Unit Operations Chapter 5. Incompressible Flow in Pipes and Channels
Chapter 5. Incompressible Flow in Pipes and Channels
Shear Stress and Skin Friction in Pipes (전단응력및표면마찰)
* Shear-stress distribution
For fully developed flow,
∑ ←=∴==
0&
FVV abab ββ
from Eq. (4.51):
0=−+−∑ = gwbbaa FFSpSpF
( )aabb VVmF ββ −∑ = &
From Eq. (4.52),
sF−=
Unit Operations Chapter 5. Incompressible Flow in Pipes and Channels
0)2()(22 =−+−∑ = τπππ rdLdpprprF
02=+
rdLdp τ
--- Eq. (5.1)
로나누면dLr2π
단면적방향으로의압력은일정)r과는무관 (관의
ww rr == at& ττ
02=+∴
w
wrdL
dp τ--- Eq. (5.2)
Eq. (5.2)에서 Eq. (5.1)을빼면,
or rrw
w⎟⎟⎠
⎞⎜⎜⎝
⎛=
ττrrw
w ττ=
Unit Operations Chapter 5. Incompressible Flow in Pipes and Channels
* Relation between skin friction & wall shear
펌프에의한일이없고마찰을고려할경우의 Bernoulli 방정식은
fbb
bbaa
aa hVgZpVgZp
+++=++22
22 αρ
αρ
일반적으로 pa > pb이므로 로표시할
--- Eq. (4.71)
수있고 fully developed flow인
수평관을대상으로하며마찰은유체와관벽사이의 skin friction hfs만존재하므로
ppp ab ∆−=
sababab ppZZVV ∆=∆=== &,,, αα (압력강하는표면마찰에의한것이므로)
이경우 Bernoulli 식은
fss
fssaa hphppp
=∆
+∆−
=ρρρ 즉, --- Eq. (5.4)
From Eq. (5.2), 02=+
∆−
w
wsrL
p τ
LD
Lr
h w
w
wfs
τρ
τρ
42==∴
를소거하면sp∆
Unit Operations Chapter 5. Incompressible Flow in Pipes and Channels
* Friction factor (마찰계수), f
여기서정의하는마찰계수 f 는 Fanning friction factor
또다른마찰계수로 Blasius or Darcy friction factor가있는데이는 4f 에해당
222
2/ VVf ww
ρτ
ρτ
=≡ --- Eq. (5.6)
wall shear stressdensity × velocity head
(단위면적당전단력)(단위부피당운동에너지)즉,
skin friction hfs와 friction factor f와의관계:
242 2V
DLfpL
rh s
w
wfs =
∆==
ρτ
ρ--- Eq. (5.7)
22 VLDpf s
ρ∆
=∴DVf
Lps
22 ρ=
∆ --- Eqs. (5.8)-(5.9)or
Unit Operations Chapter 5. Incompressible Flow in Pipes and Channels
* Flow in noncircular channels
In evaluating the diameter in noncircular channels, an equivalent diameter (등가지름)
Deq is used.
rH : hydraulic radius (수력학적반지름)Heq rD 4=
pH L
Sr ≡ S : cross-sectional area of channelLp : wetted perimeter
44/2 D
DDrH ==π
π4
4/4/ 22io
oi
ioH
DDDDDDr −
=+−
=ππππ
Deq=Do-Di
44
2 bb
brH ==
Deq=bDeq=D
1) Circular tube: 2) Annular pipes: 3) Square duct:
단면이원형이아닌관의경우 Reynolds number Re또는 friction factor f등의계산시에
D대신 Deq혹은 r 대신 2rH를대입하여계산가능함을의미.
