exercise to treat spin-dependent decays

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Exercise to treat spin-dependent decays I. Goal: Study the relationship between momentum p e accuracy/precision and a, Analyzing power <A>. Estimate the required performance of the detector. Tool: GEANT4 1 II.Exercise to check basic kinetics: 1. Energy and momentum conservation, 2. 2D event yield distribution as functions of y and cm S y = p cm e /p max cm S is an angle between spin-axis and momentum direction of decay-e + at the center-of- mass system. ( see next page) III.Check wiggle plots: “usual” wiggle plot, Today’s contents

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Exercise to treat spin-dependent decays . Tool: GEANT4 . Goal: Study the relationship between momentum p e accuracy/precision and  a , Analyzing power . Estimate the required performance of the detector . Today’s contents. Exercise to check basic kinetics: - PowerPoint PPT Presentation

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Page 1: Exercise to treat spin-dependent decays

Exercise to treat spin-dependent decays

I. Goal:– Study the relationship between momentum pe

accuracy/precision and a, Analyzing power <A>. – Estimate the required performance of the detector.

Tool: GEANT4

1

II. Exercise to check basic kinetics:1. Energy and momentum conservation,2. 2D event yield distribution as functions of y and cmS

y = pcme/pmax

cmS is an angle between spin-axis and momentum direction of

decay-e+ at the center-of-mass system. ( see next page)

III. Check wiggle plots:“usual” wiggle plot,“Beam-loss free” wiggle plot.

Today’s contents

Page 2: Exercise to treat spin-dependent decays

0,tsin,tcosS aa

Center-of-Mass system

taX,

Y

Z

Momentum

sinsin,cossin,cospp m

cmmcm

mcm

e

eDirection of decay-positron

mcm

ZB,0,0B

Magnetic field

Spin-direction

mcm

mcmm

Lab cos1cos

cos

,mLabWe measure . Lorentz boost

2

tcoscostsincossinSppcos a

mcma

mcm

e

eScm

Scm

Angle between spin-axis and momentum direction of decay-e+ at the center-of-mass system:

Page 3: Exercise to treat spin-dependent decays

2

mp

ppy

maxe

maxee

.y231y2yA ,y23yyn

,sincosyA1yn21

dyddP

2

Monte Carlo

Expected 2D event yield distribution as functions of y and cmS

3

Page 4: Exercise to treat spin-dependent decays

Monte Carlo

4

Page 5: Exercise to treat spin-dependent decays

P=300MeV/c , =3,Tc =7.4nsec, R=333mm,Ta=2/a=2.2sec.

Positron energies28 ~191 MeV

GEANT4B3 T

Condition:

5

Page 6: Exercise to treat spin-dependent decays

8.6MeV positron

50.4MeV positron

GEANT4

102MeV positron

B = 3T

6

Page 7: Exercise to treat spin-dependent decays

II. Check basic kinetic values from GEANT4

7

Page 8: Exercise to treat spin-dependent decays

Probing Spin-dependent Decay Info.

I. To be more simple, I set 100% ! II. Probe “decay process” information in the lab frame

directly. (I use “UserSteppingAction”.) Spin vector, momentum of at previous step of decay

process. Momentum and energies of daughters.

III. Check momentum/energy conservation. Within few eV at =1, within few keV at =3. why?

IV. Apply Lorentz transformation to get values in the center-of-mass system.

V. Cook values as I want!!

ee

8

Page 9: Exercise to treat spin-dependent decays

2

mp

ppy

maxe

maxee

GEANT4

XL

2Z

2YT

ppppp

2Z

2Y

2Xe pppp

X axis is always -momentum direction.

9

Page 10: Exercise to treat spin-dependent decays

Monte Carlo vs. GEANT4

y = pcme/pmax

is an angle between spin-axis and momentum direction of decay-e+ at the center-of-mass system.

