Transcript
Page 1: RTT โ€“ Conversation of Momentumย ยท Let . B. SYS = ๐‘ท. ๐‘บ๐‘บ๐‘บ (the Linear Momentum of the System) In this case: ๐’ƒ = ๐‘ท. ๐‘บ๐‘บ๐‘บ / M. SYS = ๐‘ฝ (velocity ) B. SYS

RTT โ€“ ฮ‘ฯฯ‡ฮฎ ฮดฮนฮฑฯ„ฮฎฯฮทฯƒฮทฯ‚ ฯ„ฮทฯ‚ ฮŸฯฮผฮฎฯ‚

Page 2: RTT โ€“ Conversation of Momentumย ยท Let . B. SYS = ๐‘ท. ๐‘บ๐‘บ๐‘บ (the Linear Momentum of the System) In this case: ๐’ƒ = ๐‘ท. ๐‘บ๐‘บ๐‘บ / M. SYS = ๐‘ฝ (velocity ) B. SYS

Image taken from: http://web.mit.edu/16.unified/www/FALL/thermodynamics/notes/node19.html

Page 3: RTT โ€“ Conversation of Momentumย ยท Let . B. SYS = ๐‘ท. ๐‘บ๐‘บ๐‘บ (the Linear Momentum of the System) In this case: ๐’ƒ = ๐‘ท. ๐‘บ๐‘บ๐‘บ / M. SYS = ๐‘ฝ (velocity ) B. SYS

The RTT in Mathematical Terms

CONTROL VOLUME SYSTEM

1) If BSYS is a physical Property of the System

2) And b = BSYS /MSYS (where MSYS is the mass of the system)

Volume Integral Surface Integral

Page 4: RTT โ€“ Conversation of Momentumย ยท Let . B. SYS = ๐‘ท. ๐‘บ๐‘บ๐‘บ (the Linear Momentum of the System) In this case: ๐’ƒ = ๐‘ท. ๐‘บ๐‘บ๐‘บ / M. SYS = ๐‘ฝ (velocity ) B. SYS

RTT & the Conservation of Mass Let BSYS = MSYS (the mass of the system) then b = 1

RTT โ€“ Conservation of Mass

Page 5: RTT โ€“ Conversation of Momentumย ยท Let . B. SYS = ๐‘ท. ๐‘บ๐‘บ๐‘บ (the Linear Momentum of the System) In this case: ๐’ƒ = ๐‘ท. ๐‘บ๐‘บ๐‘บ / M. SYS = ๐‘ฝ (velocity ) B. SYS

RTT & the Conservation of Momentum Let BSYS = ๐‘ท๐‘บ๐‘บ๐‘บ (the Linear Momentum of the System)

In this case: ๐’ƒ = ๐‘ท๐‘บ๐‘บ๐‘บ/ MSYS = ๐‘ฝ (velocity )

BSYS = ๐‘ท๐‘บ๐‘บ๐‘บ = โˆซ ๐‘‰ ๐œŒ ๐‘‘๐‘‰๐‘†๐‘†๐‘†

Page 6: RTT โ€“ Conversation of Momentumย ยท Let . B. SYS = ๐‘ท. ๐‘บ๐‘บ๐‘บ (the Linear Momentum of the System) In this case: ๐’ƒ = ๐‘ท. ๐‘บ๐‘บ๐‘บ / M. SYS = ๐‘ฝ (velocity ) B. SYS

Conservation of Momentum

Page 7: RTT โ€“ Conversation of Momentumย ยท Let . B. SYS = ๐‘ท. ๐‘บ๐‘บ๐‘บ (the Linear Momentum of the System) In this case: ๐’ƒ = ๐‘ท. ๐‘บ๐‘บ๐‘บ / M. SYS = ๐‘ฝ (velocity ) B. SYS
Page 8: RTT โ€“ Conversation of Momentumย ยท Let . B. SYS = ๐‘ท. ๐‘บ๐‘บ๐‘บ (the Linear Momentum of the System) In this case: ๐’ƒ = ๐‘ท. ๐‘บ๐‘บ๐‘บ / M. SYS = ๐‘ฝ (velocity ) B. SYS