Unit Operations Chapter 5. Incompressible Flow in Pipes and Channels
Laminar Flow in Pipes and Channels
* Laminar flow of Newtonian fluids
원형단면을갖는흐름을대상, 속도분포는 centerline에대해대칭
u depends only on r
rrdr
du
w
wµ
τµτ
−=−=
drduµτ −=
Eq. (5.3) 적용r
zcenterline
wall
적분하면 (경계조건: )wrru == at0
( )22
2rr
ru w
w
w −=µ
τ∫∫ −= rr
u
w
ww
rdrr
du0 µτ --- Eq. (5.15)
2
max1 ⎟⎟
⎠
⎞⎜⎜⎝
⎛−=∴
wrr
uu)0at(
2max == rru wwµ
τ --- Eq. (5.17)
Unit Operations Chapter 5. Incompressible Flow in Pipes and Channels
Average velocity
--- Eq. (4.11)∫= udSS
V 1
Eq. (5.15) 대입한후적분
rdrdS π2=
( )µ
τµ
τ40
223
wwrw
w
w rrdrrrr
V w =∫ −= --- Eq. (5.18)
이식을 와비교하면, µτ2max
wwru = 5.0max
=u
V --- Eq. (5.19)
In Laminar flow,
Kinetic energy correction factor,
Momentum correction factor,
0.2=α Eq. (4.70)에 (5.15)와 (5.18)을대입해계산
34
=β Eq. (4.50)에 (5.15)와 (5.18)을대입해계산
Unit Operations Chapter 5. Incompressible Flow in Pipes and Channels
Hagen-Poiseuille equation
--- Eq. (5.20)µL
DpV s32
2∆=
Eq. (5.7)과 Eq. (5.18)을이용하여 대신보다실제적인 로변환하면,wτ sp∆
232
DVLpsµ
=∆or
VDq4
2π=여기서 이므로 q 와 측정으로부터점도계산가능:sp∆
qLDps
128
4∆=πµ : Hagen-Poiseuille equation
)/(4 DLp ws τ=∆또한 Eq. (5.7)에서 이므로,
DV
wµτ 8
= --- Eq. (5.21)
Eq. (5.21)을 Eq. (5.7)에대입하면 f와 Re 사이의관계가유도됨:
Re1616
==ρµ
VDf --- Eq. (5.22)
Unit Operations Chapter 5. Incompressible Flow in Pipes and Channels
* Laminar flow of non-Newtonian liquids
- Power law fluids
반지름 r에따른 velocity profile:
Fig. 5.4. Velocity profiles in the laminar flowof Newtonian and non-Newtonianliquids.
n
drduK−=τ
nrr
Kru
nnw
n
w
w/11
/11/11/1
+−
⎟⎟⎠
⎞⎜⎜⎝
⎛=
++τ
Unit Operations Chapter 5. Incompressible Flow in Pipes and Channels
- Bingham model
o
oo
drdu
drduK
ττ
ττττ
<=
>−=−
at0
at
반지름 r에따른 velocity profile:
( ) ⎥⎦
⎤⎢⎣
⎡−⎟⎟
⎠
⎞⎜⎜⎝
⎛+−= 01
21 ττ
w
ww r
rrrK
u
Fig. 5.5. (a) Velocity profile and(b) Shear diagramfor Bingham plastic flow
- Some non-Newtonian mixtures at high shear violate the zero-velocity (no-slip) b. c.ex) multiphase fluids (suspensions, fiber-filled polymers) “slip” at the wall
Unit Operations Chapter 5. Incompressible Flow in Pipes and Channels
Turbulent Flow in Pipes and Channels
viscous sublayer (점성하층):viscous shear ↑, eddy ×
buffer layer (완충층) or transition layer (전이층):viscous shear & eddy 공존
turbulent core (난류중심부):viscous shear ↓, eddy diffusion ↑
C.L.
wall
viscous sublayer buffer layer
turbulent core
Velocity profile for turbulent flow:
much flatter than that for laminar flow
Eddies in the turbulent core: large but low intensity
in the buffer layer: small but high intensity
Most of the kinetic-energy content of the eddies lies in the buffer zone.
C.L.
wall
laminar flowturbulent flow
Re ↑
Unit Operations Chapter 5. Incompressible Flow in Pipes and Channels
* Velocity distribution for turbulent flow
In terms of dimensionless parameters
ρτµµ
ρ
ρτ
w
w
yyuy
uuu
fVu
=≡
≡
=≡
+
+
*
*
*2
: friction velocity
: velocity quotient (무차원)
: distance (무차원) y : distance from tube wall
Re based on u* & y)( yrrw +=∴
* Universal velocity distribution equations
i) viscous sublayer:
ii) buffer layer:
iii) turbulent core:
++ = yu05.3ln00.5 −= ++ yu
5.5ln5.2 += ++ yu
intersection으로부터
for viscous sublayer
for buffer zone
for turbulent core
5<+y
305 << +y
30>+yRe > 10,000 이상에서적용가능
Unit Operations Chapter 5. Incompressible Flow in Pipes and Channels
* Relations between maximum velocity
& average velocity V
When laminar flow changes to turbulent,
the ratio changes rapidly
from 0.5 to about 0.7,
& increases gradually to 0.87 when Re=106.
max/uV
maxu
For laminar flow, is exactly 0.5.max/uVfrom Eq. (5.19)
* Effect of roughness
Types of roughness
Rough pipe larger friction factor
k : roughness parameter
k/D : relative roughness
For laminar flow, roughness has no effect
on f unless k is so large.
