exploatare secundara
TRANSCRIPT
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Proiectarea exploatari unei sonde prin injectie ciclica
de abur
n 1:=
Sa se proiecteze o operatie de injectie ciclica de abur la o sonda la
care se cunosc urmatoarele date:
C 273.15K :=in 0.0254:=
n 1:=kcal 414:=
! 400 20 n⋅+" #:= ! 420= $adincimea pina la capatul per%oraturilor
& 7 0.4 n⋅+" #:= & 7.4= $'rosimea inter(alului per%orat
de 0.0)03:=d*+ 2
3
+ i:= $diametrul te(ilor de e,tractie
di 0.0503:=
k r 2.25 414⋅:= - $conducti(itatea termica a rocii
k r .414 103×= -
/ 0.003:= $coe%icientul de di%uzibilitate termica
/ 3. 103−×=
13.25 414⋅:= - $coe%icientul 'lobal de transmitere a caldurii de la
interiorul te(ilor de e,tractie la e,teriorul coloanei
5.543 104×=
/e 0.137:=/C+ 5
1
2+
i:= $diametrul coloanei de e,ploatare/i 0.1273:=
a 0.032:= b 10:= bar 105:=
ts a !⋅ b+:= $'radient 'eotermic
ts 23.44=
m 23.5:= $porozitate
Sa 23 n+" #:= Sa 0.24= $saturatia in apa
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ρa 1000:= $densitatea apei
ρr 24)5:= $densitatea rocii
ρt 25 ) n⋅−" #:= ρt 1= $densitatea titeiului
cr 0.2355 414×:= $caldura speci%ica a rocii
$caldura speci%ica a apeica 1 414⋅:= -
ct 0.71 414×:= ct 2.70)4 103×= $caldura speci%ica a titeiului
,0 0.:= $titlul aburului
pinj )0:= pentru aceasta presiune aburul are urmatoarele propietati:
*s 274.2:=
iabur 2.74033) 10)⋅:=
ia 1.20)2472 10)⋅:=
5500 110 n⋅+" #:= $debit masic de abur 5)10=
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Metodologia de proiectare pentru un proces de injectie
ciclica de abur
1.Se calculeaza entalpia aburului la supra%ata
i ,0 iabur ⋅ 1 ,0−( ) ia⋅+:=i 2.4)47) 10
)×=
i 2.47012 10)⋅:=
2.Se calculeaza cantitatea totala de caldura injectata in sonda la supra%ata
t 24:=
os i⋅ ⋅:= os 3.3257 1011×=
$calculul se (a %ace pe zile
k 0 20..:=tk 24 k ⋅:= t0 1:= tk
1
24
48
72
96
120
144
168
192
216
240
264
288
312
336
360
384
408
432
456
480
=
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3.Se determina (aloarea %unctiei %"t#
r 1
di
2:= r 2
/e
2:=
τ/ t⋅
r 22
:=r 1 ⋅k r
0.1410)=
lo'% τk
0.35−0.20
0.25
0.30
0.34
0.37
0.3
0.41
0.44
0.4)
0.4
0.50
0.52
0.54
0.5)
0.57
0.5
0.5
0.)0
0.)1
0.)2
:=% τ
k 10
lo'% τk :=
% τ
k
0.446684
1.584893
1.778279
1.995262
2.187762
2.344229
2.454709
2.570396
2.754229
2.884032
3.019952
3.162278
3.311311
3.467369
3.630781
3.715352
3.801894
3.890451
3.981072
4.073803
4.168694
=
τ
0
0
1
2
3
4
5
6
7
8
9
10
11
12
13
1415
16
17
18
19
20
0.79934
19.184171
38.368341
57.552512
76.736682
95.920853
115.105024
134.289194
153.473365
172.657535
191.841706
211.025877
230.210047
249.394218
268.578388287.762559
306.94673
326.1309
345.315071
364.499241
383.683412
= lo' τ( )
0
0
1
2
3
4
5
6
7
8
9
10
11
12
13
1415
16
17
18
19
20
-0.097268
1.282943
1.583973
1.760064
1.885003
1.981913
2.061094
2.128041
2.186033
2.237186
2.282943
2.324336
2.362124
2.396886
2.4290712.459034
2.487063
2.513392
2.538216
2.561697
2.583973
=
