 2 5 2 5

C. Simplifying Square Roots in Fractions:

Split up the fraction: 2 2 2

25 5 25

a

b

Simplify first by taking out “buddies” or reducing (you can only reduce two numbers that are

both under a root or two numbers that are both not in a root)

Square root top, square root bottom

If one square root is left in the denominator, multiply the top and the bottom by the square root

and simplify

OR If a binomial is left in the denominator, then multiply top and bottom by the conjugate of the

denominator (exact same expression except with the opposite sign). Remember to FOIL on the

denominator.

Reduce if possible

Simplify:

5.) 7

3 6.)

4

5+ 3 7.)

2 5

3 2

10

D. Solving Quadratic Equations Using Square Roots

Isolate the variable or expression being squared (get it ______________)

Square root both sides of the equation (include + and – on the right side!)

This means you have _____________ equations to solve!!

Solve for the variable (make sure there are no roots in the denominator)

8.) x2 = 25 9.) 3x

2 = 81

10.) 4x2 – 1 = 0 11.)

2

3 215

m

12.) (2y + 3)2 = 49 13.)

23 2 6 34x

HW #17: Pg. 202: 46-62 even, Pg. 258: 79-89 odd, pg. 269 #3-33 x 3’s

11

Notes#18: Sections 4-6 & 4-7 Complex Numbers and Completing the square

Section 4.6: Complex Numbers

A. Definitions

Define

Complex Numbers:

imaginary unit (i):

imaginary number :

B. Solving a quadratic equation with complex roots

Isolate the expression being squared

Square root both sides; write two equations Replace 1 with i. Simplify

Solve

1.) x2 = 27 2.) 2x

2 + 11 = 37 3.) 24(2 1) 8 0x

C. Adding, subtracting, and multiplying complex numbers

Distribute/FOIL. Combine like terms.

Replace 2i with (-1). Simplify.

Simplify

4.) (3 + 7i) (8 2i) 5.) (2 + 5i) + (7 2i) 6.) (2 + i)(5 + 2i) 7.) (3 i)(5 2i)

B. Dividing complex numbers

If i is part of a monomial on the denominator, multiply top and bottom by i. ex: 5

6i

If i is part of a binomial on the denominator, multiply top and bottom by the complex

conjugate of the denominator (same expression but opposite sign). FOIL. ex: 5

6 i

Replace 2i with (-1). Simplify.

8.) 3

4i 9.)

6 4

2

i

i

10.)

2

7

i

i

11.)

7 5

1 4

i

i

12

Section 4.7: Completing the Square

B. Review: Solving Using Square Roots

Factor and write one side of the equation as the square of a binomial

Square root both sides of the equation (include + and – on the right side; 2 equations!

Solve for the variable (make sure there are no roots in the denominator)

1) (k + 2)2 = 12 2.) x

2 + 2x + 1 = 8 3.) n

2 – 14n + 49 = 3

C. Completing the Square 2 0ax bx c

Take half the b (the x coefficient)

Square this number (no decimals – leave as a fraction!)

Add this number to the expression

Factor – it should be a binomial, squared ( )2

4.) x2 + 6x + _____ 5.) m

2 – 14m + _______

( )( )

( )2

Find the value of c such that each expression is a perfect square trinomial. Then write the expression as

the square of a binomial.

6.) w2 + 7w + c 7.) k

2 – 5k + c

Solving by Completing the Square:

Collect variables on the left, numbers on the right

Divide ALL terms by a; leave as fractions (no decimals!)

Complete the square on the left – add this number to BOTH sides

Square root both sides (include a ______ and _______ equation!)

Solve for the variable (simplify all roots – look for 1 i )

8.) x2 + 4x – 5 = 0 9.) m

2 – 5m + 11 = 10

13

10.) 22 9 3 17k k k 11.) 23 4 11 2 2w w w

12.) 2x2

– 3x – 1 = 0 13.) 23 2 6x x x

Cumulative Review: Solving Quadratics

Solve by factoring:

14.) 12k2 – 5k = 2 15.) 49m

2 – 16 = 0

Solve by using square roots:

16.) 4w2 = 18 17.) 3y

2 – 8 = 0

HW #18: pg. 279 #3-33 x 3’s pg. 288 #3-36 x 3’s pg. 1013: 6-32 even

14

Notes #19: Sec. 4-8 Use the Quadratic Formula and the Discriminant

A. Review of Simplifying Radicals and Fractions

Simplify expression under the radical sign ( 1 i ); reduce

Reduce only from ALL terms of the fraction.