10

Page 11: Exercise to treat spin-dependent decays

Monte Carlo

GEANT4

11

Page 12: Exercise to treat spin-dependent decays

III. Wiggle plots made by GEANT4

12

“Usual” wiggle plot and “Beam-loss free” wiggle plot

Page 13: Exercise to treat spin-dependent decays

tcosA1texpNtF a

4 free parametersCovariant matrix is OK.9.5 105 , E> 200 MeV 1.3105e+

13

Page 14: Exercise to treat spin-dependent decays

tcoscosA12N

tcoscostdydsinyayndyyn21tN

tcoscosya12yn

dydsindP

dyddP

.tcoscostsincossincos ,here

,cosya1yn41

dyddP

amcm

amomcm

y

Scm

Scm

y

amomcmS

cmScmcm

amomcma

momcm

Scm

Scm

cm

Scm

tcosAtRtLtRtLtAsym

,tcosA12N

tR ,tcosA12N

tL

a

aa

“Beam loss free” wiggle plot by knowing

momcm

Measure!

An angle between + and e+ momentum direction in the center-of-mass system.

No exponential term! 14

Page 15: Exercise to treat spin-dependent decays

LEFT RIGHT

tcosAtAsym a

No worry about -beam loss! But, need to handle left-right

detector asymmetry.9.5 105 , 1.9 105 e+ y> 0.6 , LEFT: 1 cos 0.7RIGHT:1 cos 1 0.7

15

Page 16: Exercise to treat spin-dependent decays

A big advantage to measure

.y

Ecos

,cosddyyn

cosdydcosyayn

A

thLabS

cm

cos

Scm

y

y cos

Scm

Scm

LAB

Scm

Scm

.

dyyn

dyyaynA

y

yCM

Lab-frame

Center-of-mass frame

”Effective Analyzing Power” is smeared by cos cm S

If we can measure cm S event-by-

event, ”Effective Analyzing Power” is NOT smeared by cos cm

S!

Spincm

We have bigger effective Analyzing Power 16

Page 17: Exercise to treat spin-dependent decays

Next things….

I. Study the relationship between measured momentum accuracy/precision and a, Analyzing power <A>.

II. Estimate the required performance of the detector.

Now, I am ready to think about detector performance.

I, also, will play with G4-beamline to think about -beam line. (Need a time to learn it, though.)

17

Page 18: Exercise to treat spin-dependent decays

18

How many positrons we need for EDM ?Value [e cm] statistics comment

Exp. results

( 3.7 3.4 ) 1019

(0.04 1.6 0.17) 1019

( 0.1 0.2 1.07 )1019

11.4106 e+, e

9.4106 e+

975 106 e

CERN (1974~76)E821 (1999, 2000, Trace back detector, Fig .7)*E821 ( 2001, PSD1-5, Tbl. IV)*

Predic-tion

(1.4 1.5 ) 1025   Mass scale of lepton EDMs

> 10 -23 Extended SM modelOur goal

1022 level 1024 level

~1013 @ magic=29.3~1017@ magic=29.3

~ 31014 @ =3~ 31018@ =3

cme107.4cm2

e2

EDM 14

em

Bt2 t

0

et

0e

sume

sume1

0e1

NtexpN~N

,N2AA

1

N2AA

1

EDM sensitivity:

m2eBA1

“Improved Limit on the Muon Electric Dipole Moment “ 2EAPS/123-QCD

Page 19: Exercise to treat spin-dependent decays

y vs. cos

.y231y2yA ,y23yyn

cosyA1yn21

cosdyddP

2

y

cos

19

Page 20: Exercise to treat spin-dependent decays

20

a

00

etotal

a0e

AN21

NdttNN

,tcostexpNtN

*a

*a

*

20

*2*0

**a

0**0

**00total

,AN21

AN21

,NN

,NNN

ミュービーム強度はによらず、一定だとし、(Ntotal=const.)

I checked with Toy Monte Carlo

Relationship between a and