In component Form

Page 9: RTT โ€“ Conversation of Momentumย ยท Let . B. SYS = ๐‘ท. ๐‘บ๐‘บ๐‘บ (the Linear Momentum of the System) In this case: ๐’ƒ = ๐‘ท. ๐‘บ๐‘บ๐‘บ / M. SYS = ๐‘ฝ (velocity ) B. SYS

Example 1: Water Jet Hitting a flat, vertical plate

1) What is Vโ€™? 2) What is Rx? (the force in the x-direction that is applied to the plate)

Page 10: RTT โ€“ Conversation of Momentumย ยท Let . B. SYS = ๐‘ท. ๐‘บ๐‘บ๐‘บ (the Linear Momentum of the System) In this case: ๐’ƒ = ๐‘ท. ๐‘บ๐‘บ๐‘บ / M. SYS = ๐‘ฝ (velocity ) B. SYS

Step 1: Define the Control Volume You want Vโ€™ and Rx to appear in the Control Surface (CS)

Step 2:

Page 11: RTT โ€“ Conversation of Momentumย ยท Let . B. SYS = ๐‘ท. ๐‘บ๐‘บ๐‘บ (the Linear Momentum of the System) In this case: ๐’ƒ = ๐‘ท. ๐‘บ๐‘บ๐‘บ / M. SYS = ๐‘ฝ (velocity ) B. SYS

Step 3: Conversation of Momentum (x-direction)

โˆ‘๐‘ญ๐‘ฟ = ๐๐๐ โˆซ ๐‘ฝ๐‘ฟ ๐† ๐’…๐‘ฝ๐‘ช๐‘ฝ + โˆซ ๐‘ฝ๐‘ฟ ๐†๐‘ช๐‘บ (๐‘ฝ โˆ™ ๐’) dA

Page 12: RTT โ€“ Conversation of Momentumย ยท Let . B. SYS = ๐‘ท. ๐‘บ๐‘บ๐‘บ (the Linear Momentum of the System) In this case: ๐’ƒ = ๐‘ท. ๐‘บ๐‘บ๐‘บ / M. SYS = ๐‘ฝ (velocity ) B. SYS

Example 2: Steady Flow through a 1800 bent

Step 1: Define you Control Volume (CV) -is this a steady-state problem? -should you include the anchor in the CV?

Absolute Pressure

Page 13: RTT โ€“ Conversation of Momentumย ยท Let . B. SYS = ๐‘ท. ๐‘บ๐‘บ๐‘บ (the Linear Momentum of the System) In this case: ๐’ƒ = ๐‘ท. ๐‘บ๐‘บ๐‘บ / M. SYS = ๐‘ฝ (velocity ) B. SYS

In the kitchen

Page 14: RTT โ€“ Conversation of Momentumย ยท Let . B. SYS = ๐‘ท. ๐‘บ๐‘บ๐‘บ (the Linear Momentum of the System) In this case: ๐’ƒ = ๐‘ท. ๐‘บ๐‘บ๐‘บ / M. SYS = ๐‘ฝ (velocity ) B. SYS

Step 2: Conservation of Mass

Page 15: RTT โ€“ Conversation of Momentumย ยท Let . B. SYS = ๐‘ท. ๐‘บ๐‘บ๐‘บ (the Linear Momentum of the System) In this case: ๐’ƒ = ๐‘ท. ๐‘บ๐‘บ๐‘บ / M. SYS = ๐‘ฝ (velocity ) B. SYS

Step 3: Conservation of Momentum X-direction:

Y-direction:

Absolute or Gauge Pressure?

Page 16: RTT โ€“ Conversation of Momentumย ยท Let . B. SYS = ๐‘ท. ๐‘บ๐‘บ๐‘บ (the Linear Momentum of the System) In this case: ๐’ƒ = ๐‘ท. ๐‘บ๐‘บ๐‘บ / M. SYS = ๐‘ฝ (velocity ) B. SYS

Example 3: Discharging Water from a Tank

Step 1: Define the CV

Fixed Not Fixed (?)

The rest on the boardโ€ฆ

A: the area at the bottom of the tank


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