1. B MN CTB-BC GVHD: TH.S- BI TH ANHTHUYT MINH N C NH II ------ NHM 1------Nhim v ca n : Thit k khi chn cng trnh bin trng lc tronggiai on khai thc. I.GI THIU IM CNG TRNH IC Cng trnh bin trng lc l loi cng trnh lm vic theo nguyn l mng nng, ng n nh trn mt y bin nh trng lng bn thn v trng lng cng ngh.Mt trong nhng -u im ni bt ca cng trnh bintrng lc l ton b (hoc phn ln) kt cu cng trnh-c ch to ven b, sau lai dt cng trnh ra vtr xy dng nh chm, gim thiu thi gian thi cngngoi khi do vy trnh -c nhng ri ro khi thi cngdi ngy ngoi khi. tn dng -c -u im trn y, cc cng trnhphi -c thit k sao cho t ni n nh trong qutrnh lai dt t v tr thi cng ven b n ni xydng cng trnh. tng n nh cho cng trnh, th-ngcu to phn ln h thp trng tm cng trnh.Trng tm cng thp th cng trnh cng n nh.Ngoi ra, b tng cn l vt liu r tin hn thp, c th s dng ngun nhncng a phng. Kh nng chng n mn xm thc ca mi trng mnh nhnc bin tt. Qu trnh duy tu bo dng t hn so vi cng trnh bin c nhbng thp. C th s dng cc khong khng gian ngm trong cng trnh nh ccsilo.Cc nhc im m cng trnh bin trng lc l : - Kch thc trng lngln dn n tnh linh hot km. i hi thi cng trn b phi c kh, cng ncsu.NHM 1 1

2. B MN CTB-BC GVHD: TH.S- BI TH ANHII. IM KH T NG H VN, A CH CNG TRNH.C I T 1. S liu thy triu v nc dng ti v tr xy dng cng trnh. Cc thng s bi 1H s iu chnh chiu cao sng0.4 Bin ng triu ln nht d1 (m) 1.5Nc dng tng ng vi bo thit k d2 ( m )1 2. su nc ti v tr xy dng cng trnh. do = 21m 3. S liu v sng.Chu k lpHng NNE E SE SSW W NW100 NmH, m10.8 16.19.9 6.2 8.6 12.2 9.3 7.4T, s 10.3 14.1 11.6 10.8 12.4 12.5 12.0 12.3 50 NmH, m9.7 15.6 9.2 5.6 8.0 12.4 8.8 6.9T, s 10.0 14.1 11.5 10.5 12.1 12.4 11.9 11.7 25 NmH, m8.8 14.7 8.7 5.2 7.7 11.1 8.5 6.5T, s 9.9 14.3 11.4 10.2 11.8 12.4 11.8 11.7 5 Nm H, m5.6 13.7 6.8 3.8 6.2 9.77.1 4.8T, s 9.4 13.9 11.09.4 10.6 12.1 11.6 11.0NHM 1 2 3. B MN CTB-BC GVHD: TH.S- BI TH ANH1 NmH, m 2.611.8 4.82.44.67.35.8 3.0 T, s 9.113.3 10.5 9.19.211.7 11.39.94. S liu v dng chy. Vn tc dng chy thit k vi chu k lp 100 nm, tng ng vi cc hng sng. Vn tc dng chy mt :-Cc thng H-ng sng s N NE ESE SSWW NW Vn tc 93 137 100173 22418117812 (cm/s)1H-ng () 24 242 277 41 68 79 78 1304 Vn tc dng chy y :Cc thng H-ng sng s N NE ESE SSWW NW Vn tc 68 119 90 109 18213711997(cm/s)H-ng ()2 300 60 295 32953 3291975. S liu v h bm.Phm vi h bm tnh t mc n-cChiu dy h bmthp nht tr xung(mm)NHM 13 4. B MN CTB-BC GVHD: TH.S- BI TH ANH T mc n-c thp nht (0m) n -4m 80mmT - 4m n -8m 87mmT -8m n -10m100mmT -10m n y bin70mmTrng lng ring h bm : =1.6 T/m3 6.S liu v gi. Vn tc gi trung bnh o trong 3 giy vi chu k lp 100 nm o d cao 10mso vi mc nc chun. Chu k lp - nm NNE E SES SW W NW Vn tc gi trung bnh o trong 2 pht100 38.4 46.1 0.0 20.8 2.0 35.7 34.2 33.55036.2 45.0 9.1 19.2 1.4 33.4 32.7 31.82534.2 40.6 7.4 18.2 0.4 31.5 30.4 29.21030.6 37.5 6.3 16.8 9.2 28.2 27.5 26.55 28.5 34.6 5.2 15.5 8.4 26.2 25.2 21.31 23.0 26.0 2.0 12.7 6.0 21.0 20.0 18.0 Chu k lp - nm NNE E SES SW W NW Vn tc gi trung bnh o trong 1 pht100 39.7 47.1 1.0 21.4 2.7 36.9 35.3 34.65037.4 46.5 0.1 19.8 22.134.5 33.8 32.8NHM 14 5. B MN CTB-BCGVHD: TH.S- BI TH ANH25 35.3 41.928.3 18.8 21.132.5 31.4 30.210 31.6 38.727.2 17.4 19.829.1 28.4 27.4529.4 35.726.0 16.0 19.027.1 26.0 22.0123.8 26.922.7 13.1 16.521.7 20.7 18.6Chu k lp - nmNNEE SESSWW NW Vn tc gi trung bnh o trong 3 giy10044.7 58.14.924.2 5.6 41.6 39.8 39.050 42.1 52.433.9 22.3 24.938.9 38.1 37.025 39.8 47.331.9 21.2 23.736.7 35.4 34.010 35.6 43.730.6 19.6 22.432.8 32.0 30.8533.2 40.329.3 18.0 21.430.5 29.3 24.8126.8 30.325.6 14.8 18.624.4 23.3 21.0 7. S liu v a cht cng trnh.Tn lp t Lp t Lp t Lp tCc thng s s 1 s 2s 31M t lp St pha, St muStttrngxm pha,thivng,trngcngtrng thithi doNHM 1 5 6. B MN CTB-BC GVHD: TH.S- BI TH ANH cngcng su y lp t 2(tnh t y bin tr 720 V hnxung), m 3 m W, %28,129,1 32,2 4 Khi l-ng th tch1.931.91 1.91 3t nhinw, g/cm 5 Khi l-ng th tch1.511.48 1.44 kh c, g/cm3 6 Khi l-ng rings, 2.712.70 2.71g/cm3 7 l rng n, %44.345.2 46.9 8 H s rng t nhin0.795 0.824 0.882eo 9 bo ha G, %95.895.4 98.9 10Gii hn chy WL, %46.846.9 42.8 11Gii hn chy WP, %30.829.2 28.4 12 Ch s do Ip, %16.017.7 14.4 13 st Is -0.17 -0.010.26 14Lc dnh kt C,0.360.47 0.42kG/cm2 15 Gc ma st150021304514035 16H s nn ln a1-2,0.022 0.024 0.023 cm2/kGNHM 1 6 7. B MN CTB-BCGVHD: TH.S- BI TH ANH 17Mun tng bin dng 202.4175.6152.2Eo, kG/cm2III. IM CNG TRNH. C1. su nc v nc dng. su nc ti v tr xy dng cng trnh: do = 21m - Nc dng do triu ln nht : d1 = 1.5m - Nc dng tng ng vi bo thit k : d2 = 1m Mc nc tnh ton : d = do d1 d 2 = 21 + 1.5 + 1 = 23.5 (m).H s iu chnh chiu cao sng : = 0.42. Hng t cng trnh.Cng trnh dng tr ng vi hnh dng tr v mng l dng trn. Dovy vic la chn hng t cnh trnh ch yu ph thuc vo hnh dng ca ktcu thng tng gim thiu tc ng ca mi trng. Tuy nhin ti trng mitrng tc dng ln thng tng ch l ti trng gi m ch chim khong 10 -15% tng ti trng tc dng ln cng trnh. Chnh v nhng l do ny m vic lachn hng t cng trnh bin b tng trng lc nh th no cng khng ququan trng min sao cho vic thi cng thng tng cng d dng cng tt.3. M t kin trc cng trnh. Kin trc cng trnh gm 5 phn chnh:Th-ng tng;Kt cu thng tng ; Tr ; mng; Chn khay.Th-ng tng bao gm :- Khi nh : Gm nh cho 12 ng-i, cha cc thit bo kh t-ng hi vn. Dng nh hnh bt gic, trn mil v-n kh t-ng c t cc dng c o.NHM 1 7 8. B MN CTB-BC GVHD: TH.S- BI TH ANH- Sn chu lc: kt cu nh v trong lng lm bn-c n 50m3.- Sn cng tc: nh v sinh, kho cha, gi v xung,b cha du, cu thang di dng.Tr bao gm:- Tr lm bng BTCT hoc BTCTST tit din vnh khuyn.- Dm th-ng tng. mng bao gm:- mng l khi BTCT hoc BTCTST rng vi mt bngtrn hay vung.- H thng chn khay chy vng quanh mng.- Pha trong mng c cc h dm s-n BTCT hoc vchcng vi bn y, bn np, bn thnh chia thnh cckhoang rng. ( Vi n ny, cng trnh coi nh-khng c thitb cp tu.) 4. Trng lng phn thng tng v cc thit b. - Khi nh = 70T, hot ti = 2T, d tr l-ng thcthc phm = 8T, n-c ngt = 50T.- H thng dm thp chu lc sn chu lc = 38T.NHM 1 8 9. B MN CTB-BC GVHD: TH.S- BI TH ANH- Sn cng tc: nh v sinh = 0,75T, kho = 1,45T, bcha du = 2,5T, trng l-ng bn thn sn cng tc =11T.5. c trng c hc ca vt liu. * Thp c-ng cao c cc c tr-ng c l:- Khi l-ng ring t = 7850 kG/m3- C-ng tiu chun Rc = 17.000 kG/cm2- C-ng tnh ton R = 11.000 kG/cm2- M un n hi E = 2.000.000 kG/cm2* Thp th-ng nhm CI, CII, CIII...* B tng:- Vi cu kin BTCT th-ng: BT mc #400- Vi cu kin BTCTST: BT mc #500IV.PH NG N THI CNG DKIN.1. Bc 1: ch to trn b trong kh.Ton b phn mng BTCT v mt phn ca tr BTCT c ch to trong kh. Sau khi ch to xong, tho nc vo phn KC ch to ny t nic v ko ra khu nc gn b thi cng tip bc hai.2. Bc 2: Ghp phao ph vo cng trnh (gn b). Ti v tr gn b, tin hnh gn cc phao ph bng thp vo Khi chn chto t bc 1 tng tnh ni v n nh ca h Khi chn - phao ph.3. Bc 3: Ch to v lp dng hon chnh ( gn b). Tip tc ch to nt phn tr BTCT cn li, ng thi lp khi thng tng vo khi chn . H khi chn v phao ph phi m bo tnh ni v tnhNHM 1 9 10. B MN CTB-BC GVHD: TH.S- BI TH ANH n nh cho ton b h thng cng trnh sau khi ch to v lp dng bc 3 ny.4. Bc 4: Lai dt ra v tr xy dng ngoi khi. Dng cc tu ko, lai dt h khi chn - phao ph - thng tng ra ngoi khi ( ni v tr s c nh cng trnh).5. Bc 5: San dn nn v bm nc nh chm cng trnh. Ti v tr c nh cng trnh, tin hnh cng tc san dn nn t, sau bm nc vo khi chn cng trnh t t h xung. ch phao ph lc ny vn ni trn mt nc v c tc dng nh v cng trnh, dn hng cho cng trnh t t h xung y bin.6. Bc 6: Hon chnh cc hng mc khc. Sau khi cng trnh h xung, tin hnh cc cng tc khc nhau nh : bm pht va b tng vo khe gia y mng v nn t, dn vt liu vo khi chn (nu cn), tho d phao ph ra khi cng trnh, hon tt cc vic ph khc.V. GI PHP KT C IU. 1. Gii php kt cu dm thng tng. - Kt cu thng tng c dng sn phng c cu to bng thp hnh, thpng hoc BTCT. - V cng trnh lm bng BTCT nn chn lun cu to ca kt cu thngtng lm bng BTCT ton khi. Vi tr c cc dng sau (Hnh v):3 1 2 123NHM 1 10 11. B MN CTB-BC GVHD: TH.S- BI TH ANH1. Dm thng tng2. Thnh tr 3. Giao gia cc dm 2. Gii php kt cu tr . Vi kt cu thng tng nh u bi cho th ch c mt tr . - Tr c tit din hnh vnh khuyn. i vi tc dng ca mi trngbin th y l tit din c li nht v kh nng chu lc, tc dng ca ti trng lnmi pha ca kt cu l nh nhau. Mt khc ta c li dng khong rng bn trongca tr t cc thit b khoan, ng khoan, lm cu thang ln xung v phcv cc hot ng cng ngh khc.- Trong tr c cc bn vch cch nhau mt khong h(m), to cng vn nh cho vch.- Kch thc mt ct ngang v chiu dy ca tr c th thay i.- Vic thay i tit din ko theo s phc tp trong thi cng. M su ncti v tr t cng trnh l 21 m, khng qu ln. Do vy ta chn tit din tr khngi trn sut chiu di. 3. Gii php kt cu mng. Vic chn kch thc mng ph thuc phn ln vo phng php thi cngv cc iu kin v n nh v kh nng t ni, iu kin bn v bin dng caNHM 1 11 12. B MN CTB-BC GVHD: TH.S- BI TH ANHmng. mng hnh trn, c th l hnh vung, ch nht, hnh vm hoc cth l tp hp ca cc xi l.Ni dung th 1: Xy dng ph-ng n 1. Xy dng phng n kin trc.1.1. Xc nh chiu cao KC.Chiu cao KC c xc nh theo cng thc: Hc = do+d1+d2+..Hmax+oTrong : Hc: Chiu cao KC (tnh t mt y bin n mp di ca kt cu thng tng) do: su nc ti v tr xy dng d1: bin triu d2: bin nc dng do bo : h s iu chnh chiu cao sng : h s (0.5-0.7) ph thuc l thuyt sng tnh ton o: tnh khng (o 1.5 m) - Xc nh L thuyt sng vi : d = MNTT = 23.5 (m) ;H = 0,4.16,1=6.44(m) ; T= 14.3s.*Xc nh chu k biu kin Tapp : do d/gT2 = 0.012 > 0.01 nn tra bngtheo API, vi V1/gT = 1.31/(9.81x14.3) =0.0093.Trong : V1 : vn tc mt ln nht ng vi hng sng ch o NE.Tra bng ta c : Tapp/T = 1.1 => Tapp = 15.158 (s). H6.443Tra bng vi : 2.86 x10gTapp 2 9.81x15.1582NHM 112 13. B MN CTB-BCGVHD: TH.S- BI TH ANH d23.5 0.01 gTapp 29.81x15.1582 Thuc L thuyt sng Stokes bc 5.Khi : = 0.7Vi cc d liu cho thay vo cng thc ta c:Hc = 21+1.5+1+0.4x0.7x16.4+1.5 = 30.388 (m) Chn chiu cao KC l Hc = 30.5 (m). 