copyright © 2011 pearson, inc. 6.4 polar coordinates
TRANSCRIPT
Slide 6.4 - 2 Copyright © 2011 Pearson, Inc.
What you’ll learn about
Polar Coordinate System Coordinate Conversion Equation Conversion Finding Distance Using Polar Coordinates
… and whyUse of polar coordinates sometimes simplifies complicated rectangular equations and they are useful in calculus.
Slide 6.4 - 3 Copyright © 2011 Pearson, Inc.
The Polar Coordinate System
A polar coordinate system is a plane with a point O, the pole, and a ray from O, the polar axis, as shown. Each point P in the plane is assigned polar coordinates as follows: r is the directed distance from O to P, and is the directed angle whose initial side is on the polar axis and whose terminal side is on the line OP.
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Example Plotting Points in the Polar Coordinate System
Plot the points with the given polar coordinates.
(a) P(2, π / 3) (b) Q(−1, 3π / 4) (c) R(3, −45o)
Slide 6.4 - 5 Copyright © 2011 Pearson, Inc.
Example Plotting Points in the Polar Coordinate System
Plot the points with the given polar coordinates.
(a) P(2, π / 3) (b) Q(−1, 3π / 4) (c) R(3, −45o)
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Finding all Polar Coordinates of a Point
Let the point P have polar coordinates (r,). Any
other polar coordinate of P must be of the form
(r, + 2πn) or (−r, + (2n+1)π )where n is any integer. In particular, the pole has
polar coordinates (0,), where is any angle.
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Coordinate Conversion Equations
Let the point P have polar coordinates (r,)and rectangular coordinates (x, y). Then
x=rcosy=rsinr2 =x2 + y2
tan =yx.
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Example Converting from Polar to Rectangular Coordinates
Find the rectangular coordinates of the point with the
polar coordinates (2, 7π / 6).
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Example Converting from Polar to Rectangular Coordinates
For point (2,7π / 6), r =2 and =7π / 6.x=rcos y=rsinx=2cos7π / 6 y=2sin7π / 6
x=2 −32
⎛
⎝⎜
⎞
⎠⎟ y=2 −
12
⎛
⎝⎜⎞
⎠⎟
x=− 3 y=−1
The recangular coordinate is − 3,−1( ).
Find the rectangular coordinates of the point with the
polar coordinates (2, 7π / 6).
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Example Converting from Rectangular to Polar Coordinates
Find two polar coordinate pairs for the point with
the rectangular coordinates (1,−1).
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Example Converting from Rectangular to Polar Coordinates
For the point (1,−1), x=1 and y=−1.
r2 =x2 + y2 tan =yx
r2 =12 + (−1)2 tan =−11
r2 = 2 tan =−1
r =± 2 =−π4+ nπ
Find two polar coordinate pairs for the point with
the rectangular coordinates (1,−1).
Two polar
coordinates
pairs are
2,−π4
⎛
⎝⎜⎞
⎠⎟ and
− 2,3π4
⎛
⎝⎜⎞
⎠⎟.
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Example Converting from Polar Form to Rectangular Form
Convert r =−2csc to rectangular form and
identify the graph.Support your answer with a polar graphing utility.
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Example Converting from Polar Form to Rectangular Form
r =−2cscr
csc=−2
rsin =−2y=−2
Convert r =−2csc to rectangular form and
identify the graph.Support your answer with a polar graphing utility.
The graph is the
horizontal line
y =−2.
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Example Converting from Polar Form to Rectangular Form
Convert x −2( )2+ y−3( )
2=13 to polar form.
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Example Converting from Polar Form to Rectangular Form
x −2( )2+ y−3( )
2=13
x2 −4x+ 4 + y2 −6y+9 =13
x2 + y2 −4x−6y=0
Substitute r2 =x2 + y2 ,x=rcos, and y=rsin.
Convert x −2( )2+ y−3( )
2=13 to polar form.
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Example Converting from Polar Form to Rectangular Form
Convert x −2( )2+ y−3( )
2=13 to polar form.
r =0 is a single point that is also on the other graph.Thus the equation is r =4cos +6sin.
Substitute r 2 =x2 + y2 ,x=rcos, and y=rsin.r2 −4rcos −6rsin =0
r r −4cos −6sin( ) =0
r =0 or r =4cos +6sin
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Quick Review
1. Determine the quadrants containing the terminal
side of the angle: −4π / 32. Find a positive and negative angle coterminal
with the given angle: −π / 33. Write a standard form equation for the circle with
center at ( −6,0) and a radius of 4.
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Quick Review
Use the Law of Cosines to find the measure of the third side of the given triangle.
4.40º
8 10
5.
35º
6 11
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Quick Review Solutions
1. Determine the quadrants containing the terminal
side of the angle: −4π / 3 II2. Find a positive and negative angle coterminal
with the given angle: −π / 3 5π /3, −7π /33. Write a standard form equation for the circle
with center at ( −6,0) and a radius of 4.
(x+6)2 + y2 =16