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  • 7/30/2019 cng o lng n tp

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    Cu 1: Cch xl sai ssau khi o bng pp xstk

    Sau khi thc hin php o vi cng iu kin n ln

    1. Ghi li n gi tr kt qu

    2. Tnh sai sd : =ai-atb3. Tnh sai s : | |(1) 4. Tnh sai strung bnh bnh phng:

    1 1( )2= 5. Tin hnh php o nhiu ln:

    1( 1)( )2=

    6. Xc nh kt quo:X=atb+t

    Cu 2 :

    Vai tr ca LT trong k thut

    Khi nghin cu thit k,iu chnh khai thc, lp t,vn hnh cc h thng T,VT kothko c my o

    Dc 1 ht lm vic hay iu chnh 1 TBT l 1 qu trnh o lng cc chcngtc,ly cc c tnh ca tng khi,tng khu hay ton b

    Khi lp t ,ch to cc TBT,TBVT mun c c chcng tc thc tv thng shp l th cn phi da trn cc thng s thc tc o lng da trn c sthcnghim.

    o lng gip ktra pht hin hng hc,pht hin kp thi cc sai st,gip gi chtiu kthut cao

    Phn bit gia LT v LT trong vin thng :

    o lng in tl pp dng thit bin txc nh 1 thng s vt l hoc thng s phiin(phi s dng thm cc b sensorbin cc i lng phi in thnh in)

    o lng TVT:l pp x thng s v vin thng thng qua pho LT cc nh ccthng sgii tn cao v chn

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    Cu 3 :

    Cc thng sc bn trong php o :

    Mch in ttng t : in tr Tin Cun cm Bin p Dit Transitor(tram thng v lng cc) Ic tng t

    Mch in t s : Cc phn t logic(AND,OR,NOT,XOR,NAND) Ic s

    Cu 4:

    Cc bc o c bn :

    1. Thit lp n v vt l2. Biu din tn hiu o3. So snh vs tn hiu chun4. Ghi nhn kt qu

    Cu 5:

    Cc pp o:

    o trc tip:

    pp dng my o,mu o nh gi slng ca cc i lng cn o Kt quo l tr s ca i lng cn o Pp ny n gin,nhanh loi bc sai s

    o gin tip:

    pp m KQ o ko phi l tr s ca i lng cn o m cc s liu c sca i lngcn o

    Pp ny phi tin hnh nhiu ln o nhm hn ch sai s

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    o tng quan:

    pp dng nhng qu trnh phc tp ,ko th thit lp c quan hhm sno gia cc ilng l thng s ca qu trnh nghin cu.

    Pp ny cn t nht 2 php o m thng s t kq ca chng ko ph thuc ln nhau.

    chnh xc c x= di khong tgian ca qu trnh tip theoCu 6:

    Nguyn nhn gy sai s:

    Nguyn nhn khch quan:

    mi trng: i lng o b can nhiu,ko n nh

    Nguyn nhn ch quan:

    Bn thn thit bo:

    Ngi thc hin php o: Thiu thnh tho trong qu trnh o Pp tin hnh o ko hp l

    Cu 7:

    o tn s bng pp m :

    B to dng xung: bin i tn hiu iu ho tn s f(x)thnh cc tnhiu dng xung ccng chu k vi tn hiu.

    B to xung chun: to xung c n nh cao, thng l dao ng thch anh. Ngoi racn c cc bnhn chia tn to ra nhiu tn s khc nhau.

    B chn xung v bm: thc hin vic m xung trong 1 chu k ca xung chun.Bchn xung:chn ra cc xung m trong tgian tn ti ca xung

    S khi

    Tch=nTx

    fx=nfch

    Nguyn nhn gy sai sp m:

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    chnh xc ca xung chun Tch hay sai lch ca tgian chun Vn ng b gia xung mv xung m. Do sai s ca phng php ny l sai s1

    Cch khc phc

    tng chnh xc ca phng phpny cn tng rng xung chun Tch

    Cu 8:

    o tn s bng pp cng hng:

    S khi

    B phn ghp c vai tr ghp tn hiu in p cn o vo mch o Mch cng hng c kch thch bng dng in ly th ngun cn o thng qua b

    ghp. B phn iu chun : iu chnh t ti tn s cn o B phn ch th:khi mch cng hng gy cng hng ti tn so th hin tng ny

    c pht hin bng b phn ch th

    Cu 9:

    o tn s bng my oxilo

    S dng hnh litxagiu to ra trn mn hnh Oscillo xc nh tn stheo tn hiu c

    tn s chun.

    a tn hiu cn o tn s fx vo cp phin lm lch X. a tn hiu c tn s chun fch vo cp phin lm lch Y. xc nh tn s cn o ta dng 2 ct tuyn ct dao ng Litxagiu theo 2 phng

    ng v ngang, thomn sim ct hnh Litxagiu l ti a.

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    Sgiao im theo phng X v Y ln lt l n v m. S giao im theo phng X vY ln lt l n v m.

    Lin h gia tn sfx v fch:

    Nfx=mfch fx= fch