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4.Se calculeaza cantitatea de caldura cedata stratelor tra(ersate de sonda6la
un anumit moment de timp considerat de la inceputul procesului de injectie
ck
2 π⋅ r 1⋅ ⋅ k r ⋅
k r r 1 ⋅+ % τk
+*s b−( ) !⋅
a !2⋅
2−
⋅:=
7ck
88.254109·10
88.25324·10
88.253093·10
88.252927·10
88.25278·10
88.25266·10
88.252576·10
88.252488·10
88.252347·10
88.252248·10
88.252145·10
88.252036·10
88.251922·1088.251803·10
88.251678·10
88.251614·10
88.251548·10
88.25148·10
88.251411·10
88.25134·10
88.251268·10
=
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Se calculeaza cantitatea de caldura cedata stratelor tra(ersate
c1
c0
c1
+
223⋅:=
c1
1.345 1010×=
k 2 20..:=
ck
ck 1− ck +2
24⋅:=
k 1 20..:=
3ck
101.898345·10
101.98076·10
101.980722·10
101.980685·10
101.980653·10
101.980628·10
101.980608·10
101.98058·10
101.980552·10
101.980527·10
101.980502·10
101.980475·10
101.980447·10
101.980418·10
101.980395·10
101.980379·10
101.980363·10
101.980347·10
101.98033·10
101.980313·10
=
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5.Se determina cantitatea de caldura ima'azinata in abur cind
acesta ajun'e la intrarea in strat
isk
os ck
−:=3
isk 113.135946·10
113.127704·10
113.127708·10
113.127712·10
113.127715·10
113.127718·10
113.12772·10
113.127722·10
113.127725·10
113.127728·10
113.12773·10
113.127733·10
113.127736·10
113.127739·10
113.127741·10
113.127742·10
113.127744·10
113.127746·10
113.127747·10
113.127749·10
=
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).Se determina titlul aburului la intrarea in strat
Con%orm punctului doi entalpia aburului la intrarea in strat este:
k 1 20..:=
,isk
1
k
i
isk ∑
= tk ⋅ iabur ia−( )⋅
ia
iabur ia−−:=
,isk
0.711685
0.707805
0.707807
0.707809
0.70781
0.707811
0.707812
0.707814
0.707815
0.707816
0.707817
0.707819
0.707820.707821
0.707822
0.707823
0.707824
0.707825
0.707826
0.707826
=
0 100 200 300 400 5000.70)
0.70
0.71
0.712
,isk
tk
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7.Se calculeaza cantitatea de caldura ima'azinata de un metru cub de
roca impreuna cu %luidele continute in pori
St 1 Sa−:=St 0.7)=
8 1 m−( ) ρr cr ⋅ m ρa⋅ ca⋅ Sa⋅+ m ρ t⋅ ct⋅ S⋅+:=
8 2.51)24 10)×=
.Se determina (aloarea parametrului adimensional 9
92 k r ⋅ t⋅
8 &⋅ /⋅:=
9
0.015781
0.077313
0.109337
0.13391
0.154626
0.172877
0.189378
0.204551
0.218674
0.231939
0.244485
0.256418
0.26782
0.278756
0.289279
0.299432
0.309252
0.31877
0.328011
0.337
0.345754
=
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.Se determina e%icienta termica a procesului
k 0 20..:=
+tk
1
9k ( )2
e9k ( ) 2
er%c 9k ( )⋅2 9k ⋅
π+ 1−
:=
+t
0.988252
0.944696
0.923357
0.907559
0.894612
0.883478
0.873624
0.864735
0.856607
0.849097
0.842103
0.835546
0.829368
0.823519
0.817961
0.812662
0.807596
0.802741
0.798077
0.793588
0.789259
=
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10.Se determina caldura cedata stratelor adiacente
cak
1 +tk
−( ) isk
⋅:=
3cak