1.2. La chn s b cc kch thc KC.* S b la chn cc kch th-c ca cc b phn trong mng da vo ti liu b tng ct thp: 11 + Kch th-c dm ph :hdm ph= ( ) .lnhp1220+ Kchth-cdmchnh :hdm chnh=1 1() .lnhp8 12+ B rng dm chn trong khong b=(0,30,5).hdm 1 hbldm35+Chiu dy bn : hb 250a) Tr v kt cu thng tng.+ Tr :- Tit din tr l hnh vnh khuyn, ng knh tr s b chn l6m.NHM 1 13 14. B MN CTB-BCGVHD: TH.S- BI TH ANH - Chiu dy thnh tr s b chn l 0.5m v khng thay i trn sutchiu di, do su nc khng ln (d = 23.5m), nn p lc thy tnh cng khngln. - Bn trong tr c cc bn vch cng, s b chn chiu dy bn vchl 0.4m > 0.25m, do cc vch ny bn trong tr , khng tip xc vi mitrng xm thc nn lp bo v nh hn lp bo v thnh tr . Khong cchgia cc bn vch i vi tng phng n c chn s b v c th hin trnhnh v (trong phn sau), v nm trong khong t 57m. + Kt cu thng tng:- Kt cu thng tng gm 4 dm giao nhau. S b chn chiu dica dm l 12m, do chiu rng thng tng rng 12m. V ng knh ca tr l6m nn phn tha ca dm c coi l cng xn c chiu di l 3m, t s bchn kch thc dm l 0.5x1m, do chiu cao dm bng 1/3 chiu di on cngxn, chiu cao dm s c gim dn, n mp ngoi ta chn chiu cao dm l0.6m > 0.15m, sao cho dc t 1/6 1/3. Mc ch gim l do mmen gim. - Cc kch thc ca dm thng tng th hin trn hnh v sau: 500 31 2600 10001 20003000236000 050 12000 1. Dm thng tng 2. Thnh tr 3. Giao gia cc dmNHM 114 15. B MN CTB-BC GVHD: TH.S- BI TH ANH b) Kt cu mng. Kch thc mng tha mn cc iu kin:- iu kin v thi cng ( l kh nng t ni ca cng trnh tronggiai on u khi thi cng xong t tr u tin) T < H - iu kin v n nh.ho > 0Trong : T: l mn nc ca cng trnh. H : Chiu cao ca . ho : chiu cao n nh ban u ca cng trnh. Trong cc loi hnh dng ca mng th kt cu mng dng hnhtrn l ti u. Bi v: kt cu hnh trn chu lc t mi pha l nh nhau. mngchu p lc thy tnh t mi pha, trnh cho cc bn thnh b chu un ta sdng kt cu hnh trn. S b la chn cu to mng nh sau:- ng knh mng: 20m < do = 21m.- Kt cu dm tr (dm chnh): gm 8 dm tr xuyn tm, loidm tr 2 nhnh. Kch thc ca dm tr cho tng phng n c m tsau.- H dm ph theo phng vng, s b chn kch thc l 0.4x1 m.- Chiu dy ca bn y, bn np, bn thnh chn l 0.4 m.- Chiu cao tr v cc kch thc khc th hin trong hnh v ca tngphng n.- S b chn chiu su ca chn khay l 0.5 m.NHM 1 15 16. B MN CTB-BC GVHD: TH.S- BI TH ANH 1.3. Cc phng n a ra ; vi trng lng ring ca b tng : bt = 2.5T/m3 a) Phng n 1: Tr c tit din khng i, mng dng tr trn c bn np phng. Hnh dng v cc kch thc chn s b th hin nh trn hnh v: Bng tnh cc thng s ca phng n 1:TrngSTTTn cu kin Cao trnhD,l ( m) b,t ( m) h (m) V (m3)lng(T) 1Tr di 0 6.5 6.000.86.584.95 212.37 2Tr trn 6.5 30.56.000.5024207.35 518.36 3 Vch 1 6.1 6.55.00 0.40 7.6 19 4 Vch 212.1 12.5 5.00 0.40 7.6 19 5 Vch 318.1 -18.55.00 0.40 7.6 19 6 Vch 424.1 24.5 5.00 0.40 7.6 19 7KC thng tng29.5 30.5 12.00 0.50 1.00 24.0060.00Tng 866.73 NHM 116 17. B MN CTB-BCGVHD: TH.S- BI TH ANH 5000800 800x800 1 1 60006000 600030500M CT 1-1T400 6000 4001000 2 26500 400 1000 400800 40000 104 00500 60001200020000M CT 2-2TNHM 1 17 18. B MN CTB-BCGVHD: TH.S- BI TH ANH Chn s b kch thc mng S Trng Cu kinD, l (m)h (m) b V (m3) lnglng(T)Bn y 19.20.4 1115.81 289.53 yDm vng bn y 1210.4 114.5836.44Dm ph hng tm 3 0.6 0.4 8 5.7614.40 Bn thnh 20 6.5 0.4 1 160400ThnhDm vng bn thnh 2010.4 114.55 36.4Bn np20 0.4 1125.66 314.16 NpDm vng bn np 1210.4 114.5836.44Dm ph hng tm 3 0.6 0.4 8 5.7614.40 Nhnh np710.5 828 70 Dm Nhnh y7 1.5 0.5 842105tr Sn thnh 4.510.5 818 45Chn Vng ngoi20 0.5 0.4 112.3230.79 khay Tr trong 6 0.5 0.8 1 6.5316.33Ct Ct chng dm vng trong4.5 0.4 0.4 8 5.76 14.4chng Ct chng dm vng thnh2.05 10.41613.12 32.8Tng1456Tng khi lng cng trnh trong phng n 1 l: 2322.7 T.b) Phng n 2: Tr c tit din khng i, mng c dng np mi trn xoay.Bng tnh cc thng s ca phng n 2:STTTn cu kinCao trnhD,l ( m) b,t ( m)h (m)V (m3) Trng lng,T 1 Tr di 0 9.5 60.8009.5 124.2310.4 2 Tr trn9.5 30.5 60.50021274.5686.12 3Vch 1 4.55 4.95 4.40.45.83 14.6 4Vch 216.1 16.5 5 0.45.83 14.6 5Vch 3 23.1 - 23.55 0.45.83 14.6 6Vch 429.1 -29.55 0.45.83 14.6Kt cu 729.5 30.5120.500 124 60 thng tng Tng 1114.92NHM 1 18 19. B MN CTB-BCGVHD: TH.S- BI TH ANH6000 11 400 800x8007000 500800 600030500M CT 1-1T7000 1200 0 2 1240 23500 00 400600012001000 800 400 00 104 00500 60001200020000 M CT 2-2 TNHM 1 19 20. B MN CTB-BC GVHD: TH.S- BI TH ANHChn s b kch thc mng Cu kin D, l (m) h (m) b S lng V (m3) Trng lng,T Bn y19.2 0.41 115.81 289.53 Dm vng bn y 12 10.41 14.58 36.44 y Dm ph hng 30.60.485.76 14.40 tm Bn thnh 20 60.41 123.15 307.88Thnh Dm vng nh 20 10.41 14.02 35.06bn thnh Np Bn np trn xoay22.73.50.41 161.88 404.71 Nhnh np8.851.20.58 42.48106.20 Dm Nhnh y7.5 1.50.58 45 112.50tr Sn thnh61.20.58 24 60ChnVng ngoi 20 0.50.41 12.32 30.79 khay Tr trong60.50.815.28 13.19 Tng1334.37 Tng khi lng cng trnh trong phng n 2 l: 2449.29 TCng thc tnh th tch hnh cu :V= 4r3/3 vi r l bn knh.Khi tnh khi lng bn np trn xoay, ta coi bn np l mt hnh cu ri tnhth tch ca hnh cu, n l hiu s ca 2 hnh cu (bn trong v bn ngoi, c hius ng knh bng b dy ca bn np). c) Phng n 3: Tr c tit din khng i, mng c np dc u.NHM 1 20 21. B MN CTB-BCGVHD: TH.S- BI TH ANH 600011400 7000800x800500 800600030500M CT 1-1T 70001200 2 23500 00 40 12 0 40060001200 100080040000 010 40 50 06000 12000 20000M CT 2-2TNHM 1 21 22. B MN CTB-BC GVHD: TH.S- BI TH ANHBng tnh cc thng s ca phng n 3:STTTn cu kin Cao trnh D,l ( m) b,t ( m) h (m) V (m3) Trng lng,T 1 Tr di 0 9.560.8009.5 124.2310.4 2 Tr trn9.5 30.560.50021181.4453.6 3Vch 1 4.55 4.954.40.4 5.83 14.6 4Vch 216.1 16.55 0.4 5.83 14.6 5Vch 323.1 - 23.55 0.4 5.83 14.6 6Vch 429.1 -29.5 5 0.4 5.83 14.6Kt cu 7 29.5 30.5120.500 1 2460 thng tng Tng 882.4 Chn s b kch thc mngS Trng lng Cu kin D, l (m) h (m)b V (m3)lng(T) Bn y19.2 0.4 1115.81 289.53Dm vng bny121 0.4114.5836.44 y Dm ph hng3 0.60.585.76 14.40 tm Bn thnh 206 0.41 147.78369.45ThnhDm vng nh 201 0.4123.8759.67bn thnhNpBn np dc u 20 3.50.41243.2 608 Nhnh np7.831.20.5837.5893.96 Dm Nhnh y7 1.50.58 42 105tr Sn thnh 6 1.20.58 24 60Chn Vng ngoi20 0.50.4112.3230.79khayTr trong 6 0.50.815.28 13.19 Tng1680.43Tng khi lng cng trnh trong phng n 2 l: 2562.83 TNHM 122 23. B MN CTB-BCGVHD: TH.S- BI TH ANHKhi tnh khi lng bn np dc u ta coi bn np dc u l hnh chp ct,n l hiu s th tch ca 2 hnh nn. Ta c th tch ca hnh nn ct: V = .H(R2+Rr+r2)/3 vi R l bn knh ln v r l bn knh nh, H lchiu cao.1.4. Kim tra tnh hp l ca cc kch thc chn. Tr phi tha mn cc iu kin sau:- iu kin v mnh: = 70( Theo TCVN 5574: 91)- T s: 17.7( S tay thc hnh kt cu cng trnh )Vi:ltr :chiu di tnh ton ca tr vi s tnh coi tr nh mt thanhcng xn c ngm ti mt mng, ta c: lo = 2xltr , theo s tay thc hnh kt cu.( Vi: lo l chiu di quy i ca thanh khi tnh n nh =2 : H s nh hng lin kt (ngm cng xn) ) r: bn knh qun tnh ca tit din r= J: M men qun tnh ca tit din J= x( -) A: Din tch tit din.NHM 1 23 24. B MN CTB-BC GVHD: TH.S- BI TH ANH A= x(-) ; D1 = Do-2t , vi t : b dy tr . Vi Do l ng knh ngoi ca tr. Ta c bng kim tra mnh ca tr :ltr,mlo,m D,mt,mA,m2 J,m4 R,mlo/rlo/DPhng n 1 24 48 6 0.5 8.6394 32.938 1.9526 24.583 8Phng n 2 21 42 6 0.5 8.6394 32.938 1.9526 21.517Phng n 3 21 42 6 0.5 8.6394 32.938 1.9526 21.517Kt lun: Kch thc tr ca cc phng n chn u tha mn iu kin. 2. Phn tch la chn phng n. Gii php kt cu phng n 1 vi khi chn tr trn cho kt cu b tng chu lc, chu lc tt khi p lc thy tnh tc dng ln cng trnh trong qu trnh thi cng. Vi hnh dng ny khi chn lm vic theo mi phng l nh nhau, ti trng lm vic theo mi phng l nh nhau.- Chiu cao khi l 6.5m nn c th thi cng trong kh. Do np phng nnd thi cng hn, thun tin khi kt hp vi phao ph (nu c). Tuy nhin do cs thay i t ngt v tit din nn khi thi cng trong giai on sau s c sthay i t ngt v mn nc, cn c bin php x l.- Bn np l mt phng, khi ti trng tc dng thng gc nn trong bn ch xuthin m men un, xon v lc ct. Phng n ny ph hp vi su nckhng ln, c p lc thy tnh nh.- phn mng c ct chng p lc thy tnh. Trng lng bn thn ca phng n ny : G = 2322.7T. Gii php kt cu phng n 2 vi phn c cu to vm, y l kt cu chu lc tt. cn phn tr th vn ging phng n 1 nhng cc vch ngn t i.- phn mng khng c ct , chiu cao dm chnh cao hn phng n 1.NHM 124 25. B MN CTB-BC GVHD: TH.S- BI TH ANH- Chiu cao khi l 9.5m nn c th thi cng trong kh. Np l dng trnxoay nn thi cng kh khn nht trong 3 phng n, tuy nhin do khng c sthay i tit din t ngt nn khi thi cng giai on sau khng c s thay imn nc t ngt, khng gy nguy him.- Np l loi v mng nn m men ch xut hin khu vc gn gi ta. khuvc xa gi ta ch xu hin lc dc (phn ln l lc nn), do vy cho php sdng ht kh nng chu nn ca b tng. Kh nng chu p lc thy tnh tt dolc nn chuyn mt phn thnh lc x ngang, ph hp vi su nc ln.Trng lng bn thn ca phng n ny : G = 2449.29T.Gii php kt cu phng n 3 vi phn c dng mi dc, y l loi c kh nng chu lc tng i tt, nhng khng pht huy c kh nngchu nn ca b tng.- phn mng th khng c ct chng, chiu cao dm chnh dy hn phngn 1.- phn tr th b tr t vch ngn hn do chiu cao ln.- Chiu cao khi l 9.5m nn c th thi cng trong kh. Np l dc u nnthi cng kh khn, tuy nhin do khng c s thay i tit din t ngt nn khithi cng giai on sau khng c s thay i mn nc t ngt, khng gynguy him.- Bn np dc u nn khi chu p lc thy tnh, mt phn chuyn thnh lcngang, do vy kh nng chu p lc tnh tt hn phng n np phng, ph hpvi su nc trung bnh.Trng lng bn thn ca phng n ny: G = 2562.83T.