eec4-4a-ss-lecture-08.pdf

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Signals & Systems FEEE, HCMUT Ch-4: Biểu diễn tín hiệu dùng biến đổi Fourier Lecture-8 4.4. Biến đổi Fourier và hệ thống LTI 4.5. Bộ lọc lý tưởng và thực tế 4.6. Ứng dụng trong thông tin: điều chế liên tục

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  • Signals & Systems FEEE, HCMUT

    Ch-4: Biu din tn hiu dng bin i Fourier

    Lecture-8

    4.4. Bin i Fourier v h thng LTI

    4.5. B lc l tng v thc t

    4.6. ng dng trong thng tin: iu ch lin tc

  • Signals & Systems FEEE, HCMUT

    4.4. Bin i Fourier v h thng LTI

    Xt h thng LTI vi p ng xung l h(t)

    Ta c: y(t)=f(t) h(t) Y()=F()H()

    Biu din h thng trong min tn s:

    H thng ghp lin tng:

    1 2Y()=F()H ()H ()

    jtY()H()= h(t)e dtF()

    (p ng tn s ca HT LTI)

    1 2H()=H ()H ()

  • Signals & Systems FEEE, HCMUT

    4.4. Bin i Fourier v h thng LTI

    H thng ghp song song:

    1 2Y()=F()[H ()+H ()]

    H thng ghp hi tip:

    1

    1 2

    H ()Y()=F()

    1+H ()H ()

    1 2H()=H ()+H ()

    1

    1 2

    H ()H()=

    1+H ()H ()

  • Signals & Systems FEEE, HCMUT

    4.4. Bin i Fourier v h thng LTI

    H thng LTI nhn qu n nh m t bi phng trnh vi phn:

    Q(D)y(t)=P(D)f(t)

    k kD y(t) ( j) Y()

    k kD f(t) ( j) F()

    Q(j)Y()=P(j)F()

    Y() P(j)H()=

    F() Q(j)

    V d: xc nh p ng xung ca h thng m t bi PTVP:

    (D+3)y(t)=Df(t)

    P(j) jH()=

    Q(j) j+3C:

    31

    j+33th(t) (t) 3e u(t)

  • Signals & Systems FEEE, HCMUT

    4.4. Bin i Fourier v h thng LTI

    nh hng ca p ng tn s ca h thng ln tn hiu:

    Y()=F()H()|Y()|=|F()||H()|

    Y()= F()+ H()

    H thng LTI lm thay i bin & pha ca tn hiu vo to tn

    hiu ra. Cc thnh phn tn s khc nhau s thay i khc nhau

    H thng LTI l mt b chn lc tn s - Filter

    B lc thng thp (Low pass Filter LPF)

    B lc thng cao (High pass Filter HPF)

    B lc thng di (Band pass Filter BPF)

    B lc chn di (Band Stop Filter BSF)

  • Signals & Systems FEEE, HCMUT

    4.5. B lc l tng v thc t

    B lc thng thp l tng:

    c

    2

    H()=rect( ) cc

    h(t)= sinc( t)

  • Signals & Systems FEEE, HCMUT

    4.5. B lc l tng v thc t

    B lc thng cao l tng:

    c

    2

    H()=1 rect( ) cc

    h(t)=(t) sinc( t)

  • Signals & Systems FEEE, HCMUT

    4.5. B lc l tng v thc t

    B lc thng di l tng:

    0 0

    c2 c1 c2 c1

    +

    H()=rect( )+rect( )

    c2 c1( )c2 c102

    h(t)= sinc[ t]cos t

  • Signals & Systems FEEE, HCMUT

    4.5. B lc l tng v thc t

    Nhn xt: cc b lc l tng u l h thng khng nhn qu

    khng th thc hin c trn thc t

    B lc thc t phi l h thng nhn qu v c thc hin theo

    cc phng n sau:

    Thc hin bng h thng ri rc (b lc s - s hc trong mn x

    l TH s), s dng p ng xung h(t) ca b lc l tng ct b

    phn ui ca h(t) v tr i ph hp h(t) mi l nhn qu

    Thc hin bng h thng lin tc (b lc tng t), p ng tn

    s thay i lin tc tin gn ti p ng l tng (s trnh by

    chi tit hn trong chng 7 v thit k b lc tng t)

  • Signals & Systems FEEE, HCMUT

    4.5. B lc l tng v thc t

    Vic ct b h(t) c thc hin bng cc hm ca s. Ty vo loi

    hm ca s m p ng tn s ca h thng s c s thay i khc

    nhau so vi p ng l tng

    tR T

    w (t)=rect

    tT T

    w (t)=

    R Rh (t)=h(t)w (t)

