ENERGY BALANCE(vapor) 100 000 tonne/y = 11415.525 kg/h99.8% conversionT = 139 CP = 110 kPa

Ethylbenzene = 0.998Benzene = 0.002

(liquid)F = 13193.809 kg/hT = 145.4 CP = 120 kPa

F = 13193.809 kg/h

Benzene = 15819.6 kg/hEthylbenzene = 11396.251 kg/h1,4-Diethylbenzene = 1774.727 kg/h

T-302

(liquid)B = 1778.284 kg/hT= 191.1 CP = 140 kPa

Ethylbenzene = 0. 0021,4-Diethylbenzene = 0. 998

Ref : B(l, 145.4 C, 101.3 kPa), EB(l, 191.1 C, 140 kPa), D(l, 191.1 C, 101.3 kPa)Substance (kg/h) in (kJ/kg) (kg/h) out (kJ/kg)

Benzene15819.6122.8314

Ethylbenzene (l)11396.25123.5570

Ethylbenzene (v)--11392.6945

1,4-Diethylbenzene1774.72731774.7276

B(l, 145.4 C, 101.3 kPa) B(l, 145.4 C, 120 kPa) = (1/0.879) x (1/1000) x (78 kg/mol) = 0.089 L/mol 1 = P = 0.089(120-101.3) = 1.6643 kJ/kg

EB(l, 191.1 C, 140 kPa)B(l, 145.4 C, 120 kPa) a) EB(l, 191.1 C, 140 kPa)B(l, 145.4 C, 101.3 kPa) = (1/0.867) x (1/1000) x (106.16 kg/mol) = 0.122 L/mol 2a = P = 0.122(101.3-140) = -4.7214 kJ/kg

b) EB(l, 191.1 C, 101.3 kPa) B(l, 145.4 C, 101.3 kPa) 2b = = = ( = -6944.185 kJ/kg

c) EB(l, 145.4 C, 101.3 kPa) B(l, 145.4 C, 120 kPa) = (1/0.867) x (1/1000) x (106.16 kg/mol) = 0.122 L/mol2c = P = 0.122(120-101.3) = 2.29 kJ/kg

2 = 2a + 2b + 2c = -4.7214 kJ/kg + -6944.185 kJ/kg + 2.29 kJ/kg = -6946.617 kJ/kg

D(l, 191.1 C, 101.3 kPa)D(l, 145.4 C, 120 kPa)a) D(l, 191.1 C, 101.3 kPa) D(l, 145.1 C, 101.3kPa) 3a = = + = [( = -4295.407 kJ/kg

b) D(l, 145.4 C, 101.3 kPa) D(l, 145.4 C, 120 kPa) = (0.862) x (1/1000) x (134.18 kg/mol) = 0.116 L/mol

3b = P = 0.116(120-101.3) = 2.169 kJ/kg

3= 3a + 3b = -4293.238 kJ/kg

B(l, 145.4 C, 101.3 kPa)B(v, 139 C, 110 kPa)

a) B(l, 145.4 C, 101.3 kPa) B(l, 80.10 C, 101.3 kPa) 4a = = = -9.98 kJ/kg

b) B(l, 80.10 C, 101.3 kPa) B(v, 80.10 C, 101.3 kPa) 4b = = 30.761 kJ/kg

c) B(v, 80.10 C, 101.3 kPa) B(v, 139 C, 101.3 kPa) 4c = = + = 6318.797 kJ/kg

d) B(v, 139 C, 101.3 kPa) B(v, 139 C, 110 kPa) = (1/0.879) x (1/1000) x (78 kg/mol) = 0.089 L/mol 4d = P = 0.089(110-101.3) = 8.7 kJ/kg4= 4a + 4b +4c + 4d = -9.98 kJ/kg + 30.761 kJ/kg + 6318.797 kJ/kg + 8.7 kJ/kg = 6348.278 kJ/kg

EB(l, 191.1 C, 140 kPa) EB(v, 139 C, 110 kPa)a) EB(l, 191.1 C, 140 kPa)EB(l, 191.1 C, 101.3 kPa) = (1/0.867) x (1/1000) x (106.16 kg/mol) = 0.122 L/mol 5a = P = 0.122(101.3-140) = -4.7214 kJ/kg

b) EB(l, 191.1 C, 101.3 kPa) EB(l, 136.2 C, 101.3 kPa) 5b = = = ( = -8299.326 kJ/kg

c) EB(l, 136.2 C, 101.3 kPa) EB(v, 136.2 C, 101.3 kPa) 5c = = 35.91 kJ/kg

d) EB(v, 136.2 C, 101.3 kPa) EB(v, 136.2 C, 140 kPa) = (1/0.867) x (1/1000) x (106.16 kg/mol) = 0.122 L/mol 5d = P = 0.122(140-101.3) = 4.7214 kJ/kg

5= 5a + 5b +5c + 5d = -4.7214 kJ/kg + -8299.326 kJ/kg + 35.91 kJ/kg + 4.7214 kJ/kg = -8263.416 kJ/kg

D(l, 191.1 C, 101.3 kPa)D(l, 191.1 C, 140 kPa)

a) D(l, 191.1 C, 101.3 kPa) D(l, 191.1 C, 140 kPa) = (0.862) x (1/1000) x (134.18 kg/mol) = 0.116 L/mol

6 = P = 0.116(140-101.3)

= 4.489 kJ/kg

Q = H out - H in = [(22.831x6348.278 kJ/kg) + (11392.694x-8263.416 kJ/kg) + (1774.727x4.489 kJ/kg)] [(15819.6x1.6643 kJ/kg) + (11396.251x-6946.617 kJ/kg) + (1774.727x-4293.238 kJ/kg)]

= -7.231x kJ/h