Download - transformation nucleaire
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7/25/2019 transformation nucleaire
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44
mouvements plans3
I)mouvement dun projectile dans le champ de pesanteur uniforme
1
1.1
O.
.
.
y (cm)01015202530354045
x (cm)
2x
y
2.1
y (cm)01015202530354045
x (cm)022,327,431,635,338,641,844,647,4
2x
y
2,01,92,02,02,02,02,02,0
Ctex
y
2
2.xKy
.
2
2.1
O
m
V0 0V
. G
),,,( kjiOR
.
),,,( kjiOR
Ga
.
.
xSyS S.
OP.
P (xP=OP,yP=0)
P
1
2.
22
{
}
:P
:
GGG amPamgmga
...
)0,,0(
0
0
zyx
z
y
x
agaa
a
a
a
agg
t0= 0
0v
sin.Vv
cos.Vv
V
zO
0yO
0Ox
0
0z
0y
0x
OG
0
0
0
0
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V
B
F qV B
( , )V B
( , , )qV B F
0v
sin.Vt.gv
cos.Vv
V
z
0y
0x
3z
2y
1x
z
y
x
Kv
Kt.gv
Kv
V
0a
ga
0a
a
0z
sin.Vt.g2
1y
cos.Vx
OG0
2
0
6
50
2
40
z
0y
0x
Kz
Kt.sin.Vt.g2
1y
Kt.cos.Vx
OG
0v
sin.Vt.gv
cos.Vv
V
tVxtVtgy .cos.sin..2
100
2
t: xy.
coscos
.sin.)cos
.(2
1
0
0
2
0 V
xt
xV
V
xgy
:xtgxV
gy .
cos.2
2
22
0
vy = 0 0sin.sin.
2
2cos.sin..cos. 0
0
2
00
0
Vtgg
Vt
g
V
g
VVx FFF
g
V
g
VV
g
VgyF
2
sin.sin..sin.)
sin..(
2
1 22
000
20
1sin2
2
oyxtgx
V
g
g
V
g
V
g
tgVx PPPP 0.
cos.2
2sin.sin.cos.2.cos.2 222
0
2
0
2
0
22
0
12sin2
24
g
VxP
2
0
)sin(sin)2
(2sin)2sin(2sin
1122
.
II)
1
,
q
Lorentz
:
:
.
:
:V.B.sin|q|F =
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B
0( , )V B
2
1.2
.
( Helmholtz).
.
.
= 0= 900
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7/25/2019 transformation nucleaire
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0V
m
eBrV 0
Bq
m
V
rT
.
..2.2
0
4
1.4
0V
B
.
q(q < 0 )
m.
S
.
Dm.
2.4
tansin
r
lsin
L
D
OIL
D mm
tan
r
lLDm
.
Bq
Vmr
.
. 0 B
Vm
qlLDm .
.
...
0
5
B = 10-3T
.
:
e = 1,6.10-19C
m = 9,1.10-31kg
1
2 BemV0 r.
V03 Bem T
.
T.
1
:{
}
:BVeF
P
:
F
amPFamF
..
BVm
ea
kBB
.
F
k
amF
.
),( kO
Fz= m.a
z
Fz= 0
az= 0vz= vz0= 0z = z0= 0
),,0( ji
amF
.
),,( nuM
),( uM
FT= m.aT FT= 0 aT= 0
00 dt
dvcteVv
),( nM
FN= m.aN BVeFFN ..
2vaN
2
... v
mBve
BeVm.. 0
BeVmr.. 0
V0