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UFRGS 2005
Prof. Luiz CarlosProf. Luiz Carlos
UFRGS 2005
Profs. Luiz Carlos F í s i c a
2006
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UFRGS 2005
Prof. Luiz CarlosProf. Luiz Carlos
UFRGS 2005
Profs. Luiz Carlos F í s i c a
2006
F F
F F
F F
LEI DE COULOMB
+ +
d
q1 q2
- -
d
q1 q2
+ -
d
q1 q2
A s f or ças de Coulomb sãodir et ament e pr opor cionaisao pr odut o ent r e os módulosdas car gas dos cor pos.
F q2
q1
.
A s f or ças de Coulomb sãoinver sament e pr opor cionaisao quadr ado da dist ância que separ a as cor pos car r e-gados.
2F
d
1
Fq
2q
1.
2d
Conclusões Exper iment ais de Coulomb
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UFRGS 2005
Prof. Luiz CarlosProf. Luiz Carlos
UFRGS 2005
Profs. Luiz Carlos F í s i c a
2006
Variando somente as cargas
F F+ +
d
q1 q23 26 6
F F+ +
d
q1 q24 0,52 2
F q1 . q23 26
F q1 . q24 0,52
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UFRGS 2005
Prof. Luiz CarlosProf. Luiz Carlos
UFRGS 2005
Profs. Luiz Carlos F í s i c a
2006
Variando somente a distância
+ +
d
q1 q2F F
+ +
d
F 1
d2
++++++++++++
2d
FF44
1(2d)24 d2
F
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UFRGS 2005
Prof. Luiz CarlosProf. Luiz Carlos
UFRGS 2005
Profs. Luiz Carlos F í s i c a
2006
Exercitando
Complete as lacunas de forma que a Lei de Coulomb seja respeitada.
F q1 . q2
q1
q2
F
q1
F2
q22
F6
q23
q12
F8
q24
q12
F5
q15
F20
q24
q110
q2
2
q1
2
q2
F2
q1
2q2
2
F4
q1
2q2
3q2
5
6F
q2
27
3F
q1q19
+ +
d
q1 q2F F
5F
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UFRGS 2005
Prof. Luiz CarlosProf. Luiz Carlos
UFRGS 2005
Profs. Luiz Carlos F í s i c a
2006
Exercitando
Complete as lacunas de forma que a Lei de Coulomb seja respeitada.
F
d d2
F4
d3
F9
d4
F16
d5
F25
F2
d2
F4
d2
F9
d3
F3
d4
d5
F16 F25
d3
F 1d2
+ +
d
q1 q2F F
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UFRGS 2005
Prof. Luiz CarlosProf. Luiz Carlos
UFRGS 2005
Profs. Luiz Carlos F í s i c a
2006
Gráfico F x d
1
2
3
4
1419116
1
F d
F(N)
d(m)
F 1d2
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UFRGS 2005
Prof. Luiz CarlosProf. Luiz Carlos
UFRGS 2005
Profs. Luiz Carlos F í s i c a
2006
Natureza vetorial da Força Eletrostática
+ +
d
q1 q2
+
q3
2d
FF4
FR
Módulo da resultante:
FR = F -F
4 FR =3F
4
1) FF4
+FR = F12 F2
2 + 2F1 .F2.cos
FR = F1 F2+Vetorialmente:
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UFRGS 2005
Prof. Luiz CarlosProf. Luiz Carlos
UFRGS 2005
Profs. Luiz Carlos F í s i c a
2006
Natureza vetorial da Força Eletrostática
+ +
d
q1 q2
-
q3
2d
F
Módulo da resultante:
FR = F+F
4 FR =5F
4
2) FR
F4F
F4
Vetorialmente: FR = F1 F2+
+FR = F12 F2
2 + 2F1 .F2.cos
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UFRGS 2005
Prof. Luiz CarlosProf. Luiz Carlos
UFRGS 2005
Profs. Luiz Carlos F í s i c a
2006
+
q2
q1
-
+
q3
d
2d
F1
F1
F2 F2
FR
Natureza vetorial da Força Eletrostática
3)
FR = F1 F2+
+FR = F12 F2
2 + 2F1 .F2.cos
+FR = F12 F2
2
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UFRGS 2005
Prof. Luiz CarlosProf. Luiz Carlos
UFRGS 2005
Profs. Luiz Carlos F í s i c a
2006
Natureza vetorial da Força Eletrostática
4)
+
q1
q2
-
+
q3
F1
F2
FR
FR = F1 F2+
+FR = F12 F2
2 + 2F1 .F2.cos
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UFRGS 2005
Prof. Luiz CarlosProf. Luiz Carlos
UFRGS 2005
Profs. Luiz Carlos F í s i c a
2006
Natureza vetorial da Força Eletrostática
5)
+
q1
q2
-
+
-2q3
F1
F2
FR
FR = F1 F2+
+FR = F12 F2
2 + 2F1 .F2.cos