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СОУ ГИМНАЗИЈА“МИРЧЕ АЦЕВ“-ПРИЛЕП
>>БРАК, СЕМЕЈСТВО, РАЗВОД
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СОДРЖИНА
# ВОВЕД%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%#
! БРАК%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%!
$ БРАКОТ ВО &РИСТИЈАНСТВОТО%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%$
' СЕМЕЈСТВО%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%'
'%# П()* + .*./01(%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%'
'%! В)2(1) 3 4(201( 1( .23( .*./01(%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
'%$ О67)8) 3 .*./01(%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
5 РАЗВОД%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%9
ЗАКЛУЧОК%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%;
9 КОРИСТЕНА ЛИТЕРАТУРА%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
#
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1 ВОВЕД
С.*./01(0( . 3.+*.37)1 4.2)3 1( =(/ (1.=(0 . ?(4*)4 ==( 7)3(0, 1(=(/ @)1.. +2(1(7A1/B) C) 3.=() (2 1()0. 3/1@3) D(04.6) =() *(@0 2 6)20
+2(1(7.3) *( 1( .*./01(0(%
С.*./01(0( . D.8)?)3 6)(-(8)/73 +.23)8 3 7AE.% Т )* *3(CA
+3/3 A7(C 1( 4+1(/(0 3 (1.=(0, 3( 3. *( 3 (1.=(0 0A=A ) 3 (DF0.01(0(
1((DF0(% С.*./01(0( . +0D3)= *.EA (DF0.01(0( ) D(.2)3.8(0, 3( .*./01(0(
14F) D(1.B. ?A3=8)) (2 6)7( =(/ 24AC (DF0.01.3 C4AD% С( ?(4*)4G.0( 3
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3.C(1(0( @)1..G.%
!
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2 БРАК
Б4=(0 D4.001A1 +.23)8 3 21. )7) D(1.B. 7)8 (2 4+7).3 D(7 ) ==(
0=1 D4.001A1 (3(1 + C42.G. 3 .*./01(% М@)0. 1( 64=(0 AF0. .
34.=A10 ) (D4AC, @.3)0. (D4AC%
Б4=(0 *(@. 2 6)2. 2(64(1(7.3 - =(C 643)0. D403.4) *), D( 1(/ 1(7/
. 4.F10 2 / ?(4*)40 +.23)80, )7) 2(C(1(4.3 - D( 37(C 3 24AC) 7)8,
3/.0( 4(2)0.7)0. 3 643)0. D403.4) )7) D(F)4(=)(0 .*..3 =4AC, .*./3)(0
04.F)3, D7.*.3=)(0 04.F)3 ) 03%
В( 2.3.F3( 14.*. 64=(0 .0( . D()0(1.0A1 ( 3.(?)8)/73)0. +.23)8) 3
)0(D(7(1) .2)3=), 3( 0=1)0. +.23)8) 3. *(@0 2 . 34.0 64= D(42)
6)(7(F=0 D4..3(0 2 )+C420 .*./01( H+.23)8 3 4(2)0.7 ) D(0(*01(% Б4=
) J(*(.=A73 +.23)8 . +.23)8) =() . 4+7)3) D( 8.7 ) *)7, D(42) F0( )
. =(4)00 21 0.4*)3%
Б4=(0, (1.3 (8)(7(F=, )* ) 4.7)C)(+3 D4)4(2%
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3 БРАКОТ ВО ХРИСТИЈАНСТВОТО
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4/(0 / (1.0)7 6430 14= =(C C( 67C(7(1)7 А2* ( Е1% С*0 0/3 .
)+14FA1 1( 4.2)30 3 84=10, D4.2 С1.0)(0 К40 ) С1.0(0( Е13C.7).% Д1. 1@3)
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• 1..3 )+/1 3 *72(@.3.8(0 ) 3.1.00 D4.2 84=10 2.= 7(6(23(
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*@(0 ) @.30 . =4A3)A10 .2.3 ( 24AC, “и двајцата постануваат едно тело“%
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• К413( 4(201( )7) D4)4(23( 4(201( =(. . +3(1A1 14+ 4EG.
• С10(1=( 4(201( =(. . (+21 ( @.3)26 )7) *@.G.
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• ДAJ(13( 4(201( H=A*, 2.1.4, 04(10, D(640)*
О#$и%и !а семејство
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.*./01(:
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+.23)=( D(0.=(7% Д.80 . (24.2A10 D( */)3 7)3)/ ) 1( (3(1 .
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)0. 2.8 ==( 2 . 3.C(1)% С03A1 +6(4 + *04)/4J0.3 (67)= 3
.*./01(%
• С.*./3 2(*B)3= +.23)8 =(/ . =4=0.4)+)4 ( D(/1 3
00=(1=( .*./1(, D04)/4J0%
• П04)/4J73( =(3/AC73( .*./01( . =4=0.4)+)4 ( D(0(.G. 3
04.F)3 =(/ )* D(7A03 170 ) 0(/ (27AA1 + .% О1(/
D04)/4J7.3 04.F)3 C( )+6)40 00=(18)0. 3. .*./010 =() .