0
101.734292·10
102.397155·10
102.891276·10
103.296218·10
103.644481·10
103.952694·10
104.230712·10
104.484944·10
104.719829·10
104.938592·10
105.143662·10
105.336923·10
105.519871·10
10
5.693713·10105.859444·10
106.017891·10
106.169757·10
106.315638·10
106.456049·10
106.591436·10
=
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11.Se calculeaza raza sondei incalzite ca raza interioara a zonei in(adata
de apa calda
isk
1
k
i
isk ∑
=tk
:= isk
iabur ,isk
⋅ 1 ,isk
−( ) ia⋅+⋅:=
3is
0
0
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
0
101.306644·10
101.30321·10
101.303212·10
101.303213·10
101.303215·10
101.303216·10
101.303216·10
101.303218·10
101.303219·10
101.30322·10
101.303221·10
101.303222·10
101.303223·10
101.303224·10
101.303225·10
101.303226·10
101.303227·10
101.303227·10
101.303228·10
101.303229·10
= :is
0
0
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
96.767047·10
101.306644·10
101.30321·10
101.303212·10
101.303213·10
101.303215·10
101.303216·10
101.303216·10
101.303218·10
101.303219·10
101.30322·10
101.303221·10
101.303222·10
101.303223·10
101.303224·10
101.303225·10
101.303226·10
101.303227·10
101.303227·10
101.303228·10
101.303229·10
=
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Supra%ata zonei incalzite se determina cu relatia
;k
isk
8⋅ /⋅ &⋅
4 k r 2⋅ *s ts−( )⋅
e9k ( ) 2
er%c 9k ( )⋅2 9k ⋅
π+ 1−
:=
;
0
61.819
120.52765
177.698453
233.551608
288.306232
342.108886
395.066336
447.260782
498.757699
549.610803
599.865335
649.559857
698.727758
747.398291
795.597136
843.34734
890.669833
937.583392
984.105098
31.030251·10
=
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Se determina raza zonei incalzite
r k ;k
π:=
r
0
4.435944
6.19396
7.520849
8.622168
9.579704
10.435355
11.213988
11.931786
12.59998
13.226736
13.818215
14.379198
14.913482
15.424146
15.913718
16.384316
16.837726
17.275476
17.698881
18.109085
=
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12.Se determina raza zonei ocupate de abur la %iecare moment de timp
r iabur ia−:= $caldura latenta de condensare
isk
,isk
⋅ r⋅:=
3isk
0
0
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
0
96.299394·10
96.265055·10
96.26507·10
96.265086·10
96.265099·10
96.265109·10
96.265118·10
96.26513·10
96.265141·10
96.265152·10
96.265162·10
96.265173·10
96.265185·10
96.265197·10
96.265207·10
96.265213·10
96.26522·10
96.265227·10
96.265234·10
96.265241·10
=
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;k
isk
8⋅ /⋅ &⋅
4 k r 2⋅ *s ts−( )⋅
e9k ( ) 2
er%c 9k ( )⋅2 9k ⋅
π+ 1−
:=
rk ;k
π:=
;k
0
29.803238
57.942483
85.426895
112.277931
138.600899
164.466231
189.925256
215.017558
239.774586
264.222114
288.381935
312.272588
335.91013
359.308626
382.480321
405.43627
428.18663
450.740426
473.105873
495.290479
= rk
0
3.080043
4.294609
5.214617
5.978225
6.642141
7.235415
7.775287
8.272981
8.736282
9.170851
9.580961
9.969927
10.340383
10.694461
11.033914
11.36021
11.674589
11.978111
12.271686
12.556108
=