(You can’t reduce a number outside of a radical with a number inside of a radical)

Make sure that you have TWO answers

Simplify:

1.) 6 18

2

2.)

5 20

2

3.) 4 20

4

4.) 8 27

2

5.) 29 ( 5) (5)(2)(3)

4

6.)

29 (6) 4( 3)( 3)

4

B. Solving Quadratics using the Quadratic Formula

So far, we have solved quadratics by: (1) _______________, (2) ______________, and

(3) ___________________.

The final method for solving quadratics is to use the quadratic formula.

Solving using the quadratic formula:

Put into standard form (ax2 + bx + c = 0)

List a = , b = , c =

Plug a, b, and c into

2 4

2

b b acx

a

Simplify all roots (look for 1 i ); reduce

15

Solve by using the quadratic formula:

1.) x2 + x = 12

2 4

2

b b acx

a

(std. form):

a = _____

b = _____

c = _____

2.) 5x2 – 8x = -3

2 4

2

b b acx

a

(std. form):

a = _____

b = _____

c = _____

3.) -x2 + x = -1 4.) 3x

2 = 7 – 2x

5.) -x2 + 4x = 5 6.) 24( 1) 6 2x x

16

C. Using the Discriminant

Quadratic equations can have two, one, or no solutions (x-intercepts). You can determine how

many solutions a quadratic equation has before you solve it by using the ________________.

The discriminant is the expression under the radical in the quadratic formula: 2 4

2

b b acx

a

Discriminant = b2 – 4ac

If b2 – 4ac < 0, then the equation has 2 imaginary solutions

If b2 – 4ac = 0, then the equation has 1 real solution

If b2 – 4ac > 0, then the equation has 2 real solutions

A. Finding the number of x-intercepts

Determine whether the graphs intersect the x-axis in zero, one, or two points.

1.) 24 12 9y x x 2.) 23 13 10y x x

B. Finding the number and type of solutions

Find the discriminant of the quadratic equation and give the number and type of solutions of the

equation.

3.) 23 5 1x x 4.) 2 3 7x x

5.) 9x2 – 6x = 1 6.) 4x

2 = 5x + 3

17

Cumulative Review Problems:

Solve by factoring:

7.) 4m2 +5m – 6 = 0 8.) 3x

3 – 27x = 0

Solve by using square roots:

9.) 4b2 + 1 = 0 10.) (3x + 1)

2 = 18

Solve by completing the square:

11.) 4m2 + 12m +5 = 0 12.) x

2 – 7x – 18 = 0

For #13, find the vertex of the parabola. Graph the function and find the requested information 13.) g(x) = -2x

2 + 8x – 5

-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9 10

x

-10

-9

-8

-7

-6

-5

-4

-3

-2

-1

1

2

3

4

5

6

7

8

9

10

y

Vertex: _______

Max or min value: _______


Compare width to y = x2 :

_______________


HW #19: Pg. 265 #1-12 pg. 296 #4-48 x 4’s pg. 299 #76-86even

18

Notes #20: Section 4-9 Graph and Solve Quadratic Inequalities

GRAPHING A QUADRATIC INEQUALITY IN TWO VARIABLES

To graph a quadratic inequality, follow these steps:

Step 1 Graph the parabola with equation y = ax2+ bx + c.

Make the parabola _______________ for inequalities with < or > and ______________ for inequalities

with or .

Step 2 Test a point (x, y) ______________ the parabola to determine whether the point is a solution of the

inequality.

Step 3 Shade the region ______________ the parabola if the point from Step 2 is a solution. Shade the

region ________________ the parabola if it is not a solution.