Dkf /&Reofnft'=∴
Unit Operations Chapter 5. Incompressible Flow in Pipes and Channels
* Friction factor chart
↑Dk /
Friction factor plot for circular pipes (log-log plot)
Unit Operations Chapter 5. Incompressible Flow in Pipes and Channels
* Friction factor for smooth tube* Drag reduction
Dilute polymer solutions in waterdrag reduction in turbulent flow
Application: fire hose (a few ppm of PEO in water can double the capacity of a fire hose)
632.0
62.0
103Re000,3forRe
125.0014.0
10Re000,50forRe046.0
×<<+=
<<= −
f
f
(wide range)
* Non-Newtonian fluids
↑ppm↑n
Unit Operations Chapter 5. Incompressible Flow in Pipes and Channels
* Friction loss from sudden expansion
Ke can be calculated theoretically from the momentum balance equation (4.51) and the Bernoulli equation (4.71).
2
2a
efeVKh =
: average velocity of smaller or upstream section)Ke : expansion loss coefficient
aV
2
1 ⎟⎟⎠
⎞⎜⎜⎝
⎛−=
b
ae S
SK for turbulent flow ( )1&1 ≅≅ βα
3/4&2 == βαLaminar flow인경우에는 을사용하면 Ke를구할수있다.
Unit Operations Chapter 5. Incompressible Flow in Pipes and Channels
* Friction loss from sudden contraction
cross section of minimum area
2
2b
cfcVKh = : average velocity of smaller or downstream section)
Kc : contraction loss coefficientbV
Kc < 0.1 for laminar flow hfc is negligible.
⎟⎟⎠
⎞⎜⎜⎝
⎛−=
a
bc S
SK 14.0 for turbulent flow (empirical equation)
Unit Operations Chapter 5. Incompressible Flow in Pipes and Channels
* Friction loss from fittings
2
2a
fffVKh = : average velocity in pipe leading to fitting
Kf : fitting loss coefficientaV
Table 5.1 Loss coefficients for standard pipe fittings
24
2VKKKDLfh fecf ⎟
⎠⎞
⎜⎝⎛ +++=
skin friction loss coeff.fitting loss coeff.
expansion loss coeff.contraction loss coeff.
Bernoulli equation without pump: ( ) fbaba hZZgpp
=−+−ρ
* Total friction
대입
Ex. 5.2) Homework
Unit Operations Chapter 5. Incompressible Flow in Pipes and Channels
05.0≈cK
To minimize expansion loss, the angle between the diverging walls of a conical expander must be less than 7o.
For angles > 35o The loss through this expander can become greater than that through a sudden expansion.
separation point (분리점)
Separation of boundary layer in diverging channel
* Minimizing expansion and contraction losses
. Contraction loss can be nearly eliminated by reducing the cross section gradually.
In this case, separation & vena contracta do not occur.
. Expansion loss can also be minimized by enlarging the cross section gradually
Unit Operations Chapter 5. Incompressible Flow in Pipes and Channels
* Flow through parallel plates (Prob. 5.1 & 5.3과연관)
In laminar flow between infinite parallel plates,
yx
W
L
bpa pb
2yτ
τ
upper plate
lower plate
flow
212
bLVpp ba
µ=− 임을보이고 를구하시오.maxmax /,/ uVuu
LWyWpyWp ba τ222 =−(풀이) Force balance: from Eq. (4.52)
yLpp ba τ
=−
dyduµτ −=
대입
Unit Operations Chapter 5. Incompressible Flow in Pipes and Channels
∫−=∫− uy
bba dudyy
Lpp
02/)(
µ
적분하면,
( ) 2
max 22⎟⎠⎞
⎜⎝⎛−
=∴b
Lppu ba
µ
b.c. 대입(umax at y=0)
⎟⎟⎠
⎞⎜⎜⎝
⎛−⎟
⎠⎞
⎜⎝⎛−
= 22
22)( yb
Lppu ba
µ
( )L
bpp
dyuWbW
dSuS
V
ba
a
µ12
11
2
2/0
−=
∫∫ ==
212
bLVpp ba
µ=−∴
⎟⎟
⎠
⎞
⎜⎜
⎝
⎛⎟⎟⎠
⎞⎜⎜⎝
⎛−=∴
2
max )2/(1
by
uu
32
max=∴
uV
Related problems:
(Probs.) 5.4, 5.8, 5.10, 5.12, 5.13, 5.17, 5.20 and 5.21