example calculation ram rmm
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CONTOH PENGIRAAN
MELIBATKAN JISIM ATOM
RELATIF (Jar) DAN JISIM
MOLEKUL RELATIF (Jmr)
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PENGIRAAN JISIM ATOM RELATIF (Jar)
CONTOH 1 : HITUNG BERAPA KALIKAH JISIM SATUATOM KARBON LEBIH BERATBERBANDING SATU ATOM HELIUM?
[Jar : He, 4 ; C, 12]
JAWAPAN :
JISIM 1 ATOM KARBON = 12JISIM 1 ATOM HELIUM 4
= 3 KALI
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CONTOH 2 : JISIM SATU ATOM SULFUR ADALAH 2KALI LEBIH BESAR DARIPADA JISIM SATU ATOM OKSIGEN. APAKAH JISIM ATOM RELATIF BAGI SULFUR?
[Jar : O, 16]
JAWAPAN :
JISIM 1 ATOM SULFUR = 2 X JISIM 1 ATOM OKSIGEN
= 2 X 16= 32
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JAWAPAN :
KATAKAN BILANGAN ATOM MAGNESIUM = N
JISIM N ATOM Mg = JISIM 2 ATOM Ag
N X 24 = 2 X 108N = 2 X 108 = 9
24
CONTOH 3 : BERAPA KALIKAH ATOM MAGNESIUM
AKAN SAMA JISIMNYA DENGAN DUA
ATOM PERAK? [JAR : Mg, 24; Ag, 108]
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PENGIRAAN JISIM MOLEKUL RELATIF @ JISIM FORMULA RELATIF
CONTOH 1 : HITUNG JISIM MOLEKUL BAGI
AIR [ Jar : H,1 ; O, 16]
JAWAPAN :
FORMULA UNTUK AIR IALAH H2O
Jmr H2O = 2H + O
= 2(1) + 16 = 18
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CONTOH 2 : KIRA JISIM MOLEKUL RELATIF BAGI
AMMONIA. [ Jar : N,14 ; H,1 ]
JAWAPAN :
FORMULA UNTUK AMMONIA IALAH NH3
Jmr NH3 = N + 3H
= 14 + 3(1)= 17
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CONTOH 3 : KIRA JISIM MOLEKUL RELATIF BAGI
ETANOL. [ Jar : C,12 ; H,1 ; O,16 ]
JAWAPAN :
JMR C2H5OH = 2C + 5H + O + H= 2(12) + 5(1) + 16 + 1= 46
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CONTOH 4 : HITUNGKAN JISIM FORMULA
RELATIF BAGI NATRIUM
KLORIDA [ Jar : Na,23 ; Cl,35.5 ]
JAWAPAN :
FORMULA NATRIUM KLORIDA IALAH NaCl
Jfr NaCl = Na + Cl
= 23 + 35.5= 58.5
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CONTOH 5 : KIRA JISIM FORMULA RELATIF BAGI
ALUMINIUM SULFAT. [Jar : Al,27 ; S, 32;O,16 ]
JAWAPAN :
FORMULA ALUMINIUM SULFAT IALAH Al2(SO4)3
Jfr Al2(SO4)3 = 2 Al + 3 SO4
= 2(27) + 3[ 32 + 4(16) ]= 342
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CONTOH 6 : KIRA JISIM FORMULA RELATIF BAGI
KUPRUM (II) SULFAT TERHIDRAT.
[JAR : Cu,64 ; S, 32 ; O,16 ]JAWAPAN :
FORMULA KUPRUM (II) SULFAT TERHIDRAT
IALAH CuSO4.5H2O
Jfr CuSO4.5H2O = Cu + S + 4O + 5H2O
= 64 + 32 + 4(16) + 5[2(1) +16]
= 250