1.) y x2 2x + 3

-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9 10

x

-10

-9

-8

-7

-6

-5

-4

-3

-2

-1

1

2

3

4

5

6

7

8

9

10

y

2.) y ≥ x2 3x – 4

-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9 10

x

-10

-9

-8

-7

-6

-5

-4

-3

-2

-1

1

2

3

4

5

6

7

8

9

10

y

19

3.) y > 3x2 +3x 5

y x2 +5x + 10

4.) y -x2 +4

y x2 − 2x− 3

-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9 10

x

-10

-9

-8

-7

-6

-5

-4

-3

-2

-1

1

2

3

4

5

6

7

8

9

10

y

HW #20: pg. 304 #4-24 x 4’s Pg. 323 #1-24 all

20

Notes# 21: Sec. 4-10 Write Quadratic Functions and Models

A. When given the vertex and a point

Plug the vertex in for (h, k) in 2( )y a x h k

Plug in the given point for (x, y)

Solve for a. Plug in a, h, k into 2( )y a x h k

1.) Write a quadratic equation in vertex form

for the parabola shown.

2.) Write a quadratic function in vertex form for the function whose graph has its vertex at (2, 1) and

passes through the point (4, 5).

B. When given the x-intercepts and a third point

Plug in the x-intercepts as p and q into y = a(x p)(x q)

Plug in the given point for (x, y)

Solve for a. Plug in a, h, k into y = a(x p)(x q)

3.) Write a quadratic function in intercept form

for the parabola shown.

21

B. When given three points on the parabola

Label all three points as (x, y)

Separately, plug in each point into 2y ax bx c

You now have 3 equations with three variables: a, b, c

Solve for a, b, and c using elimination (see notes #13). Plug back into 2y ax bx c

4.) Write a quadratic function in standard form for the parabola that passes

through the points (2, 6), (0, 6) and (2, 2).

5.) Write a quadratic function in standard form for the parabola that passes

through the points (1, 2), (1, 4) and (2, 1).

HW #21: pg. 312 #4-14even Pg. 1013: 1-21 odd, 29-39 all, 43, 48

Chapter 4 Test and Notes Check on Friday

22

Notes #22: Chapter 4 Review

To graph a quadratic function, you must FIRST find the vertex (h, k)!!

(A) If the function starts in standard form 2y ax bx c :

1st: The x-coordinate of the vertex, h, =

2

b

a

2nd

: Find the y-coordinate of the vertex, k, by plugging the x-coordinate into the function &

solving for y.

(B) If the function starts in intercept form ( )( )y a x p x q :

1st: Find the x-intercepts by setting the factors with x equal to 0 & solving for x.

2nd

: The x-coordinate of the vertex is half way between the x-intercepts.

3rd

: Find the y-coordinate of the vertex, k, by plugging the x-coordinate into the function &

solving for y.

(C) If the function starts in vertex form 2( )y a x h k :

1st: pick out the x-coordinate of the vertex, h. REMEMBER: h will have the OPPOSITE sign

as what is in the parenthesis!!

2nd

: Pick out the y-coordinate of the vertex, k. It will have the SAME sign as the what is in the

equation!

AFTER finding the vertex:

Make a table of values with 5 points: The vertex, plug in 2 x-coordinates SMALLER than

the x-coordinate of the vertex & 2 x-coordinates LARGER than the x-coordinate of the

vertex.

Direction of Opening:

If a is positive, the graph opens up

If a is negative, the graph opens down.

Width of the function:

If 1a , the graph is narrower than 2y x

If 1a , the graph is wider than 2y x

23

Graph each function by making a table of values with at least 5 points. (A) State the vertex. (B)

State the direction of opening (up/down). (C) State whether the graph is wider, narrower, or the

same width as 2y x .

1.) 21( ) ( 6) 5

2f x x

-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9 10

x

-10

-9

-8

-7

-6

-5

-4

-3

-2

-1

1

2

3

4

5

6

7

8

9

10

y

Vertex: _______



_________________________

2.) k(x) = x2 + 2x + 1

-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9 10

x

-10

-9

-8

-7

-6

-5

-4

-3

-2

-1

1

2

3

4

5

6

7

8

9

10

y

Vertex: _______



_________________________

3.) f(x) = x2 – x – 6

-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9 10

x

-10

-9

-8

-7

-6

-5

-4

-3

-2

-1

1

2

3

4

5

6

7

8

9

10

y

Vertex: _______



_________________________

24

4.) 2( ) 2 3f x x x

-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9 10

x

-10

-9

-8

-7

-6

-5

-4

-3

-2

-1

1

2

3

4

5

6

7

8

9

10

y

Vertex: _______



_________________________

5.) 2( ) 2 4 1h x x x

-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9 10

x

-10

-9

-8

-7

-6

-5

-4

-3

-2

-1

1

2

3

4

5

6

7

8

9

10

y

Vertex: _______



_________________________

6.) 1

( ) ( 4)( 6)3

g x x x

-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9 10

x

-10

-9

-8

-7

-6

-5

-4

-3

-2

-1

1

2

3

4

5

6

7

8

9

10

y

Vertex: _______



_________________________

25

Methods for Solving Quadratic Equations:

A.) Factoring

1st: Set equal to 0

2nd

: Factor out the GCF

3rd

: Complete the X & box method to find the factors

4th

: Set every factor that contains an x in it, equal to 0 & solve for x.