    T Th (t)=h(t)w (t)

  • Signals & Systems FEEE, HCMUT

    4.5. B lc l tng v thc t

    Mt s hm ca s v c tnh ca chng

    Window w(t) Mainlobe

    Width

    Rolloff

    Rate

    dB/oct

    Peak

    Sidelobe

    Level dB

    1. Rectangular: tT

    rect

    2. Bartlett: tT

    3. Hanning: 2tT

    0.5[1 cos ]

    4. Hamming: 2tT

    0.54 0.46cos

    5. Blackman: 2t 4tT T

    0.42 0.5cos 0.08cos

    6. Kaiser:

    2tT0

    0

    I [ 1 4 ];1 10

    I ()

    4/T 6 13.3

    8/T 12 26.5

    8/T

    8/T

    18

    6

    31.5

    42.7

    12/T 18 58.1

    11.2/T 6 59.9

    ( 8.168)

  • Signals & Systems FEEE, HCMUT

    4.6. ng dng trong thng tin: iu ch lin tc

    4.6.1. Gii thiu

    4.6.2. iu ch bin (AM)

    4.6.3. iu ch gc (PM, FM)

  • Signals & Systems FEEE, HCMUT

    4.6.1. Gii thiu

    iu ch : dch ph tn s ca tn hiu tin tc ln tn s cao hn

    Mc ch:

    Ghp knh theo tn s

    Tha mn nguyn l bc x in t khi truyn v tuyn

    Thnh phn trong tn hiu iu ch:

    Tn hiu sng mang

    Tn hiu bng gc (tn hiu mang thng tin)

    Cc loi iu ch:

    iu ch bin (AM)

    iu ch gc: FM, PM

  • Signals & Systems FEEE, HCMUT

    4.6.2. iu ch bin (AM)

    a) iu ch/gii iu ch AM-DSB-SC

    b) Gii iu ch/gii iu ch AM

    c) Ghp knh/phn knh theo tn s (FDM)

    d) iu ch/gii iu ch AM-SSB

  • Signals & Systems FEEE, HCMUT

    a) iu ch/gii iu ch AM-DSB-SC

    S h thng iu ch:

    AM cy (t)=m(t)cos t Tn hiu iu ch:

  • Signals & Systems FEEE, HCMUT

    a) iu ch/gii iu ch AM-DSB-SC

    Ph ca tn hiu iu ch: 1 12 2AM c cY ()= M( )+ M( )

    c M

    Ph ca tn hiu iu ch cha c 2 di bn LSB & USB v khng

    cha thnh phn sng mang nn c gi l iu bin 2 di bn trit

    sng mang (AM-DSB-SC)

  • Signals & Systems FEEE, HCMUT

    a) iu ch/gii iu ch AM-DSB-SC

    H thng gii iu ch:

    Yu cu: ng b sng mang my pht v my thu T/sng ng b

  • Signals & Systems FEEE, HCMUT

    b) iu ch/gii iu ch AM

    H thng iu ch: nh AM-DSB-SC nhng cng thm sng mang

    pm= : modulation index

    K

    Tn hiu iu ch:

  • Signals & Systems FEEE, HCMUT

    b) iu ch/gii iu ch AM

  • Signals & Systems FEEE, HCMUT

    b) iu ch/gii iu ch AM

    Ph ca tn hiu iu ch:

    1 12 2AM c c c cY () K(- )+K(+ )+ M(- )+ M(+ )

    H thng gii iu ch:

    Tch sng ng b: tng t nh AM-DSB-SC

    Tch sng khng ng b hoc tch sng ng bao

    Ging ph tn hiu AM-DSB-SC nhng c thm sng mang nn

    c hiu sut thp hn v mt cng sut.

  • Signals & Systems FEEE, HCMUT

    Tch sng khng ng b:

    1

    c>> M: lun tha trn thc t (500KHz-2MHz)

    b) iu ch/gii iu ch AM

  • Signals & Systems FEEE, HCMUT

    Ghp knh: cc tn hiu mang tin (cc knh) c cng bng thng,

    khi truyn trn mt knh chung s phn bit bi tn s sng mang

    Frequency-Division Multiplexing (FDM)

    c) Ghp knh/phn knh theo tn s (FDM)

  • Signals & Systems FEEE, HCMUT

    c) Ghp knh/phn knh theo tn s (FDM)

    Ph ca tn hiu FDM:

    Phn knh theo tn s:

    Thc t ngi ta dng phng php i tn phn knh v gii iu

    ch ti cng 1 tn s (thng gi l trung tn)

  • Signals & Systems FEEE, HCMUT

    d) iu ch/gii iu ch AM-SSB

    Xt tn hiu FDM:

    USBLSB

    USBLSB

    Mi knh u c 2 di bn nn chim dng bng thng knh truyn

    gp i bng thng ca tin hiu.