*Do vy cn c vo cc phn tch trn ta quyt nh la chn phng n 3 tnh ton, thit k v thi cng cng trnh.3. Kim tra cc kch thc kt cu mng ca phng n chn. *Kim tra n nh ni:- Vi cc kch thc s b nh chn trn, trng lng ca tng cukin c thng k trong bng sau: Vi ta Zi c ly so vi gc ta c chn l tm ca tr, nm trnmt y bin.NHM 125 26. B MN CTB-BCGVHD: TH.S- BI TH ANH Cu kinGi(T) ZiG(m)MiZG,Tm Bn y289.53 0.257.906y Dm vng bn y 36.44 0.2 7.288Dm ph hng tm14.40.22.88Bn thnh 369.4531108.35 ThnhDm vng nh bn thnh59.67 5.8 346.086NpBn np dc u6088.35046.4Nhnh np93.967.75728.19DmNhnh y 105 0.25 26.25 tr Sn thnh603 180 Chn Vng ngoi 30.79-0.25 -7.6975khay Tr trong 13.19-0.25 -3.2975 Tng 1680.437492.355 Khi vt th trong mi trng nc n chu mt lc y ni, vt cn bng vilc y ni khi trng lng ca n bng lc y ni. FN = GKC = 1680.43T.Th tch nc m khi chn chon ch, vi trng lng ring nc binnb=1.025T/m3 : GKCD V= 1639.44(m3).nbDo mng chn c phn chn khay cao 0.5(m), cho nn phn th tch mng v tr khng tnh phn chn khay v c cc phn cu kin tnh t mpy bn y tr xung l:Vv= V - V1- V2- V3Xc nh th tch chon nc phn pha di bn y:+/ Vng ngoi chn khay: Pck=30.79T => V1 = 30.04m3NHM 1 26 27. B MN CTB-BC GVHD: TH.S- BI TH ANH+/ Tr trong chn khay : Ptt = 13.19T => V2 = 12.87m3+/ Dm chnh di bn y: Pdc = 35T => V3 =34.15m3 Vy c : Vv = 1562.38m3 T y xc nh c mn nc ca phn kt cu khi tho nc vo khcch y chn khay mt on: Vv1562.38T = 0.5+ 0.5 5.473m Sde202 4 Vy T = 5.473 < 0.5 + 6 =6.5m => tha mn iu kin ni.*iu kin n nh tnh: Chiu cao n nh ban u c xc nh theo cng thc sau:ho = r - ZG + ZC Trong : ZG : Ta trng tm ca vt ni. ZC : Ta ph tm ca phn ngp nc.ICn r c xc nh: rV Trong : I : Mmen qun tnh mt ng nc.V : Th tch vt chim ch. Lng nc chon ch nh tnh trn l: V = 1639.44(m3).NHM 127 28. B MN CTB-BC GVHD: TH.S- BI TH ANH Mmen qun tnh ng mt nc : I=D4 =204 7853.9m46464 IT , ta c :r=4.8m V+/ Xc nh tm ni : Ta tm ni c tnh theo cng thc sau: M xyZC = VTrong mmen tnh th tch i vi trc ta OXY l :2 Sck hck Sde (T hck ) 2 M xy2Din tch chn khay : Sck = D 2 ( D 2t )2 24.63m24Din tch phn :S =202314.2m24Chiu cao chn khay : hck = 0.5mVy : M xy = 3888.3m4 => ZC = 2.37m Gi .Zi7492.355 ZG = 4.458mGi 1680.43T y tnh c :ho = 4.8-4.458+2.37 =2.71m > 0 => tha mn iu kin nnh tnh. Kt lun : Cc kch thc kt cu cng trnh chn l tng i hp l.NHM 128 29. B MN CTB-BCGVHD: TH.S- BI TH ANHNi dung th 2: Tnh ton ti trng1. Cc loi ti trng tc dng ln cng trnh. * Ti trng th-ng xuyn bao gmTi trng bn thn ca cng trnh.Trng l-ng trang thit b c nh.Trng l-ng dn.p lc thu tnh ca n-c .* Ti trng tm thi bao gm Trang thit b c th thay i hay di chuyn. Vt t- khc (n-c ngt, du...). * Ti trng do s c - Ti trng va chm do tu cp vo cng trnh -Mt s chi tit b hng do nguyn nhn khc nhau. * Ti trng ng t.* Ti trng mi tr-ng bao gm.- Cc ti trng sng, gi, dng chytc dng ln cng trnh. * T hp ti trng :Trong n ny ch yu nghin cu quy trinh tinh toncng trnh trong trng thi s dng chu tc ng catrng thi cc hn. Do ta ch xt mt t hp titrng, h s t hp -c ly nh- sau : Ti trng th-ng xuyn ly h s l 1. Ti trng mi tr-ng ly h s l 0,9.2. Ti trng bn thn khi chn .Trng lng KC v kt cu thng tng l 2562.83T Trng lng thng tng v cc thit b ph tr l 183.7TNHM 1 29 30. B MN CTB-BCGVHD: TH.S- BI TH ANH3. Ti trng h bm. Vi trng lng ring h bm l : hb = 1.6T/m3BNG TNH H BM Phn tr STT D,m D,m H,m V1,m3V2,m3Vtr,m316.08 64116.1334 113.0973 3.03603526.08764116.4009 113.0973 3.3036013 6.1 6258.44933 56.54867 1.90066446.07 61.543.41 42.41 1520.07 206 1898.21884.9613.24 Tng th tch phn tr trn22.4803 Phn mi dc STT r1,m r2,m R1,m R2,m H,m Vmd,m363 3.035 1010.0353.55.02Th tch tng thV=Vtr+Vmd 27.5 Khi lng h bmFHB,T 44Vy, tng ti trng do h bm : FHB = 44T4. Ti trng gi (tnh tnh).Ti trng gi -c tnh ton theo tiu chun APIvi h-ng gi t-ng ng vi h-ng sng chn (NE). Tnh ti trng do gi tc dng ln phn cng trnhnm pha trn mc n-c tnh(SWL). Bn cht ca titrng gi l ng, nh-ng qua thc nghim cho thy rngNHM 1 30 31. B MN CTB-BC GVHD: TH.S- BI TH ANHti trng gi ch chim khong 10% tng ti trng mitr-ng tc dng ln cng trnh nn y ta coi trongtnh ton ti trng gi l tnh.Cng thc xc nh ti trng gi theo API: 2 F 0.0473.Vz .Cs .A. Trong :F: l lc gi tc dng ln kt cu (N).Vz: Vn tc gi trung bnh ti cao z so vi mc nc chun(km/h). 1 Z n VzV 10 ..10 A: Hnh chiu din tch ca vt cn lnph-ng vung gc h-ng gi (m2).Cs : H s kh ng (xc nh theo quiphm). Loi kt cuCs Kt cu dm, nh t-ng1,5 c Kt cu tr trn0.5 Sn cng tc1.0Ti trng gi phn thng tng tnh theo mc nc tnh SWL, tnh vi gihng NE, chu k lp 100 nm, o trong 3 giy. V 10 = 57.4m/s = 207km/h.Ta chia phn thng tng lm 4 khi Block tnh ti trng gi, bao gm:NHM 131 32. B MN CTB-BC GVHD: TH.S- BI TH ANH - Block sn kh tng, Cs = 1.5 - Block khi nh , Cs = 1 - Kt cu thng tng, Cs =1.5 - Phn tr khng ngp nc, Cs =0.5 Cc lc gi tc ng c quy v tng im nh hnh v sau: F4 F3 F2 d m t h n g t n g t r F1 s WL Kt qu tnh ton ti trng gi tc dng ln cc block: TNH TON TI TRNG GILoi Kt CuZi,m B,m L,m A,m2VzCsF(T)NHM 132 33. B MN CTB-BC GVHD: TH.S- BI TH ANHTr (F1) 4.25 68.551186 0.54.1729Kt cu thng tng (F2)9 112 12 204.29 1.53.5533Nh (F3)12.5 612 72 212.861 15.43Sn kh tng (F4) 16.25 1.512 18 219.95 1.56.1784Tng lc gi (T)29.3355. Ti trng sng v dng chy tc dng ln KC. Xc nh l thuyt sng tnh ton:Theo phn trn ta c sng lan truyn cng trnh l sng Stock bc 5, nn tachn l thuyt sng Stock bc 5 tnh ton. Tnh ton vi sng theo hng NE chu k lp 100 nm.L thuyt sng Stock bc 5.a) Chn h trc ta .-Trc 0z thng ng v trng vi trc ca khi chn .-Trc 0x nm ngang, trng vi phng gi thi v chuyn ng sng dng chy.-Trc 0y nm ngang, vung gc vi trc 0x.-Gc ta 0 ti mt y bin.b) Cc thnh phn vn tc, gia tc.* Theo l thuyt sng Stokes bc 5, khi sng c chiucao H, s sng k v tn s vng lan truyn theo chiud-ng ca trc x, th dng ca b mt cht lng sovi mt n-c tnh c th biu din d-i dng :NHM 133 34. B MN CTB-BC GVHD: TH.S- BI TH ANH51Fn cos n kx tk n 1Trong : F1 = a ;F2 = a2.F22 + a4.F24;F3 = a3.F33 + a5.F35 ; F4 = a4.F44;F5 = a5.F55 . * Cc thng s hnh dng ca sng F22, F24 ... ( phthuc vo kd = 2 d/L ; -c xc nh theo bng tra ),v thng s chiu cao sng H quan h vi nhau bi biuthc :k.H 2. a a 3 .F33a 5 . F35 F55 * Thnh phn vn tc theo ph-ng ngang Vx v ph-ngng Vz ca phn t cht lng c ta ( x,z ) gy nnbi s la truyn sng b mt trong vng c su d, cth nhn -c t biu thc :5 chnkzVx Gncos n kxtk n 1shnkd5 shnkz Vz Gn cos n kxtk n 1shnkdTrong :G1 = aG11 + a3G13 + a5G15 ;G2 =2( a2G22+a4G24 ) ;G3=3(a3G33+ a5G35 ); G4 =4a4G44 ;G4 =5 a5G55. y G11 , G13 ... l cc thng s sng ph thuc vok.d ( tra bng ).NHM 134 35. B MN CTB-BCGVHD: TH.S- BI TH ANH* Cc thnh phn gia tc theo phng ngang v phng ng ti im c ta (x,z) trong vng nc c su nc d c xc nh nh sau:kc 2 5ax R n sin n kxt 2 n 1 kc 25 az S n cos n kx t2 n 1Trong :R1 = 2U1- U1U2 - U2U3 - V1V2 - V2V3 ;R2 = 4U2 U12 + V12 2U1U3 -2V1V3 ;R3 = 6U3 3U1U2 + 3V1V2 3U1U4 - 3V1V4;R4 = 8U4 2U22 + 2V22 4U1U3 + 4V1V3;R5 =10U4 5U1U4 5U2U3 + 5V1V4 + 5V2V3;S1 = 2V1 - 3U1V2 - 3U2V1 5U1V3 5U3V2 ;S2 = 4V2 - 4U1V3 - 4U3V1 ;S3 = 6V3 - U1V2 + U2V1 5U1V4 5U4V1 ;S4 = 8V4 - 2U1V3 + 2U3V1 + 4U2V2 ;S5 = 10V5 - 3U1V4 +3U4V1 - U2V3 + U3V2 ; Cc gi tr Un (n=1..5) v Vn (n=1..5) tnh theo biu thc:ch(nkz ) Un Gn .sh(nkd ) sh(nkz ) Vn Gn . sh(nkd )* Quan h gia tn s vng v tn s sng c dng : 2 gk 1 a 2 C1 a 4 C 2 .thkd* Vn tc truyn sng c:NHM 1 35 36. B MN CTB-BCGVHD: TH.S- BI TH ANH1/ 2g c1 a 2 C1 a 4 C 2 thkdk Trong : C1, C2 thng s sng, ph thuc vo t s d/L, tra bng.c) Cc c trng ca chuyn ng sng b mt theo hng NE. Cc thng s c trng cho chuyn ng sng l: - su tnh ton: d=23.5m -Chiu cao sng : H=16,4.0.4 = 6.56m -Chu k sng : T=14.3s -Chu k sng c nh hng dng chy : Tapp=15.158s gT 22 -Chiu di sng : L(1 a 2C1 a 4C2 )thd209.423m ( gii bng phng 2Lphp lp).-T s d/L=0.11-Thng s a=0.09-S sng k=0.03d) Xc nh ch sng phn chia. Ta thy vi kch thc ca tr v mng chn ( DT =6m, D=20m), tht s :DT/L = 6/209.423=0.0286 1000T/m2 nn ly chiu su tt ln H khi z bt 5Kt qu tnh ton c lp thnh bng nh sau:NHM 1 57 58. B MN CTB-BCGVHD: TH.S- BI TH ANH im LpZi(m) bt(T/m2) a/b z/bko zi(T/m2) tnh 00 01 01 9 I 14 10.8410.20.96048.6436 27 18.9710.35 0.84577.6109 3 11 29.7 10.55 0.654 5.883 4 15 40.5 10.75 0.48564.3704 II5 19 51.3 10.95 0.36193.2571 6 23 62.1 11.15 0.27492.4737 7 27 72.9 11.35 0.21361.922T bng tnh ta thy chiu su tt ln ti phn t th nht ca lp th II. Ta c : Lp I : St pha, trng thi cng.Lp II : St mu xm vng, trng thi cng.NHM 158 59. B MN CTB-BCGVHD: TH.S- BI TH ANH P =9T/M2 o+0.00 0 9T/M24000 10.84T/M2 8.6436T/M2 1 13500-7.0018.97T/M2 7.6109T/M2 240002 29.7T/M25.8829T/M2 3Tnh ln theo cng thc :S h tb iEo Trong : h s tnh t h s Poisson ca t, c th ly = 0.8btz tb 2hi chiu dy lp t th i. Kt qu tnh ton c trnh by trong bng sau:NHM 1 59 60. B MN CTB-BC GVHD: TH.S- BI TH ANHTng hi (m) Eo(T/m2) z(T/m2) Si(m) 140.8202414.242 0.0225 230.8202423.032 0.0273 340.8175631.082 0.0566Vy ln bng :SSi 0.1064m Khi ta tnh c cng tng cng ca l xo lin kt gia mng vit nn theo cng thc sau :P2790.53 K 26227T / mS0.1064o.. Ta chia mt ct ngang mng thnh 32 nt, v 5 ng trn ng tm, khi ta c bng tnh cng ca cc l xo phn b nh sau:K(T/m)R(m) A(m2) Ai(m2) Ki(T/m)2622710314.2 1.96 163.6126227 8314.2 3.53 294.6626227 6314.2 2.75 229.5526227 4314.2 1.96 163.6126227 2314.2 1.18 98.497Tnh ton p lc thy tnh.NHM 160 61. B MN CTB-BCGVHD: TH.S- BI TH ANHp lc thy tnh trong giai on khai thc gy nn cc b bn thnh v tr.p lc thy tnh phn b theo chiu su nc ln nht ti y bin, ti v tr ybin c gi tr: P = n*dTrong :n =1.025(T/m3) : Trng lng ring ca nc bin 4250 3500 3750 z 3500SWL350035003500 3500 P11750P23000 3000 1750OP3NHM 1 61 62. B MN CTB-BCGVHD: TH.S- BI TH ANHSTTcao trnh Z,m chiu cao,m Loi cu kin ,T/m3p lc,T/m21 023.5 1.025 24.08752 122.5 1.025 23.06253 221.5 1.025 22.03754 320.5 1.025 21.01255 419.5 1.025 19.98756 518.5 1.025 18.96257 617.5 1.025 17.93758 716.5 Np 1.025 16.91259 815.5Np1.025 15.8875 10 914.5 Np 1.025 14.8625 11 9.5 14Np 1.025 14.35 12 10.513 Tr1.02513.325 13 11.512 Tr1.02512.3 14 12.511Tr 1.02511.275 15 13.510Tr 1.025 10.25 16 14.59 Tr 1.025 9.225 17 15.58 Tr 1.0258.2 18 16.57 Tr 1.025 7.175 19 17.56 Tr 1.0256.15 20 18.55 