Download - 5.Pilecap P2
-
Data
Mutx = 5.61 kNm H tebal = 500 mmMulx = 5.61 kNm D' = 70 mmMuty = 5.61 kNm Dimensi = 16 mmMuly = 5.61 kNm
Fc = 22 MpaFy = 390 Mpa
dx = 422 mmdy = 406 mm
Atas Xb = 3000 dx = 422
Mn Mu 5.61 0.8
= 7.0125
Rn Mn b * dx2 3000 422
= 0.01312583
m fy 0.85 * fc 0.85 22
= 20.855615
Rasio Tulangan min = 1.4
Fy
= 1.4390
= 0.00358974
b = 0.85 fc600 + fy
= 0.85 22600 + 390
= 0.02470085
Perhitugan Pilecap
0.85 600390
600fy
= = 390
= =
= =7.0125
-
max = 0.75 x b= 0.75 x 0.024701= 0.01852564
aktual = 1 2 m Rnm
= 1 2 20.85561 0.0131320.855615
= 3.3668E-05
0.00358974
As perlu = pakai b dx= 0.00358974 3000 422= 4544.61538
Jarak Antar TulanganS 0.25 d2 b
0.25 3.14 16 3000
= 132.658091 125 mm
Kontrol Terhadap Kapasitas Momen > As perlu
0.25 d2 b > 4544.615 mm
0.25 3.14 16 3000 > 4544.615 mm
> 4544.615 mm
a As ada x fy0.85 fc b
4823.04 x 3900.85 22 3000
= 33.5291551 mm
Mn a2
33.529162
= 762241994 mm= 762.241994 kNm
= 4823.04 390 422 -
=
=
= As ada fy dx -
1254823.04 ok aman
maka jarak antar tulangan
As ada
s
=As perlu
= 4544.62
390
maka pakai adalah min
fy
1 - 1 -
1 - 1 -
-
Mn > Mu / 762.242 > 7.0125
Bawah Xb = 1000 ( diambil per 1 m ) dy = 406
Mn Mu 5.61 0.8
= 7.0125
Rn Mn b * dx2 1000 406
= 0.04254228
m fy 0.85 * fc 0.85 22
= 20.855615
Rasio Tulangan min = 1.4
Fy
= 1.4390
= 0.00358974
b = 0.85 fc600 + fy
= 0.85 22600 + 390
= 0.02470085
max = 0.75 x b= 0.75 x 0.024701= 0.01852564
aktual = 1 2 m Rnm
= 1 2 20.85561 0.04254
fy
1 - 1 -
1 - 1 -
0.85 600390
600fy
= = 390
= =
= =7.0125
ok aman
-
20.855615
= 0.00010921
0.00358974
As perlu = pakai b dx= 0.00358974 1000 406= 1457.4359
Jarak Antar TulanganS 0.25 d2 b
0.25 3.14 16 1000
= 137.885996 125 mm
Kontrol Terhadap Kapasitas Momen > As perlu
0.25 d2 b > 1457.436 mm
0.25 3.14 16 1000 > 1457.436 mm
> 1457.436 mm
a As ada x fy0.85 fc b
1607.68 x 3900.85 22 1000
= 33.5291551 mm
Mn a2
33.529162
= 244048742 mm= 244.048742 kNm
Mn > Mu / 244.0487 > 7.0125 ok aman
= 1607.68 390 406 -
=
=
= As ada fy dx -
1251607.68 ok aman
maka jarak antar tulangan
As ada
s
=As perlu
= 1457.44
390
maka pakai adalah min
1 - 1 -
-
Data
Mutx = 5.61 kNm H tebal = 500 mmMulx = 5.61 kNm D' = 70 mmMuty = 5.61 kNm Dimensi = 12 mmMuly = 5.61 kNm
Fc = 22 MpaFy = 390 Mpa
dx = 422 mmdy = 410 mm
Atas Yb = 3000 dx = 422
Mn Mu 5.61 0.8
= 7.0125
Rn Mn b * dx2 3000 422
= 0.01312583
m fy 0.85 * fc 0.85 22
= 20.855615
Rasio Tulangan min = 1.4
Fy
= 1.4390
= 0.00358974
b = 0.85 fc600 + fy
= 0.85 22600 + 390
= 0.02470085
0.85 600390
600fy
7.0125
= = 390
= =
= =
-
max = 0.75 x b= 0.75 x 0.024701= 0.01852564
aktual = 1 2 m Rnm
= 1 2 20.85561 0.01320.855615
= 3.3668E-05
0.00358974
As perlu = pakai b dx= 0.00358974 3000 422= 4544.61538
Jarak Antar TulanganS 0.25 d2 b
0.25 3.14 16 3000
= 132.658091 125 mm
Kontrol Terhadap Kapasitas Momen > As perlu
0.25 d2 b > 4544.615 mm
0.25 3.14 16 3000 > 4544.615 mm
> 4544.615 mm
a As ada x fy0.85 fc b
4823.04 x 3900.85 22 3000
= 33.5291551 mm
Mn a2
33.529162
= 762241994 mm= 762.241994 kNm
4823.04 390 422 -
As ada fy dx -
=
=
=
=
1254823.04 ok aman
maka jarak antar tulangan
As ada
s
=As perlu
= 4544.62
1 - 390
maka pakai adalah min
1 - fy
1 -
1 -
-
Mn > Mu / 762.24 > 7.0125
Bawah Yb = 1000 ( diambil per 1 m ) dy = 406
Mn Mu 5.61 0.8
= 7.0125
Rn Mn b * dx2 1000 406
= 0.04254228
m fy 0.85 * fc 0.85 22
= 20.855615
Rasio Tulangan min = 1.4
Fy
= 1.4390
= 0.00358974
b = 0.85 fc600 + fy
= 0.85 22600 + 390
= 0.02470085
max = 0.75 x b= 0.75 x 0.024701= 0.01852564
aktual = 1 2 m Rnm
= 1 2 20.85561 0.0431 -
1 - fy
1 -
1 -
0.85 600390
600fy
7.0125
= = 390
= =
= =
ok aman
-
20.855615
= 0.00010921
0.00358974
As perlu = pakai b dx= 0.00358974 1000 406= 1457.4359
Jarak Antar TulanganS 0.25 d2 b
0.25 3.14 16 1000
= 137.885996 125 mm
Kontrol Terhadap Kapasitas Momen > As perlu
0.25 d2 b > 1457.436 mm
0.25 3.14 16 1000 > 1457.436 mm
> 1457.436 mm
a As ada x fy0.85 fc b
1607.68 x 3900.85 22 1000
= 33.5291551 mm
Mn a2
33.529162
= 244048742 mm= 244.048742 kNm
Mn > Mu / 244.05 > 7.0125
1607.68 390 406 -
ok aman
As ada fy dx -
=
=
=
=
1251607.68 ok aman
maka jarak antar tulangan
As ada
s
=As perlu
= 1457.44
1 - 390
maka pakai adalah min
1 -