    Vi cch gii iu ch kho st ta thy rng ch cn truyn i di

    cao USB hoc LSB th vn c th gii iu ch c

    Nu truyn i mt di bn ca tn hiu ngi ta gi l iu bin

    AM mt di bn. Mc ch: tit kim bng thng ca knh truyn

  • Signals & Systems FEEE, HCMUT

    Phng php iu ch 1: iu ch AM-DSB + Filter

    H()

    d) iu ch/gii iu ch AM-SSB

  • Signals & Systems FEEE, HCMUT

    Phng php iu ch 2: 900 phase-shift network

    d) iu ch/gii iu ch AM-SSB

  • Signals & Systems FEEE, HCMUT

    4.6.3 iu ch gc (PM, FM)

    a) Nguyn tc iu ch gc

    b) Bng thng ca tn hiu iu ch gc

    c) Phng php iu ch/gii iu ch gc

  • Signals & Systems FEEE, HCMUT

    a) Nguyn tc iu ch gc

    Nguyn tc: gn tn hiu tin tc m(t) vo gc pha (t) ca sng mang

    y (t)=Acos[(t)] (t)=[m(t)]vi

    Tn s tc thi: it

    (t) d(t) = lim

    t dt0

  • Signals & Systems FEEE, HCMUT

    iu ch FM: tn s tc thi t l tuyn tnh theo m(t)

    i c f = +k m(t)t

    c f(t)= t+k m()d

    iu ch PM: pha tc thi t l tuyn tnh theo m(t)

    c p(t)= t+k m(t) i c pdm(t)

    = +kdt

    Quan h gia FM & PM:

    a) Nguyn tc iu ch gc

  • Signals & Systems FEEE, HCMUT

    V d v tn hiu iu ch PM & FM

    a) Nguyn tc iu ch gc

  • Signals & Systems FEEE, HCMUT

    b) Bng thng ca tn hiu iu ch gc

    Quan h ph tn hiu iu ch vi tn hiu tin tc khng n gin

    khng xt chi tit y!!!

    c lng bng thng ca tn hiu iu ch:

    Xt tn hiu iu ch dng: cy (t)=Acos[ t+k(t)]

    pk=kPM:

    (t)=m(t)

    f

    t

    k=kPM:

    (t)= m()d

    Xt trng hp c bit k

  • Signals & Systems FEEE, HCMUT

    b) Bng thng ca tn hiu iu ch gc

    c lng bng thng ca tn hiu iu ch:

    Xt trng hp tng qut: tn s tn hiu iu ch thay i quanh

    tn s sng mang c. Gi s l c- n c+ Bng thng

    ca y (t) l 2 !!!?

    Tm : i c

    d(t) = +k

    dtp p

    d(t)=k' ;' max | |

    dt

    Nu chn k 0 th =0 y (t) c bng thng bng 0!!!?

    Bng thng ca y (t) c dng: 2 +X MX=2

    M2[ + ]Kt qu bng thng ca y (t) l:

    f p M p

    p p M p

    FM: 2[k m + ]; m max | m(t) |

    PM: 2[k m' + ]; m' max | m'(t) |

  • Signals & Systems FEEE, HCMUT

    b) Bng thng ca tn hiu iu ch gc

    So snh vi AM:

    Bng thng lun ln hn hoc bng AM

    Bng thng c th iu chnh c bng cch thay i kp, kf

    Li im: tnh chng nhiu tt

  • Signals & Systems FEEE, HCMUT

    c) Phng php iu ch/gii iu ch gc

    iu ch di hp (k 0): c cy (t) Acos( t) kA(t)sin( t)

    Tng t nh AM

    iu ch di rng (tng qut):

    c 1 c 1 c 1y(t)=Acos[ t+k (t)] Acos( t) k A(t)sin( t); k 0

    2 2

    c 1 c 1

    A Ay (t)=Acos [ t+k (t)]= cos[2 t+2k (t)]

    2 22

    M c 1y (t) BBF:2, y (t)=Acos[2 t+2k (t)]

    iu ch trc tip dng VCO

    Gii iu ch: c c

    dy (t)= A[ +k'(t)]sin[ t+k(t)]

    dt

    Tch sng ng bao

    Gii iu ch dng PLL