Tr 1.025 5.125 21 19.54 Tr 1.0254.1 22 20.53 Tr 1.025 3.075 23 21.52 Tr 1.0252.05 24 22.51 Tr 1.025 1.025 25 23.50 Tr 1.025 0M hnh ha ti trng thng tng.Mt cch gn ng c th coi ti trng th-ng tngthng qua sn th-ng tng phn b u ln mt tipNHM 1 62 63. B MN CTB-BCGVHD: TH.S- BI TH ANH xc gia kt cu th-ng tng v mt trn ca tr . Khi ti trng nt -c tnh theo cng thc sau: Ggi nTrong : G:tng ti trngth-ng tng,G=183.7+60243.7T gi: ti trng th-ng tng chia v nt th ica l-i phn t hu hn ti mt tip xc gia tr vi kt cu th-ng tng.n: tng s nt trn thnh bin ca tr ti mt tip xc gia tr vi kt cu th-ngtng, y n=32. gi = 7.62T.M hnh ha ti trng gi.Phn tr tit din vnh khuyn khng ngp n-c lmt mt cn gi. Ti trng gi ln phn khng ngp n-cc th -c tnh theo quy phm (TCVN-2737-1995).S tc dng ca ti trng gi ln cng trnh c th hin trong nhng hnhv di y:M hnh ti trng sng.i vi cc tr c kch th-c nh, ti trng sng tc dng ln tr -c xc nh theo cng thc Morisson l lc tp trung t ti trc thanh. Mt cch gn ng c th coi lc ngang do sng tc ng ln tr -c phn b u trn chu vi ca tr .NHM 1 63 64. B MN CTB-BC GVHD: TH.S- BI TH ANHKhi lc ngang ti nt th i -c xc nh nh-sau :Q qin Trong :Q: ti trng ngang ti cao trnh th i -c xc nhtheocng thc Morisson. qi: ti trng ngang chia v nt th i cal-iphnt huhn trn bin ca tr ti caotrnh th in: tng s nt trn thnh bin ca tr ti cao trnh th i Sau y l s tc dng ca cc ti trng ln cng trnh:NHM 164 65. B MN CTB-BCGVHD: TH.S- BI TH ANHHnh 6: Ti trng thng tng.NHM 1 65 66. B MN CTB-BCGVHD: TH.S- BI TH ANHHnh 7: Ti trng gi.NHM 1 66 67. B MN CTB-BC GVHD: TH.S- BI TH ANHHnh 8: Ti trng sng.NHM 167 68. B MN CTB-BC GVHD: TH.S- BI TH ANHHnh 9: M hnh ha khi chn .2. Xc nh ni lc cho cc cu kin tr v mng. Cc bc tnh ton xc nh ni lc:- Bc 1: Nhp s tnh, s dng cc phn t tm, v, thanh v lin kt lxo m hnh ha kt cu.- Bc 2: Nhp ton b ti trng tc dng ln cng trnh.- Bc 3: Tnh ton ng sut ca cc l xo.- Bc 4: Loi b cc l xo c ng sut dng (chu ko). - Bc 5: Tnh ton li, lp li bc 2 v bc 3 cho n khi no khng cnl xo chu ko na th dng.NHM 1 68 69. B MN CTB-BCGVHD: TH.S- BI TH ANH - Bc 6: Xut ni lc v tnh ton cu to cc cu kin.Sau khi chy Sap ta c c kt qu ni lc trong cc kt cu nh sau:Ni lc ca Shell F11 F22 F12 M11M22M12V13 V23Tn cu kin T/m T/m T/m Tm/mTm/m Tm/mT/m T/mMax 00 0 20.63 28.4626.2134.6222.5 Bn yMin 00 0-26.35 -48.26 -16.25 -15.26-19.26 BnMax 50.952.53 48.34 19.243 42.123 5.23 32.5817.8thnh Min -8.23 -6.616 -42.3 -16.25-9.325-4.26 26.34 -26.53Max22.59 26.21 18.24 20.63 26.2129.8234.18 16.78 Bn npMin-18.24 -3.26 -15.24 -17.2-40.5 -24.19 -23.62-17.26VchMax36.921 7.215 13.261 5.263 7.9352.68516.23520.154cngMin-12.26 -4.265 -14.84 -3.692 -8.265 -3.265 -14.26-21.26Max 00 0 28.53 32.8929.5442.1230.2ChnkhayMin00 0-31.59 -38.3 -23.58 -24.18-31.6 ng sut tr trong Cao ,mng sut ko Max,T/m2ng sut nn Max,T/m2 09.5750.3218 -1281.6529.516.5312.4653 -712.2658 16.523.5121.3624 -316.3584 23.530.565.1658 -120.34539NHM 169 70. B MN CTB-BCGVHD: TH.S- BI TH ANH Ni lc FrameTn cu kin P(T) V2(T) V3(T) M2(Tm) M3(Tm) Dm vng Max014.2360 017.895bn y Min0-36.250 0-16.248Dm ph Max016.2650 021.654y hng tm Min 0-17.290 0-28.589 Dm tr Max039.5860 080.542 nhnh y Min 0-41.250 0-72.156 Dm vng Max 56.8214.265 2.165 7.2652.2658nh bn thnhMin 19.695-4.265 -3.158 -9.625 -4.278 Thnh Dm tr Max 60.32115.246 8.26531.2546.921 sn thnh Min -9.623-31.75 -1.258 -18.25 -59.254 Dm tr Max 42.85626.159 8.6144.25449.257Np nhnh np Min -2.356 -5.265 -12.25 -9.952 -57.265 Nhng lin kt chu nh cn c gia c: Lin kt chu ko Nt F1F2F3M1M2 M3 140.10910.1632 3.8227 -0.0660.0442 3E-17 150.07510.1814 3.8227 -0.0730.0304 3E-17 160.16950.4092 23.14 -0.036 0.0149 -7E-16 170.24610.3683 23.14 -0.032 0.0217 1E-16 300.07510.1814 3.8227 -0.0730.0304 -3E-17 310.16950.4092 23.14 -0.036 0.0149 -9E-16 380.07510.1814 5.2289 -0.3980.165 3E-18 390.16950.4092 23.14 -0.036 0.0149 2E-15 460.07510.1814 3.8227 -0.0730.0304 5E-17 470.16950.4092 23.14 -0.036 0.0149 2E-15NHM 1 70 71. B MN CTB-BCGVHD: TH.S- BI TH ANH540.07510.1814 3.8227-0.073 0.0304 -2E-17550.16950.4092 23.14 -0.036 0.01496E-16620.07510.1814 3.8227-0.073 0.0304 -5E-18630.16950.4092 23.14 -0.036 0.0149 -4E-16700.07510.1814 5.2289-0.398 0.165-3E-17710.16950.4092 23.14 -0.036 0.0149 -3E-16780.07510.1814 3.8227-0.073 0.03049E-17790.16950.4092 23.14 -0.036 0.0149 -2E-15860.07510.1814 3.8227-0.073 0.03041E-16870.16950.4092 23.14 -0.036 0.01491E-15940.07510.1814 3.8227-0.073 0.0304 -1E-17950.16950.4092 23.14 -0.036 0.01492E-15102 0.07510.1814 5.2289-0.398 0.165 1E-17103 0.16950.4092 23.14 -0.036 0.01499E-1611125.825.826.2900011225.825.828.1650.4419 -0.4420+/ Bin php: cc lin kt c an ton th ta cn phi loi b cc lin kt kotrn, sau khi b cc lin kt , ti cc lin kt ko ta s khng cho lin kt na.3. Xc nh chuyn v ti nh tr.Cc thnh phn chuyn v ti nh trU1(m)U2(m)U3(m) R1(rad) R2(rad)R3(rad)0.02480.0040241 0.000230.001298 0.001453 0.001118131+/ Nhn xt: chuyn v max=U1=2.48cm ng knh ng ghen tithiu cha c b thp trn l D = 3.36 cm. Tham kho catalog ca Cng ty C phn Vt t Thit b Cng trnh Minh cta chn loi ng ghen c ng knh trong l: d = 60mm, dy l 0.3mm.Sau khi chn ta c bng b tr ct thp nh sau:Z (m)n Fghen (cm2 )As (cm2) s (T/m2) 0 - 9.5 8028.274 709.61400009.5 - 16.5 3228.274 283.84 100000 16.5 - 23.5 1628.274 141.92 100000 23.5 - 30.5828.274 70.96100000NHM 1 75 76. B MN CTB-BC GVHD: TH.S- BI TH ANH ng knh trong30 3540 455055 606570 Dung sai 0.5 dy tiu chun ca 0.25 0.3 thp ng knh trong105110115 120125130 135140150 Dung sai 1.0 dy tiu chun ca 0.3- thp ng knh trong 30 50 5560 Cp 15 1245 - S l tiu chun Cp 13 125- 68 ng knh trong 100105120 130 Cp 151819 -212731 S l tiu chun Cp 132527313437 4344 ng knh trong75 8085 9095100 Dung sai0.5 1.0 dy tiu chun ca thp0.3 ng knh trong160180200 220240280 Dung sai 1.0 dy tiu chun ca thp - ng knh trong708090 Cp 1567 891017 S l tiu chun Cp 13 910141522 ng knh trong140 160 Cp 15 34374355 S l tiu chun Cp 13 5455 -NHM 1 76 77. B MN CTB-BCGVHD: TH.S- BI TH ANH1.3. Xc nh cc hao tn ng sut trc. i vi cc cng trnh bin trng lc b tng, khng dng kt cu b tng lpghp, thng to ng sut trc bng phng php cng sau, cng trn b tng,cc hao tn c tnh nh sau: - Nhm cc hao tn xy ra trong qu trnh ch to: ht1 = neo + ms - Nhm cc hao tn xy ra trong qu trnh khai thc: ht2 = ch + co + fb a) Hao tn do bin dng ca neo t thit b cngneo Ea (T / m2 )L Trong : : tng bin dng ca bn thn neo c xc nh bng thc nghim.Nu khng c s liu thc nghim c th ly = 2 (mm).Ea: mun n hi ca vt liu lm neo, Ea = 2x107 (T/m2), ly bngthp cng cao. L: chiu di b tho c cng (mm). Bng kt qu tnh ton:Z (m)L (mm)neo (T/m2)0 - 9.5 9500 4210.526329.5 - 16.57000 5714.2857116.5 - 23.5 7000 5714.2857123.5 - 30.5 7000 5714.28571 b) Hao tn do ma st ca ct thp 1 ms s 1 kx (T / m2 )e Trong : e c s logarit t nhin. k: h s tra bng, ph thuc vo b mt tip xc, k = 0.003 : h s ma st gia ct thp v thnh ng, = 0.35 (thp si).NHM 1 77 78. B MN CTB-BCGVHD: TH.S- BI TH ANH x: chiu di ct thp t thit b cng n tit din tnh ton. : tng gc quay ca tit din tnh ton, = 0 s: ng sut trong b thp ng sut trc khng k n cc hao tnng sut. Bng kt qu tnh ton: Z (m) sxms 0 - 9.5 140000124950.3589 9.5 - 16.51000005 1488.806 16.5 - 23.5 100000102955.4466 23.5 - 30.5 1000005 1488.806 c) Hao tn do hin tng chng ng sut khi cng c gii s ch(0.22 0.1) s RacTrong : s : ng sut trong b thp ng sut trc (T/m2) Rac: Cng tiu chun ca thp ng sut trc tnh bng (T/m2) Bng kt qu tnh ton: Z (m) s Rac ch 0 - 9.5 140000 186000 9182.7957 9.5 - 16.5100000 186000 1827.957 16.5 - 23.5 100000 186000 1827.957 23.5 - 30.5 100000 186000 1827.957 d) Hao tn do co ngt ca b tngB tng s dng Mc 500 c hao tn do co ngt l co = 3500 T/m2NHM 1 78 79. B MN CTB-BC GVHD: TH.S- BI TH ANH e) Hao tn do t bin ca b tng bbtb 20000 .k .(T/m2) khi 0 .6R0R0b tbn 40000.k .(b 0.3) (T/m2) khi 0 .6R0R0 Trong :- k =1 : h s ng cng t nhin.- Ro: cng khi vung b tng lc bung ct thp,Ro = 2150 T/m2 - b: ng sut nn trong b tng ti mc ct thp cng k n cchao tn trn (h = neo + ms + ch + co ). M .aNs As h As s Ash As bNjA A ABng tnh ton c th:Z (m)n(T/m2)s(T/m2) h(T/m2)As(m2) b(T/m2)tb(T/m2)0 - 9.5 -1281.652 140000 21843.681 0.07096 -2160.4036 28193.55629.5 - 16.5-712.2658 100000 12531.049 0.028384 -712.2830 6625.888116.5 - 23.5 -316.3584 100000 13997.689 0.014192 -317.1109 2949.868823.5 - 30.5-120.34539 100000 12531.049 0.007096 -210.3702 1956.9324 f) Tng hp cc hao tn ng sut trc - Hao tn tng cng trong c 2 giai on: ht = ht1 + ht2 - Gi tr ng sut ko cng khi thi cng l: = s + ht Z (m) s(T/m2)ht1(T/m2) ht2(T/m2)(T/m2) 0 - 9.5140000 9160.885 40876.352190037.237 9.5 - 16.5 100000 7203.092 11953.845119156.937 16.5 - 23.5100000 8669.732 8277.826 116947.558 23.5 - 30.5100000 7203.092 7284.889 114487.981NHM 179 80. B MN CTB-BC GVHD: TH.S- BI TH ANH1.4. Kim tra li cc tr BTCT ng sut trca) Tnh li cc c trng tit dinDin tch tit din tr i phn gim yu t do ng ghen cha thp STchim ch: Fhd = Fbt Fghen Trong : Fbt: din tch mt ct ngang tit din BTCT. Fghen: tng din tch ng ghen trong tit din.Bng tnh ton c th nh sau:Z (m) Fbt(m2) Fghen(m2) Fh(m2)0 - 9.5 13.069 0.22619467 12.8439.5 - 16.5 8.639 0.090477878.54916.5 - 23.58.639 0.045238938.59423.5 - 30.58.639 0.022619478.617b) Kim tra li ng sut nn trong b tng c k n cc hao tn ng sut trctrn tit din gim yuM N ( s h ). As. As b nJ hdFhd FhdFhd iu kin : b < 0.5C ( Tit din chu nn lch tm) C : Cng chu nn ti hn ca B Tng.Kt qu kim tra nh sau:NHM 180 81. B MN CTB-BC GVHD: TH.S- BI TH ANHZ (m)n(T/m2)(T/m2) As(m2) Fhd(m2) b(T/m2) 0,5.Rc Kt lun0 - 9.5 -1281.652 190037.24 0.07096 12.843 -2331.657 1075KTM9.5 - 16.5 -712.266 119156.94 0.028384 8.549 -1107.890 1075KTM16.5 - 23.5-316.358 116947.56 0.014192 