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Page 1: Day 3 of Free Intuitive Calculus Course: Limits by Factoring
Page 2: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 1

Page 3: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 1

Let’s consider the limit:

Page 4: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 1

Let’s consider the limit:

limx→2

x2 − 4

x − 2

Page 5: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 1

Let’s consider the limit:

limx→2

x2 − 4

x − 2

We note that at x = 2, our function is indeterminate.

Page 6: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 1

Let’s consider the limit:

limx→2

x2 − 4

x − 2

We note that at x = 2, our function is indeterminate.It equals 0

0 !.

Page 7: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 1

Let’s consider the limit:

limx→2

x2 − 4

x − 2

We note that at x = 2, our function is indeterminate.It equals 0

0 !.But we can factor:

Page 8: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 1

Let’s consider the limit:

limx→2

x2 − 4

x − 2

We note that at x = 2, our function is indeterminate.It equals 0

0 !.But we can factor:

limx→2

x2 − 4

x − 2=

Page 9: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 1

Let’s consider the limit:

limx→2

x2 − 4

x − 2

We note that at x = 2, our function is indeterminate.It equals 0

0 !.But we can factor:

limx→2

x2 − 4

x − 2= lim

x→2

Page 10: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 1

Let’s consider the limit:

limx→2

x2 − 4

x − 2

We note that at x = 2, our function is indeterminate.It equals 0

0 !.But we can factor:

limx→2

x2 − 4

x − 2= lim

x→2

(x − 2)(x + 2)

x − 2

Page 11: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 1

Let’s consider the limit:

limx→2

x2 − 4

x − 2

We note that at x = 2, our function is indeterminate.It equals 0

0 !.But we can factor:

limx→2

x2 − 4

x − 2= lim

x→2

����(x − 2)(x + 2)

���x − 2

Page 12: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 1

Let’s consider the limit:

limx→2

x2 − 4

x − 2

We note that at x = 2, our function is indeterminate.It equals 0

0 !.But we can factor:

limx→2

x2 − 4

x − 2= lim

x→2

����(x − 2)(x + 2)

���x − 2

= limx→2

(x + 2)

Page 13: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 1

Let’s consider the limit:

limx→2

x2 − 4

x − 2

We note that at x = 2, our function is indeterminate.It equals 0

0 !.But we can factor:

limx→2

x2 − 4

x − 2= lim

x→2

����(x − 2)(x + 2)

���x − 2

= limx→2

(x + 2) = 2 + 2 =

Page 14: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 1

Let’s consider the limit:

limx→2

x2 − 4

x − 2

We note that at x = 2, our function is indeterminate.It equals 0

0 !.But we can factor:

limx→2

x2 − 4

x − 2= lim

x→2

����(x − 2)(x + 2)

���x − 2

= limx→2

(x + 2) = 2 + 2 = 4

Page 15: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 1

Page 16: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 1

What is the graph of this function?

Page 17: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 1

What is the graph of this function?

f (x) =x2 − 2

x + 2

Page 18: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 1

What is the graph of this function?

f (x) =x2 − 2

x + 2

Page 19: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 1

What is the graph of this function?

f (x) =x2 − 2

x + 2

It is the graph of x + 2, but with a hole!

Page 20: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 2

Page 21: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 2

limx→1

x3 − 1

x − 1

Page 22: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 2

limx→1

x3 − 1

x − 1

Remember how to factor the numerator?

Page 23: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 2

limx→1

x3 − 1

x − 1

Remember how to factor the numerator?

limx→1

x3 − 1

x − 1=

Page 24: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 2

limx→1

x3 − 1

x − 1

Remember how to factor the numerator?

limx→1

x3 − 1

x − 1= lim

x→1

Page 25: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 2

limx→1

x3 − 1

x − 1

Remember how to factor the numerator?

limx→1

x3 − 1

x − 1= lim

x→1

(x − 1)(x2 + x + 1)

x − 1

Page 26: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 2

limx→1

x3 − 1

x − 1

Remember how to factor the numerator?

limx→1

x3 − 1

x − 1= lim

x→1

����(x − 1)(x2 + x + 1)

