Gi lnh boxedminipage.sty
Nguyn Hu inKhoa Ton - C - Tin hc
HKHTN H Ni, HQGHN
1 Gii thiu
ng khung mt khi vn bn vi cc kch c khc nhau c gi lnh boxedminipage.styti a ch
http://tug.ctan.org/tex-archive/macros/latex/contrib/misc/
do Mario Wolczko vit. Bi ny cp n vn khung ca khi vn bn ty . V cbn gi lnh ny l sa i mi trng minipage c ca LaTeX.
2 Mi trng minipage
Mi trng minipage l mun mt khi vn bn nh mt trang vn bn nh, c c phpnh sau
\begin{minipage}[]{}
\end{minipage}
1. l mt o theo chiu ngang v d 6cm, hoc 4in,...
2. l sp xp trang nh vi cc trang khc theo chiu ng, v ddi y ch ra hai trang nh lin nhau vi cc ty chn
[ ] khng c ty chn, cn ngang vo gia nhau
[t] t trang ln pha trn ca trang
[b] t trang ln pha di ca trang
[c] t trang ln pha gia ca trang
3. Xem cc v d sau vi ty chn trong trang, hai trang lin nhau to ra cng hngngang vi ty chn khc nhau s khc.
[ ]
[ ][ ]
[t]
[ ]
[c][ ]
[b]
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[b]
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[ ][c]
[t]
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5. Dng minipage thit k hai dng ni vi mt dng v ngc li
Nhng dng tch bit 1
Nhng dng tch bit 2
\begin{minipage}{8cm}Nhng dng tch bit 3
Nhng dng tch bit 4\end{minipage}
Nhng dng tch bit 5
Nhng dng tch bit 6
2
Nhng dng tch bit 1
Nhng dng tch bit 2
Nhng dng tch bit 3Nhng dng tch bit 4
Nhng dng tch bit 5
Nhng dng tch bit 6
Mt dng ri n hai 1
Mt dng ri n hai 2\begin{minipage}{8cm}Mt dng ri n hai 3
Mt dng ri n hai 4\end{minipage}
Mt dng ri n hai 5
Mt dng ri n hai 6
Mt dng ri n hai 1
Mt dng ri n hai 2 Mt dng ri n hai 3Mt dng ri n hai 4
Mt dng ri n hai 5
Mt dng ri n hai 6
Hai dng ri n mt dng tip tc 1
Hai dng ri n mt dng tip tc 2
\begin{minipage}{6cm}Hai dng ri n mt dng tip tc 3
Hai dng ri n mt dng tip tc 4\end{minipage}Hai dng ri n mt dng 5
Hai dng ri n mt dng tip tc 6
Hai dng ri n mt dng tip tc 1
Hai dng ri n mt dng tip tc 2
Hai dng ri n mt dng tip tc 3Hai dng ri n mt dng tip tc 4
Hai dng ri n mt dng 5
Hai dng ri n mt dng tip tc 6
Mt dng n hai dng ri li mt 1
Mt dng 2\begin{minipage}{3cm}n hai dng 3
3
n hai dng 4\end{minipage}ri li mt 5
Mt dng n hai dng ri li mt 6
Mt dng n hai dng ri li mt 1
Mt dng 2 n hai dng 3n hai dng 4
ri li mt 5
Mt dng n hai dng ri li mt 6
6. Mt trang nh ging nh mt trang ln, nu xung dng on cng tht u dng vch thch ngay di chn trang, v d
y l v d c ch thch 1
y l v d c ch thch 2
\bigskip\begin{minipage}{8cm}
y l v d c ch thch 3\footnote{Cn ch thch}
y l v d c ch thch 4\footnote{CH thch nh}\end{minipage}
y l v d c ch thch 5
y l v d c ch thch 6
y l v d c ch thch 1
y l v d c ch thch 2
y l v d c ch thch 3a
y l v d c ch thch 4b
aCn ch thchbCH thch nh
y l v d c ch thch 5
y l v d c ch thch 6
3 Mi trng boxedminipage
Mi trng ny phi c gi lnh boxedminipage.sty nhng kt hp c vi mi trngminipage.
\begin{boxedminipage}{}
\end{boxedminipage}
1. V d kt hp vi mi trng minipage
\begin{boxedminipage}{.4\textwidth}Ti liu c ng khung\end{boxedminipage}\begin{minipage}{.2\textwidth}
4
\hfill\end{minipage}\begin{minipage}{.4\textwidth}Ti liu c ng khung
Ti liu c ng khung\end{minipage}
Ti liu c ng khungTi liu c ng khungTi liu c ng khung
2. ng khung nh l, nh ngha, mnh ,....
\noindent \begin{boxedminipage}{\textwidth}\begin{theorem}Cnh huyn ca mt tam gic vung bnh phng bngtng bnh phng ca cc cnh gc vung.\end{theorem}\end{boxedminipage}
nh l 1 Cnh huyn ca mt tam gic vung bnh phng bng tng bnh phng cacc cnh gc vung.
3. Khong cch t vn bn ti khung bng lnh \setlength{\fboxsep}{1cm} mc nhl \setlength{\fboxsep}{3pt}
\setlength{\fboxsep}{1cm}\begin{boxedminipage}{.4\textwidth}Ti liu c ng khung\end{boxedminipage}
Ti liu c ngkhung
\setlength{\fboxsep}{3pt}\begin{boxedminipage}{.4\textwidth}Ti liu c ng khung\end{boxedminipage}
Ti liu c ng khung
4. Lnh khung m \setlength{\fboxrule}{1cm}
\setlength{\fboxrule}{1cm}\begin{boxedminipage}{.4\textwidth}Ti liu c ng khung\end{boxedminipage}
Ti liu c ngkhung
5
Mc nh l \setlength{\fboxrule}{1pt}
\setlength{\fboxrule}{1pt}\begin{boxedminipage}{.4\textwidth}Ti liu c ng khung\end{boxedminipage}
Ti liu c ng khung
5. ng khung cng thc ton
\begin{center}\begin{boxedminipage}{5cm}\begin{center}ng thc\end{center}\vspace{-32pt}\begin{align*}x^2-y^2 &= (x+y)(x-y) \\x^3-y^3 &=(x-y)(x^2+xy+y^2)\end{align*}\end{boxedminipage}\end{center}
ng thcx
2 y
2 = (x + y)(x y)
x3 y
3 = (x y)(x2 + xy + y2)
\begin{center}\begin{boxedminipage}{7cm}\begin{center}ng nh\end{center}\vspace{-32pt}\begin{align}x^2-y^2 &= (x+y)(x-y) \\x^3-y^3 &=(x-y)(x^2+xy+y^2)\end{align}\end{boxedminipage}\end{center}
ng nhx
2 y
2 = (x + y)(x y) (1)
x3 y
3 = (x y)(x2 + xy + y2) (2)
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