8.594-509.481 1075 TM23.5 - 30.5-120.345 114487.98 0.007096 8.617-214.628 1075 TM+/ Nhn xt: Ta thy c 2 on tr khng tha mn, bin php a ra l b trthm thp thng tham gia chu nn cng b tng. Tnh ton c th c trnh by phn sau.c) Kim tra iu kin khng xy ra vt nt xinTa c ng sut tip: QS J 2tTrong :2 3 S: mmen tnhS R1 R323 R1, R2 : bn knh ngoi v trong ca tit din vnh khuynt: dy ca tit din vnh khuynJ: Mmen qun tnh. Q: lc ct ti tit din y = S23ng sut php cc i trn mt ct tr;. AsN Fhdng sut ko chnh:NHM 181 82. B MN CTB-BC GVHD: TH.S- BI TH ANH22 12 2 Kim tra iu kin khng nt( khng xy ra vt nt xin) 10.33 Rn Bng kt qu tnh ton:2 Z (m) (T/m2)(T/m2) 1(T/m2) 0.33 Rn (T/m )Kt lun 0 - 9.5 203.8024673 -2331.66 17.68 15.30 KTM 9.5 - 16.598.96315779 -1107.898.77 15.30 Tha mn 16.5 - 23.5 4.916708614-509.480.05 15.30 Tha mn 23.5 - 30.5 3.624426332-214.630.06 15.30 Tha mn d) Kim tra li ng sut ko trong b tng c k n cc hao tn ng sut trctrn tit din gim yuM .a N S ASh AS AS ( S h ) k k J hd Fhd Fhd Fhd Trong :M: M men ngoi lc tc dng ti titdin N: Lc dc tc dng ti tit dinS : ng sut tr-c AS: Tng din tch thp ng sut tr-ch:Tng ng sut hao ( hh1h2 )Jhd, Fhd: M men qun tnh v din tch tit din tr nhng v tr gim yu do ng ghen cha thp ngsut tr-c chim chNHM 182 83. B MN CTB-BCGVHD: TH.S- BI TH ANH (S h ) : ng sut ko khi thi cng. Nh- vy mun cng sut tr-c bng S th phi to ra ng sut tr-cl ( Sh ) , l-ng ng sut tr-c h s hao tn sau khibung neo. Bng kt qu tnh ton :Z (m)n(T/m2)(T/m2)As(m2)Fhd(m2) k (T/m2)0 - 9.5750.3218 190037.24 0.07096 12.843 -299.6849.5 - 16.5 312.4653 119156.940.0283848.549-83.15916.5 - 23.5121.3624 116947.560.0141928.594-71.76023.5 - 30.565.1658114487.980.0070968.617-29.116+/ Nhn xt: T bng tnh ton trn ta thy b tng khng b chu ko, nn khngcn kim tra iu kin vt nt do un gy ra: k c Vic l c-ng chu ko ca b tng.2. Tnh ton b tr ct thp thng cho tr a) Tnh ton ct thp dc Theo tnh ton trn th c 2 on tr pha di khng tha mn iu kin chunn nn ta cn b tr thm thp thng chu nn cho on tr chu nn cngb tng. Vic tnh ton thp thng chu nn c tnh ton theo cng thc sau: . AS a .FabN0,5. C AhdTrong : a : l ng sut nn ln thp thng t ti vng nn tng khnng chu nn cho tit din b tng.Fa : Tng din tch thp thng b tr u theo chu vi tit dinvnh khuyn gia cng kh nng chu nn cho b tngNHM 183 84. B MN CTB-BCGVHD: TH.S- BI TH ANH Gii phng trnh trn ta tnh c a.Fa tnh din tch thp thng chu nn Fa ta gi thit ch khai thc thp chu nnsao cho: a = co + tb Khi din tch thp thng chu nn cn thit l: a .FaF a cotbBng tnh ton c th:Z(m)a.Fa(T) a(T/m2)Fa(cm2) (mm) N 0 - 9.5 16139.0390131693.5562 5092.2146 32 633.16494369.5 - 16.5 281.171393710125.8881 277.67579 25 56.56764653Trong : N s thanh thp ti thiu.Cch b tr nh sau: +/ Trong khong cao t 0 9.5 m: tit din hnh vnh khuynD x t = 6000 x 800 mm, ta b tr 5 lp thp theo chiu dy ca tit din. - Mi lp b tr 128 32 theo chu vi tit din, khong cch gia ccthanh l 180 mm. Tng din tch thp : Fa = 640x8.042 = 5146 (cm2) +/ Trong khong cao t 9.5 16.5 m: Do s lng thanh thp ti thiuqu t nn ta c th t thp trn on ny theo cu to. t 4 lp thp theo b dytit din, mi lp b tr 160 25, khong cch cc thanh 90 mm.+/ Trong cc cao cn li ta cng b tr ct thp theo cu to. t 4 lpthp theo b dy tit din, mi lp b tr 160 25, khong cch cc thanh 90 mm. b) Tnh ton ct thp aiNHM 1 84 85. B MN CTB-BCGVHD: TH.S- BI TH ANH Theo tnh ton kim tra trnt th trn ton b tr khng xy ra vt nt xin, do ta t ct thp ai theo cu to. t 4 lp ct ai 10 a200 theo b dy ca titdin tr.3. Tnh ton b tr ct thp cho dm tr thng tng. Ti trng do thng tng tc dng ln 1 dm l: Q = = 45.925 (T). Dm c tit din: bxhxl = 0.5x1x12 (m) => Ti trng bn thn dm: 15T Coi ti trng thng tng tc dng phn b u trn dm, ta tnh c ti trngdo tc dng ln 1m di ca dm:45.925 15q 5.1(T / m)12S tnh v biu ni lc nh hnh v: 5.1T/m 3000 6000 3000 S tnhNHM 185 86. B MN CTB-BC GVHD: TH.S- BI TH ANH 22.95Tm 22.95Tm 22.95Tm Biu m men15.3T15.3TBiu lc ctNi lc tnh ton ct thp dm thng tng:M = 22.95 (Tm)Q = 15.3 (T)a) Tnh ton ct thp dc dm thng tng.Chn chiu dy bo v ct thp l a =5 cm, chiu cao lm vic ca tit din lho = h a = 100 5 = 95 cm. Tnh ton cc thng s:m === 0.025 = 0.032NHM 1 86 87. B MN CTB-BC GVHD: TH.S- BI TH ANH( H s R tra bng ph thuc vo Mc b tng, nhm ct thp v iu kin lmvic, tra bng ta c R = 0.56) R = 0.41 m < R ta tnh ton nh tit din t ct thp n ( khng cn tnh tonct thp chu nn).T m = 0.025 tra bng ta c = 0.98Din tch ct thp cn thit l: MFaRa . .hoCt thp nhm CII c Ra = 28000 T/m2Thay s ta c: Fa = = 9 (cm2)Chn 425 c Fa = 19.635 cm2 b tr thnh 1 lp. Hm lng ct thp == x 100% = 0.41 % > 0.05%Thp cu to chn ging nh thp dc chu lc (425), t vng b tngchu nn. Ngoi ra, do tit din dm ln hn 500( Theo ti liu BTCT) nn khonggia dm, b tr thm ct cu to l cc thanh 18. b) Tnh ton ct ai.- Kim tra kh nng chu ct ca b tng: kn.nc.Qmax = 1.2x1x15.3 = 18.36 (T)Vi kn: h s ph thuc vo cp cng trnh( an ton ta cho tng lc ctca b tng ln kim tra, y chon kn = 1.2).nc: H s ph thuc vo loi t hp ti trng+/ iu kin cn kim tra:NHM 1 87 88. B MN CTB-BCGVHD: TH.S- BI TH ANHmb3.Qb = k1.Rk.b.ho.mb3( Theo Ti liu BTCT 1).Trong :mb3 = 1.15 : h s iu kin lm vic ca b tngRk = 120 T/m2 : cng chu ko ca b tngk1 = 0.5 + 2. = 0.5 + 2x0.048 = 0.596Do : mb3.Qb = 0.596x120x0.5x0.95x1.15 = 39.0678 (T)kn.nc.Qmax < mb3.Qb khng cn tnh ton ct ai chu ct. Chn ct aitheo cu to, chn ct ai 10 a100 ti cc vng cn gi ta (gn tr), ct ai 10a200 ti cc vng cn li( do ti vng gia nhp th dm ch yu chu un, chu ctrt t).c) Tnh ton kim tra vt ntChiu rng vt nt aT vung gc vi trc dc dm c xc nh theo cngthc:abdatk .Cd . . .7. 4 100 . dEaTrong : k : h s k n tnh cht chu lc ca cu kin, vi dm ngang chu unly bng 1. : h s k n loi ct thp, vi thp A-II c gi th = 1 Cd : h s ph thuc tnh cht tc dng ca ti trng, xem ti trng tcdng lu di, ly Cd =1.3 a : ng sut trong ct thp chu ko, i vi cu kin chu un th aMc xc nh nh sau : a, trong Z l cnh tay n ni ngu lc. Fa .Z x.ho 0.048 x95Cho php ly Zho ho 9592.72( cm) 22 2NHM 1 88 89. B MN CTB-BCGVHD: TH.S- BI TH ANH 2295000 a 1060.6 kG / cm 219, 635 x92, 72 bd : ng sut ko ban u trong c thp do trng n b tng( Trongphm vi n chn bng 0). : hm lng ct thp trong tit din d ng knh thanh ct thp (mm) Ea : m un n hi ca thp. Ea = 2.1x106 Kg/cm2 1060.6 at 1x1.3x1x x7 x 4 100.0.41% x 25 2.1x106= 0.072 mm < 0.08 mmKt lun: Chn thp 425 tha mn iu kin vt nt. Ni dung th 5: Thit k cu kin mng. 1. Tnh ton b tr ct thp cho h thng kt cu chu un. a) C s l thuytCu kin c tnh nh bn k 4 cnh, ta ct mt di bn b rng 1m, tnhton nh tit din dm ch nht chu un vi chiu cao l chiu dy bn. tnh ct thp theo phng no ta ct di bn vung gc vi phng vs dng mmen quay quanh trc vung gc vi phng : - Ct thp theo phng 1-1( trc t), ct di bn vung gc vi phng1-1, dng m men M22 tnh ton. - Ct thp theo phng 2-2(trc r), ct di bn vung gc vi phng 2-2, dung m men M11 tnh ton.H trc ta ca cc cu kin bn nh sau:NHM 1 89 90. B MN CTB-BC GVHD: TH.S- BI TH ANHKt cu Trc 1(trc t) Trc 2(trc r)Bn np Theo phng vngHng tmBn y Theo phng vngHng tm Bn thnhTheo phng vngHng tm Vch cngTheo phng vngHng tmb) Tnh ton ct thp theo cc phng theo cc cng thc sau: + Tnh h s: m =Trong :kn: H s tin cy, vi cng trnh cp II ly kn = 1.2 (Bng 2 TCVN4116-1985)nc: H s t hp ti trng vi t hp c bn ly nc = 1.0 (Bng 3 TCVN4116-1985)mb: H s iu kin lm vic ca b tng ly mb = 1 (Bng 5 TCVN 4116- 1985) + Tra bng xc nh c R, t tnh c R = R(1- 0.5R) + Vi m < R ,tra bng tm + Din tch ct thp yu cu: kn .nc .MFa ma .Ra . .b.ho(ma = 0.9: h s iu kin lm vic ca ct thp)T M+ Fa ; M- Fa + B tr ct thp chn lp vo v a; tnh ho + Kim tra hm lng ct thp= > minNHM 1 90 91. B MN CTB-BC GVHD: TH.S- BI TH ANH+/ Tnh ton ct aiDo chiu dy bn ln nn cn thit phi b tr ct thp ai cho bn. Kim trakh nng chu ct ca b tng theo cng thc:kn.nc.Q mb3.Qb Vi Qb = k.Rk.b.ho.tgk = 0.5 + 2tg = : gc gia mt ct nghing v trc dc cu kin : chiu cao tng i ca vng nn, xc nh theo cng thc:= x mb13 =1.15 : h s iu kin lm vic ca b tngNu iu kin lm vic trn c tha mn, b tng kh nng chu ct,khng cn tnh ton ct thp ai chu ct. Ct thp ai c chn theo cu to.Kim tra iu kin m rng vt nt:( Trang 118, TCVN 4116-1985)Chiu rng vt nt an vung gc vi trc di bn c xc nh theo cngthc: an = k x Cd x x x 7 (4 100)Trong : k : h s k n tnh cht chu lc ca cu kin. Vi dm ngang chu unly bng 1.0 : h s k inh loi ct thp. Vi thp A-II c g th = 1.0 Cd : h s ph thuc tnh cht tc dng ca ti trng. Xem ti trng tcdng lu di, ly Cd = 1.3 a : ng sut trong ct thp chu ko. i vi cu kin chu un th ac xc nh nh sau:a =Trong Z l cnh tay n ni ngu lc, ly Z = ho - = ho bd : ng sut ko ban u trong ct thp do trng n b tng. i vicu kin nm di nc th bd = 20 MpaNHM 191 92. B MN CTB-BCGVHD: TH.S- BI TH ANH : hm lng ct thp trong tit din, 0.02d : ng knh thanh ct thpEa : m un n hi ca thp. Ea = 21x1041.2. Kt qu tnh ton v b tr thpTnh ton, b tr thp cho h thng kt cu bnnp:+/ S tnh: Ta tnh ton v b tr cho tng bn( theo phng cnh ngn ca bn).Ct 1 di bn di 1m tnh ton, khi ta coi bn nh 1 dm c tit din 1x0,4.Chn 1 bn c ni lc ln tnh ton:2800 40.5Tm17.2TmA B26.21Tm 7000Theo biu mmen trn th ta s b tr thp gi A theo mmen M1=40.5Tmcho lp trn bn trong khong cch a=2.8m, cn cc v tr cn li lp trn s btr thp theo mmen M2=17.2Tm. Cn thp pha di bn th b tr theo mmenM3=26.2Tm. Thp theo phng cn li th b tr u theo ct thp ln nht theophng cnh kia( ng ra l phi tnh ton theo 2 phng ca bn ring bit nhngthin v an ton ta tnh cho phng c mmen ln nht).Tnh ton c th nh sau:NHM 1 92 93. B MN CTB-BCGVHD: TH.S- BI TH ANHThp nhm Ra =28000T/m2 AII Ea2.1x107 T/m2 B tng Mc 400# c Rn =1750T/m2 Rk =120 T/m2H s iu kin lm vic ca 0.9 thp maH s iu kin lm vic ca 1.15bt mbR 0.573R 0.4088355 kn1.2 nc 1 b1 m h 0.4m a 0.05 m h00.35 m+/ Vi mmen M1=40.5Tm: kn .nc .M m = 0.197, tra bng ta c : = 0.889mb .Rn .b.h0 2kn .nc .MFa =61.972(cm2)ma .Ra . .b.h0Fa61.972Hm l-ng ct thp :=100% = 1.8% >min=bh0100 350.05%Chn ct thp36 cfa = 10.2 cm2 10, 2.1000Chn a = 150 (mm), suy ra Fa68 cm2150 Fa 68Hm l-ng ct thp :=100% = 1.94% > min bh0100 35= 0,05%NHM 193 94. B MN CTB-BCGVHD: TH.S- BI TH ANH+/ Vi mmen M2=17.2Tm:Tng t nh trn, ta tnh c : 2Fa =24.47(cm )Fa 24.47Hm l-ng ct thp :=100% = 0.7% >min =bh0 100 350.05%Chn ct thp28 cfa = 6 cm26.1000Chn a = 150 (mm), suy ra Fa 40 cm2 150Fa40Hm l-ng ct thp :=100% = 1.1% >min =bh0 100 350,05%+/ Vi mmen M3=26.2Tm:Tng t nh trn, ta tnh c : 2Fa =38.3(cm )Fa38.3Hm l-ng ct thp :=100% = 1.2% >min =bh0 100 350.05%Chn ct thp32 cfa = 8 cm28.1000Chn a = 150 (mm), suy ra Fa 53 cm2 150Fa53Hm l-ng ct thp :=100% = 1.5% >min =bh0 100 350,05%Kim tra kh nng chu ct ca b tng:+/ Lc ct ln nht trong bn l : Q=V23 =16.78TVi ct thp dc b tr ta c h0 = 35 cm.Ta c:NHM 194 95. B MN CTB-BC GVHD: TH.S- BI TH ANHk n nc Q = 1.2 x 1 x 16.78 = 20Tkmb Rk bh0 = 1.