Transcript
  • 1.2.EB1.2.

  • 1.2.

  • v0E

  • F=0F FF

  • v0E

  • .1LdUBm+qhPP.PD1P

  • 2E=6N/CB=4T6m=410 -3kgq=+510-3CAg10 ms2B2Ef =f= qv0 Bv0 = 2.5m/s

  • +qABAB. FGF3ABt, LB


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