DAp AN DE THI HQC PHAN: KINH TE LUQNGMa hoc phfin: 4051201 S&tin chi: 03Kh6a: -I>~ihoc h~ Chinh quyNgay thi: I I Su d\mg tal li~u: Bugc D Khang dugcQ

Call Y Noidllng Di~m1 2

Mo hinh co dang: NSj = ~l + ~2CPj+ ~3TTj + u,0,5Ham h6i quy: E(NS/CPj, TTi) = ~l + ~2CPj+ ~3TTj

Voi rna hinh nay y nghia cac h~ s6 nhir sau:+ ~l cho biSt khi CP = TT = °hay lao dong chua qua dao tao, 0,5khong co tiSn thuong thi nang su~t lao dong trung binh bang ~l

+ ~2cho biSt khi chi phi dao tao tang them 1 don vi, tiSn thuong0,5nhtr nhau thi nang su~t tang them P2dan vi.

+H~ s6 P3cho biet khi chi phi dao tao nhir nhau, tiSn thuongtang them 1 don vi thi nang su~t cao hon nang suat trung binh P3.don vi.

0,5Theo rna hinh nay, hieu qua cua CP va TT la khong d6i, nghia ladu voi lao dong nao thi hieu qua cua chi phi dao tao va tienthuong la nhu nhau.

2 5a 1

1\ 1\ 1\

Ham hoi quy mau co dang: SRF: Y; = f31+P2Xi 0,251\

P2= 0,635; 0,251\

PI = 2,047 0,251\

Ham h6i quy m~u SRF: Yi = 2, 047 + 0,63 5Xi 0,25b 1

1\

f3, = 2,047 cho biSt khi thu nhap = ° thi tieu dung trung binh la2,04 7 trieu dong. 0, 5

1\

f32= 0,635 cho biet neu thu nhap tang len 1 treu d6ng thi chi tieutrung binh tang them khoang 0,635 trieu d6ng. 0,5

c 11\

IT = 0,664 0,25

TOAN_KTL_DHCQ_A-Q TRANG 1/3-MD: 100515111

2(0-2) 2(8) 2(0 2) _ 2(8) _ 45 0,25XI d =XO,975 =2,1797; i; - XO,025 -17,5322

,,2 ,,2(n-2)0- 2 (n-2)0- 0,25

2(0-2) :::;0-:::; 2(0-2)

XCI. X a1--2 2<=? 0,201::S;0-2::s; 1,618 0,25=> 0,448 < 0-< 1,272

1dCap gia thuyet ki@m dinh:

0,25Ho: B2= ° (chi tieu khong phu thuoc VaGthu nhap)HI: 02;t:. 0 (chi tieu phu thuoc VaGthu nhap)

"_ B2-0 = 0,6356 =11,15

0,25tqs- Se(&2) 0,057

Voi a = 0,05; n = 10 ta co0,25t(n-2)= t(8) = 2 3060./2 0,025 ,

Vi t < It I> t(~;2)nen bac be Ho, thua nhan HI.0,25qs ,qs a

Vay voi rmrc y nghia 5%, chi tieuQh\! thuoc VaGthu nhap.e 1

Cap gia thuyet kiem dinh:Ho: B2:::;0,6 (khuynh huang tieu dung kh6ng tren 0,6) 0,25HI: JlI > 0,6 (khuynh huang tieu dung kh6ng tren 0,6)

" 0,25B2- 0,6 0,6356 - 0,6 = 0,625t - -- -qs " 0,057Se(B2)

Voi a = 0,05; n = 10 ta co 0,25t(n-2)= t(8) = 1 86a 0,05'

Vi tqs< t~n-2)nen chua co co sa bac bo Ho.Vay voi mire y nghia 5%, kh6ng thS cho rang khuynh huang tieu 0,25dung la tren 0,6.

33

M6 hinh: P, = al + a2Kj + a3Lj +Vj co R2 = 0,822 0,5Nhan xet tnrc tiep cho thay rmrc c!Q lien quan tuyen tinh gifra Pvoi ~ va L lit kha cao. DS phan tich chinh xac, kiem djnh cap gia 0,5thuyet:Ho: RL = 0: P kh6ng lien quan tuyen tinh v6i K, L

I 0,5TOAN_KTL_DHCQ_A-Q

TRANG 2/3-MD: 100515111

Ho: R2> 0: P lien quan tuyen tinh voi K, LR2 n-k 0, 5Taco Fqs= 2 .--

l-R k-lR2 n-k 0,5F = --qs l-R2' k +I

Tra bang F(2,27)::::3 49a '

Vi Fqs> F~2,27)nen bac bo Ho, thira nhan HI; rna hinh ban d~u co 0, 5

hien nrong da cong tuyen va cong tuyen amire dQkha cao.

TOAN KTL DHCQ_A-QTRANG 3/3-MD: 100515111