Download - THEVENIN’S THEOREM
![Page 1: THEVENIN’S THEOREM](https://reader036.vdocuments.pub/reader036/viewer/2022082818/568132d2550346895d999590/html5/thumbnails/1.jpg)
THEVENIN’S THEOREM
• Thevenins Theorem states that "Any linear circuit containing several voltages and resistances can be replaced by just a Single Voltage in series with a Single Resistor".
![Page 2: THEVENIN’S THEOREM](https://reader036.vdocuments.pub/reader036/viewer/2022082818/568132d2550346895d999590/html5/thumbnails/2.jpg)
THEVENIN’S THEOREM
20 V
6 4
5 2
For example, refer to the circuit Find IL
IL
I1 I2
![Page 3: THEVENIN’S THEOREM](https://reader036.vdocuments.pub/reader036/viewer/2022082818/568132d2550346895d999590/html5/thumbnails/3.jpg)
Step 1 : Open circuit of 2Ω resistor
20 V 5
6 4
A
B
2
A
B
Open circuit
![Page 4: THEVENIN’S THEOREM](https://reader036.vdocuments.pub/reader036/viewer/2022082818/568132d2550346895d999590/html5/thumbnails/4.jpg)
Step 2 : Find the Thevenin voltage, VTH at A - B
• Thevenin voltage is the voltage across the terminals A and B is equal to the amount of algebra, which fell on the resistor voltage at 4Ω and 5Ω.
• To find the voltage dropped on both the resistor, is in looking to further advance the Ohm's law using the current multiplied by resistance (IR).
• In addition the voltage drop on both the resistor can also be found by using the following voltage divider.
![Page 5: THEVENIN’S THEOREM](https://reader036.vdocuments.pub/reader036/viewer/2022082818/568132d2550346895d999590/html5/thumbnails/5.jpg)
Calculation of VTH
• VTH
Voltage drop across• 4 dan 5 = (4 + 5 ) x 20 V
(4 + 5 ) + 6 = 12V
20 V 5
6 4
A
B
![Page 6: THEVENIN’S THEOREM](https://reader036.vdocuments.pub/reader036/viewer/2022082818/568132d2550346895d999590/html5/thumbnails/6.jpg)
Step 3 : Find the Thevenin Resistance, RTH – short circuit the power supply.
RTH
Short circuit the power supplies and find the Thevenin resistance is read at the terminal A and B
RTH = 6x9 (6+9)
= 54 / 15 = 3.6Ω
5
6 4
A
B
![Page 7: THEVENIN’S THEOREM](https://reader036.vdocuments.pub/reader036/viewer/2022082818/568132d2550346895d999590/html5/thumbnails/7.jpg)
Step 4 : Draw the Thevenin Equivalent circuit
ITH is the current through resistor 2Ω = IL is required in the original question.
VTH = 12V
RTH =3.6Ω
RL = 2Ω
ITH
ITH = IL = VTH / (RTH+RL) = 12 / (3.6+2) = 2.143 Amp
![Page 8: THEVENIN’S THEOREM](https://reader036.vdocuments.pub/reader036/viewer/2022082818/568132d2550346895d999590/html5/thumbnails/8.jpg)
Exercises ;
10
15 20
20 V
Refer to the circuit below, find I3 that flowing through 15Ω
1I
I1 I3
I2
![Page 9: THEVENIN’S THEOREM](https://reader036.vdocuments.pub/reader036/viewer/2022082818/568132d2550346895d999590/html5/thumbnails/9.jpg)
Calculation ;
10
20 20V
15
Step 1: Open circuit the 15
THV
![Page 10: THEVENIN’S THEOREM](https://reader036.vdocuments.pub/reader036/viewer/2022082818/568132d2550346895d999590/html5/thumbnails/10.jpg)
From the circuit ;Step 2 A VTH
BFind VTH = Voltage drop at 20Ω (using voltage
divider) VTH = 20Ω x 20 V = 13.33 V (10Ω + 20Ω)
10
20 20V
![Page 11: THEVENIN’S THEOREM](https://reader036.vdocuments.pub/reader036/viewer/2022082818/568132d2550346895d999590/html5/thumbnails/11.jpg)
• Step 3
• RTH
• Short circuit supplies and find RTH ( perintang 10 selari dengan perintang 20 )
• RTH = 10 // 20• = 10x20/(10+20)• = 6.67
10
20
![Page 12: THEVENIN’S THEOREM](https://reader036.vdocuments.pub/reader036/viewer/2022082818/568132d2550346895d999590/html5/thumbnails/12.jpg)
Step 4 Draw the Thevenin equvalent circuit
6.67
15 13.33 V
ITH
ITH = I3 = VTH /(RTH+RL) = 13.33 / (6.67+15)) = 0.615 A
![Page 13: THEVENIN’S THEOREM](https://reader036.vdocuments.pub/reader036/viewer/2022082818/568132d2550346895d999590/html5/thumbnails/13.jpg)
Exercise ;