4√97− x+ 4

√x = 5 (1)

x

(6− x

x+ 1

)(6− x

x+ 1+ x

)= 8 (2)

y3 − 6x2 + 12x− 8 = 0z3 − 6y2 + 12y − 8 = 0x3 − 6z2 + 12z − 8 = 0

(3)

x2 − xy + y2 = 7x2y + xy2 = −2

}(4)

3x2−x−y + 3y

2−y−z + 3z2−z−x = 1 (5)

4√6561 · 12

√x = 6x (6)

√a−

√a+ x = x (7)

x2 + 2ax+1

16= −a+

√a2 + x− 1

16(8)

x4 − 6x2y2 + y4 = 14x3y − 4xy3 = 1

}(9)

x+ y + z = ax2 + y2 + z2 = b

xy = z2

(10)

x2 + y = 3x+ 42y3 + z = 6y + 62z3 + x = 9z + 8

(11)

Demuestra que:

3

√20 + 14

√2 +

3

√20− 14

√2 = 4 (12)

log5 x+ 3log3y = 7xy = 512

}(13)

xx+y = yx−y

x2y = 1

}(14)

√19− x+

√97 + x = 14 (15)

1

2x− 1+

1

2x+ 1+

1

4x2 − 1= 1 (16)

x(x+ y + z) = 26y(x+ y + z) = 27z(x+ y + z) = 28

(17)

2x(4− x) = 2x+ 4 (18)

x2 +√

y2 + 12 =√y2 + 60

y2 +√z2 + 12 =

√z2 + 60

z2 +√x2 + 12 =

√x2 + 60

(19)

y3 − 6x2 + 12x− 8 = 0z3 − 6y2 + 12y − 8 = 0x3 − 6z2 + 12z − 8 = 0

(20)

log(35− x3)

log(5− x)= lım

n→∞ln

(n+ 4

n+ 1

)n

(21)

√3x− 2y

2x+

√2x

3x− 2y= 2

4y2 − 1 = 3y(x− 1)

(22)

1