���x − 1

Page 27: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 2

limx→1

x3 − 1

x − 1

Remember how to factor the numerator?

limx→1

x3 − 1

x − 1= lim

x→1

����(x − 1)(x2 + x + 1)

���x − 1

= limx→1

(x2 + x + 1

)

Page 28: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 2

limx→1

x3 − 1

x − 1

Remember how to factor the numerator?

limx→1

x3 − 1

x − 1= lim

x→1

����(x − 1)(x2 + x + 1)

���x − 1

= limx→1

(x2 + x + 1

)= 12 + 1 + 1

Page 29: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 2

limx→1

x3 − 1

x − 1

Remember how to factor the numerator?

limx→1

x3 − 1

x − 1= lim

x→1

����(x − 1)(x2 + x + 1)

���x − 1

= limx→1

(x2 + x + 1

)= 12 + 1 + 1 = 3

Page 30: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 3

Page 31: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 3

limh→0

(a+ h)3 − a3

h

Page 32: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 3

limh→0

(a+ h)3 − a3

h

Here a is a constant. Let’s expand (a+ h)3:

Page 33: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 3

limh→0

(a+ h)3 − a3

h

Here a is a constant. Let’s expand (a+ h)3:

limh→0

a3 + 3a2h + 3ah2 + h3 − a3

h

Page 34: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 3

limh→0

(a+ h)3 − a3

h

Here a is a constant. Let’s expand (a+ h)3:

limh→0

��a3 + 3a2h + 3ah2 + h3 −��a3

h=

Page 35: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 3

limh→0

(a+ h)3 − a3

h

Here a is a constant. Let’s expand (a+ h)3:

limh→0

��a3 + 3a2h + 3ah2 + h3 −��a3

h=

limh→0

3a2h + 3ah2 + h3

h

Page 36: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 3

limh→0

(a+ h)3 − a3

h

Here a is a constant. Let’s expand (a+ h)3:

limh→0

��a3 + 3a2h + 3ah2 + h3 −��a3

h=

limh→0

3a2h + 3ah2 + h3

h= lim

h→0

Page 37: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 3

limh→0

(a+ h)3 − a3

h

Here a is a constant. Let’s expand (a+ h)3:

limh→0

��a3 + 3a2h + 3ah2 + h3 −��a3

h=

limh→0

3a2h + 3ah2 + h3

h= lim

h→0

h(3a2 + 3ah + h2

)h

Page 38: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 3

limh→0

(a+ h)3 − a3

h

Here a is a constant. Let’s expand (a+ h)3:

limh→0

��a3 + 3a2h + 3ah2 + h3 −��a3

h=

limh→0

3a2h + 3ah2 + h3

h= lim

h→0

�h(3a2 + 3ah + h2

)�h

Page 39: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 3

limh→0

(a+ h)3 − a3

h

Here a is a constant. Let’s expand (a+ h)3:

limh→0

��a3 + 3a2h + 3ah2 + h3 −��a3

h=

limh→0

3a2h + 3ah2 + h3

h= lim

h→0

�h(3a2 + 3ah + h2

)�h

= limh→0

(3a2 + 3ah + h2

)

Page 40: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 3

limh→0

(a+ h)3 − a3

h

Here a is a constant. Let’s expand (a+ h)3:

limh→0

��a3 + 3a2h + 3ah2 + h3 −��a3

h=

limh→0

3a2h + 3ah2 + h3

h= lim

h→0

�h(3a2 + 3ah + h2

)�h

= limh→0

(3a2 + 3ah + h2

)= 3a2 + 3a.0 + 02

Page 41: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

Example 3

limh→0

(a+ h)3 − a3

h

Here a is a constant. Let’s expand (a+ h)3:

limh→0

��a3 + 3a2h + 3ah2 + h3 −��a3

h=

limh→0

3a2h + 3ah2 + h3

h= lim

h→0

�h(3a2 + 3ah + h2

)�h

= limh→0

(3a2 + 3ah + h2

)= 3a2 + 3a.0 + 02 = 3a2

Page 42: Day 3 of Free Intuitive Calculus Course: Limits by Factoring

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