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  • Bi 1: Find the specific volume of n-butane at 393.3 K and 16.6 atm using the RedlichKwong EOS.

    Phng trnh Redlich-Kwong EOS cho thnh phn tinh khit:

    Sau khi bin i, phng trnh tr thnh:

    v cc thng s:

    Tra Perry's Chemical Engineers' Handbook cho n-butane, ta tm c cc gi tr:

    Tc= 425.12 K, pc= 3.770E+06 Pa= 37.2 atm (1 atm = 101325 Pa)

    Gi tr R= 0.08206 Latm/(g mol K)

    Bi 2: Khc du thang o bnh cha Cho bi ton c bn cha hnh cu r= 5 m hy lp mt thang o th tch ng vi chiu cao ca mc cht lng trong bnh.

    a. L Thuyt tnh ton:

    Bi ton y t ra yu cu. Trong thc t sn xut thong thng ngi ta ch c th xc nh chiu cao mc cht lng ri sau tnh xem th tch cht lng lc ny l bao nhiu. Nhng tin li ngi ta s tnh ton v khc ln trn bnh mt thang o th tch tng ng vi chiu cao m th tch cht lng t c thong qua mt php tnh.

    Nhim v ta l xc lp mt dy chiu cao tng ng vi mt dy th tch:

  • v(m3) 50 100 20 300 400 500

    h(m) ? ? ? ? ? ?

    Bi 3: Mt vch tng thu nhit t ngun bc x sau truyn nhit t b mt vch ra mi trng khng kh bng hnh thc i lu. Ga s khng mt mt nhit, bit nhit mi trng 300K th nhit vch l bao nhiu. Cc thng s khc t cho.

    a.L thuyt

    Qa trnh truyn nhit xy ra 3 qu trnh vi iu kin:

    -Xem nh khng c tn tht nhit

    -Nhit khng truyn qua vch trong m ch i lu khng kh

    -Vch ch nhn nhit duy nht t ngun bc x

    Cn bng nhit :

    Nhit lng m vch thu c:

    q1= *F**(TR4-T4)

    = 5.67*10^-8 W/(m2K4)h s Stefan-Boltzman

    F= 1 m2 din tch truyn nhit.

    = 1 hiu sut truyn nhit.

    TR : nhit ngun bc x. Cho TR = 1000 K

    T : nhit vch. Cn tm.

    Vy q1= **(TR4-T4)

    T TR

    Tmt

  • Nhit lng mt i :

    q2= h*(T-Tmt)

    h: h s cp nhit i lu. Cho h= 800 W/(m2*K)

    Tmt: nhit mi trng. Tmt= 300 K

    Bi 4:

    Lp bng tnh Excel gii phng trnh phi tuyn bng phng php chia i

    Bi 5 : Bi ton chng n gin

    The vapor pressure of the pure substance

    10 = 1

    + 1

    20 = 2

    + 2

    The constant is characteristic for substance and can find in the handbook

    The vapor pressure of the substances in the solution obey Raoults Law

    1 = 110 2 = 220

    is the mole fraction in the liquid phase

    a1, b1 : -3330 17.403

    a2, b2 : -3810 17.785

    P [mmHg]

    Ptotal=760

    Number of plates: 6

    Mole fraction at first plate: 0.1

    Establish the model for this problem

    Find the mole fraction at each plate.

    Bi 2: Khc du thang o bnh cha


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