exampleh-x.pdf
TRANSCRIPT
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Example
In the counterflow heat exchanger shown in Fig. 5-4, a flowrate of 0.5 kg/s of water enters one circuit of the heatexchanger at a temperature of 30C, and the same flow rateof water enters the other circuit at a temperature of 65C.The UA of the heat exchanger is 4 kW/K.
What is the mean temperature difference between the twostreams?
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( )12 cccp TTcmQ = &
mTUAQ =
( )2121
/ln TT
TTT
m
=
122
211
ch
ch
TTT
TTT
=
=
( )21 hhhp TTcmQ = &
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( ) ( )
( )( )( ) ( )
( )( ) ( )
( ) ( )
( ) ( )
( ) ( )1221
1221
1221
1221
12
1212
21
2121
:
kW/K2.095kW/K2.095kW/K2.095
K)]kJ/(kg.[4.19kg/s)(0.5kW/K2.095
K)]kJ/(kg.[4.19kg/s)(0.5
chchm
chch
cchh
cchh
cc
cccccp
hh
hhhhhp
TTTTT
TTTT
rearrange
TTTT
TTTTTT
TTTTcmQTT
TTTTcmQ
==
=
=
=
=
===
==
&
&
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( )( ) ( )
( ) ( )
( ) ( )( ) ( ) ( )
( ) ( )( ) ( )
( ) ( ) ( ) 12300305.42
0305.42
2792.1229093.2652792.579093.1
65kW/K2.095304
kW/K2.0954
kW/K2.095
9530653065
kW/K2.095
kW/2.095
1221
2
2
22
22
2112
211221
1221
22222
1221
12
21
====
=
==
==
===
==
=+==
=
=
=
chchm
h
h
hh
hh
hhch
hhchch
chchm
cchch
cchh
cc
hh
TTTTT
T
TTT
TT
TTTT
TTTTUATTUAQ
TTTTT
TTTTT
TTTT
TTQ
TTQ
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Example EVAPORATORS AND CONDENSERS A special set of equations is possible-and indeed necessary-when one of
the fluids flowing through a heat exchanger changes phase.
In an evaporator or condenser, as shown in Fig. 5-5, assume that there isno superheating or subcooling of the fluid that changes phase. That fluidwill then remain at a constant temperature, provided that its pressure does
not change.
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For a heat exchanger of known characteristics Eq. (5.10) can
be used to compute the outlet temperature of the fluid that doesnot change phase when its entering temperature and the
temperature of the boiling or condensing fluid tc are known.
The characteristic shape of the temperature curves of the two
fluids is shown in Fig. 5-6, applicable to a condenser.
( ) ( )
( ) ( )[ ] ( )
( ) ( )[ ] ( ) ( )[ ]
( ) ( )
( )( )p
p
cmUA
icio
ic
iiococic
cmUA
icococic
p
iopocic
ocic
etttt
tt
tttttttte
ttttttttcm
UA
ttcmtttt
ttttUAq
&
&
&
&
/
/
1
Then
/
givesantilogthetaking
/ln/ln
formtheintoconvertedbecan5.9Equation
/ln
+=
+==
==
=
=
The log-mean temperature difference still applies and in combination with a heatbalance gives
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Example 5.2.
Water is continuously heated from 25 to 50C by steamcondensing at 110C. If the water flow rate remains
constant but its inlet temperature drops to 15C, what will
its new outlet temperature be?
Solution. The terms U, A, m, cp, and tc all remain constant.
9.42
15110
15
25110
2550
1/
=
=
==
o
o
ic
iocmUA
ic
io
t
t
tt
tte
tt
tt p&
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Example What is the maximum rate of heat transfer possible in a
counterflow heat exchanger shown in Fig. 5-7 if water
enters at 30C and cools oil entering at 60C?
=
=
water)/(19.4
oil)/(2.2heatSpecific
water/5.1oil/6.2rateFlow
KkgkJ
KkgkJ
skgskg
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Solution: The break in the heat exchanger
indicates that to achieve the maximum rate ofheat transfer the area must be made infinite.
The next question, then, is: What are the
outlet temperatures? Does the oil leave at30C, or does the water leave at 60C?
From energy balances those two options give
the following consequences:
1. Oil leaves at 30C
3.57)]/(19.4)[/5.1(
6.17130
6.171)3060)](/(2.2)[/6.2(
=+
==
kgKkJskg
kW
avesandwaterle
kWkgKkJskgq
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2 water leaves at 60
The second case is clearly impossible because
the oil temperature would drop below that of theentering water, which would violate the second
law of thermodynamics. Thus, qmax = 171.6 kW.
272.26.2
6.18860
6.188)3060(19.45.1
=
== kWq
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( )( ) fluidstwotheofsmallertheiswhere
)(
min
,,min
pp
incoldinhotp
actual
wccm
ttcm
q
&
& =
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Example Compute the effectiveness of a counterflow heat
exchanger having a U value of 1.1 kW/(m2. K) and an
area of 16 m2 when one fluid has a flow rate of 6 kg/s
and a specific heat of 4.1 kJ/(kg .K) and the other fluid a
flow rate of 3.8 kg/s and a specific heat of 3.3 kJ/(kg .K).
( )
668.51.
1
5.13Eq.Formand
686..51-11.4D5.14Eq.From
67.5.9Fig.From
4.154.12
161.1
Wdesignate54.123.38.3
6.241.46
686.
686.
min
min
=
=
==
=
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e
e
C
UANTU
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a