extra class for from exam math sem 1

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SPM Mathemati cs Form 5 Chapter 2: Graph Of Function II 超超 2011 SPM 13 超超超 我我我我我我我我 我我我我我我我我 1. 2. 1 [KEDAH NO. 1] On the graph in the answer space, shade the region which satisfy the three inequalities y. [3 marks] 3. 4. [PERLIS NO. 1] [PERAK NO. 1] [NEGERI SEMBILAN NO. 1] On the graph provided , shade the region which satisfy the three inequalities [3 marks] On the graph in the answer space, shade the region which satisfy the three inequalities 2. [3 marks] On the graph in the answer space, shade the region which satisfy the three inequalities [3 marks]

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SPMMathematicsForm 5 Chapter 2: Graph Of Function II 2011SPM 13

1.

2.

1 [KEDAH NO. 1]

3.

4.

[PERLIS NO. 1] [PERAK NO. 1][NEGERI SEMBILAN NO. 1]

SPMMathematicsForm 5 Chapter 2: Graph Of Function II 2011SPM 13

5.

6.2[TERENGGANU NO. 1]

7.

8. [JOHOR NO. 1] [MELAKA NO. 1] [SBP NO. 1]

SPMMathematicsForm 5 Chapter 2: ANSWER 2011SPM 13

1.KEDAH NO.1

2.PERAK NO.1

13.PERLIS NO.1

x

4.NEGERI SEMBILAN NO.1SPMMathematicsForm 5 Chapter 2: ANSWER 2011SPM 13

5.TERENGGANU NO.16.MELAKA NO.1

xy

27.JOHOR NO.18.SBP NO.1

SPMMathematicsForm 5 Chapter 2: Graph of function 2011SPM 13

6.[ Negeri Sembilan NO.12 ]

(b) For this part of the question , use the graph paper provided on page 21.You may use a flexible curve ruler.Using a scale of 2cm to 1 unit on the x-axis and 2cm to 10 unit on the y-axis , draw the graph of y = -x+4x+5 for -4 4. [4 marks](c) From your graph, findThe value of y when x = 3.5,The value of x when y = 15. [2 marks](d) Draw a suitable straight line on your graph to find all values of x which satisfy the equation x=14 x +10 for -4 4. State these values of x. [4 marks]Answer:X-4-3-2-101234Y5352585-10(b)Refer graph on page 21.(c) (i) y=______________________________ (ii)x=_______________________________(d) The equation of the straight line:______________________X = _________________________________________Table(a)[3 marks]65

SPMMathematicsForm 5 Chapter 3: Transformation 2011SPM 13

8.

Diagram shows points J and K drawn on a Cartesian plane.15SPMMathematicsForm 5 Chapter 3: Transformation 2011SPM 13

[ Melaka NO.13 ]

(b) Diagram shows three quadrilaterals , ABCD , JKLM and PQLR drawn on a Cartesian plane.

(i) PQLR is the image of ABCD under the combined transformation VU. Describe in full the transformation:(a) U(b) V

(ii) It is given that the area of the shaded region PQKJMR is 152cm. Calculate the area , in cm , of ABCD. [8 marks]16

(a) (i) (3,4)2Note: (1,2) seen or marked , award 1 mark (ii) (6,0)2Note: (6,6) seen or marked , award 1 mark

(b) (i) (a) U-Rotation, 180, about centre (8,3)3Note: (1) Rotation only award 1 mark (2) Rotation 180, award 2 marks (3) Rotation, centre (8,3), award 2 marks (b) V: Enlargement with scale factor =3 , centre=L.3Note:1. Enlargement with scale factor =3 only @ Enlargement at centre L award 2 marks 2. Enlargement only award 1 mark (ii) 3 (area of ABCD)-area of ABCD=152 or equivalent1 area of ABCD=191 12