B.) Completing the Square

1st: Move the constant (number with no variable) to the right so that all variables are on the left

& all constants are on the right.

2nd

: Divide every term in the equation by the value of a, if it is not already 1.

3rd

: Create a perfect square trinomial on the left side by adding

2

2

b

to both sides.

4th

: Factor the left side into a

2

2

bx

and simplify the value on the right side.

5th

: Take the square root of both sides of the equation. REMINDER: Don’t forget the

6th

: Solve for x

C.) Finding Square Roots

1st: Isolate the term with the square.

2nd

: Take the square root of both sides of the equation. REMINDER: Don’t forget the

3rd

: Solve for x.

D.) Quadratic Formula

1st: Set the equation equal to 0.

2nd

: Find the values of a, b, and c & plug them into the Quadratic Formula:

2 4

2

b b acx

a

3rd

: Simplify the radical as much as possible.

4th

: If possible, simplify the numerator into integers.

5th

: Divide. REMINDER: If you have 2 terms in the numerator (ex: 4 6 3

2

), divide BOTH

terms by the number in the denominator (the example would result in 2 3 3 )

Examples: Solve each equation by the method stated.

By Square Roots:

1.) (2y + 3) 2

= 49

2.) (3m – 1) 2

= 20

3.) 2(3 5) 1 11r

26

By Factoring:

4.) x2 – 4x – 5 = 0 5.) 23 2 21x x

6.) 22 15x x

By Completing the Square:

7.) x2 – 6x – 11 = 0 8.) 2y

2 + 6y – 18 = 0

9.) 2x2

– 3x – 1 = 0

By Quadratic Formula:

10.) x2 + x = 12

11.) 5x2 – 8x = -3 12.) 2x

2 = 4 – 7x

HW #22—Chapter 4 Review Sheet all (check answers online!!)

Chapter 4 Test and Notes Check on Friday

27

Chapter 4 Review Sheet

Please complete each problem on a separate sheet of paper. Show all of your work and please use

graph paper for all graphs.

For questions 1-3, solve by factoring.

1. 2 12 32 0x x 2. 23 8 5 0x x 3. 22 4 30 0x x

For questions 4-5, solve by finding square roots.

4. 21( 1) 16 0

4x 5.

22 1 3 6x

For questions 6-8, solve by completing the square.

6. 2 16 15 0x x 7. 25 10 20 0x x 8. 214 6 0

2x x

For questions 9-10, solve by using the quadratic formula.

9. 2 3 5 0x x 10. 2 23 2 5 1x x x x

For questions 11-13, simplify each expression.

11. 48 32

4

12.

5

48 13. 252 3

For questions 14-16, write each function in vertex form, graph the function, and label the vertex

and axis of symmetry.

14. 2 16 2y x x 15. 22 4 7y x x 16. 21( 4) 8

3y x

For question 17-19, graph each inequality.

17. 22( 1) 5y x 18. 2 8 2y x x 19. 22 12 16y x x

For questions 20-21, write a quadratic function in vertex form whose graph has the given vertex

and passes through the given point.

20. Vertex (2, 3) and passes through (-3, 7)

21. Vertex (-1, -5) and passes through (2, -1)

For questions 22-23, write a quadratic function in standard form whose graph passes through

the given points.

22. (1, 1), (0, -2), (2, 8) 23. (-1, -7), (1, -5), (2, -1)

For questions 24-28, write the expression as a complex number in standard form.

24. (7 3 ) (9 4 )i i 25. (6 2 )( 8 3 )i i 26. ( 3 7 ) (9 2 )i i

27. 2 5

7

i

i

28.

4 7

3

i

i

Chapter 4 Test and Notes Check Tomorrow!

chapter 4 notes packet on quadratic functions and · pdf fileunit 2 notes packet on quadratic...

Documents