(0.5 + 2 x 0.01) x 120 x 1 x 0.35= 21.84TThy k n nc Q < kmb Rk bh0B tng kh nng chu ct.Tham kho cc n trc, ta chn thp chng nh v li thp trn vdi l 16a100.(Cc h s k v mb trn c tra trong TCVN 4116-1985) Tnh ton theo m rng vt nt: Chiu rng vt nt aT vung gc vi trc dc dm-c xc nh theo cng thc:at = k Cdabd7 (4)d EaTrong : k =1;= 1.0 ; Cd = 1.3M x .h00.197 35 a=vi Z h0h0 35= 31.6 cm Fa Z 2 2240.5 105a= = 1200 Kg/cm268 31.6 bd = 0; = 1.94%; d = 36mm; Ea = 2.1 x 1062Kg/cm 1200 0at = 1 1.3 1 7 (4 1.94)36 2.1 106 = 0.074 mm < 0.08 mm.Tha mn nt gii hn cho php.Tnh ton, b tr thp cho h thng kt cu bny:Tnh ton tng t nh bn np, ta cng c biu mmen nh sau:( Ta lpbiu mmen bng tm v tr c mmen nguy him nht)NHM 195 96. B MN CTB-BCGVHD: TH.S- BI TH ANH Sau khi tm hiu ta thy mmen theo phng vung gc vi dm vng l lnnht, ta chn mt di bn tnh ton. T biu mmen di ta s b tr thp theo phng vung gc vi di tnhton nh sau: +/ S b tr thp vi mmen M1=48.26Tm t gi C ra 1 ona=1.2m, tip theo s b tr thp vi mmen M2=26.35Tm qua gi D mt onb=1.8m, on cn li s b tr thp vi mmen M3=19.26Tm. Thp lp di sb tr thnh 2 on vi mmen M4=34.62Tm v M5=22.5Tm +/ Thp b tr dc theo theo phng tnh ton vi mmen M1( thinv an ton).48.26Tm1200 26.35Tm 1800 19.26Tm22.5Tm34.62TmC DE3000 4000NHM 1 96 97. B MN CTB-BC GVHD: TH.S- BI TH ANH phn bn np BA C phn bn yDE Tnh ton c th nh sau:+/ Vi mmen M1=48.26Tm: Tng t nh tnh ton bn np, ta tnh c : 2Fa =75.98(cm )Fa75.98 Hm l-ng ct thp : = 100% = 2.17% >minbh0100 35= 0.05% Chn ct thp 36 cfa = 10.2 cm210, 2.1000 Chn a = 130 (mm), suy ra Fa78.46 cm2 130Fa78.46 Hm l-ng ct thp : = 100% = 2.24% >minbh0100 35= 0,05%NHM 197 98. B MN CTB-BCGVHD: TH.S- BI TH ANH+/ Vi mmen M2=34.26Tm:Tng t nh trn, ta tnh c : 2Fa =51.32(cm )Fa51.32Hm l-ng ct thp : =100% = 1.46% >minbh0100 35= 0.05%Chn ct thp32 cfa = 8 cm28.1000Chn a = 150 (mm), suy ra Fa 53 cm2 150 Fa 53Hm l-ng ct thp :=100% = 1.5% >min= bh0100 350,05%+/ Vi mmen M3=26.35Tm:Tng t nh trn, ta tnh c : 2Fa =38.5(cm ) Fa 38.5Hm l-ng ct thp :=100% = 1.1% >min= bh0100 350.05%Chn ct thp28 cfa = 6 cm26.1000Chn a = 150 (mm), suy ra Fa 40 cm2 150 Fa 40Hm l-ng ct thp :=100% = 1.1% >min= bh0100 350,05%+/ Vi mmen M4=22.5Tm:Tng t nh trn, ta tnh c : 2Fa =32.5(cm )NHM 198 99. B MN CTB-BCGVHD: TH.S- BI TH ANHFa 32.5Hm l-ng ct thp : =100% = 0.93% >minbh0100 35= 0.05%Chn ct thp28 cfa = 6 cm26.1000Chn a = 150 (mm), suy ra Fa 40 cm2 150 Fa 40Hm l-ng ct thp :=100% = 1.1% >min= bh0100 350,05%+/ Vi mmen M5=19.26Tm:Tng t nh trn, ta tnh c : 2Fa =28(cm ) Fa 28Hm l-ng ct thp :=100% = 0.8% >min= bh0100 350.05%Chn ct thp28 cfa = 6 cm26.1000Chn a = 150 (mm), suy ra Fa 40 cm2 150 Fa 40Hm l-ng ct thp :=100% = 1.1% >min= bh0100 350,05%Kim tra kh nng chu ct ca b tng:+/ Lc ct ln nht trong bn l : Q=V23 =15.26TVi ct thp dc b tr ta c h0 = 35 cm.Ta c:k n nc Q = 1.2 x 1 x 15.26= 18.3Tkmb Rk bh0 = 1.(0.5 + 2 x 0.01) x 120 x 1 x 0.35= 21.84TThy k n nc Q < kmb Rk bh0B tng kh nng chu ct.NHM 199 100. B MN CTB-BCGVHD: TH.S- BI TH ANHTham kho cc n trc, ta chn thp chng nh v li thp trn vdi l 16a100.(Cc h s k v mb trn c tra trong TCVN 4116-1985) Tnh ton theo m rng vt nt: Chiu rng vt nt aT vung gc vi trc dc dm-c xc nh theo cng thc: at = k Cdabd 7 (4)dEaTrong : k =1; = 1.0 ; Cd = 1.3 M x .h00.197 35a=vi Z h0h0 35= 31.6 cmFa Z 2 22 48.26 105 a== 1105 Kg/cm276 31.6bd = 0; = 1.94%; d = 36mm; Ea = 2.1 x 106 2Kg/cm 1105 0 at = 1 1.3 17 (4 1.94) 36 2.1 106 = 0.068 mm < 0.08 mm.Tha mn nt gii hn cho php.Tnh ton, b tr thp cho h thng kt cu bnthnh:Tnh ton tng t nh bn np, bn y ta cng c biu mmen nh sau:(Ta lp biu mmen bng tm v tr c mmen nguy him nht) T biu mmen ta thy b tr thp vng bn ngoi vi thp M1=19.24Tm(do mmen 2 u gi gn ging nhau), cn b tr thp bn trong vi mmenM2=42.12Tm. Cn thp dc theo dm th b tr theo M2.NHM 1100 101. B MN CTB-BC GVHD: TH.S- BI TH ANH19.24Tm 16.5Tm42.12TmFG6000FGNHM 1 101 102. B MN CTB-BC GVHD: TH.S- BI TH ANHTnh ton c th nh sau:+/ Vi mmen M1=19.24Tm:Tng t nh tnh ton bn np v bn y, ta tnh c :2Fa =28(cm ) Fa 28Hm l-ng ct thp :=100% = 0.8% > min= bh0100 350.05%Chn ct thp 28 c fa = 6 cm26.1000Chn a = 150 (mm), suy ra Fa 40 cm2 150 Fa 40Hm l-ng ct thp :=100% = 1.1% > min= bh0100 350,05%+/ Vi mmen M2=42.12Tm:Tng t nh trn, ta tnh c : 2Fa =64.8(cm ) Fa 64.8Hm l-ng ct thp :=100% =1.85% > min= bh0100 350.05%Chn ct thp 36 c fa = 10.2 cm210, 2.1000Chn a = 150 (mm), suy ra Fa 68 cm2150Fa 68Hm l-ng ct thp : =100% = 1.94% > minbh0100 35= 0,05%Tnh ton, b tr thp cho h thng kt cu dmchnh:Kt cu dm chnh gm c dm tr nhnh np, nhnh y v dm tr sn thnh, c kch thc ln lt l 1.2x0.5,1.5x0.5 v 1.2x0.5.NHM 1 102 103. B MN CTB-BCGVHD: TH.S- BI TH ANHTa coi nh h thng dm ny ngm vo trong tr thng tng bn trong, tachn mt khung c gi tr mmen nguy him nht tnh ton. Sau khi tm hiugi tr mmen trong s tnh trong Sap, ta c biu mmen nh sau:NHM 1 103 104. B MN CTB-BCGVHD: TH.S- BI TH ANH 57.265Tm A1 31.25Tm 49.257Tm 31.25Tm A246.921Tm 72.15Tm 59.254TmA3 A4 59.254Tm 80.54Tm+/ Dm tr bn np:NHM 1104 105. B MN CTB-BC GVHD: TH.S- BI TH ANHTnh ton ct dc : *Ta c : Tit din dm : b x h = 50x120(cm.) Chn abv = 5 (cm)h0 = 120 - 5 = 115 (cm).Vi mmen m gi A1: M = 57.265Tm.Tng t nh cc phn trn ta tm c din tch ct thp yu cu:Fa = 24.026 (cm2 ). Ta chn s b 4 28 c Fa = 24.63(cm2) Fa 24.63 Hm lng ct thp :100% 0.43% min 0.05% bho 50 x115Vi s lng ct thp chn nh trn, ta s t thnh 1 lp v b tr t mp tr thng tng ra ngoi mt on bng lnhp/4=7.83/4=2m, ngoi ra cn phi cngthm mt on ni ct thp( Theo Ti liu B tng ct thp 1), nhng ngin ha, ta chn on thp ch ny l 1m ( thin v an ton), cn on gia 2gi pha trn ta b tr 1 lp ct cu to 4 25.Vi mmen m gi A2: M = 31.25Tm.Tng t nh cc phn trn ta tm c din tch ct thp yu cu:Fa = 13.03 (cm2 ). Ta chn s b 4 28 c Fa = 24.63(cm2) Fa 24.63 Hm lng ct thp :100% 0.43% min 0.05% bho 50 x115Ta b tr thp cng tng t nh gi A1.Vi mmen dng gia nhp: M = 49.257Tm.Tng t nh cc phn trn ta tm c din tch ct thp yu cu:Fa = 20.63 (cm2 ). Ta chn s b 4 28 c Fa = 24.63(cm2)NHM 1 105 106. B MN CTB-BCGVHD: TH.S- BI TH ANHFa 24.63Hm lng ct thp :100% 0.43% min0.05%bho 50 x115 Vi ct thp bn di, ta cng b tr 1lp, nhng ko di tn vo trong gi.Tnh ton ct ai : Kim tra kh nng chu ct ca b tng: Vi ct thp dc b tr ta c ho = 115(cm) Ta c: Lc ct ln nht l: Qmax = V2 = 26.159 (T) Qbmin = 3 (1 f n ) Rbt bh o 0,6.1,5.120.0,5.1,15=53T Thy Qmax < Qbmin => Khng cn phi tnh ton ct ai.t theo cu to : Chn s nhnh ct ai l n=4, 10a150mm. (Cc h s trn c ly theo B tng ct thp 1)Do chiu cao dm ln hn 70cm( Theo BTCT 1) nn cn b tr thm ct gi, chntheo cu to: 25Tnh ton theo s hnh thnh v m rng vt nt :Chiu rng vt nt at vung gc vi trc dc dm-c xc nh theo tiu chun TCVN 4116 85 nh- sau: at = k C d abd7 (4 ) d mmEa Trong :k - H s k n tnh cht chu lc ca cu kin.Vi dm ngang chu un ly bng 1.0Cd - H s ph thuc tnh cht tc dng ca titrng. Xem ti trng tc dng lu di, ly Cd = 1.3 - H s k n loi ct thp. Vi thp A-II c gth= 1.0 - ng sut trong ct thp chu ko. i vi cu akin chu un th -c xc nh nh- sau :NHM 1106 107. B MN CTB-BC GVHD: TH.S- BI TH ANHM a= Trong Z l cnh tay n ni ngu lc. Fa ZTrong :Z = h0 x/2vi x l chiu cao vng. Cho php ly:x .h0 0.0285 115 Zh0 h0 115108.72(cm)2 22 57.265 105a =1135 kG / cm 224.63 108.72 bd - ng sut ko ban u trong ct thp dotr-ng n b tng. i vi kt cu nm trn kh thbd= 0. - Hm l-ng ct thp trong tit din.= 0.43%d - -ng knh thanh ct thp (d = 28 mm) Ea - Mun n hi ca thp. Ea = 2.1 x 106(kG/cm2).1135 0at= 1 1.3 1 7 (4 0.43) 28 0.068(mm) 0.08 (mm) 2.1 106Tha mn iu kin vt nt.+/ Dm tr bn y:*Ta c : Tit din dm : b x h = 50x150(cm.) Chn abv = 5 (cm) h0 = 150 - 5 = 145 (cm).Vi mmen m gi A3: M = 59.254Tm.Tng t nh cc phn trn ta tm c din tch ct thp yu cu:Fa = 24.873 (cm2 ).Ta chn s b 4 36 c Fa = 40.7(cm2)NHM 1 107 108. B MN CTB-BCGVHD: TH.S- BI TH ANHFa 40.7 Hm lng ct thp : 100% 0.56% min 0.05%bho 50 x145Ta cng b tr ct thp nh cc gi trn.Vi mmen m gi A4: M = 80.54Tm.Tng t nh cc phn trn ta tm c din tch ct thp yu cu: Fa = 36.76 (cm2 ). Ta chn s b 6 36 c Fa = 61(cm2)Fa61 Hm lng ct thp : 100% 0.84% min 0.05%bho 50 x145 y ta b tr thnh 2 lp, lp trn th ging cc gi trn cn lp di ta b tr2 thanh 2 bn.Vi mmen dng gia nhp: M = 72.15Tm.Tng t nh cc phn trn ta tm c din tch ct thp yu cu: Fa = 32.85 (cm2 ). Ta chn s b 6 32 c Fa = 48.25(cm2)Fa 48.25 Hm lng ct thp : 100% 0.67% min 0.05%bho 50 x145 Vi ct thp thp ging gi A4, nhng ko di tn vo trong gi.Tnh ton ct ai :Kim tra kh nng chu ct ca b tng:Vi ct thp dc b tr ta c ho = 115(cm)Ta c: Lc ct ln nht l:Qmax = V2 = 39.586 (T)Qbmin = 3 (1 f n ) Rbt bh o 0,6.1,5.120.0,5.1,15=53TThy Qmax < Qbmin => Khng cn phi tnh ton ct ai. t theo cu to : Chn s nhnh ct ai l n=4, 10a150mm.