Download - 11.3 角平分线的性质
Transcript
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11.3
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1AB=AD,BC=DCA,ABAD,ACAE,AE?
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2 ACDACB AD=AB DC=BC CA=CA ACD ACBSSS CAD=CAB ACDAB
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ONOMCE
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AOC
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1AOB
2OCCDCDAB 3
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(1)AOB (2):.
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OC AOB 1= 2 PD OAPE OB PDO= PEO PDOPEO PDO= PEO 1= 2 OP=OP PDO PEOAAS PD=PE OCAOBPOCPDOADPEOBE: PD=PE(3)
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(4) ?()
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OABEDOCAOB ,P OC,PE=PD??CPPD,PEOA,OB,,
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ABCC=90 ADBACDEABEFACBD=DF CF=EB :CF=EB,,RtCDF RtEDB. BD=DF(),DC=DE () HL.
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1()2 3
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1.OCAOB PD=PEPDOAPEOB
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2.,ABCACBCADBACDEABAB7AC3BEEDCBA
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3.RtABCBDABC DEABEDEAB10BC8AC6BEAEAED