exampleh-x.pdf

Upload: osamaalkhateeb

Post on 02-Jun-2018

219 views

Category:

Documents


0 download

TRANSCRIPT

  • 8/11/2019 ExampleH-X.pdf

    1/13

    Example

    In the counterflow heat exchanger shown in Fig. 5-4, a flowrate of 0.5 kg/s of water enters one circuit of the heatexchanger at a temperature of 30C, and the same flow rateof water enters the other circuit at a temperature of 65C.The UA of the heat exchanger is 4 kW/K.

    What is the mean temperature difference between the twostreams?

  • 8/11/2019 ExampleH-X.pdf

    2/13

    ( )12 cccp TTcmQ = &

    mTUAQ =

    ( )2121

    /ln TT

    TTT

    m

    =

    122

    211

    ch

    ch

    TTT

    TTT

    =

    =

    ( )21 hhhp TTcmQ = &

  • 8/11/2019 ExampleH-X.pdf

    3/13

    ( ) ( )

    ( )( )( ) ( )

    ( )( ) ( )

    ( ) ( )

    ( ) ( )

    ( ) ( )1221

    1221

    1221

    1221

    12

    1212

    21

    2121

    :

    kW/K2.095kW/K2.095kW/K2.095

    K)]kJ/(kg.[4.19kg/s)(0.5kW/K2.095

    K)]kJ/(kg.[4.19kg/s)(0.5

    chchm

    chch

    cchh

    cchh

    cc

    cccccp

    hh

    hhhhhp

    TTTTT

    TTTT

    rearrange

    TTTT

    TTTTTT

    TTTTcmQTT

    TTTTcmQ

    ==

    =

    =

    =

    =

    ===

    ==

    &

    &

  • 8/11/2019 ExampleH-X.pdf

    4/13

    ( )( ) ( )

    ( ) ( )

    ( ) ( )( ) ( ) ( )

    ( ) ( )( ) ( )

    ( ) ( ) ( ) 12300305.42

    0305.42

    2792.1229093.2652792.579093.1

    65kW/K2.095304

    kW/K2.0954

    kW/K2.095

    9530653065

    kW/K2.095

    kW/2.095

    1221

    2

    2

    22

    22

    2112

    211221

    1221

    22222

    1221

    12

    21

    ====

    =

    ==

    ==

    ===

    ==

    =+==

    =

    =

    =

    chchm

    h

    h

    hh

    hh

    hhch

    hhchch

    chchm

    cchch

    cchh

    cc

    hh

    TTTTT

    T

    TTT

    TT

    TTTT

    TTTTUATTUAQ

    TTTTT

    TTTTT

    TTTT

    TTQ

    TTQ

  • 8/11/2019 ExampleH-X.pdf

    5/13

    Example EVAPORATORS AND CONDENSERS A special set of equations is possible-and indeed necessary-when one of

    the fluids flowing through a heat exchanger changes phase.

    In an evaporator or condenser, as shown in Fig. 5-5, assume that there isno superheating or subcooling of the fluid that changes phase. That fluidwill then remain at a constant temperature, provided that its pressure does

    not change.

  • 8/11/2019 ExampleH-X.pdf

    6/13

    For a heat exchanger of known characteristics Eq. (5.10) can

    be used to compute the outlet temperature of the fluid that doesnot change phase when its entering temperature and the

    temperature of the boiling or condensing fluid tc are known.

    The characteristic shape of the temperature curves of the two

    fluids is shown in Fig. 5-6, applicable to a condenser.

    ( ) ( )

    ( ) ( )[ ] ( )

    ( ) ( )[ ] ( ) ( )[ ]

    ( ) ( )

    ( )( )p

    p

    cmUA

    icio

    ic

    iiococic

    cmUA

    icococic

    p

    iopocic

    ocic

    etttt

    tt

    tttttttte

    ttttttttcm

    UA

    ttcmtttt

    ttttUAq

    &

    &

    &

    &

    /

    /

    1

    Then

    /

    givesantilogthetaking

    /ln/ln

    formtheintoconvertedbecan5.9Equation

    /ln

    +=

    +==

    ==

    =

    =

    The log-mean temperature difference still applies and in combination with a heatbalance gives

  • 8/11/2019 ExampleH-X.pdf

    7/13

  • 8/11/2019 ExampleH-X.pdf

    8/13

    Example 5.2.

    Water is continuously heated from 25 to 50C by steamcondensing at 110C. If the water flow rate remains

    constant but its inlet temperature drops to 15C, what will

    its new outlet temperature be?

    Solution. The terms U, A, m, cp, and tc all remain constant.

    9.42

    15110

    15

    25110

    2550

    1/

    =

    =

    ==

    o

    o

    ic

    iocmUA

    ic

    io

    t

    t

    tt

    tte

    tt

    tt p&

  • 8/11/2019 ExampleH-X.pdf

    9/13

    Example What is the maximum rate of heat transfer possible in a

    counterflow heat exchanger shown in Fig. 5-7 if water

    enters at 30C and cools oil entering at 60C?

    =

    =

    water)/(19.4

    oil)/(2.2heatSpecific

    water/5.1oil/6.2rateFlow

    KkgkJ

    KkgkJ

    skgskg

  • 8/11/2019 ExampleH-X.pdf

    10/13

    Solution: The break in the heat exchanger

    indicates that to achieve the maximum rate ofheat transfer the area must be made infinite.

    The next question, then, is: What are the

    outlet temperatures? Does the oil leave at30C, or does the water leave at 60C?

    From energy balances those two options give

    the following consequences:

    1. Oil leaves at 30C

    3.57)]/(19.4)[/5.1(

    6.17130

    6.171)3060)](/(2.2)[/6.2(

    =+

    ==

    kgKkJskg

    kW

    avesandwaterle

    kWkgKkJskgq

  • 8/11/2019 ExampleH-X.pdf

    11/13

    2 water leaves at 60

    The second case is clearly impossible because

    the oil temperature would drop below that of theentering water, which would violate the second

    law of thermodynamics. Thus, qmax = 171.6 kW.

    272.26.2

    6.18860

    6.188)3060(19.45.1

    =

    == kWq

  • 8/11/2019 ExampleH-X.pdf

    12/13

    ( )( ) fluidstwotheofsmallertheiswhere

    )(

    min

    ,,min

    pp

    incoldinhotp

    actual

    wccm

    ttcm

    q

    &

    & =

  • 8/11/2019 ExampleH-X.pdf

    13/13

    Example Compute the effectiveness of a counterflow heat

    exchanger having a U value of 1.1 kW/(m2. K) and an

    area of 16 m2 when one fluid has a flow rate of 6 kg/s

    and a specific heat of 4.1 kJ/(kg .K) and the other fluid a

    flow rate of 3.8 kg/s and a specific heat of 3.3 kJ/(kg .K).

    ( )

    668.51.

    1

    5.13Eq.Formand

    686..51-11.4D5.14Eq.From

    67.5.9Fig.From

    4.154.12

    161.1

    Wdesignate54.123.38.3

    6.241.46

    686.

    686.

    min

    min

    =

    =

    ==

    =

    =

    ==

    ==

    ==

    e

    e

    C

    UANTU

    C

    C

    b

    a