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1 DIRECTCURRENT CIRCUITS BASIC CONCEPTS Resistors in circuits. Kirchhoff’s Rules Ammeters and Voltmeters RC Circuits

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Page 1: DIRECT CURRENT CIRCUITS - Physics and …people.physics.tamu.edu/adair/phys208/chapt26/CHAPTER 26.pdfDIRECT‐CURRENT CIRCUITS ... The charge on the capacitor goes from 0 to ... Microsoft

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DIRECT‐CURRENT CIRCUITS

BASIC CONCEPTS

Resistors in circuits.

Kirchhoff’s Rules

Ammeters and Voltmeters

R‐C Circuits

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In Chapter 24 we found equivalent

capacitance for combinations of capacitors.

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For resistors we need similar equations.

The current I through each R is same.

The voltage

And

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Therefore

Can replace the three resistors with one

resistor with resistance

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The total current I is divided between

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And

Therefore

Or

For Parallel.

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Consider the following circuit.

What is the current through the 6 Ω

resistor?

12V

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ΩΩ

Therefore there are 6A through the 1Ω

resistor.

Ω

The emf of the battery is

Ω

The current through the resistor is

Ω

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Example:

1.25A

What does the voltmeter read?

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KIRCHHOFF’S RULES

Junction Rule

The sum of the currents into a junction is

zero.

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Loop Rule

The sum of the potential differences in a

loop is zero.

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Sign Convention

For resistors:

For batteries:

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Example:

Loop 1 (start at a)

Loop 2 (start at c)

I1

I2

IR

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Loop 3 (start at a)

Junction a

Junction b

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R‐C CIRCUITS

No current.

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Then close switch.

Apply Kirchhoff’s Loop Rule.

Across resistor potential change

Across battery potential change

Across capacitor potential change

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Start at a.

The current is

Put in equation.

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The charge on the capacitor goes from 0 to

Q. Start the stopwatch when the switch is

closed and time goes from 0 to t.

Integrate

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The charge on the capacitor increases

exponentially with time.

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Charge on capacitor:

Current in circuit:

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And

Define

Current starts and decreases

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EXALMPLE: Consider this circuit:

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Find:

a. The time constant

b. The maximum charge on C

c. The time for the charge to reach 99%

of .

d. The current when

e.

f. Q when

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DISCHARGING CAPACITOR

After long time capacitor has charge .

Connect points a and c.

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Now capacitor discharges through the

resistor and:

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Integrate from while

Then