Transcript
1,
1.
2.
6. “” .
:


“”“”





“” “”



2
4
1(20062)
y=exy=f(x)y=x
(A) f(2x)= e2x (xR) (B) f(2x)= ln2lnx (x>0)
(C) f(2x)= 2e2x (xR) (D) f(2x)= ln2+lnx (x>0)
2 (200519)

(2)(1)h(x)
(3)g(x)= f(x+a)αR y=f(x)αh(x)=cos4x
y=f(x)y=g(x)

xDf xDg x
xDf xDg x=1
x1h(x)≥4x=2;
x1h(x)≤0x=0;
∴h(x)
g(x)= f(x+a)h(x) = cos4x = f(x)g(x)
1 cos4x
2




a=2 x1f(x)(∞,1), (1,+∞).
a>2
f(x)>1 f(x)>f(0)
a>2,f(x)f(0)
f(x)>1 f(x)>f(0)=1.
a≤0,x∈(0,1),
e−ax≥1



1(200618)
()
3(200518)
()
{xn}{yn}x1=x2=1y1=y2=2
(λn=234…)
(1)x1x3x5λ
{xn}{yn}x1=x2=1y1=y2=2
(λn=234…)
(3)λ>1
3 (200615)
___________
6
0
-4
-6
-6
-4
0
6
y
4
3
2
1
0
-1
-2
-3
x
ax2+bx+c>0___________

Top Related