D(2 3.C1 +F0)0 ) 1(201(%
• И32)1)2A73( =(3/AC73( .*./01( . .*./01(0( =(. . 0)D)3( +
*(2.43(0( (DF0.01(% О1 +.23)8 . *(3(C*3 ) / )30 3/67)=)
4(23)8), 4(2)0.7) ) 2.8%
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• т"аи%ио!а$!о семејство- 0A= A7(C)0. . D(2.7.3) D(4.2 1(+40 ) D(7(0%
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==1) D41 ) (614=) )*0 *@)0. ==1) @.3)0.%
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• &ат"ија"'а$!о M D()1 3 1413)(0 ) 3.D4)=(3(1.3 10(4)0.0 3 C710 3
.*./01(0(-00=(0(%
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C.3.48)) . 1( =72 ( =7(3(0)0. ) D((63(0)0. 3 1()0. 7.3(1)%
• !-*$е"!о M (1 .*./01( . (01.3( (2 4(2)0.7) ) 2.8 ) . =4=0.4)0)3( +
(14.*.3(0( 2(6%
• &"о.и"е!о- (1 .*./01( . ()3.0( (2 D(67)=) ) D(27.3) 4(23)8) =()
@)1.0 D(2 +.23)=) D(=4)1%
• &от&о$!о M 0( . .*./01( (01.3( (2 (D4A@3)8) ) 2.8%
• !е&от&о$!о M0A= 3.2(0A1 .2.3 (2 (D4A@3)8)0.-4(2)0.7%
Г713( +3.G. 3 64=(0 . +.23)=)(0 @)1(0 3 (D4A@3)8)0., 7)=(1)0(
D4)=@3( ==( “2.7.G. 3 *0 ) D(0.70“% В( *(2.43)0. +D23) +.*/) . *.02.= (D4A@3)8)0. ( 0DA1G. 1( 64= C) 3DAF00 1()0. 2(0(CF3) .*./01 )
?(4*)40 3(1( .*./01( )7) 2(*B)301(% В( )2.73) A7(1) 0( . D(0)C3A1 0=
F0( 3(1(?(4*)43(0( .*./01( . 1.7A1 1( 1(/ =AB )7) 03% В( 042)8)(373)
4.2)3), *.EA0(, FD(.0 . 7A/(0 2 @.30 . D4)24A@A1 =(3 .*./01(0( 3
(D4AC(0, 1( 3.=() 7A) =(C 03A1 +6(4 + *04)/4J03) +.23)8), (D4AC(0 .
D4)24A@A1 =(3 .*./01(0( 3 @.30%
В( 3.=() 7A) (3.1(+*(@.3( . 3)13(0( +.23)=( @)1..G., 3/.0( (2
(6/.=0)13) D4))3), ==( F0( . 6(7.0, +01(4= =+3 )7) 2(7C(04/3( (0A101( 3
.2.3 (2 D403.4)0. +42) 46(0% В( 3.=() 7A) 643)0. 24AC4) @)1.0 (21(.3(
(2 ?)33)=) D4))3), (23(3( (2 3.*(@3(0 2 01(40 (D01.3( 2(*B)301(L
)7*(0 0=1 )0A8)/ / D4)+31 1( D(.63 )30)0A8)/ Н)= М)/4, (23(3(
64.3 2(C(1(4 ( =(/ (D4A@3)8)0. . (0=@A10 (2 2(7@3(0)0. 3 +.23)=)(0
@)1(0% В@3(0 3 +.23)=)(0 @)1(0 *3(CA *(2.43) +=(3(2101C( 3C7A10 (
0( F0( C( *.00 ==( 2(=+ + )D413(0 3 64=(0 =(C 0(/ D4.001A1 (3(1 +
3.=() D41 )7) D4)1)7).C)), ==( F0( .3 D4% (8)/73 D(*(F )7) D41( 3
043=) 24@1/3)3 2 @)1.. 1( +.*/0 3 1(/(0 D403.4%
/ РА0ВОД
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D4) D(3)F0A1G.0(, 1.23F D(7. 0(/ )3 D403.4)0. 1.B. 3.*0 3)==1) D41 )
9
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(614=) .2.3 =(3 24AC% О2 D()*(0 4+1(2, 4+7).3 . ) D(*(0 4+2.76, D4) F0(
(D4A@3)8)0. D(1.B. 3. @)1.0 +.23( 3( 64=(0 )* . .AF0. 17)2.3% П(0(/0 )
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)30.4. 3 D(0(*01(0(%
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1( *3(CA 24@1) ( (1 1.4()D(1.0, 4+1(2(0 . 4.70)13( 2(83 1(1.2.3 1( 3)13)0.
D413) )0.*), 3 D4% HИ07)/, ND3)/, П(40AC7)/ ) И4= .AF0. 3. .
2(+1(7.3 3 М70 ) Н Ф)7)D)3)0.%
Р+1(2(0 3 64=(0 . D(7.2)8 3 2(7C(04/3 3.7(C ) =(3?7)=0) *.EA
D403.4)0.% Д( 4+1(2 2(E =(C *.EA.63)(0 (23( 3. C( +2(1(7A1 .2.3 )7) 21/80
D403.4), 2( 0 *.4 F0( 0). 1.B. 3. *(@0 2 @)1.0 +.23( D(2 0). A7(1)% 4+1(2(0
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В( D(7.23)0. C(2)3) 1( 4+4.FA1G.0( 3 D4(67.*)0. ( D403.4(0 . D(1.B.
. 1=7AA10 643) (1.0A17)F0, 1( =() 3/3D4.2 . D410 (6)2) + 32*)3A1G.
3 D4)(67.*)0. ) D4(2(7@A1G. 3 +.23)=)(0 @)1(0, ) 3*7A1G. 3 F0.00 F0(
/ D4))3A1 4+1(2(0, 2(=(7=A . 3.*)3(1.3%
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5 КОРИСТЕНА ИТЕРАТРА
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