enb 471 week-2 lecture notes

15
ENB 471: DESIGN OF CONCRETE BUILDINGS AND FOUNDATION 1 original presentation by Ario Y. Darestani modified by Charles Jetann

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Design of Concrete Structures

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  • ENB 471: DESIGN OF CONCRETE

    BUILDINGS AND FOUNDATION 1 original presentation by

    Ario Y. Darestanimodified by

    Charles Jetann

  • AGENDA

    Issues that may influence your design

    Initial loading estimate (LL and SDL)

    Initial sizing of members

    Fire Requirements

    Columns

    Initial Loading Estimate (DL)

    2

    Rule of Thumb

    Group Project Scope

    First AssignmentSecond Assignment

    Introduction to Tutorial Problem Scope

  • ISSUES THAT MAY INFLUENCE YOUR DESIGN

    Site specific conditions;

    Lateral stability system;

    Fire Resistance

    3

    Durability

    Architectural requirements that restrict structural zonesor which introduce misalignment of vertical supportresulting in transfer loads

  • INITIAL LOADING ESTIMATE (LL AND SDL)

    4

    Refer AS 1170.1 to determine LL and SDL acting on

    your structure as follows:

    Table 3.1 for LL acting on Floors;

    Table 3.2 for LL acting on Roof;

    Table 3.4 for Dynamic factors;

    Appendix A for unite weight of materials and construction

    Supp 1:2003 Appendix CA Unit Weight of Materials

  • INITIAL LOADING ESTIMATE (LL) - EXAMPLE

    5

    3

    Roof Area:

    Table 3.1 Section E: Plant Room

    LL = 5 kPa

    Table 3.1 Section C3: Roof

    LL = 4 kPa

    Table 3.1 Section A1: Non-Habitable Roof

    LL = 0.5 kPa

    Engineering Justification

    for Roof with minimum

    access (Table 3.1 Section A1) :

    LL = 2.0 kPa

  • INITIAL LOADING ESTIMATE (SDL) - EXAMPLE

    6

    ctu

    re N

    ote

    3

    Roof Area:

    Clay Tiling, 13 mm Thick : Table A2

    SDL = 0.27 kPa

    Mortar, 10 mm thick: Table

    CA2(A),

    SDL = 21 x 0.01 = 0.21 kPa

    Damp-proof membrane

    SDL = 0.025 kPa

    Suspended Metal lath and

    gypsum plaster, FRL of 2 hrs

    SDL = 0.5 kPa

    SDL = 0.27 + 0.21 + 0.025 + 0.5 =1.005 kPa

  • INITIAL SIZING OF MEMBERS - FIRE REQUIREMENTS

    7

    Refer Section 5 of AS 3600 (FRL of 2 hrs):

    For Slabs (Clause 5.5.1): T = 120 mm; For Beams (Clause 5.4.1B): Minimum Width = 200 mm; For Columns (Clause 5.6.3, N*f / Nu 0.5): Minimum

    dimension = 350 mm, Shall at least contain 8 bars

    distributed evenly on all sides of section

  • 8

    INITIAL SIZING OF MEMBERS

    For One-Way Slab and Beams: RC:

    PT: L/32 for Single span, L/40 for End Span, and L/45 for Interior span

    Rule of Thumb

  • 9

    INITIAL SIZING OF MEMBERS

    For Columns: Consider at least 2.5% of column dimension for

    eccentricity in each direction;

    Assuming square cross section:

    EQ - 1

    Note: Minimum Dimension of column is based on

    Fire Design.

    Rule of Thumb

  • 10

    INITIAL SIZING OF MEMBERS EXAMPLE

    Define Beam Direction Define Direction of Slabs For End Spans:

    RC : T = L/24=325 mm PT : T = L/40=195 mm Both > 120 mm

    For Interior Span: RC : T = L / 28=360 mm PT : T = L/45=225 mm

    For RC Beams End Span: T =L/18.5= 315 mm

    If using RC Slab, T = 325 mm

    Interior Spans: T=L/21= 280 mm

    If using RC Slab, T= 360 mm for

    mid-bay

    Beams

    78

    00

    10

    ,00

    07

    80

    0

    4 @ 5800

  • 11

    INITIAL SIZING OF MEMBERS EXAMPLE

    SD Column

    Determine DL acting on the Floor Assuming using RC Slab, for the

    Interior columns:

    DL1= 0.325 x 25 = 8.125 kPa

    DL2= 0.36 x 25 = 9 kPa

    DLB = NA

    Determine loading area of column A1= 3.9 x 5.8 = 22.62 m

    2

    A2= 5 x 5.8 = 29 m2

    AT =51.62 m2

    Determine P* (Refer AS 1170.0, Clause 4.2 for load combinations):

    DL = 9 x 29 + 8.125 x 22.62 =

    = 445 kN

    SDL = 1.005 x 51.62 = 51.88 kN

    LL = (5+2)/2 x 51.62 = 180.67 kN

    325 mm

    360 mm

  • 12

    INITIAL SIZING OF MEMBERS EXAMPLE

    SD Column

    P* = 1.2 x (DL + SDL) + 1.5 x LL

    = 867.26 kN

    Determine Bending Actions: Mx = My = 0.025 x P* x a (kN.mm)

    Using EQ-1, a can be calculated for fc = 32 MPa:

    a = 279.8 or 280 mm

    This is less than 350 mm. Hence, a = 350 mm is used

    325 mm

    360 mm

    2 =1.3

    0.45 = 78294.4 2

  • bSD of Supper b /2013L

    Geotechnical Investigation

    SD of Supper Structures Earthquake

    Engineering

    To Assess the Soil; To Determine or Estimates Soil

    i h i d f

    Gravity Loads

    Lateral Loads

    properties those required for foundation design

    SD of one-way RC Wind E i i

    Foundation Design

    yor PT Slabs

    SD of RC Beams SD of Columns

    Engineering

    13

    SD of Lateral Stability Systems 13

    First Report

    D of PT

    D of

    SCHEMATIC DESIGN (SD)

    SCOPE OF WORK FOR THE FIRST PROJECT ISSUE

    CALCULATION OF FORCESPRELIMINARY SIZES OFSTRUCTURAL FLOOR,

    FRAMING AND FOOTINGS

    Shallow FootingsShallow FootingsDeep Footings (Pi

  • Design Development of the one-way RC or PT Slab

    Gravity Loads SD of one-way RC or PT Slabs

    DD of the RC beamsWind and

    Earthquake Forces

    Gravity Loads Lateral Loads SD of RC Beams

    DD of Lateral Resisting Gravity Loads L l L dDD of Lateral Resisting Systems Lateral Loads SD of Lateral Stability Systems

    Gravity Loads

    14

    DD of Columns Gravity Loads Lateral Loads SD of Columns

    14

    Second Report

    DEVELOPED DESIGN (DD)SCOPE OF WORK FOR THE SECOND PROJECT ISSUE

    CALCULATIONS FOR THE DESIGNOF REINFORCED AND

    POST-TENSIONED MEMBERS

  • CONSTRUCTION DOCUMENTATION (CD)

    SCOPE OF WORK FOR THE SECOND PROJECT ISSUE

    INCORPORATE ALL OF THE FEEDBACK FROMPREVIOUSLY ISSUED ASSIGNMENTS AND PREPAREA FINAL SET OF DRAWINGS AND CALCULATIONS TO

    BE PRESENTED FOR EVALUATION BY THELECTURER AND COURSE COORDINATOR

    15