(Cc h s trn c ly theo B tng ct thp 1)NHM 1108 109. B MN CTB-BC GVHD: TH.S- BI TH ANHDo chiu cao dm ln hn 70cm( Theo BTCT 1) nn cn b tr thm ct gi, chntheo cu to: 25Tnh ton theo s hnh thnh v m rng vt nt :Chiu rng vt nt at vung gc vi trc dc dm-c xc nh theo tiu chun TCVN 4116 85 nh- sau:at = k C d abd 7 (4 ) d mm EaTrong :k - H s k n tnh cht chu lc ca cu kin.Vi dm ngang chu un ly bng 1.0Cd - H s ph thuc tnh cht tc dng ca titrng. Xem ti trng tc dng lu di, ly Cd = 1.3 - H s k n loi ct thp. Vi thp A-II c gth= 1.0 - ng sut trong ct thp chu ko. i vi cu akin chu un th -c xc nh nh- sau : Ma= Trong Z l cnh tay n ni ngu lc.Fa Z Trong :Z = h0 x/2 vi x l chiu cao vng. Cho php ly: x .h0 0.0285 145Zh0 h0 145143.72(cm) 2 22 80.54 105 a = 918 kG / cm 2 61 143.72bd - ng sut ko ban u trong ct thp dotr-ng n b tng. i vi kt cu nm trn kh thbd= 0.NHM 1 109 110. B MN CTB-BC GVHD: TH.S- BI TH ANH - Hm l-ng ct thp trong tit din.= 0.67%d - -ng knh thanh ct thp (d = 36 mm) Ea - Mun n hi ca thp. Ea = 2.1 x 106(kG/cm2).918 0at= 1 1.3 1 7 (4 0.67) 36 0.06(mm) 0.08 ( mm) 2.1 106Tha mn iu kin vt nt.+/ Dm tr sn thnh:Tnh ton ct dc :* Ta c : Tit din dm : b x h = 50x120(cm.)Chn abv = 5 (cm) h0 = 120 - 5 = 115 (cm). Vi mmen m gi A2,A3 th b tr nh dm tr bn np v bn y( do c cng mmen), ct thp bn ngoi.Vi mmen dng gia nhp: M = 46.924Tm.Tng t nh cc phn trn ta tm c din tch ct thp yu cu:Fa = 20.19 (cm2 ).Ta chn s b 4 28 c Fa = 24.63(cm2) Fa 24.63Hm lng ct thp : 100% 0.43% min 0.05% bho 50 x115Vi ct thp bn trong, ta cng b tr 1lp, nhng ko di tn vo trong gi.Tnh ton ct ai : Kim tra kh nng chu ct ca b tng: Vi ct thp dc b tr ta c ho = 115(cm) Ta c: Lc ct ln nht l: Qmax = V2 = 31.75 (T) Qbmin = 3 (1 f n ) Rbt bh o 0,6.1,5.120.0,5.1,15=53TNHM 1110 111. B MN CTB-BC GVHD: TH.S- BI TH ANHThy Qmax < Qbmin => Khng cn phi tnh ton ct ai. t theo cu to : Chn s nhnh ct ai l n=4, 10a150mm.(Cc h s trn c ly theo B tng ct thp 1)Do chiu cao dm ln hn 70cm( Theo BTCT 1) nn cn b tr thm ct gi, chntheo cu to: 25Tnh ton theo s hnh thnh v m rng vt nt :Chiu rng vt nt at vung gc vi trc dc dm-c xc nh theo tiu chun TCVN 4116 85 nh- sau:at = k C d abd 7 (4 ) d mm EaTrong :k - H s k n tnh cht chu lc ca cu kin.Vi dm ngang chu un ly bng 1.0Cd - H s ph thuc tnh cht tc dng ca titrng. Xem ti trng tc dng lu di, ly Cd = 1.3 - H s k n loi ct thp. Vi thp A-II c gth= 1.0 - ng sut trong ct thp chu ko. i vi cu akin chu un th -c xc nh nh- sau : Ma = Trong Z l cnh tay n ni ngu lc.Fa Z Trong :Z = h0 x/2 vi x l chiu cao vng. Cho php ly:x.h0 0.0285 115Zh0 h0 115108.72(cm)22246.924 105a = 1024 kG / cm 2 24.63 108.72NHM 1 111 112. B MN CTB-BC GVHD: TH.S- BI TH ANH bd - ng sut ko ban u trong ct thp dotr-ng n b tng. i vi kt cu nm trn kh thbd= 0. - Hm l-ng ct thp trong tit din. = 0.43%d - -ng knh thanh ct thp (d = 28 mm) Ea - Mun n hi ca thp. Ea = 2.1 x 106(kG/cm2).1020 0at= 1 1.3 1 7 (4 0.43) 280.062(mm) 0.08 (mm) 2.1 106Tha mn iu kin vt nt.Tnh ton, b tr thp cho h thng kt cu vchcng:Tnh ton nh cc bn shell trn, y ta chn Mmen ln nht trong vch tnh ton( thin v an ton). Ta b tr ct thp theo 2 phng nh nhau. Ct 1 di1m tnh toan, khi ta c kch thc cn tnh ton l 0.4x1m.Tnh ton c th nh sau:+/ Vi mmen M=7.935Tm: Tng t nh tnh ton bn np, ta tnh c :2Fa =11(cm ) Fa 11 Hm l-ng ct thp := 100% = 0.3% > min = bh0100 350.05% Chn ct thp18 c fa = 2.54 cm22,54.1000 Chn a = 130 (mm), suy ra Fa 16.93 cm2 150NHM 1 112 113. B MN CTB-BCGVHD: TH.S- BI TH ANHFa16.93Hm l-ng ct thp : =100% = 0.48% > minbh0100 35= 0,05% Kim tra kh nng chu ct ca b tng:+/ Lc ct ln nht trong bn l : Q=V23 =10.154TVi ct thp dc b tr ta c h0 = 35 cm.Ta c: k n nc Q = 1.2 x 1 x10.154 = 12.2T kmb Rk bh0 = 1.(0.5 + 2 x 0.01) x 120 x 1 x 0.35= 21.84TThy k n nc Q < kmb Rk bh0B tng kh nng chu ct.Tham kho cc n trc, ta chn thp chng nh v li thp trn vdi l 16a150.(Cc h s k v mb trn c tra trong TCVN 4116-1985) Tnh ton theo m rng vt nt: Chiu rng vt nt aT vung gc vi trc dc dm-c xc nh theo cng thc: at = k Cd abd7 (4 )d EaTrong : k =1; = 1.0 ; Cd = 1.3 Mx.h00.197 35a=vi Z h0 h035= 31.6 cmFa Z2227.935 105 a= = 1216 Kg/cm2 16.93 31.6bd = 0; = 1.94%; d = 18mm; Ea = 2.1 x 106 2Kg/cm 1216 0 at = 1 1.3 17 (4 0.48) 18 2.1 106NHM 1113 114. B MN CTB-BCGVHD: TH.S- BI TH ANH= 0.072 mm < 0.08 mm.Tha mn nt gii hn cho php.Tnh ton, b tr thp cho h thng kt cu dm ph:Kt cu dm ph gm c dm vng bn y, dm vng nh bn thnh vdm ph hng tm, c kch thc ln lt l 1x0.4,1x0.4 v 0.6x0.4Tnh ton tng t nh cc dm chnh, n gin ha th ta chn mmen maxv min b tr thp cho cc dm ny. Mmen dng b tr thp bn di,momen m b tr bn trn. Ta b tr thp chy dc dm.+/ Dm vng nh bn thnh: *Ta c : Tit din dm : b x h = 40x100(cm.) Chn abv = 5 (cm) h0 = 100 - 5 = 95 (cm).Vi mmen m: M=-9.625TmTng t nh cc phn trn ta tm c din tch ct thp yu cu:Fa =4.84(cm2 ). Ta chn s b 2 25 c Fa = 9.8(cm2)Fa 9.8 Hm lng ct thp :100% 0.26% min 0.05%bho 40 x95Vi mmen dng: M=7.3TmTng t nh cc phn trn ta tm c din tch ct thp yu cu:Fa =3.7(cm2 ). Ta chn s b 2 25 c Fa = 9.8(cm2)Fa 9.8 Hm lng ct thp :100% 0.26% min 0.05%bho 40 x95Tnh ton ct ai :NHM 1114 115. B MN CTB-BCGVHD: TH.S- BI TH ANHKim tra kh nng chu ct ca b tng:Vi ct thp dc b tr ta c ho = 95(cm)Ta c: Lc ct ln nht l:Qmax = V2 = 4.265 (T)Qbmin = 3 (1 f n ) Rbt bh o 0,6.1,5.120.0,5.1,15=53TThy Qmax < Qbmin => Khng cn phi tnh ton ct ai. t theo cu to : Chn s nhnh ct ai l n=2, 10a150mm.(Cc h s trn c ly theo B tng ct thp 1)Do chiu cao dm ln hn 70cm( Theo BTCT 1) nn cn b tr thm ct gi, chntheo cu to: 18Tnh ton theo s hnh thnh v m rng vt nt :Chiu rng vt nt at vung gc vi trc dc dm-c xc nh theo tiu chun TCVN 4116 85 nh- sau:at = k C dabd7 (4 ) d mmEaTrong :k - H s k n tnh cht chu lc ca cu kin.Vi dm ngang chu un ly bng 1.0Cd - H s ph thuc tnh cht tc dng ca titrng. Xem ti trng tc dng lu di, ly Cd = 1.3 - H s k n loi ct thp. Vi thp A-II c gth= 1.0 - ng sut trong ct thp chu ko. i vi cu akin chu un th -c xc nh nh- sau : Ma =Trong Z l cnh tay n ni ngu lc.Fa Z Trong :Z = h0 x/2 vi x l chiu cao vng. Cho php ly:NHM 1115 116. B MN CTB-BC GVHD: TH.S- BI TH ANHx .h00.0285 95 Zh0 h0 95 93.64(cm)2 229.625 105a = 1049 kG / cm 2 9.8 93.6 bd - ng sut ko ban u trong ct thp dotr-ng n b tng. i vi kt cu nm trn kh thbd= 0. - Hm l-ng ct thp trong tit din.= 0.26%d - -ng knh thanh ct thp (d = 25 mm) Ea - Mun n hi ca thp. Ea = 2.1 x 106(kG/cm2).1049 0at= 1 1.3 1 7 (4 0.26)250.062(mm) 0.08 (mm) 2.1 106Tha mn iu kin vt nt.+/ Dm vng bn y:* Ta c : Tit din dm : b x h = 40x100(cm.) Chn abv = 5 (cm)h0 = 100 - 5 = 95 (cm). Vi mmen m: M=-16.3TmTng t nh cc phn trn ta tm c din tch ct thp yu cu:Fa =8.2(cm2 ).Ta chn s b 2 28 c Fa = 12.3(cm2) Fa 12.3Hm lng ct thp :100% 0.32% min 0.05% bho 40 x95 Vi mmen dng: M=17.9TmTng t nh cc phn trn ta tm c din tch ct thp yu cu:Fa =9.026 (cm2 ).NHM 1 116 117. B MN CTB-BC GVHD: TH.S- BI TH ANH Ta chn s b 2 28 c Fa = 12.3(cm2)Fa 12.3Hm lng ct thp : 100%0.32% min 0.05%bho 40 x95Tnh ton ct ai : Kim tra kh nng chu ct ca b tng: Vi ct thp dc b tr ta c ho = 95(cm) Ta c: Lc ct ln nht l: Qmax = V2 = 36.25 (T) Qbmin = 3 (1 f n ) Rbt bh o 0,6.1,5.120.0,5.1,15=53T Thy Qmax < Qbmin => Khng cn phi tnh ton ct ai.t theo cu to : Chn s nhnh ct ai l n=2, 10a150mm. (Cc h s trn c ly theo B tng ct thp 1)Do chiu cao dm ln hn 70cm( Theo BTCT 1) nn cn b tr thm ct gi, chntheo cu to: 18Tnh ton theo s hnh thnh v m rng vt nt :Chiu rng vt nt at vung gc vi trc dc dm-c xc nh theo tiu chun TCVN 4116 85 nh- sau: at = k C d abd7 (4 ) d mmEa Trong :k - H s k n tnh cht chu lc ca cu kin.Vi dm ngang chu un ly bng 1.0Cd - H s ph thuc tnh cht tc dng ca titrng. Xem ti trng tc dng lu di, ly Cd = 1.3 - H s k n loi ct thp. Vi thp A-II c gth= 1.0 - ng sut trong ct thp chu ko. i vi cu akin chu un th -c xc nh nh- sau :NHM 1 117 118. B MN CTB-BC GVHD: TH.S- BI TH ANHM a=Trong Z l cnh tay n ni ngu lc. Fa ZTrong :Z = h0 x/2vi x l chiu cao vng. Cho php ly:x .h00.0285 95 Zh0 h0 95 93.64(cm)2 2217.9 105a = 1256 kG / cm 212.3 93.6 bd - ng sut ko ban u trong ct thp dotr-ng n b tng. i vi kt cu nm trn kh th bd= 0. - Hm l-ng ct thp trong tit din. = 0.32%d - -ng knh thanh ct thp (d = 28 mm) Ea - Mun n hi ca thp. Ea = 2.1 x 106(kG/cm2). 1256 0at= 1 1.3 17 (4 0.26)28 0.071(mm) 0.08 ( mm) 2.1 106Tha mn iu kin vt nt.+/ Dm ph hng tm:* Ta c : Tit din dm : b x h = 50x60 (cm.) Chn abv = 5 (cm)h0 = 60 - 5 = 55 (cm).Vi mmen m: M=-28.589TmTng t nh cc phn trn ta tm c din tch ct thp yu cu:Fa =25.49(cm2 ).Ta chn s b 4 32 c Fa =32.2(cm2)NHM 1 118 119. B MN CTB-BC GVHD: TH.S- BI TH ANH Fa 32.2Hm lng ct thp :100% 1.46%min0.05% bho 40 x55Vi mmen dng: M=21.654TmTng t nh cc phn trn ta tm c din tch ct thp yu cu:Fa =19.2 (cm2 ).Ta chn s b 4 28 c Fa =24.63(cm2) Fa24.63Hm lng ct thp :100% 1.1% min 0.05% bho 50 x55Tnh ton ct ai :Kim tra kh nng chu ct ca b tng:Vi ct thp dc b tr ta c ho = 55(cm)Ta c: Lc ct ln nht l:Qmax = V2 = 16.3 (T)Qbmin = 3 (1 f n ) Rbt bh o 0,6.1,5.120.0,5.0,55=53TThy Qmax < Qbmin => Khng cn phi tnh ton ct ai. t theo cu to : Chn s nhnh ct ai l n=2, 10a150mm.(Cc h s trn c ly theo B tng ct thp 1) Do chiu cao dm h< 70cm( Theo BTCT 1) nn khong cn b tr thm ct gi.Tnh ton theo s hnh thnh v m rng vt nt :Chiu rng vt nt at vung gc vi trc dc dm-c xc nh theo tiu chun TCVN 4116 85 nh- sau:at = k C d abd 7 (4 ) d mm EaTrong :k - H s k n tnh cht chu lc ca cu kin.Vi dm ngang chu un ly bng 1.0Cd - H s ph thuc tnh cht tc dng ca titrng. Xem ti trng tc dng lu di, ly Cd = 1.3NHM 1 119 120. B MN CTB-BC GVHD: TH.S- BI TH ANH - H s k n loi ct thp. Vi thp A-II c gth= 1.0 - ng sut trong ct thp chu ko. i vi cu akin chu un th -c xc nh nh- sau : Ma=Trong Z l cnh tay n ni ngu lc.Fa Z Trong :Z = h0 x/2 vi x l chiu cao vng. Cho php ly: x .h00.0285 55Zh0 h0 55 54.2(cm) 2 22 28.589 105 a =1124 kG / cm 232.2 54.2bd - ng sut ko ban u trong ct thp dotr-ng n b tng. i vi kt cu nm trn kh thbd= 0.- Hm l-ng ct thp trong tit din. = 1.46% d - -ng knh thanh ct thp (d = 32 mm) Ea - Mun n hi ca thp. Ea = 2.1 x 106(kG/cm2). 1124 0 at= 1 1.3 1 7 (4 1.46)32 0.058(mm) 0.08 (mm) 2.1 106Tha mn iu kin vt nt.Tnh ton, b tr thp cho h thng kt cu chnkhay:Tnh ton nh cc bn shell trn, y ta chn Mmen ln nht trong shell tnh ton( thin v an ton). Ta b tr ct thp thnh cc vng thp. Ta c kchthc cn tnh ton l 0.4x0.5m v 0.8x0.5mNHM 1120 121. B MN CTB-BC GVHD: TH.S- BI TH ANHCc thp thng trong chn khay th ta s ko di thp ng bn thnh xung, y ta ch tnh ton thp vng ngang. Cn i vi vng trong th ko di thpthng chu lc ca tr trong xung.Tnh ton c th nh sau:+/ Vng ngoi:Tnh ton c th nh sau:+/ Vi mmen M=28.53Tm:Tng t nh tnh ton bn np v bn y, ta tnh c :2 Fa =31.6(cm ) Fa31.6Hm l-ng ct thp := 100% = 1.75% > min bh040 45= 0.05%Chn ct thp 32 cfa = 8 cm2 8.400Chn a = 100 (mm), suy ra Fa 32 cm2100Fa 32Hm l-ng ct thp : = 100% = 1.7% > min=bh040 450,05%+/ Vng trong:Tnh ton c th nh sau:+/ Vi mmen M=38.3Tm:Tng t nh tnh ton bn np v bn y, ta tnh c :2 Fa =43.15(cm )Fa43.15Hm l-ng ct thp : =100% = 1.2% >min=bh080 450.05%Chn ct thp 32 cfa = 8 cm2NHM 1 121 122. B MN CTB-BCGVHD: TH.S- BI TH ANH 8.800Chn a = 100 (mm), suy ra Fa 64 cm2100Fa 64Hm l-ng ct thp : = 100% = 1.7% >min =bh080 450,05% Kim tra kh nng chu ct ca b tng:+/ Lc ct ln nht trong bn l : Q=V23 =21.6TVi ct thp dc b tr ta c h0 = 45 cm.Ta c: k n nc Q = 1.2 x 1 x21.6 = 25.92T kmb Rk bh0 = 1.(0.5 + 2 x 0.01) x 120 x 1 x 0.45= 26.3TThy k n nc Q < kmb Rk bh0B tng kh nng chu ct.(Cc h s k v mb trn c tra trong TCVN 4116-1985) Tnh ton theo m rng vt nt: Chiu rng vt nt aT vung gc vi trc dc dm-c xc nh theo cng thc: at = k Cd abd7 (4 )d EaTrong : k =1;= 1.0 ; Cd = 1.3M x.h00.197 45a= vi Z h0h045= 44.21cm Fa Z 22238.3 105 a = = 912Kg/cm264 44.21bd = 0;= 1.7%; d = 32mm; Ea = 2.1 x 106 Kg/cm2912 0 at = 1 1.3 1 7 (4 1.7) 322.1 106 = 0.062 mm < 0.08 mm. Tha mn nt gii hn cho php.NHM 1122 123. B MN CTB-BCGVHD: TH.S- BI TH ANH Ni dung th 6: Thit k nn mng cng trnh. 1. Tnh ton n nh tng th.Khi tnh ton n nh nn mng ca cng trnh bin trng lc th chng ta phitnh ton cho tt c cc tnh hung khc nhau ca ti trng( sng, gi, dngchy,), k c bin lng v lc c bo( ng vi bn v tr c trng ca nhsng). n gin ha th ta s tnh ton vi trng hp ti trng sng tc dngmax, l thi im 17T/20, khi tng ti trng sng tc dng ln cng trnh l264.62T.a) Kim tra n nh lt c kim tra phn trn.b) Kim tra n nh trt ngangFv FH fNu viln, khi tnh ton kh nng chngtr-t ca mng phi k n p lc ca t tc dng lnthnh bn ca mng. Nu vi nh, khi tnh ton khnng chng tr-t ca mng c th b qua p lc ca ttc dng ln thnh bn ca mng. i vi cng trnh bin trng lc, mng th-ngc kch th-c ln, khi mng ln gp dng chy y,c th sy ra hin t-ng xi mng, vic b qua plc ca t tc dng ln thnh bn ca mng khi tnhton kim tra n nh tr-t thin v an ton. TrongNHM 1123 124. B MN CTB-BCGVHD: TH.S- BI TH ANHtnh ton d-i y b qua p lc ln thnh bn ca mng.iu kin n nh chng trtfuk Trong : k : h s an ton chng trt ly theo quy phm, thng ly k = 1.2 : ng sut tip ti y mng do lc ngang FH, coi lc ngang FH phnb u trn y mng: =FH : tng lc ngang ln y mng A: din tch y mngfu : cng chng trt ti hn ca mng fu = c + .tgc : lc dnh ca t : gc ma st trong ca t : ng sut y mng, = vi Fv l tng lc nn tc dng lny mng.Trong trng thi nn nhiu lp, lp t s 1 c chiu dy khng ln, lps 2 l lp t yu, ta phi kim tra iu kin trt gia hai lp t. ng sut tipgia hai lp t xc nh nh sau: FH 21,2A y:NHM 1124 125. B MN CTB-BC GVHD: TH.S- BI TH ANH FH2 : tng lc ngang tc dng ln y lp 1, nu b qua p lc hng,thin v an ton c th coi FH2 = FH=const.1,2 : ng sut tip xc gia lp t s 1 v s 2A: din tch y mng m m rng n ht lp t s 1D 2A. 4Vi D = D + 2.tg1.h1Fv FH 1 B 2 B+/ Kt qu tnh ton: Trng lng khi chn : 2562.83 (T) Trng lng thng tng: 183.7 (T) Trng lng h bm: 44 (T) Lc y ni: 3667.73 (T) Trng lng vt liu dn: 3280 (T) Tng lc ng Fv = 2402.8 (T) Lc ngang tc dngNHM 1 125 126. B MN CTB-BCGVHD: TH.S- BI TH ANH Tng ti trng sng&dng chy: 264.62(T) Tng ti trng gi: 29.335(T) Tng lc ngang FH = 293.955 (T) Do lp t 1 v 2 u tt nn s tha mn iu kin chng trt. Sau y l bngtnh ton kim tra n nh trt ngang ca cng trnh. Fv(T)FH(T) A(m2) C(T/m2) ()k fu(T/m2) (T/m2) kim tra Lp2402.8 293.955 314.2 3.60.26 1.25.65 0.94 tha mn 12. Tnh ton nn mng cng trnh (theo tiu chun API).Tnh ton kim tra mng theo iu kin v cng Theo tiu chun API iu kin an ton ca mng trng lc- iu kin an ton chu lc nn PDB SB .QDB- iu kin an ton chu lc ngang PDSSS .H DSTrong :PDB: ti trng ng gy nn mngPDS: ti trng ngang gy mt n nh trt mngQDB: cng ca t nnHDS: sc khng trt cc i ca nn tSB: h s an ton khng nn ca mng, vi mng nng SB = 0.67SS: h s an ton khng trt ca mng, vi mng nng SS = 0.8Tnh ton c th nh sau: +/ Xc nh ti trng tc dng ln mng* Ti trng ng gy nn PDB Tng ti trng ng tnh thm vt liu dn:NHM 1 126 127. B MN CTB-BC GVHD: TH.S- BI TH ANHPDB = Fv = 2402.8 (T) * Ti trng ngang gy mt n nh PDSTng ti trng ngang PDS = FH = 293.955 (T)+/ Xc nh kh nng chu ti ca nn t a) Xc nh cng ca nn t: QDBCng ca nn t c xc nh theo cng thc:QDB = qu.AVi:A: din tch hiu dng ca mngqu: sc chu ti ca mng theo nn t lch tm ca ti trng:e== = 1.23 (m)Trong : M men tc dng ln mng:M = Ms-dc + Mgi = 1956.24+988.28=2944.52 (Tm)Din tch hiu dng ca mng xc nh nh sau A = 2.S = B.LTrong :.R 2eSe. R 2 e2 R 2 .sin 12 R3,14.1021.23 1.23. 102 1.232 102.sin1 2 10= 157 [1.23x9.92 + 12.3]= 132.5NHM 1 127 128. B MN CTB-BCGVHD: TH.S- BI TH ANHA = 2.S = 2x132.5 = 265 (m2) 1 1 1 2 1 2 R e 2 10 1.23 2 L2.S .2 x132.5 x 18.8(m) R e 10 1.23 11 R e 210 1.23 2 B L . 18.8 x 14.6(m) R e10 1.23NHM 1128 129. B MN CTB-BCGVHD: TH.S- BI TH ANH FV FVe M M e=FV a) Ta tro g tng ngin2Be1 = M 1 FVe2 = M 2 FV L1 e1 L e2B b) Die tch hie du g cu a mog ch t n u n a y n nha2Ce= MFV OB = OD LOO 1BDeABc) Die tch hie du g cu a mog tron u n a y n nNHM 1129 130. B MN CTB-BC GVHD: TH.S- BI TH ANHSc chu ti ca mng theo t nn trong trng thi mng chu nn lch tm qu(sc chu ti thot nc) xc nh theo cng thc: quc .N c .K c. X .N q .K q 0,5. .B.N .KTrong : c : lc dnh hu hiu, c = clp 1 = 3.6 (T/m2) Nq, Nc, N : cc hm khng th nguyn ca gc ma st hu hiu = lp 1 = 15o02. Tra bng ta c:Nq Nc No15 023.94 10.982.29 : Dung trng ca t ngp nc = 1.93 1.025 = 0.905 (T/m3) B : b rng mng, B = 14.6m X : su vi mng, n gin thin v an ton X = 0 kc, kq, k : cc h s hiu chnh, c xc nh theo cng thc sau: kc ic .Sc .d c .bc .g c kq iq .S q .d q .bq .g q ki .S .d .b .gTrong : ic, iq, i : cc h s hiu chnh nghing ca ti trngmHiq 1 Q B .L .c.tg1 iqic iq N c .tgm 1Hi1 Q B .L .c.tgNHM 1 130 131. B MN CTB-BCGVHD: TH.S- BI TH ANHH = FH ; Q = Fv ; m mL .cos 2 mB .sin 2 LB22 mLB mB L LvB 1 1 BLFH : gc nghing ca ti trngtg 1 ()FVTnh ton ta c: (rad) mB mLm iq ici 0.18 1.61.5 1.40.87 0.290.7Sc, Sq, S : h s hiu chnh hnh dng mngVi mng n ta xc nh nh sau:Nq 3,51 Sc111,343Nc10, 23 Sq1 tg 1 tg (13, 75) 1, 245 S0, 6dq, dc, d : h s hiu chnh su vi mngX dq1 2.tg (1 sin ) 2 .B d 1 1 dq dcdq N c .tgX dqddc01 11bq, bc, b : h s hiu chnh nghing mt y mngNHM 1 131 132. B MN CTB-BCGVHD: TH.S- BI TH ANH bqb(1.tg ) 21 bq bcbqN c .tggq, gc, g : h s hiu chnh dc ca mt nn t gqg(1 tg ) 21 gq gcgqN c .tgTrong : , l gc nghing ca mng v nn t so vi phng nmngang, gi thit y mng v nn bng phng = = 0 bq bc b gq gc g 00111111Thay cc h s tnh ta nh trn ta c sc chu ti ca mng theo nn tnh sau: Sc chu ti ca mng theo t nn qu = 53.265 (T/m2) Cng ca nn t: QDB = qu.A= 53.265x265 = 14115.2 (T)b) Xc nh sc khng trt cc i ca nn t HDSSc khng trt ngang cc i ca t nn theo API c xc nh theocng thc sau:HDS = c.A + Q.tg Trong :A : din tch y mng c, : lc dnh v gc ma st hu hiu, ly bng lc dnh v gc ma stca lp t di y mng (lp 2).Q : tng ti trng ng gy nn mngNHM 1 132 133. B MN CTB-BCGVHD: TH.S- BI TH ANHKt qu tnh ton: c (rad)A (m2)Q (T) HDS (T/m2)3.60.239983314.159 2013.92 1969.35Kim tra iu kin an ton ca mng v cng :PDB SB QDB (T) SB.QDB(T)iu kin2402.80.67 14115.2 9457.2Tha mnPDS SS HDS (T) SS.HDS(T)iu kin293.955 0.81969.35 1575.48 Tha mnKt lun: Mng m bo an ton theo iu kin v cng Tnh ton kim tra mng theo iu kin v bin dng ( ln):Tnh ln theo phng php cng ln, coi mng dng hnh ch nht:nn iiSSihi gl i 1i 1 EoiTrong :Si : ln ca lp th ii : h s ph thuc v h s n hng ca t (vi t st pha = 0.5 ; st = 0.57)Eoi : m un bin dng ca lp t th ihi : chiu dy lp t th iCng th tnh ng sut gy ln:gl = KR.PglGi thit ti trng phn b u di y mng vi cng Fv 2013.92Ptb6.41(T / m2 )Ax102NHM 1 133 134. B MN CTB-BC GVHD: TH.S- BI TH ANHTi trng gy ln: Pgl = PTb .hm = PTb = 6.41 (T/m2)KR : H s tra bng ph thuc vo t sng sut do ti trng bn thn t c tnh theo cng thc:1 bt i. zi Vi i: trng lng ring y ni ca lp t ngp nc iini : trng lng ring nc bin, n = 1.025 (T/m3)Ta coi im ct ln ti su c bt > 5. glTa c bng tnh ln nh sau: im LpZi(m) bt(T/m2)a/bz/b ko zi(T/m2) tnh 000 101 9 I 1410.84 1 0.20.96048.6436 2718.97 1 0.35 0.84577.6109 3 1129.71 0.55 0.654 5.883 4 1540.51 0.75 0.48564.3704 II5 1951.31 0.95 0.36193.2571 6 2362.11 1.15 0.27492.4737 7 2772.91 1.35 0.21361.922T bng tnh ta thy chiu su tt ln ti phn t th nht ca lp th II. Ta c : Lp I : St pha, trng thi cng.Lp II : St mu xm vng, trng thi cng.NHM 1 134 135. B MN CTB-BC GVHD: TH.S- BI TH ANHP =9T/M2o +0.000 9T/M2 4000 10.84T/M28.6436T/M2 11 3500 -7.00 18.97T/M2 7.6109T/M22 4000 229.7T/M25.8829T/M23 Kt qu tnh ton c trnh by trong bng sau:Tnghi (m) Eo(T/m2) z(T/m2) Si(m) 1 40.8 202414.242 0.0225 2 30.8 202423.032 0.0273 3 40.8 175631.082 0.0566Vy ln bng :S Si 0.1064mNHM 1 135 136. B MN CTB-BC GVHD: TH.S- BI TH ANHNHM 1 136